Exception handling behaviour of code with two similar catch sections - c++

I have a short code that i created only for practice purposes, I wanted to check what is going to happen if I have two catch sections, one captures by reference (int&) and the second one catches by value (int). The problem is that when I run this code it appears that capture by reference occurs even though I threw "regular" integer. Why is this happening?
NOTE: When I compile this on MSVS17 I get error C2313:
'int': is caught by reference ('int&') on line 15
but when I use online compiler it works just fine.
When I remove one of the catch sections, it works just fine even in MSVS17, but still, why is catch section with reference invoked and not the other one
#include <iostream>
using namespace std;
int main()
{
int i = 5;
try {
if (i)
throw(i);
return 0;
}
catch (int &)
{
cout << "Int&";
}
catch (int)
{
cout << "Int";
}
}

TL;DR
There is no priority in catch-matching. A catch either matches or it does not match. And reference is a match.
Not-So-Short Answer
cppreference says:
When an exception of type E is thrown by any statement in compound-statement, it is matched against the types of the formal parameters T of each catch-clause in handler-seq, in the order in which the catch clauses are listed.
i.e. The first match is selected (there is no concept "better" or "worse" match; a catch either matches or not.)
Further it says:
The exception is a match if any of the following is true:
...
T is an lvalue-reference to (possibly cv-qualified) E
...
Therefore, catch(int&) is a match; catch(int) doesn't even have the opportunity to be considered.
Martin Bonner's example
Martin Bonner provides an excellent example to let you understand this, and the OP understands it thoroughly:
try {
throw 5;
}
catch (int) { // int first
// ...
}
catch (int&) { // this is not even considered!
// ...
}

Related

Throwing bad_exception when calling current_exception()

Link https://en.cppreference.com/w/cpp/error/current_exception provides the following description of current_exception():
If called during exception handling (typically, in a catch clause), captures the current exception object and creates an std::exception_ptr that holds either a copy or a reference to that exception object (depending on the implementation).
...
If the implementation of this function requires copying the captured exception object and its copy constructor throws an exception, the returned pointer will hold a reference to the exception thrown. If the copy constructor of the thrown exception object also throws, the returned pointer may hold a reference to an instance of std::bad_exception to break the endless loop.
I am trying to find out if the implementation of current_exception() in GCC7 copies captured exception object, or just returns the reference to an already existing object. So far, I think that GCC implements the second case. I've tried to check it by executing the following code:
class my_copy_exception : public exception
{
public:
my_copy_exception () : exception () {}
my_copy_exception (const my_copy_exception& other) :
exception(other)
{
throw my_copy_exception();
}
const char* what () const throw() {return "my_copy_exception";}
};
int main()
{
try
{
throw my_copy_exception();
}
catch (const exception& e)
{
cout << e.what() << endl;
exception_ptr eptr = current_exception();
try
{
rethrow_exception(eptr);
}
catch(const std::exception& en)
{
cout << en.what() << endl;
exception_ptr eptrn = current_exception();
cout << (eptr == eptrn) << endl;
}
}
}
It produces the following output:
my_copy_exception
my_copy_exception
1
Whether it is possible to claim that there is no copying of the exception object? If not, how to make current_exception() throw bad_exception?
The good thing about open source software like GCC 7 is that, rather than attempt to reverse engineer what it probably is doing, you can simply go and look at the source code to see exactly what it is doing.
In the case of GCC 7.4, the implementation of std::current_exception() can be found in libstdc++, more specifically, in libsupc++/eh_ptr.cc line 177:
std::exception_ptr
std::current_exception() noexcept
{
__cxa_eh_globals *globals = __cxa_get_globals ();
__cxa_exception *header = globals->caughtExceptions;
if (!header)
return std::exception_ptr();
// Since foreign exceptions can't be counted, we can't return them.
if (!__is_gxx_exception_class (header->unwindHeader.exception_class))
return std::exception_ptr();
return std::exception_ptr(
__get_object_from_ambiguous_exception (header));
}
The fist couple of lines here just fetch the currently active exception. If there is no active exception or the active exception did not come from this C++ runtime, then it returns an empty exception_ptr (see here, here, here, here, here, here, and here for the details on how these checks operate). If there is an active exception that did come from the C++ runtime, it then gets itself a pointer to the active exception object and constructs an exception_ptr. The exception_ptr constructor it uses simply increments the reference counter of the exception object.
Thus, it would seem that libstdc++ exceptions are reference-counted and a copy is never made in the libstdc++ implementation of std::current_exception() for GCC 7, which is in accordance with the requirements of the specification and seems to match your observations…

Why doesn't C++ use std::nested_exception to allow throwing from destructor?

