Unit test a variable for both true and false - c++

I'm working on a C++ production code here with googletest/googlemock. I've stumble upon this idea when working with one of the function in A.cpp:
bool A::process_(false);
bool A::process()
{
if ( !process_ ){
process_ = true;
}
return process_;
}
where the header contains:
protected:
static bool process_;
public:
static bool process();
I am stuck in a way that I can only test the function for an expected output of true or an input of false like so:
TEST(ATest, processVal){
A a;
EXPECT_TRUE(a.process());
}
Is there a way to test the function so that both *true* and *false* value of process_ is passed ? So that the test covers the decision for both.
I was thinking mocking so that it can expect a call for both true and false but because it is not a function in a member of a class, I guess you can not do mocking for process_ ?
If you can, how to mock the variable?
Note: I'm on linux and gcc :) thank you !

Solution1: To access any protected attribute/method from a test
without modifying production code
You can easily modify _process even if protected, just do this:
class SubA : public A
{
public:
void setProcess( bool val ) { process_ = val; }
};
A a;
SubA* pA = (SubA*) &a;
pA->setProcess( false );
This will work pretty well and is safe. Even if you are casting A* to SubA* which is not really valid, it will work as SubA objects in memory are the same as A objects (as SubA does not declare any extra attribute).
This only works because process_ is protected, so you create a derived class SubA and use it because compiler will allow this subclass to access the protected stuff.
Solution2: To access any protected and even private attribute/method from a test without modifying production code
Now, if process_ was private, this would not work...but, private/protected is only managed by the compiler...the attributes are here in memory and you may access them even if you are not "allowed to".
It's ugly but works perfectly:
#define protected public
#define private public
#include "A.h"
#undef private
#undef protected
{
A a;
a._process = false;
}
This hack makes it easy to access any private/protected attributes/functions from your test programs.

Declare a subclass of A. Since process_ is protected, you can use the subclass of A to set it totrueorfalse`, before running the test.

Related

Mock class object as parameter of function

I am using junit and mokito to write unit test of my java program.
public MyClass {
private ClassA a;
public void process(ClassB b) {
if(b.method()) a = ClassA.builder().build();
}
}
Now I have write a MockClassA and MockClassB. But I don't know how to :
Pass a MockClassB instantiation to process function
How to verify whether private variable a is set successfully
Can anybody help?
You can use something like:
#Test
public void shouldDoSomething() {
// given
ClassB mock = Mockito.mock(ClassB.class);
Mockito.when(mock.method()).thenReturn(true);
MyClass classUnderTest = new MyClass();
// when
classUnderTest.process(mock);
// then
// Insert assertions
}
However, if your field is private you are unable to test it properly. You should provide a getter for this field if you want to make some assertions against it.
But remember that internal representation of MyClass should not be tested, only the behavior of it so maybe you want to try different approach

