Rotating line inside rectangle bounds - c++
What I try to achieve is to rotate a line around rectangle center so it always stays in its bounds touching them (or having some padding).
Now I have the following routine for this, as you see I use tan calculations dividing my rectangle into 8 parts (red lines)
It works so far, but for some reason I have inconsistency using other calculation for radius drawing (green line), the lines won't always match as expected and I wonder why.
Basically the same could be achieved using just sin/cos calculations and finding cross points between lines and rect borders, but for some reason I could not get it to work.
std::pair<Point, Point>
MathUtils::calculateRotatingLine(Size size, double degrees)
{
auto width = size.width;
auto height = size.height;
double diagonalAngleTopRight = radiansToDegrees(atan((width / 2) / (height / 2)));
double diagonalAngleBottomRight = 90 + (90 - diagonalAngleTopRight);
double diagonalAngleBottomLeft = 180 + diagonalAngleTopRight;
double diagonalAngleTopLeft = 180 + diagonalAngleBottomRight;
double x, y;
/*
* *8*1*
* 7* *2
* 6* *3
* *5*4*
*/
// 1
if (degrees >= 0 && degrees <= diagonalAngleTopRight) {
x = width / 2 + height / 2 * tan(degreesToRadians(degrees));
y = 0;
}
// 2
else if (degrees > diagonalAngleTopRight && degrees <= 90) {
x = width;
y = width / 2 * tan(degreesToRadians(degrees - diagonalAngleTopRight));
}
// 3
else if (degrees > 90 && degrees <= diagonalAngleBottomRight) {
x = width;
y = height / 2 + width / 2 * tan(degreesToRadians(degrees - 90));
}
// 4
else if (degrees > diagonalAngleBottomRight && degrees <= 180) {
x = width - height / 2 * tan(degreesToRadians(degrees - diagonalAngleBottomRight));
y = height;
}
// 5
else if (degrees > 180 && degrees <= diagonalAngleBottomLeft) {
x = width / 2 - height / 2 * tan(degreesToRadians(degrees - 180));
y = height;
}
// 6
else if (degrees > diagonalAngleBottomLeft && degrees <= 270) {
x = 0;
y = height - width / 2 * tan(degreesToRadians(degrees - diagonalAngleBottomLeft));
}
// 7
else if (degrees > 270 && degrees <= diagonalAngleTopLeft) {
x = 0;
y = height / 2 - width / 2 * tan(degreesToRadians(degrees - 270));
}
// 8
else {
x = height / 2 * tan(degreesToRadians(degrees - diagonalAngleTopLeft));
y = 0;
}
return {Point{width / 2, height / 2}, Point{x, y}};
}
Green line calculation
Point
MathUtils::calculateCirclePoint(double radius, double degrees)
{
return {radius * cos(degreesToRadians(degrees)), radius * sin(degreesToRadians(degrees))};
}
EDIT
Awesome, it works thanks to #MBo
Point
MathUtils::calculateCrossPoint(Size size, double degrees)
{
auto x0 = size.width / 2;
auto y0 = size.height / 2;
auto vx = cos(degreesToRadians(degrees - 90));
auto vy = sin(degreesToRadians(degrees - 90));
//potential border positions
auto ex = vx > 0 ? size.width : 0;
auto ey = vy > 0 ? size.height : 0;
//check for horizontal/vertical directions
if (vx == 0) {
return {x0, ey};
}
if (vy == 0) {
return {ex, y0};
}
// in general case find times of intersections with horizontal and vertical edge line
auto tx = (ex - x0) / vx;
auto ty = (ey - y0) / vy;
// and get intersection for smaller parameter value
if (tx <= ty) {
return {ex, y0 + tx * vy};
}
return {x0 + ty * vx, ey};
}
Pseudocode to find intersection of ray emitted from rectangle center (with angle an in radians) with edges. (Works also for other (x0,y0) positions)
x0 = width / 2;
y0 = height / 2;
vx = cos(an);
vy = sin(an);
//potential border positions
ex = vx > 0? width: 0
ey = vy > 0? height: 0
//check for horizontal/vertical directions
if vx = 0 then
return cx = x0, cy = ey
if vy = 0 then
return cx = ex, cy = y0
//in general case find times of intersections with horizontal and vertical edge line
tx = (ex - x0) / vx
ty = (ey - y0) / vy
//and get intersection for smaller parameter value
if tx <= ty then
return cx = ex, cy = y0 + tx * vy
else
return cx = x0 + ty * vx, cy = ey
Related
How do I get correct answers using my code with the barycentric formula?