The main problem with throwing exceptions from destructor is that in the moment when destructor is called another exception may be "in flight" (std::uncaught_exception() == true) and so it is not obvious what to do in that case. "Overwriting" the old exception with the new one would be the one of the possible ways to handle this situation. But it was decided that std::terminate (or another std::terminate_handler) must be called in such cases.
C++11 introduced nested exceptions feature via std::nested_exception class. This feature could be used to solve the problem described above. The old (uncaught) exception could be just nested into the new exception (or vice versa?) and then that nested exception could be thrown. But this idea was not used. std::terminate is still called in such situation in C++11 and C++14.
So the questions. Was the idea with nested exceptions considered? Are there any problems with it? Isn't the situation going to be changed in the C++17?
There is one use for std::nested exception, and only one use (as far as I have been able to discover).
Having said that, it's fantastic, I use nested exceptions in all my programs and as a result the time spent hunting obscure bugs is almost zero.
This is because nesting exceptions allow you to easily build a fully-annotated call stack which is generated at the point of the error, without any runtime overhead, no need for copious logging during a re-run (which will change the timing anyway), and without polluting program logic with error handling.
for example:
#include <iostream>
#include <exception>
#include <stdexcept>
#include <sstream>
#include <string>
// this function will re-throw the current exception, nested inside a
// new one. If the std::current_exception is derived from logic_error,
// this function will throw a logic_error. Otherwise it will throw a
// runtime_error
// The message of the exception will be composed of the arguments
// context and the variadic arguments args... which may be empty.
// The current exception will be nested inside the new one
// #pre context and args... must support ostream operator <<
template<class Context, class...Args>
void rethrow(Context&& context, Args&&... args)
{
// build an error message
std::ostringstream ss;
ss << context;
auto sep = " : ";
using expand = int[];
void (expand{ 0, ((ss << sep << args), sep = ", ", 0)... });
// figure out what kind of exception is active
try {
std::rethrow_exception(std::current_exception());
}
catch(const std::invalid_argument& e) {
std::throw_with_nested(std::invalid_argument(ss.str()));
}
catch(const std::logic_error& e) {
std::throw_with_nested(std::logic_error(ss.str()));
}
// etc - default to a runtime_error
catch(...) {
std::throw_with_nested(std::runtime_error(ss.str()));
}
}
// unwrap nested exceptions, printing each nested exception to
// std::cerr
void print_exception (const std::exception& e, std::size_t depth = 0) {
std::cerr << "exception: " << std::string(depth, ' ') << e.what() << '\n';
try {
std::rethrow_if_nested(e);
} catch (const std::exception& nested) {
print_exception(nested, depth + 1);
}
}
void really_inner(std::size_t s)
try // function try block
{
if (s > 6) {
throw std::invalid_argument("too long");
}
}
catch(...) {
rethrow(__func__); // rethrow the current exception nested inside a diagnostic
}
void inner(const std::string& s)
try
{
really_inner(s.size());
}
catch(...) {
rethrow(__func__, s); // rethrow the current exception nested inside a diagnostic
}
void outer(const std::string& s)
try
{
auto cpy = s;
cpy.append(s.begin(), s.end());
inner(cpy);
}
catch(...)
{
rethrow(__func__, s); // rethrow the current exception nested inside a diagnostic
}
int main()
{
try {
// program...
outer("xyz");
outer("abcd");
}
catch(std::exception& e)
{
// ... why did my program fail really?
print_exception(e);
}
return 0;
}
expected output:
exception: outer : abcd
exception: inner : abcdabcd
exception: really_inner
exception: too long
Explanation of the expander line for #Xenial:
void (expand{ 0, ((ss << sep << args), sep = ", ", 0)... });
args is a parameter pack. It represents 0 or more arguments (the zero is important).
What we're looking to do is to get the compiler to expand the argument pack for us while writing useful code around it.
Let's take it from outside in:
void(...) - means evaluate something and throw away the result - but do evaluate it.
expand{ ... };
Remembering that expand is a typedef for int[], this means let's evaluate an integer array.
0, (...)...;
