Achieve conditional function call by template specialization - c++

I'm trying to do dependency injection to the legacy code, since performance matters, dynamic polymorphism cannot be applied.
The following is my current thought, it CANNOT be compiled.
// myclass.h
class MyClass {
public:
MyClass(GlobalsImpl *globals) { globalsImpl = globals; }
MyClass(GlobalsTest *globals) { globalsTest = globals; }
std::string test();
private:
template<bool> auto getGlobals();
private:
bool isImpl;
GlobalsImpl *globalsImpl;
GlobalsTest *globalsTest;
};
// myclass.cc
template<bool> auto MyClass::getGlobals() { return getGlobals<> }
template<> Impl * MyClass::getGlobals<true>() { return globalsImpl; }
template<> Test * MyClass::getGlobals<false>() { return globalsTest; }
std::string MyClass::test() { return ""; }
My intuition is to achieve if test called, then return globalsTest; else return globalsImpl.
globalsImpl is the real implementation, while globalsTest is my injection.
How can I achieve that?

Related

Storage of function pointer in polymorphic class without explicit template specialization

I am trying to create a helper class to abstract invoking function pointers. With feedback from others on SO, I am using a polymorphic class to achieve this (shown below). Templates are also used to reduce code duplication.
typedef void(*PFNFOO1) (int);
typedef void(*PFNFOO2) (double);
typedef void(*PFNBAR1) (long);
typedef void(*PFNBAR2) (float);
typedef struct FOO_TABLE
{
PFNFOO1 pfnFoo1;
PFNFOO2 pfnFoo2;
} FOO_TABLE;
typedef struct BAR_TABLE
{
PFNBAR1 pfnBar1;
PFNBAR2 pfnBar2;
} BAR_TABLE;
enum TABLE_TYPE
{
TYPE_FOO = 0,
TYPE_BAR = 1,
};
template <typename T>
class FooBarImpl : public FooBarBase
{
public:
// GetFunc is created to centralize needed validation before function is invoked
void* GetFunc(size_t funcOffset)
{
// do some validation
return reinterpret_cast<void*>(m_FooBarTable + funcOffset);
}
void* GetpfnFoo1() { return GetFunc(offsetof(T, pfnFoo1)); }
void* GetpfnFoo2() { return GetFunc(offsetof(T, pfnFoo2)); }
void* GetpfnBar1() { return GetFunc(offsetof(T, pfnBar1)); }
void* GetpfnBar2() { return GetFunc(offsetof(T, pfnBar2)); }
T* m_FooBarTable;
};
class FooBarBase
{
public:
static FooBarBase* CreateFooBar(TABLE_TYPE tableType)
{
switch(tableType)
{
case (TYPE_FOO) :
{
return new FooBarImpl<FOO_TABLE>();
}
break;
case (TYPE_BAR) :
{
return new FooBarImpl<BAR_TABLE>();
}
break;
}
}
virtual void* GetpfnFoo1() = 0;
virtual void* GetpfnFoo2() = 0;
virtual void* GetpfnBar1() = 0;
virtual void* GetpfnBar2() = 0;
};
int _tmain(int argc, _TCHAR* argv[])
{
{
FooBarBase *pFooBar = FooBarBase::CreateFooBar(TYPE_FOO);
// Initialize Foo table
auto p = reinterpret_cast<PFNFOO1>(pFooBar->GetpfnFoo1());
int parameter = 1;
p(parameter);
}
{
FooBarBase *pFooBar = FooBarBase::CreateFooBar(TYPE_FOO);
// Initialize Bar table
auto p = reinterpret_cast<PFNBAR2>(pFooBar->GetpfnBar2());
float parameter = 1.0f;
p(parameter);
}
return 0;
}
This is currently giving me complication errors as "C2039: 'pfnBar1' : is not a member of 'FOO_TABLE'" which makes sense because one of the implicit template specialization will try to do "offsetof(FOO_TABLE, pfnBar1)," which isn't allowed. I have two questions. First, I am wondering what's the best way to address this error. I think I can possibly address this by providing explicit template specializations for FooBarImpl and FooBarImpl, but I'd like to avoid doing that because it means that if I were to add a new table type later, I'd have to add another specialization. Also, it increases code duplication. Therefore, if there's a way to fix this issue without explicit template specialization, please let m know.
For my second question, if explicit template specialization cannot be avoided, I have also tried this:
class FooBarBase;
template <typename T>
class FooBarImpl : public FooBarBase
{
};
template <>
class FooBarImpl<FOO_TABLE> : public FooBarBase
{
public:
typedef FOO_TABLE T;
// GetFunc is created to centralize needed validation before function is invoked
void* GetFunc(size_t funcOffset)
{
// do some validation
return reinterpret_cast<void*>(m_FooBarTable + funcOffset);
}
void* GetpfnFoo1() { return GetFunc(offsetof(T, pfnFoo1)); }
void* GetpfnFoo2() { return GetFunc(offsetof(T, pfnFoo2)); }
T* m_FooBarTable;
};
template<>
class FooBarImpl<BAR_TABLE> : public FooBarBase
{
public:
typedef BAR_TABLE T;
// GetFunc is created to centralize needed validation before function is invoked
void* GetFunc(size_t funcOffset)
{
// do some validation
return reinterpret_cast<void*>(m_FooBarTable + funcOffset);
}
void* GetpfnBar1() { return GetFunc(offsetof(T, pfnBar1)); }
void* GetpfnBar2() { return GetFunc(offsetof(T, pfnBar2)); }
T* m_FooBarTable;
};
But for some reason, I keep getting this error "error C2504: 'FooBarBase' : base class undefined" even if it was working fine before I specialized the templates.
If anyone has ideas about these 2 questions, I'd really appreciate your feedback. Thanks.

