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How can I get from string "C27_W112_V113_Table__6__1" string "6" or from string "C27_W120_V153_Table__22__1" string "22". thx
You can achieve it by two ways
Regex approach:
const re = /(\d+)__\d+$/;
let values = [
'C27_W112_V113_Table__6__1',
'C27_W120_V153_Table__22__1'
];
values.forEach(str => console.log(str.match(re)[1]));
string manipulation (I assume the value is always at the same place):
values.forEach(str => {
let reversed = str.split('').reverse().join('');
let index = reversed.indexOf('__');
console.log(reversed.slice(index+2, reversed.indexOf('__', index+1)));
});
Here a snippet
const re = /(\d+)__\d+$/;
let values = [
'C27_W112_V113_Table__6__1',
'C27_W120_V153_Table__22__1'
];
values.forEach(str => console.log(str.match(re)[1]));
console.log('--------');
values.forEach(str => {
let reversed = str.split('').reverse().join('');
let index = reversed.indexOf('__');
console.log(reversed.slice(index+2, reversed.indexOf('__', index+1)));
});
Related
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I have the below format of a string:
str1 = "a, b, c, d, e";
str2 = "aa, ba, ca, da, essd";
str2 = "aass, bsda, cads, dsda, esssdsd";
I want to extract the end of the string after splitting --> e, essd, esssdsd.
Assuming these are std::strings, I'd use rfind to find the last occurrence of the delimiter, and then take a substring from there. E.g.:
size_t index = str.rfind(", ");
string last_element = str.substr(index + 2); // 2 is the size of the delimiter
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I would like to use string class, to extract some information from the string.
Given the string: <12,Apple>,<20,Orange>,<49,iPhone>
I would like to let 12, 20, 49 to a int array.
that means a[0] = 12, a[1] = 20, a[2] = 49.
And let Apple, Orange, iPhone to a String array.
that means b[0] = "Apple", b[1] = "Orange" b[2] = "iPhone"
How should I do?
Assume the string follows the format <int,string>,.... Please find the pseudo-code below:
Loop through the string `str` and
{
smaller_sign_pos = str.find('<', prev_pos)
entry_comma_pos = str.find(',', smaller_sign_pos+1)
greater_sign_pos = str.find('>', entry_comma_pos+1)
if (all pos values are not `npos`)
{
int_value = atoi(str.substr(smaller_sign_pos+1, entry_comma_pos-smaller_sign_pos-1))
str_value = str.substr(entry_comma_pos+1, greater_sign_pos-entry_comma_pos-1)
prev_pos = greater_sign_pos+1
append int_value to int array
append str_value to string array
optional: you can check if the comma after '>' exists
}
else
{
break or set the end of loop flag
}
}
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I'm looking for an regex that returns everything after pid- in this example URL.
URL:
www.example.com/bla-pid-123456
Expected match:
123456
Using PCRE-Compatible Grep
$ echo 'www.example.com/bla-pid-123456' | pcregrep -o 'pid-\K\d+'
123456
>>> import re
>>> pat = re.compile('pid-(\d+)$')
>>> m = pat.search('www.example.com/bla-pid-123456')
>>> m.groups()[0]
'123456'
you could do it like this: (in swift because i don't know which language you use):
func findStringAfterFirstOccurenceOfString(stringToFind: NSString, inString stringToSearch: NSString) -> NSString?
for (var i = 0, i <= stringToSearch.length - stringToFind.length; i++) {
let range = NSMakeRange(i, stringToFind.length)
let sub = stringToSearch.substringWithRange(range)
if sub == stringToFind {
return stringToSearch.substringFromIndex(i + stringToFind.length)
}
}
return nil // No occurrence found
}
stringToFind would be "pid-" in this case.
try this
var result = 'www.example.com/bla-pid-123456'.match(/.*pid-(\d+)/);
result = (result) ? result[1] : "";
Since I don't know if you can acccept alpha and/or numberic after the PID, I have this. mileage may vary.
in javascript
just for alphanumberic:
var str = "www.example.com/bla-pid-123456",
re = /pid[-](\w+)$/ ,
val = str.match(re) ? str.match(re)[1] : null;
note: I explicitly capture ONLY if its "pid-.....", otherwise I assign null to "val". This is a bit more what you might need, but since I do not know your intent, and the url can have 'gig-asdfasdf', or 'whatever-whater'... I want something explicit.
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I have a String like this
String s1="1 AND 1 OR 1";
I want split with AND OR and my result should be 1,1,1
I am using JAVA /eclipse
package com.test;
String s1="1 AND 1 OR 1";
String[] splits=s1.split("[AND\OR]");
for (int i = 0; i < splits.length; i++) {
System.out.println(splits[i]);
}
}
}
Can I get any help how to do this?
Any Help appreciated
I am unsure about the language, but for C# you can use the following:
string s1 = "1 AND 1 OR 1";
string s2 = s1.Replace("AND", ",").Replace("OR", ",");
Console.WriteLine(s2);
Which doesn't use regular expressions.
If you want an array, you can use the following:
string s1 = "1 AND 1 OR 1";
string[] s2 = Regex.Split(s1.Replace(" ", string.Empty), "AND|OR");
In Java you can replace using the same mechanism:
String s1 = "1 AND 1 OR 1";
String s2 = s1.replace("AND", ",").replace("OR", ",");
System.out.println(s2);
And to get an array:
String s1="1 AND 1 OR 1";
String[] s2 = s1.replace(" ", "").split("AND|OR");
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What's the PHP ereg() equivalent in Visual Basic .NET?
I'm trying to translate this tripcode encoder from PHP to VB.NET
function tripcode($name)
{
if(ereg("(#|!)(.*)", $name, $matches))
{
$cap = $matches[2];
$cap = strtr($cap,"&", "&");
$cap = strtr($cap,",", ",");
$salt = substr($cap."H.",1,2);
$salt = ereg_replace("[^\.-z]",".",$salt);
$salt = strtr($salt,":;<=>?#[\\]^_`","ABCDEFGabcdef");
return "!".substr(crypt($cap,$salt),-10)."";
}
}
$Str = "#your_tripcode_password"
Dim Reg As New Regex("(#|!)(.*)")
If Reg.IsMatch(Str) Then
Dim Cap$ = Reg.Matches(Str)(0).Groups(2).Value
End If