means the first integer is zero - remember that in c++ it's illegal to define a zero-length array. What if args... represents 0 parameters? This 0 ensures that the array has at lease one integer in it.
(ss << sep << args), sep = ", ", 0);
uses the comma operator to evaluate a sequence of expressions in order, taking the result of the last one. The expressions are:
s << sep << args - print the separator followed by the current argument to the stream
sep = ", " - then make the separator point to a comma + space
0 - result in the value 0. This is the value that goes in the array.
(xxx params yyy)... - means do this once for each parameter in the parameter pack params
Therefore:
void (expand{ 0, ((ss << sep << args), sep = ", ", 0)... });
means "for every parameter in params, print it to ss after printing the separator. Then update the separator (so that we have a different separator for the first one). Do all this as part of initialising an imaginary array which we will then throw away.
The problem you cite happens when your destructor is being executed as part of the stack unwinding process (when your object was not created as part of stack unwinding)1, and your destructor needs to emit an exception.
So how does that work? You have two exceptions in play. Exception X is the one that's causing the stack to unwind. Exception Y is the one that the destructor wants to throw. nested_exception can only hold one of them.
So maybe you have exception Y contain a nested_exception (or maybe just an exception_ptr). So... how do you deal with that at the catch site?
If you catch Y, and it happens to have some embedded X, how do you get it? Remember: exception_ptr is type-erased; aside from passing it around, the only thing you can do with it is rethrow it. So should people be doing this:
catch(Y &e)
{
if(e.has_nested())
{
try
{
e.rethrow_nested();
}
catch(X &e2)
{
}
}
}
I don't see a lot of people doing that. Especially since there would be an exceedingly large number of possible X-es.
1: Please do not use std::uncaught_exception() == true to detect this case. It is extremely flawed.
Nested exceptions just add most-likely-ignored information about what happened, which is this:
An exception X has been thrown, the stack is being unwound, i.e. destructors of local objects are being called with that exception “in flight”, and the destructor of one of those objects in turn throws an exception Y.
Ordinarily this means that cleanup failed.
And then this is not a failure that can be remedied by reporting it upwards and letting higher level code decide to e.g. use some alternative means to achieve its goal, because the object that held the information necessary to do the clean up has been destroyed, along with its information, but without doing its cleanup. So it's much like an assertion failing. The process state can be very ungood, breaking the assumptions of the code.
Destructors that throw can in principle be useful, e.g. as the idea Andrei once aired about indicating a failed transaction on exit from a block scope. That is, in normal code execution a local object that hasn't been informed of transaction success can throw from its destructor. This only becomes a problem when it clashes with C++'s rule for exception during stack unwinding, where it requires detection of whether the exception can be thrown, which appears to be impossible. Anyway then the destructor is being used just for its automatic call, not in its cleanup rôle. And so one can conclude that the current C++ rules assume the cleanup rôle for destructors.
The real problem is that throwing from destructors is a logical fallacy. It's like defining operator+() to perform multiplication.
Destructors should not be used as hooks for running arbitrary code. Their purpose is to deterministically release resources. By definition, that must not fail. Anything else breaks the assumptions needed to write generic code.
The problem that may happen during stack unwinding with chaining exceptions from destructors is that the nested exception chain may be too long. For example, you have std::vector of 1 000 000 elements each of which throws an exception in its destructor. Let's assume the destructor of std::vector collects all exceptions from destructors of its elements into single chain of nested exceptions. Then resulting exception may be even bigger than original std::vector container. This may cause performance problems and even throwing std::bad_alloc during stack unwinding (that even couldn't be nested because there is not enough memory for doing that) or throwing std::bad_alloc in other unrelated places in the program.