My function getHeightOfTerrain() is calling a barycentric formula function that is not returning the correct height for the one set test height in : heightMapFromArray[][]. I've tried watching OpenGL JAVA Game tutorials 14,21, 22, by "thin matrix" and I am confused on how to use my array: heightMapforBaryCentric in both of the supplied functions, and how to set the arguments that are passed to the baryCentic() function in some sort of manner so that I can solve the problem. int creaateTerrain(int height, int width) { float holderY[6] = { 0.f ,0.f,0.f,0.f,0.f,0.f }; float scaleit = 1.5f; float holder[6] = { 0.f,0.f,0.f,0.f,0.f,0.f }; for (int z = 0, z2 =0; z < iterationofHeightMap;z2++) { //each loop is two iterations and creates one quad (two triangles) //however because each iteration is by two (i.e. : x=x+2) om bottom //the amount of triangles is half the x value // //number of vertices : 80 x 80 x 6. //column for (int x = 0, x2 = 0; x < iterationofHeightMap;x2++) { //relevant - A : first triangle - on left triangle //[row] [colum[] holder[0] = heightMapFromArray[z][x]; //holder[0] = (float)imageData[(z / 2 * MAP_Z + (x / 2)) * 3]; //holder[0] = holder[0] / 255;// *scaleit; vertices.push_back(glm::vec3(x, holder[0], z)); //match height map with online barycentric use heightMapforBaryCentric[x2][z2] = holder[0]; holder[1] = heightMapFromArray[z+2][x]; //holder[1] = (float)imageData[(((z + 2) / 2 * MAP_Z + ((x) / 2))) * 3]; //holder[1] = holder[1] / 255;// 6 * scaleit; vertices.push_back(glm::vec3(x, holder[1], z + 2)); //match height map with online barycentric use heightMapforBaryCentric[x2][z2+1] = holder[1]; holder[2] = heightMapFromArray[z+2][x+2]; //holder[2] = (float)imageData[(((z + 2) / 2 * MAP_Z + ((x + 2) / 2))) * 3]; //holder[2] = holder[2] / 255;// *scaleit; vertices.push_back(glm::vec3(x + 2, holder[2], z + 2)); ////match height map with online barycentric use heightMapforBaryCentric[x2+1][z2+1] = holder[2]; //relevant - B - second triangle (on right side) holder[3] = heightMapFromArray[z][x]; //holder[3] = (float)imageData[((z / 2)*MAP_Z + (x / 2)) * 3]; //holder[3] = holder[3] / 255;// 256 * scaleit; vertices.push_back(glm::vec3(x, holder[3], z)); holder[4] = heightMapFromArray[x+2][z+2]; //holder[4] = (float)imageData[(((z + 2) / 2 * MAP_Z + ((x + 2) / 2))) * 3]; //holder[4] = holder[4] / 255;// *scaleit; vertices.push_back(glm::vec3(x + 2, holder[4], z + 2)); holder[5] = heightMapFromArray[x+2][z]; //holder[5] = (float)imageData[((z / 2)*MAP_Z + ((x + 2) / 2)) * 3]; //holder[5] = holder[5] / 255;// *scaleit; vertices.push_back(glm::vec3(x + 2, holder[5], z)); x = x + 2; } z = z + 2; } return(1); } float getHeightOfTerrain(float worldX, float worldZ) { float terrainX = worldX; float terrainZ = worldZ; int gridSquareSize = 2.0f; gridX = (int)floor(terrainX / gridSquareSize); gridZ = (int)floor(terrainZ / gridSquareSize); xCoord = ((float)(fmod(terrainX, gridSquareSize)) / (float)gridSquareSize); zCoord = ((float)(fmod(terrainZ, gridSquareSize)) / (float)gridSquareSize); if (xCoord <= (1 - zCoord)) { answer = baryCentric( //left triangle glm::vec3(0.0f, heightMapforBaryCentric[gridX][gridZ], 0.0f), glm::vec3(0.0f, heightMapforBaryCentric[gridX][gridZ+1], 1.0f), glm::vec3(1.0f, heightMapforBaryCentric[gridX+1][gridZ+1], 1.0f), glm::vec2(xCoord, zCoord)); // if (answer != 1) // { // fprintf(stderr, "Z:gridx: %d gridz: %d answer: %f\n", gridX, gridZ,answer); // // } } else { //right triangle answer = baryCentric(glm::vec3(0, heightMapforBaryCentric[gridX][gridZ], 0), glm::vec3(1,heightMapforBaryCentric[gridX+1][gridZ+1], 1), glm::vec3(1,heightMapforBaryCentric[gridX+1][gridZ], 0), glm::vec2(xCoord, zCoord)); } if (answer == 1) { answer = 0; } //answer = abs(answer - 1); return(answer); } float baryCentric(glm::vec3 p1, glm::vec3 p2, glm::vec3 p3 , glm::vec2 pos) { float det = (p2.z - p3.z) * (p1.x - p3.x) + (p3.x - p2.x) * (p1.z - p3.z); float l1 = ((p2.z - p3.z) * (pos.x - p3.x) + (p3.x - p2.x) * (pos.y - p3.z)) / det; float l2 = ((p3.z - p1.z) * (pos.x - p3.x) + (p1.x - p3.x) * (pos.y - p3.z)) / det; float l3 = 1.0f - l1 - l2; return (l1 * p1.y + l2 * p2.y + l3 * p3.y); } My expected results were that the center of the test grid's height to be the set value .5 and gradually less as the heights declined. My results were the heights being all the same, varied, or increasing. Usually these heights were under the value of one.
