I have strings like this:
<img src="http://www.example.com/app_res/emoji/1F60A.png" /><img src="http://www.example.com/app_res/emoji/1F389.png" />
<img src="http://www.example.com/app_res/emoji/1F61E.png" /><img src="http://www.example.com/app_res/emoji/1F339.png" />
I want them to be like this:
😊 🎉
😞 🌹
In Notepad++, I tried this :
Find what: ^\s*<img src="http://www.example.com/app_res/emoji/(1F.*).png" />
Replace with: &#x\1;
The result is not as expected:
😊.png" /><img src="http://www.example.com/app_res/emoji/1F389;
How to best isolate the regular expression ?
Any help is welcome ! Thank you
You're using the unspecific . together with the greedy star *. Don't do that here, as this tends to overshoot the target.
Be more specific.
The file name (in your case) does not contain dot's. Let's use "anything except a dot" ([^.]*) instead of "anything" (.*):
^\s*<img src="http://www.example.com/app_res/emoji/(1F[^.]*).png" />
You may try the following find and replace, in regex mode:
Find: <img src=".*?/([A-Z0-9]+\.\w+"\s*/><img src=".*?/([A-Z0-9]+\.\w+"\s*/>
Replace: &#x$1; &#x$2;
Here is a working regex demo.
Try
Find:^<.*?/(1\w+).*?/(1\w+).*
Replace:&#x$1; &#x$2;
Related
I want to find the following pattern:
Image not found: /Images/IMG-20160519-WA0015.jpg
And replace with some markup, including the image name from the above text like:
<a href="IMG-20160519-WA0015.jpg"><img src="IMG-20160519-WA0015.jpg" width="180" height="240" alt="IMG-20160519-WA0015.jpg" class="image" />
Is it possible with some kind of Regex or plugin or I'm simply burning neurones?
Thanks.
Try finding ^Image not found: \/Images\/(IMG-.*\.jpg) and replacing with <a href="\1"><img src="\1" width="180" height="240" alt="\1" class="image" />
Note that the caret (^) in the regex says that it must be at the beginning of the line, not sure if that's the case for you but I suspect that it is. I also assumed that the "IMG-" prefix is constant, if not then you can just remove those four characters from the regex.
If you're not aware of it, RegExr is a nice interactive way to build and test regular expressions.
EDIT: Since you mentioned having trouble in the comments, here's an image of my settings:
I need some help with Regular expression to Search and Replace in Sublime to do the following.
I have HTML-code with links like
href="http://www.example.com/test=123"
href="http://www.example.com/test=6546"
href="http://www.example.com/test=3214"
I want to replace them with empty links:
href=""
href=""
href=""
Please help me to create a Reg. ex. filter to match my case. I guess it would sound like "starts with Quote, following with http:// .... ends with Quote and has digitals and '=' sign", but I'm not very confident of how to write this in Reg. ex. way.
(?<=href=")[^"]*
Try this.Replace by empty string.
See demo.
https://regex101.com/r/sH8aR8/40
I'm trying to sanitize HTML tags, e.g. turn
<input type="image" name="name" src="image.png">
into the correct empty-element form
<input type="image" name="name" src="image.png" />
with a slash at the end.
I'm using Eclipse's Find/Replace with regular expressions like this:
Find: <(input .*)[^/]>
Replace with: <\1 />
But I end up with
<input type="image" name="name" src="image.png />
I.e. the last quote is missing.
Is that an error in my regex, or a bug in Eclipse?
The term [^/] is consuming the quote. Move it inside the captured group:
Find: <(input .*[^/])>
Replace: <\1 />
The error is in your regex. The [^/] at the end captures the last non-> character. \1 represents the first capturing group, which would be (input.*). In short, you are getting everything inside the tag except the last character. If you put the [^\] inside your group, your replace should work.
Also, you may run into issues if you have a / inside of one of your attribute values. For performance reasons, I would recommend using the following regex:
<(input [^/]*(/[^/]*)*)>
In this case, it does not have to backtrack if you have a / inside of one of your attributes. Your regex should capture everything you need though.
I was trying the replace-regexp command in Emacs but I've no idea about how to construct the right regexp. My file looks like the following:
<img src="http://s.perros.com/content/perros_com/imagenes/thumbs/1lundehund2.jpg" />
<img src="http://s.perros.com/content/perros_com/imagenes/thumbs/1pleon2.jpg" />
And I want to replace for:
<img src="" class="class-1lundehund2.jpg" />
<img src="" class="class-1pleon2.jpg" />
I was using this regexp with no success (Replaced 0 occurrences):
M-x replace-regexp
Replace regexp: src\=\"http\:\/\/s\.perros\.com\/content\/perros_com\/imagenes\/thumbs\/\([a-zA-Z0-9._-]+\)\"
Replace regexp with: src\=\"\" class\=\"class-\1\"
But in re-builder mode with the same regexp (changing \([a-zA-Z0-9.-]+\) by \\([a-zA-Z0-9.-]+\\)) all the results are right highlighted. I've no idea of what's happening, any tip?
I think you're escaping too many things. regexp = src="http://s\.perros\.com/content/perros_com/imagenes/thumbs/\([^"]*\)", replacement = src="" class="class-\1"
In my HTML I have below tags:
<img src="../images/img.jpg" alt="sometext"/>
Using regex expression I want to remove alt=""
How would I write this?
Update
Its on movable type. I have to write it a like so:(textA is replaced by textB)
regex_replace="textA","textB"
Why don't you just find 'alt=""' and replace it with ' ' ?
On Movable Type try this:
regex_replace="/alt=""/",""
http://www.movabletype.org/documentation/developer/passing-multiple-parameters-into-a-tag-modifier.html
What regex you are asking for ? Straight away remove ..
$ sed 's/alt=""//'
<img src="../images/img.jpg" alt=""/>
<img src="../images/img.jpg" />
This does not requires a regex.
The following expression matches alt="sometext"
alt=".*?"
Note that if you used alt=".*" instead, and you had <img alt="sometext src="../images/img.jpg"> then you would match the whole string alt="sometext src="../images/img.jpg" (from alt=" to the last ").
The .* means: Match as much as you can.
The .*? means: Match as little as you can.
s/ alt="[^"]*"//
This regex_replace modifier should match any IMG tag with an alt attribute and capture everything preceding the alt attribute in group #1. The matched text is then replaced with the contents of group #1, effectively stripping off the alt attribute.
regex_replace='/(<img(?:\s+(?!alt\b)\w+="[^"]*")*)\s+alt="[^"]*"/g','$1'
Is that what you're looking for?