C++ - A few questions about throwing exceptions

I've got a few questions about throwing exceptions in C++.
From what I know about them...
An exception can be thrown from within the main() function. Any block of code that can throw an exception in the main() function should be surrounded by try and catch statements as follows
void foo(//args) {
if (...) {
throw "Error reached";
} ...
int main() {
...
try {
//Code that can throw an excpetion
} catch(const char* msg) (
cerr << msg << endl;
}
...
}
In the example above, why is the argument to the catch a const char *. Doesn't C++ allow for strings? Also, is it possible to throw an exception that isn't a const char *, like an int? or a char?
Does throwing an exception in foo, terminate the foo function?
Are there cases where you could put the try and catch statements in the same function as the throw?
Sorry if these are basic questions.
Thanks SO
why is the argument to the catch a const char *
Because you threw string literal which decays to const char*. In short, you catch what you throw.
Doesn't C++ allow for strings?
It does, but to catch string, you need to throw string in first place.
is it possible to throw an exception that isn't a const char *,
You can throw literally anything. It is a good idea to throw special exception classes, like std::exception and derived from it.
Does throwing an exception in foo, terminate the foo function?
Yes, it does.
Are there cases where you could put the try and catch statements in the same function as the throw?
If you want, you can do that. There are not much cases where doing it is a good idea.
It looks like you need to get a good book and read chapter about exceptions. In the meantime this super-FAQ entry might help you/
You can throw an object of any type.
EDIT: (Hopefully I got this right now)
What you have done is throw a C-string, which is of type const char[13] in this case. C-Arrays will decay to pointers to their first element, in this case a pointer of type const char*.
Typically what you want to do is throw a predefined exception object. They can be found in header <stdexcept> and are derived from a base class std::exception. The derived exception classes are for instance std::logic_error, std::range_error, std::bad_alloc etc.
Their constructors take a string as argument, so you can for instance
throw std::logic_error{"Negative values not allowed."};
This message can be accessed in a catch statement like this:
catch(std::exception &e) // capture reference to base class
{
std::cout << e.what() << '\n'; // what() of derived is called, since virtual
}
If an exception is caught, so-called stack unwinding takes place. You can then deal with the error locally, or rethrow the exception. Only when an exception is thrown and never caught, std::terminate() is called an the program aborted.
You can put try/catch statements anywhere. However, remember what the term "exception" actually means. Cases that can easily dealt with using a simple conditional expression if (n < 0) break; or something like that, don't need the exception treatment. Especially if you can realistically expect this kind of unwanted condition to be true often. Then it is not something "exceptional".
If you decide to deal with an error using exceptions and they can not be treated locally, you may put try/catch clauses around the beginning and end of main().
Since you can put several catch statements directly after a try statement, you can then begin to deal with more specific errors, or simply catch anything via catch(...) { //... }.
This is all described in great detail (including pointers on when and when not to use it, in the C++ FAQ.
EDIT: Here's an example that makes use of try/catch statements. However, not an exception object is caught, but an int (errno). Just to show, that you can really throw/catch anything you like. Let process_several_files() be a function somewhere nested in your code:
std::vector<std::string> process_several_files(std::vector<std::string> const& files)
{
std::vector<std::string> contents{};
contents.reserve(files.size()); // files contains file names from user input
for (auto const& file : files)
{
try
{
contents.emplace_back(get_file_contents(file.c_str())); // A "C like" function. get_file_contents() will throw "errno", if a file does not exist
}
catch(int err)
{
std::cerr << "***Error while opening " << file << " : " << std::strerror(err) << "***\n";
continue; // "scope" didn't change, just keep iterating!
}
}
return contents;
}

How does C++ treat assignments in try catch blocks?

I use the clang analyzer to check my C++ code for bugs and errors. I have the following construct:
#include <cstdlib>
#include <iostream>
double
somethingThatMayThrow() throw (std::exception)
{
if( rand() % 2 ) {
throw std::exception();
}
return 5.0;
}
int
main()
{
double value = 2.0;
try {
value = somethingThatMayThrow();
} catch( const std::exception& ) {
std::cout << "oops" << std::endl;
}
double someOtherValue = value + 1.0;
std::cout << someOtherValue << std::endl;
return 0;
}
The analyzer now complains that the initial value of variable value is never read. However, it is clear that the value is used in the last line if and only if there is an exception in the try block. Is this understanding correct, and am I looking at a bug in the analyzer? Or am I missing something here?
How does the standard define this behavior? What happens to the left hand side of the assignment if the right hand side throws?
The screenshot below shows the actual code that the analyzer complained about, which has the same structure as my example above:
The analyser is wrong. You are right.
The analyser could be right if the code inside the try block can never throw std::exceptions or objects of a type derived from it (e.g. with noexcept, or with only objects of other types being thrown).
Either way, your interpretation is correct: the assignment will never occur if evaluation of the value-to-be throws. As such, the original value will remain intact.
The compiler sees that you are assigning someValue in the initialization of value but then, inside the try block, you are reassigning it.
And the analyzer is right in the case in which no exception is thrown, but not in the opposite case, where value will still be the same as original someValue.

When is a function try block useful?