Google Mock for NonVirtual and Private Functions

I'm attempting to write Mocks for Private / Non Virtual / Static functions and come across a way to do the same.
Here is how it looks like..
Lets assume that I have a class A which needs to be mocked and used inside class UsingA. The definition of both classes looks like
class A
{
friend class UsingA;
int privateFn() {}
public:
int nonVirtual() {}
};
// The UsingA class
class UsingA {
A &a1;
public:
UsingA(A & _a1) : a1(_a1) {}
int CallFn() {
return a1.nonVirtual();
}
int CallFn2() {
return a1.privateFn();
}
};
I know that Mocks are meant for generating the behavior of the class and while creating Mocks, we need to derive from the original class.
However, to Mock the behavior I decided not to derive from the original class, instead comment the class A and generate a Mock class with the same Name i.e class A.
Here is how my mock class looks like
// Original class A is commented / header file removed
class A {
public:
MOCK_METHOD0(nonVirtual, int());
MOCK_METHOD0(privateFn, int());
};
And my tests are usual mock tests
TEST(MyMockTest, NonVirtualTest) {
A mstat;
UsingA ua(mstat);
EXPECT_CALL(mstat, nonVirtual())
.Times(1)
.WillOnce(Return(100));
int retVal = ua.CallFn();
EXPECT_EQ(retVal,100);
}
TEST(MyMockTest, PrivateTest) {
A mstat;
UsingA ua(mstat);
EXPECT_CALL(mstat, privateFn())
.Times(1)
.WillOnce(Return(100));
int retVal = ua.CallFn2();
EXPECT_EQ(retVal,100);
}
And everything works fine and I'm able to test UsingA by this mock.
Question is.
This looks easier and serves the purpose, still I haven't seen this kind of examples while browsing for google mock examples. Is there anything that would go wrong if I do this?
Honestly, I didn't find any.
NOTE: Folks, I'm using friend for demonstration only. My actual use case is totally different. Thanks
The wrong is that you are not testing real code, because of that:
comment the class A
generate a Mock class with the same name
These operations alter the code under test.
An example what can go wrong:
Change return type: long nonVirtual in Mock - previously was int
Test that on, let say, nonVirtual() == 0xFF'FFFF'FFFF (which is bigger than INTMAX) some action is being done
Forget to change in real A - so real UsingA have branch that is tested but never reachable in real code
An example code:
class A {
public:
MOCK_METHOD0(nonVirtual, long()); // change
MOCK_METHOD0(privateFn, int());
};
void UsingA::processA()
{
if (a.nonVirtual() > VERY_BIG_NUMBER)
{
throw runtime_error("oops");
}
}
TEST_F(UsingATest, throwOnVeryBigNumber)
{
EXPECT_CALL(aMock, nonVirtual()).WillOnce(Return(VERY_BIG_NUMBER + 1));
ASSERT_THROW(objectUndertTest.processA());
}
But real A did not change - so we test non reachable code in UsingA class:
class A {
public:
int nonVirtual(); // not changed
...
};
The best solution is (in order):
To test in isolation you have to isolate classes - so to use dependency injection (virtual functions etc, base interfaces, etc...) - this is sometimes called London School of TDD
Test both classes A and UsingA w/o any stubbing - test them together in one testcase - thus you test real code - this is called Detroit Shool of TDD
Separate by template code with good restriction on interface - this approach is most similar to yours:
Regarding 3 - you might use something like this:
template <class T = A>
class UsingA {
T &a1;
public:
UsingA(T & _a1) : a1(_a1) {}
long CallFn() {
using ANonVirtualResult = std::invoke_result_t<&T::nonVirtual>;
static_assert(std::is_same<long, ANonVirtualResult>::value);
return a1.nonVirtual();
}
...
};
And in test:
class UsingATest : public ::testing::Test
{
protected:
StrictMock<AMock> aMock;
using ClassUnderTest = UsingA<AMock>;
ClassUnderTest objectUnderTest{aMock};
};
TEST_F(UsingATest, useNonVirtual)
{
const auto VALUE = 123456;
EXPECT_CALL(aMock, nonVirtual()).WillOnce(Return(VALUE));
ASSERT_EQ(VALUE, objectUnderTest.CallFn());
}
You might note that some assumption about A might be tested during compilation as static_assert or via some SFINAE technics (more complicated).
Actually, there are examples with template code in googlemock as workaround for mocking classes w/o virtual functions.
We use your type of using mocks inside a few of our test projects to check callbacks on a larger class that we pass along using dependency injection. In our case, the methods are declared virtual.
In your case, they are not. Your mock implementation would hide the original implementation - if there was any. So I don't think there's an issue here.