C++ Rotating 2D Shape List
I am having a bit of an issue with rotating a shape with given degrees. void Shape::rotate(double degrees) { // rotates the vertices of a shape by a specified angle in degrees int x, y, xx, yy; double radians; x = centroid.getX(); y = centroid.getY(); vertices.push_back(Vertex(x, y)); x = vertices.back().getX() - centroid.getX(); y = vertices.back().getY() - centroid.getY(); radians = (degrees * PI) / 180; xx = round(x * cos(radians) - y * sin(radians)); yy = round(y * cos(radians) + x * sin(radians)); xx = xx + centroid.getX(); yy = yy + centroid.getY(); vertices.push_back(Vertex(xx, yy)); radians = (degrees * PI) / 180; xx = round(x * cos(radians) - y * sin(radians)); yy = round(y * cos(radians) + x * sin(radians)); xx = xx + centroid.getX(); yy = yy + centroid.getY(); vertices.push_back(Vertex(xx, yy)); radians = (degrees * PI) / 180; xx = round(x * cos(radians) - y * sin(radians)); yy = round(y * cos(radians) + x * sin(radians)); xx = xx + centroid.getX(); yy = yy + centroid.getY(); vertices.push_back(Vertex(xx, yy)); } but the output i get is this: Messed up rhombus Any ideas where I'm going wrong?
2d rotation opengl
Here is the code I am using. #define ANGLETORADIANS 0.017453292519943295769236907684886f // PI / 180 #define RADIANSTOANGLE 57.295779513082320876798154814105f // 180 / PI rotation = rotation *ANGLETORADIANS; cosRotation = cos(rotation); sinRotation = sin(rotation); for(int i = 0; i < 3; i++) { px[i] = (vec[i].x + centerX) * (cosRotation - (vec[i].y + centerY)) * sinRotation; py[i] = (vec[i].x + centerX) * (sinRotation + (vec[i].y + centerY)) * cosRotation; printf("num: %i, px: %f, py: %f\n", i, px[i], py[i]); } so far it seams my Y value is being fliped.. say I enter the value of X = 1 and Y = 1 with a 45 rotation you should see about x = 0 and y = 1.25 ish but I get x = 0 y = -1.25. Also my 90 degree rotation always return x = 0 and y = 0. p.s I know I'm only centering my values and not putting them back where they came from. It's not needed to put them back as all I need to know is the value I'm getting now.