I'm wondering when programmers use function try blocks. When is it useful?
void f(int i)
try
{
if ( i < 0 )
throw "less than zero";
std::cout << "greater than zero" << std::endl;
}
catch(const char* e)
{
std::cout << e << std::endl;
}
int main() {
f(1);
f(-1);
return 0;
}
Output: (at ideone)
greater than zero
less than zero
EDIT: As some people might think that the syntax of function defintion is incorrect (because the syntax doesn't look familiar), I've to say that no its not incorrect. Its called function-try-block. See §8.4/1 [dcl.fct.def] in the C++ Standard.
You use it in constructors to catch errors from initializers. Usually, you don't catch those errors, so this is a quite exceptional use.
Otherwise, it is useless: unless I'm proven wrong,
void f() try { ... } catch (...) { ... }
is strictly equivalent to
void f() { try { ... } catch (...) { ... } }
Function try block are useful for me in two contexts.
a) To have a catch all clause around main() allowing to write small utilities without having to worry about local error handling:
int main()
try {
// ...
return 0;
}
catch (...) {
// handle errors
return -1;
}
which is clearly just syntactic sugar for having a try/catch inside main() itself.
b) to handle exceptions thrown by base class constructors:
struct B {
B() { /*might throw*/ }
};
struct A : B {
A()
try : B() {
// ...
}
catch (...) {
// handle exceptions thrown from inside A() or by B()
}
};
Aside from the functional uses mentioned, you can use the function-try-block to save yourself one level of indentation. (Ack, an answer about coding styles!)
Typically you see examples with the function-try-block like so:
void f(/*...*/)
try {
/*...*/
}
catch(/*...*/) {
/*...*/
}
Where the function scope is indented to the same level as if there were no function-try-block. This can be useful when:
you have an 80 character column limit and would have to wrap lines given the extra indentation.
you are trying to retrofit some existing function with try catch and don't want to touch all the lines of the function. (Yeah, we could just use git blame -w.)
Though, for functions that are entirely wrapped with a function-try-block, I would suggest not alternating between some functions using function-try-blocks and some not within the same code base. Consistency is probably more important then line wrapping issues.
:)
Notes regarding how function try blocks operate:
For constructors, a function try block encompasses the construction of data members and base-classes.
For destructors, a function try block encompasses the destruction of data members and base-classes. It gets complicated, but for C++11, you have to include noexcept(false) in the declaration of your destructor (or that of a base/member class) or any destruction exception will result in termination at the conclusion of the catch block. It may be possible to prevent this by putting a return statement in the catch block (but this won't work for constructors).
A catch block in a constructor or destructor must throw some exception (or it will implicitly rethrow the caught exception). It is not legal to simply return (at least in constructor's function catch block). Note, however, that you could call exit() or similar, which might make sense in some situations.
A catch block can't return a value, so it doesn't work for functions returning non-void (unless they intentionally terminate the program with exit() or similar). At least that is what I've read.
The catch block for a constructor-function-try can't reference data/base members since they will have either have 1) not been constructed or 2) been destructed prior to the catch. As such, function try blocks are not useful for cleaning up an object's internal state -- the object should already be completely "dead" by the time you get there. This fact makes it very dangerous to use function try blocks in constructors, since it is difficult to police this rule over time if your compiler(s) don't happen to flag it.
valid (legal) uses
Translating an exception (to a different type/message) thrown during the constructor or it's base/member constructors.
Translating or absorbing and exception thrown during the destructor or it's base/member destructors (destructor etiquette notwithstanding).
Terminating a program (perhaps with a useful message).
Some kind of exception logging scheme.
Syntactic sugar for void-returning functions that happen to need a fully encapsulating try/catch block.
It might be useful if you want to catch exceptions from constructor's initializer.
However, if you do catch exception in constructor that way, you have to either rethrow it or throw new exception (i.e. you cannot just normally return from constructor). If you do not rethrow, it just happens implicitly.
#include <iostream>
class A
{
public:
A()
try {
throw 5;
}
catch (int) {
std::cout << "exception thrown\n";
//return; <- invalid
}
};
int main()
{
try {
A a;
}
catch (...) {
std::cout << "was rethrown";
}
}
Another thing you can use them for is to provide extra data during debugging, in a manner that doesn't interfere with the finished build. I haven't seen anyone else use or advocate it, but it's something I find convenient.
// Function signature helper.
#if defined(_WIN32) || defined(_WIN64)
#define FUNC_SIG __FUNCSIG__
#elif defined(__unix__)
#define FUNC_SIG __PRETTY_FUNCTION__
// Add other compiler equivalents here.
#endif /* Function signature helper. */
void foo(/* whatever */)
#ifdef DEBUG
try
#endif /* DEBUG */
{
// ...
}
#ifdef DEBUG
catch(SomeExceptionOrOther& e) {
std::cout << "Exception " << e.what() << std::endl
<< "* In function: " << FUNC_SIG << std::endl
<< "* With parameters: " << /* output parameters */ << std::endl
<< "* With internal variables: " << /* output vars */ << std::endl;
throw;
}
#endif /* DEBUG */
This would allow you to both obtain useful information while testing your code, and easily dummy it out without affecting anything.