C++ Policy Based Design With Variable Type Return Value

I want to used Policy Based Design to have the return type of a host class change based on the policies I'm using. Here is an example:
class IntPolicy {
public:
int doIntPolicy(double anInput) {
return static_cast<int>(anInput);
}
};
class DoublePolicy {
public:
double doDoublePolicy(int anInput) {
return static_cast<double>(anInput);
}
};
template<typename IntPolicyType, typename DoublePolicyType>
class SimpleHost {
private:
IntPolicyType _intPolicy;
DoublePolicyType _doublePolicy;
public:
template<typename InputType>
auto doHost(InputType input) -> decltype(_doublePolicy.doDoublePolicy(_intPolicy.doIntPolicy(input))) {
auto aVar = _intPolicy.doIntPolicy(input);
return _doublePolicy.doDoublePolicy(aVar);
}
};
Here is how I'd use the host class and policies:
typedef SimpleHost<IntPolicy, DoublePolicy> Host;
Host host;
auto theOutput = host.doHost(5);
While this compiles and works, notice that I must essentially put the body of the doHost method inside the decltype function so that the compiler can deduce the trailing return. If the body of the doHost function was large then this would look incredibly ugly. Is there any way I can avoid this?
If you don't like how it looks then probably try define?
#define RECURSE_POLICY(E) policy2.doPolicy(policy1.doPolicy(E))
template<typename InputType>
auto doHost(InputType input) -> decltype(RECURSE_POLICY(input)) {
return RECURSE_POLICY(input);
}
Having said that, something doesn't look right that you have to call doPolicy twice. Maybe you can refactor it out.
1.- Extending the template
#include <stdio.h>
#include <string>
#include <iostream>
class IntPolicy {
public:
int doIntPolicy(double anInput=NULL) {
if(!NULL)
{
return static_cast<int>(anInput);
}
else
{
return -1;
}
}
};
class DoublePolicy {
public:
double doDoublePolicy(int anInput=NULL) {
if(!NULL)
{
return static_cast<double>(anInput);
}
else
{
return -1;
}
}
};
template<typename IntPolicyType, typename DoublePolicyType,
class __Type >
class SimpleHost {
private:
IntPolicyType _intPolicy;
DoublePolicyType _doublePolicy;
public:
template<typename InputType>
auto doHost(InputType input) -> __Type {
auto aVar = _intPolicy.doIntPolicy(input);
return _doublePolicy.doDoublePolicy(aVar);
}
};
int main()
{
IntPolicy foo;
DoublePolicy bar;
typedef SimpleHost<IntPolicy, DoublePolicy,
decltype(bar.doDoublePolicy(foo.doIntPolicy()))> Host;
Host host;
auto theOutput = host.doHost(5);
return 0;
}
2.- The simplest way would be to rename the impl, if you are using an external library you could consider Wrapping it for this purpose
class IntPolicy {
public:
int doPolicy(double anInput) {
return static_cast<int>(anInput);
}
};
class DoublePolicy {
public:
double doPolicy(int anInput) {
return static_cast<double>(anInput);
}
};
template<typename IntPolicyType, typename DoublePolicyType>
class SimpleHost {
private:
IntPolicyType _intPolicy;
DoublePolicyType _doublePolicy;
public:
template<typename InputType>
auto doHost(InputType input) -> decltype(_doublePolicy.doPolicy(_intPolicy.doPolicy(input)))
{
auto aVar = IntPolicyType.doPolicy(input);
return DoublePolicyType.doPolicy(aVar);
}
But to really help you, we need the specific functions you are trying to call, I mean I feel like this is a mess already.