Your bracket placement doesn't look right to me. I would expect: px[i] = (vec[i].x + centerX) * cosRotation - (vec[i].y + centerY) * sinRotation; py[i] = (vec[i].x + centerX) * sinRotation + (vec[i].y + centerY) * cosRotation;
Your brackets are wrong. It should be px[i] = ((vec[i].x + centerX) * cosRotation) - ((vec[i].y + centerY) * sinRotation); py[i] = ((vec[i].x + centerX) * sinRotation) + ((vec[i].y + centerY) * cosRotation); instead
Wrong pixel locations with glDrawPixels
I have been playing around with trying to draw a 320 by 240 full screen resolution image in opengl using java and lwjgl. I set the resolution to 640 by 480 and doubled the size of the pixels to fill in the space. After a lot of google searching I found some information about using the glDrawPixels function to speed up drawing to the screen. I wanted to test it by assigning random colors to all the pixels on the screen, but it wouldn't fill the screen. I divided the width into 4 sections of 80 pixels each and colored them red, green, blue, and white. I saw that I was interleaving the colors but I can't figure out how. Here is an image of the output: Here is where I run the openGL code: // init OpenGL GL11.glMatrixMode(GL11.GL_PROJECTION); GL11.glLoadIdentity(); GL11.glOrtho(0, 640, 0, 480, 1, -1); GL11.glMatrixMode(GL11.GL_MODELVIEW); while (!Display.isCloseRequested()) { pollInput(); // Clear the screen and depth buffer GL11.glClear(GL11.GL_COLOR_BUFFER_BIT | GL11.GL_DEPTH_BUFFER_BIT); randomizePixels(); GL11.glRasterPos2i(0, 0); GL11.glDrawPixels(320, 240,GL11.GL_RGBA, GL11.GL_UNSIGNED_BYTE,buff); GL11.glPixelZoom(2, 2); Display.update(); } Display.destroy(); } and here is where I create the pixel color data: public void randomizePixels(){ for(int y = 0; y < 240; y++){ for(int x = 0; x < 320; x+=4){ /* pixels[x * 320 + y] = (byte)(-128 + ran.nextInt(256)); pixels[x * 320 + y + 1] = (byte)(-128 + ran.nextInt(256)); pixels[x * 320 + y + 2] = (byte)(-128 + ran.nextInt(256)); pixels[x * 320 + y + 3] = (byte)(-128 + ran.nextInt(256)); */ if(x >= 0 && x < 80){ pixels[y * 240 + x] = (byte)128; pixels[y * 240 + x + 1] = (byte)0; pixels[y * 240 + x + 2] = (byte)0; pixels[y * 240 + x + 3] = (byte)128; }else if(x >= 80 && x < 160){ pixels[y * 240 + x] = (byte)0; pixels[y * 240 + x + 1] = (byte)128; pixels[y * 240 + x + 2] = (byte)0; pixels[y * 240 + x + 3] = (byte)128; }else if(x >= 160 && x < 240){ pixels[y * 240 + x] = (byte)0; pixels[y * 240 + x + 1] = (byte)0; pixels[y * 240 + x + 2] = (byte)128; pixels[y * 240 + x + 3] = (byte)128; }else if(x >= 240 && x < 320){ pixels[y * 240 + x] = (byte)128; pixels[y * 240 + x + 1] = (byte)128; pixels[y * 240 + x + 2] = (byte)128; pixels[y * 240 + x + 3] = (byte)128; } } } buff.put(pixels).flip(); } If you can figure out why I can't get the pixels to line up to the x and y coordinates I want them to go to that would be great. I have read that glDrawPixels probably isn't the best or fastest way to draw pixels to the screen, but I want to understand why I'm having this particular issue before I have to move on to some other method.
Just load your image (unscaled) into a texture and draw a textured quad. Don't use glDrawPixels. This function was never properly optimized in most drivers and has was deprecated since OpenGL-2 and got removed from OpenGL-3 core and later.
I spot 2 issues in your randomizePixels(). 1. Indexing Pixel Buffer The total size of pixel buffer is 320x240x4 bytes because the pixel type is GL_RGBA. So, indexing each pixel with subscript operator, [], it would be; for(int y = 0; y < 240; y++) { for(int x = 0; x < 320; x++) { pixels[y * 320 * 4 + x * 4 + 0] = ... // R pixels[y * 320 * 4 + x * 4 + 1] = ... // G pixels[y * 320 * 4 + x * 4 + 2] = ... // B pixels[y * 320 * 4 + x * 4 + 3] = ... // A } } 2. Colour Value The max intensity of 8bit colour is 255, for example, an opaque red pixel would be (255, 0, 0, 255).
your operating on the texture. better do it on quadrature. it would yield good results
drawing centered arcs in raphael js
I need to draw concentric arcs of various sizes using raphael.js. I tried to understand the code behind http://raphaeljs.com/polar-clock.html, which is very similar to what I want, but, whithout comments, it is quite difficult to fathom. Ideally, I would need a function that creates a path that is at a given distance from some center point, starts at some angle and ends at some other angle.
That answer is ok, but cant be animated. I ripped the important stuff out of polar-clock for you. Here is a red arc that animates growing. enjoy. // Custom Arc Attribute, position x&y, value portion of total, total value, Radius var archtype = Raphael("canvas", 200, 100); archtype.customAttributes.arc = function (xloc, yloc, value, total, R) { var alpha = 360 / total * value, a = (90 - alpha) * Math.PI / 180, x = xloc + R * Math.cos(a), y = yloc - R * Math.sin(a), path; if (total == value) { path = [ ["M", xloc, yloc - R], ["A", R, R, 0, 1, 1, xloc - 0.01, yloc - R] ]; } else { path = [ ["M", xloc, yloc - R], ["A", R, R, 0, +(alpha > 180), 1, x, y] ]; } return { path: path }; }; //make an arc at 50,50 with a radius of 30 that grows from 0 to 40 of 100 with a bounce var my_arc = archtype.path().attr({ "stroke": "#f00", "stroke-width": 14, arc: [50, 50, 0, 100, 30] }); my_arc.animate({ arc: [50, 50, 40, 100, 30] }, 1500, "bounce");
Here's how I have done it. The following code allows you to specify a start and end angle as well as an inner and outer radius (useful for doing those trendy donut style pie charts). The solution doesn't rely on approximating a curve with line segments and can be animated as per the clock example mentioned in the original question. First create your Raphael drawing area; the following assumes a div with id "raphael_paper" in your HTML file: var paper = Raphael("raphael_paper", 800, 800); to this Raphael object we add a custom arc attribute, a function which takes the center of a circle (x and y coords), a start angle, an end angle, an inner radius and an outer radius: paper.customAttributes.arc = function (centerX, centerY, startAngle, endAngle, innerR, outerR) { var radians = Math.PI / 180, largeArc = +(endAngle - startAngle > 180); // calculate the start and end points for both inner and outer edges of the arc segment // the -90s are about starting the angle measurement from the top get rid of these if this doesn't suit your needs outerX1 = centerX + outerR * Math.cos((startAngle-90) * radians), outerY1 = centerY + outerR * Math.sin((startAngle-90) * radians), outerX2 = centerX + outerR * Math.cos((endAngle-90) * radians), outerY2 = centerY + outerR * Math.sin((endAngle-90) * radians), innerX1 = centerX + innerR * Math.cos((endAngle-90) * radians), innerY1 = centerY + innerR * Math.sin((endAngle-90) * radians), innerX2 = centerX + innerR * Math.cos((startAngle-90) * radians), innerY2 = centerY + innerR * Math.sin((startAngle-90) * radians); // build the path array var path = [ ["M", outerX1, outerY1], //move to the start point ["A", outerR, outerR, 0, largeArc, 1, outerX2, outerY2], //draw the outer edge of the arc ["L", innerX1, innerY1], //draw a line inwards to the start of the inner edge of the arc ["A", innerR, innerR, 0, largeArc, 0, innerX2, innerY2], //draw the inner arc ["z"] //close the path ]; return {path: path}; }; now we can use this to draw arcs of a specified thickness, starting and ending wherever we want them to eg. var redParams = {stroke: "#f00", "stroke-width": 1, fill:"#eee"}, greenParams = {stroke: "#0f0", "stroke-width": 1, fill:"#eee"}, blueParams = {stroke: "#00f", "stroke-width": 1, fill:"#eee"}, cx = 300, cy = 300, innerRadius = 100, outerRadius = 250, var red = paper.path().attr(redParams).attr({arc: [cx, cy, 0, 90, innerRadius, outerRadius]}); var green = paper.path().attr(greenParams).attr({arc: [cx, cy, 270, 320, innerRadius, outerRadius]}); var blue = paper.path().attr(blueParams).attr({arc: [cx, cy, 95, 220, innerRadius, outerRadius]}); This should result in three grey arc segments with red, blue and green 1px borders.