Macro to return the 'this' pointer, or NULL when it's not available

Is it possible to access the this pointer in non-static context and use something else in static context automatically? Do you know any macro or template magic?
#define LOG std::cout << _is_the_this_pointer_available_ ? this : 0
class Foo {
void test() {
LOG;
}
};
void staticTest() {
LOG;
}
Do you know any macro or template magic?
Honestly, I wouldn't do this with a macro. When something can be done without macros, I'd suggest to prefer avoiding them. Here is a possible solution based on overloading, CRTP, and inheritance (no macros):
int get_this() { return 0; }
template<typename T>
struct get_this_helper
{
T* get_this() { return static_cast<T*>(this); }
};
The only overhead is that you have to make your classes derive from the proper specialization of get_this_helper<>, as shown below:
#include <iostream>
#define LOG std::cout << get_this() << std::endl;
class Foo : public get_this_helper<Foo> {
// ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
// This is the only thing that requires
// being changed wrt your version of Foo
public:
void test() {
LOG;
}
};
void staticTest() {
LOG;
}
Here is a simple test program:
int main()
{
Foo f;
f.test();
staticTest();
}
And a live example.
I am using the following technique to write this pointer to a log:
#define GET_THIS() __if_exists(this) { this; } __if_not_exists(this) { nullptr; }
However it is Microsoft specific.
#define LOG std::cout << isThisAvailable()
bool isThisAvailable() { return false; }
struct X
{
bool isThisAvailable() { return true; }
void test() { LOG; }
};
void staticTest()
{
LOG;
}
Calling isThisAvailable inside the class will return true. Calling outside the class context will call the free function and return false.