Actually found the answer myself. I first thought of something fancy involving bezier curves, but this just works. -> creates a path using SVG path syntax, which works as is with raphael function arc(center, radius, startAngle, endAngle) { angle = startAngle; coords = toCoords(center, radius, angle); path = "M " + coords[0] + " " + coords[1]; while(angle<=endAngle) { coords = toCoords(center, radius, angle); path += " L " + coords[0] + " " + coords[1]; angle += 1; } return path; } function toCoords(center, radius, angle) { var radians = (angle/180) * Math.PI; var x = center[0] + Math.cos(radians) * radius; var y = center[1] + Math.sin(radians) * radius; return [x, y]; }
Just to remove some guesswork from user592699's answer, this is the complete code that works: <script src="raphael.js"></script> <script> var paper = Raphael(20, 20, 320, 320); function arc(center, radius, startAngle, endAngle) { angle = startAngle; coords = toCoords(center, radius, angle); path = "M " + coords[0] + " " + coords[1]; while(angle<=endAngle) { coords = toCoords(center, radius, angle); path += " L " + coords[0] + " " + coords[1]; angle += 1; } return path; } function toCoords(center, radius, angle) { var radians = (angle/180) * Math.PI; var x = center[0] + Math.cos(radians) * radius; var y = center[1] + Math.sin(radians) * radius; return [x, y]; } paper.path(arc([100, 100], 80, 0, 270)); // draw an arc // centered at (100, 100), // radius 80, starting at degree 0, // beginning at coordinate (80, 0) // which is relative to the center // of the circle, // going clockwise, until 270 degree </script>
For those who want the arc to be made with closed path and not stroke, I have extended genkilabs answer to make a solution. In cases when you need to give outer stroke to your arc, this might help. // Custom Arc Attribute, position x&y, value portion of total, total value, Radius, width var archtype = Raphael("canvas", 200, 100); archtype.customAttributes.arc = function (xloc, yloc, value, total, R, width) { if(!width) width = R * 0.4; var alpha = 360 / total * value, a = (90 - alpha) * Math.PI / 180, w = width / 2, r1 = R + w, r2 = R - w, x1 = xloc + r1 * Math.cos(a), y1 = yloc - r1 * Math.sin(a), x2 = xloc + r2 * Math.cos(a), y2 = yloc - r2 * Math.sin(a), path; if (total == value) { path = [ ["M", xloc, yloc - r1], ["A", r1, r1, 0, 1, 1, xloc - 0.01, yloc - r1], ["Z"], ["M", xloc - 0.01, yloc - r2], ["A", r2, r2, 0, 1, 0, xloc, yloc - r2], ["Z"] ]; } else { path = [ ["M", xloc, yloc - r1], ["A", r1, r1, 0, +(alpha > 180), 1, x1, y1], ["L", x2, y2], ["A", r2, r2, 0, +(alpha > 180), 0, xloc, yloc - r2], ["L", xloc, yloc - r1], ["Z"] ]; } return { path: path }; }; //make an arc at 50,50 with a radius of 30 that grows from 0 to 40 of 100 with a bounce var my_arc = archtype.path().attr({ "fill": "#00f", "stroke": "#f00", "stroke-width": 5, arc: [50, 50, 0, 100, 30] }); my_arc.animate({ arc: [50, 50, 40, 100, 30] }, 1500, "bounce"); JSFiddle
You can also do this without having to use loops. The following achieves this and works with negative angles as well. Pass in a Raphael object as r. The angles start with 0 degrees, which is the top of the circle rather than the right as was listed in a couple of other solutions. function drawArc(r, centerX, centerY, radius, startAngle, endAngle) { var startX = centerX+radius*Math.cos((90-startAngle)*Math.PI/180); var startY = centerY-radius*Math.sin((90-startAngle)*Math.PI/180); var endX = centerX+radius*Math.cos((90-endAngle)*Math.PI/180); var endY = centerY-radius*Math.sin((90-endAngle)*Math.PI/180); var flg1 = 0; if (startAngle>endAngle) flg1 = 1; else if (startAngle<180 && endAngle<180) flg1 = 0; else if (startAngle>180 && endAngle>180) flg1 = 0; else if (startAngle<180 && endAngle>180) flg1 = 0; // edited for bugfix here, previously this was 1 else if (startAngle>180 && endAngle<180) flg1 = 1; return r.path([['M',startX, startY],['A',radius,radius,0,flg1,1,endX,endY]]); };
I have adapted genkilabs answer to include rotation and inversion abilities. Also, how much of the ring is filled was changed to a single-number percent. (The inversion was adapted from this post). Hope it's helpful! paper.customAttributes.arc = function (xloc, yloc, percent, rad, rot, invert) { var alpha = 3.6 * percent, a = (90 - alpha) * Math.PI / 180, x = xloc + rad * Math.cos(a), y = yloc - rad * Math.sin(a), path; if (invert) { x = xloc - rad * Math.cos(a); } if (percent >= 100) { path = [ ["M", xloc, yloc - rad], ["A", rad, rad, 0, 1, 1, xloc - 0.01, yloc - rad] ]; } else { path = [ ["M", xloc, yloc - rad], ["A", rad, rad, 0, +(alpha > 180), +(!invert), x, y] ]; } return { path: path, transform: "r"+rot+","+xloc+","+yloc, }; };