C++ Dynamic Dispatch without Virtual Functions

I've got some legacy code that, instead of virtual functions, uses a kind field to do dynamic dispatch. It looks something like this:
// Base struct shared by all subtypes
// Plain-old data; can't use virtual functions
struct POD
{
int kind;
int GetFoo();
int GetBar();
int GetBaz();
int GetXyzzy();
};
enum Kind { Kind_Derived1, Kind_Derived2, Kind_Derived3 /* , ... */ };
struct Derived1: POD
{
Derived1(): kind(Kind_Derived1) {}
int GetFoo();
int GetBar();
int GetBaz();
int GetXyzzy();
// ... plus other type-specific data and function members ...
};
struct Derived2: POD
{
Derived2(): kind(Kind_Derived2) {}
int GetFoo();
int GetBar();
int GetBaz();
int GetXyzzy();
// ... plus other type-specific data and function members ...
};
struct Derived3: POD
{
Derived3(): kind(Kind_Derived3) {}
int GetFoo();
int GetBar();
int GetBaz();
int GetXyzzy();
// ... plus other type-specific data and function members ...
};
// ... and so on for other derived classes ...
and then the POD class's function members are implemented like this:
int POD::GetFoo()
{
// Call kind-specific function
switch (kind)
{
case Kind_Derived1:
{
Derived1 *pDerived1 = static_cast<Derived1*>(this);
return pDerived1->GetFoo();
}
case Kind_Derived2:
{
Derived2 *pDerived2 = static_cast<Derived2*>(this);
return pDerived2->GetFoo();
}
case Kind_Derived3:
{
Derived3 *pDerived3 = static_cast<Derived3*>(this);
return pDerived3->GetFoo();
}
// ... and so on for other derived classes ...
default:
throw UnknownKindException(kind, "GetFoo");
}
}
POD::GetBar(), POD::GetBaz(), POD::GetXyzzy(), and other members are implemented similarly.
This example is simplified. The actual code has about a dozen different subtypes of POD, and a couple dozen methods. New subtypes of POD and new methods are added pretty frequently, and so every time we do that, we have to update all these switch statements.
The typical way to handle this would be to declare the function members virtual in the POD class, but we can't do that because the objects reside in shared memory. There is a lot of code that depends on these structs being plain-old-data, so even if I could figure out some way to have virtual functions in shared-memory objects, I wouldn't want to do that.
So, I'm looking for suggestions as to the best way to clean this up so that all the knowledge of how to call the subtype methods is centralized in one place, rather than scattered among a couple dozen switch statements in a couple dozen functions.
What occurs to me is that I can create some sort of adapter class that wraps a POD and uses templates to minimize the redundancy. But before I start down that path, I'd like to know how others have dealt with this.
You can use a jump table. This is what most virtual dispatches look like under the hood, and you CAN construct it manually.
template<typename T> int get_derived_foo(POD*ptr) {
return static_cast<T>(ptr)->GetFoo();
}
int (*)(POD*) funcs[] = {
get_derived_foo<Derived1>,
get_derived_foo<Derived2>,
get_derived_foo<Derived3>
};
int POD::GetFoo() {
return funcs[kind](this);
}
For a short example.
What exactly are the limitations of being in shared memory? I realized that I don't know enough here. Does it mean that I can't use pointers, because someone in another process will be trying to use those pointers?
You could use a string map, where each process gets it's own copy of the map. You'd have to pass this in to GetFoo() so that it can find it.
struct POD {
int GetFoo(std::map<int, std::function<int()>& ref) {
return ref[kind]();
}
};
Edit: Of course, you don't have to use a string here, you could use an int. I just used it as example. I should change it back. Infact, this solution is pretty flexible, but the important thing is, make a copy of process-specific data, e.g. function pointers or whatever, and then pass it in.
Here's the template-metaprogramming path I'm going down now. Here is what I like about it:
Adding support for a new kind only requires updating LAST_KIND and adding a new KindTraits.
There is a simple pattern for adding a new function.
Functions can be specialized for particular kinds if necessary.
I can expect compile-time errors and warnings, rather than mysterious run-time misbehavior, if I screw anything up.
There are a couple of concerns:
POD's implementation is now dependent upon the interfaces of all the derived classes. (This is already true in the existing implementation, so I'm not worried about it, but it is a bit of a smell.)
I'm counting on the compiler to be smart enough to generate code that is roughly equivalent to the switch-based code.
Many C++ programmers will scratch their heads upon seeing this.
Here's the code:
// Declare first and last kinds
const int FIRST_KIND = Kind_Derived1;
const int LAST_KIND = Kind_Derived3;
// Provide a compile-time mapping from a kind code to a subtype
template <int KIND>
struct KindTraits
{
typedef void Subtype;
};
template <> KindTraits<Kind_Derived1> { typedef Derived1 Subtype; };
template <> KindTraits<Kind_Derived2> { typedef Derived2 Subtype; };
template <> KindTraits<Kind_Derived3> { typedef Derived3 Subtype; };
// If kind matches, then do the appropriate typecast and return result;
// otherwise, try the next kind.
template <int KIND>
int GetFooForKind(POD *pod)
{
if (pod->kind == KIND)
return static_cast<KindTraits<KIND>::Subtype>(pod)->GetFoo();
else
return GetFooForKind<KIND + 1>(); // try the next kind
}
// Specialization for LAST_KIND+1
template <> int GetFooForKind<LAST_KIND + 1>(POD *pod)
{
// kind didn't match anything in FIRST_KIND..LAST_KIND
throw UnknownKindException(kind, "GetFoo");
}
// Now POD's function members can be implemented like this:
int POD::GetFoo()
{
return GetFooForKind<FIRST_KIND>(this);
}
You can experiment with Curiously recurring template pattern. It's a bit complicated, but when you cannot use pure virtual functions it can be helpful.
Here is an approach that uses virtual methods to implement the jump table, without requiring the Pod class or the derived classes to actually have virtual functions.
The objective is to simplify adding and removing methods across many classes.
To add a method, it needs to be added to Pod using a clear and common pattern, a pure virtual function needs to be added to PodInterface, and a forwarding function must be added to PodFuncs using a clear and common pattern.
Derived classes need only have a file static initialisation object to set things up, otherwise look pretty much like they already do.
// Pod header
#include <boost/shared_ptr.hpp>
enum Kind { Kind_Derived1, Kind_Derived2, Kind_Derived3 /* , ... */ };
struct Pod
{
int kind;
int GetFoo();
int GetBar();
int GetBaz();
};
struct PodInterface
{
virtual ~PodInterface();
virtual int GetFoo(Pod* p) const = 0;
virtual int GetBar(Pod* p) const = 0;
virtual int GetBaz(Pod* p) const = 0;
static void
do_init(
boost::shared_ptr<PodInterface const> const& p,
int kind);
};
template<class T> struct PodFuncs : public PodInterface
{
struct Init
{
Init(int kind)
{
boost::shared_ptr<PodInterface> t(new PodFuncs);
PodInterface::do_init(t, kind);
}
};
~PodFuncs() { }
int GetFoo(Pod* p) const { return static_cast<T*>(p)->GetFoo(); }
int GetBar(Pod* p) const { return static_cast<T*>(p)->GetBar(); }
int GetBaz(Pod* p) const { return static_cast<T*>(p)->GetBaz(); }
};
//
// Pod Implementation
//
#include <map>
typedef std::map<int, boost::shared_ptr<PodInterface const> > FuncMap;
static FuncMap& get_funcmap()
{
// Replace with other approach for static initialisation order as appropriate.
static FuncMap s_funcmap;
return s_funcmap;
}
//
// struct Pod methods
//
int Pod::GetFoo()
{
return get_funcmap()[kind]->GetFoo(this);
}
//
// struct PodInterface methods, in same file as s_funcs
//
PodInterface::~PodInterface()
{
}
void
PodInterface::do_init(
boost::shared_ptr<PodInterface const> const& p,
int kind)
{
// Could do checking for duplicates here.
get_funcmap()[kind] = p;
}
//
// Derived1
//
struct Derived1 : Pod
{
Derived1() { kind = Kind_Derived1; }
int GetFoo();
int GetBar();
int GetBaz();
// Whatever else.
};
//
// Derived1 implementation
//
static const PodFuncs<Derived1>::Init s_interface_init(Kind_Derived1);
int Derived1::GetFoo() { /* Implement */ }
int Derived1::GetBar() { /* Implement */ }
int Derived1::GetBaz() { /* Implement */ }
Here is an example using Curiously recurring template pattern. This may suit your needs if you know more info at the compile time.
template<class DerivedType>
struct POD
{
int GetFoo()
{
return static_cast<DerivedType*>(this)->GetFoo();
}
int GetBar()
{
return static_cast<DerivedType*>(this).GetBar();
}
int GetBaz()
{
return static_cast<DerivedType*>(this).GetBaz();
}
int GetXyzzy()
{
return static_cast<DerivedType*>(this).GetXyzzy();
}
};
struct Derived1 : public POD<Derived1>
{
int GetFoo()
{
return 1;
}
//define all implementations
};
struct Derived2 : public POD<Derived2>
{
//define all implementations
};
int main()
{
Derived1 d1;
cout << d1.GetFoo() << endl;
POD<Derived1> *p = new Derived1;
cout << p->GetFoo() << endl;
return 0;
}
Expanding on the solution you ended up with, the following solves the mapping to derived functions at program initialization:
#include <typeinfo>
#include <iostream>
#include <functional>
#include <vector>
enum Kind
{
Kind_First,
Kind_Derived1 = Kind_First,
Kind_Derived2,
Kind_Total
};
struct POD
{
size_t kind;
int GetFoo();
int GetBar();
};
struct VTable
{
std::function<int(POD*)> GetFoo;
std::function<int(POD*)> GetBar;
};
template<int KIND>
struct KindTraits
{
typedef POD KindType;
};
template<int KIND>
void InitRegistry(std::vector<VTable> &t)
{
typedef typename KindTraits<KIND>::KindType KindType;
size_t i = KIND;
t[i].GetFoo = [](POD *p) -> int {
return static_cast<KindType*>(p)->GetFoo();
};
t[i].GetBar = [](POD *p) -> int {
return static_cast<KindType*>(p)->GetBar();
};
InitRegistry<KIND+1>(t);
}
template<>
void InitRegistry<Kind_Total>(std::vector<VTable> &t)
{
}
struct Registry
{
std::vector<VTable> table;
Registry()
{
table.resize(Kind_Total);
InitRegistry<Kind_First>(table);
}
};
Registry reg;
int POD::GetFoo() { return reg.table[kind].GetFoo(this); }
int POD::GetBar() { return reg.table[kind].GetBar(this); }
struct Derived1 : POD
{
Derived1() { kind = Kind_Derived1; }
int GetFoo() { return 0; }
int GetBar() { return 1; }
};
template<> struct KindTraits<Kind_Derived1> { typedef Derived1 KindType; };
struct Derived2 : POD
{
Derived2() { kind = Kind_Derived2; }
int GetFoo() { return 2; }
int GetBar() { return 3; }
};
template<> struct KindTraits<Kind_Derived2> { typedef Derived2 KindType; };
int main()
{
Derived1 d1;
Derived2 d2;
POD *p;
p = static_cast<POD*>(&d1);
std::cout << p->GetFoo() << '\n';
p = static_cast<POD*>(&d2);
std::cout << p->GetBar() << '\n';
}

How to call a templated operator overload without using the word 'operator'?

class RunAround;
class HopUpAndDown;
class Sleep;
template<typename Acts> int doThis();
template<> int doThis<RunAround>() { /* run run run.. */ return 3; }
template<> int doThis<HopUpAndDown>() { /* hop hop hop.. */ return 2; }
template<> int doThis<Sleep>() { /* zzz.. */ return -2; }
struct Results
{
template<typename Act> int& operator()()
{
static int result;
return result;
}
};
int main()
{
Results results;
//results<RunAround>() = doThis<RunAround>();
results.operator ()<RunAround>() = doThis<RunAround>();
results.operator ()<Sleep>() = doThis<Sleep>();
return 0;
};
If I remove the comment, the compiler thinks I am calling operator() in non-existant template class Results<RunAround> when I want operator<RunAround>() in class Results.
If I want to continue using an operator overload instead of a normal name, am I doomed to use the awful syntax below the comment (which does work)?
The most comfortable thing is to let template argument deduction work for you:
struct Results {
template<typename Act> int& operator()(Act) { /* ... */ }
};
results(RunAround()) = /* ... */;