should we create object of any class on class level or function level

Which approach is better: I tried to find it on web, but I couldn't get a better answer.
1.
public class OtherClass
{
public int Add(int x, int y)
{
return x + y;
}
}
public class TestClass
{
OtherClass oClass = new OtherClass();
public int Fun1()
{
return oClass.Add(1,2);
}
public int Fun2()
{
return oClass.Add(1, 2);
}
}
2.
public class TestClass
{
public int Fun1()
{
OtherClass oClass = new OtherClass();
return oClass.Add(1, 2);
}
public int Fun2()
{
OtherClass oClass = new OtherClass();
return oClass.Add(1, 2);
}
}
I think it depends on what you are trying to test.
If you're testing the effects of a sequence of functions being executed on the same class instance then you might want to create a single instance (such as stress testing)
But otherwise I'd say it's always better to create a new instance of the class in each test function to ensure that the context of each test is predictable. If your test methods shared an instance of a class, and one test method fails and corrupts the state of the object under test, your subsequent test may fail for no other reason than the state of the object under test was corrupted by the previous failed test (it might appear the multiple tests are failing when in fact only one of the early ones is a true failure).
Depends on the scenario, if the class is gonna be shared on multiple functions and there are no specific arguments needed to create an instance of that class then it's better of being at the class level.
Let's say you're using the Fun1 and Fun2 often, having the instance creation on the method will have instance creation overhead rather than it being at the class level having a single instance, or better yet, make it static or make it singleton if you're sure that it's going to be a single instance throughout the whole app.
One benefit of having it in the class level is if you're doing unit testing, you can make an interface like IOtherClass and Inject it in the constructor of TestClass.
It would look something like this.
public class OtherClass : IOtherClass
{
public int Add(int x, int y)
{
return x + y;
}
}
public class TestClass
{
IOtherClass oClass;
public TestClass(IOtherClass _oClass)
{
oClass = _oClass;
}
public int Fun1()
{
return oClass.Add(1,2);
}
public int Fun2()
{
return oClass.Add(1, 2);
}
}
You're better off having it as a field in the class rather than declaring a new one in each method. The reason for this is simple, there won't be a line of code in each method declaring the variable meaning that if your declaration statement changes you will only have to change it in one place, not every method. Also it will make your code easier to read and add to because this line won't be duplicated everywhere.
Just remember if that field needs to be disposed your class should implement the IDisposable interface.

Make Object available to all methods c++

Can anyone help me with this? basically I have a test class, wihtin this test class I have a number of methods which all use the same type of setup. Let me show you by example:
class Test:public CxxTest::TestSuite
{
public:
void Test1(){/*...*/}
void Test2(){/*...*/}
};
Each test method requires the same type of setup:
Class c_objectName = AnotherClass::method("c_name","c_name","c_name");
class c_newObjectName = AnotherCLass::create(c_objectName);
I am currently setting this in every single method, because each of the above i started with "c_..." needs to be different.
I tried to make a "global method" that would take in a string to rename these each time, but then I cant seems to access them from the method calls. I tried the following:
class Test:public CxxTest::TestSuite
{
public:
void method()
{ Class c_objectName = AnotherClass::method("c_name","c_name","c_name"); <--- cant access these
Class c_newObjectName = AnotherClass::create(c_objectName);
}
void Test1(){/*...*/}
void Test2(){/*...*/}
};
Is there a way to put this in a "global method" of some sort so that I can access these from the methods?
Im really bad at explaining things so sorry and thanks in advance
I can't make heads and tails of the question, but it looks like something like this would help:
struct TestFixture
{
Class c_objectName;
Class c_newObjectName;
};
TestFixture makeFixture()
{
TestFixture fixture;
fixture.c_objectName = new Class("c_name","c_name","c_name");
fixture.c_newObjectName = create(c_objectName);
return fixture;
}
(assuming your Class (classes?) are copyable. If not, return a pointer to a new instance of TestFixture or something like scoped_ptr
Then you could use it in your test methods:
void Test1()
{
TestFixture fixture = makeFixture();
// use fixture.c_objectName etc.
If you don't mind sharing the data, you could just make them fields of class Test.
Edit Oh, I just realized you are using CxxTest, which probably has a better way of creating fixtures/setup/teardown for unit tests. However, the above approach should work in any framework.

How to divert "non public" method in public class moles

I have a public method that uses a local private method to get data from the Db.
private string SomeMethod(string)
{
...
Doing some operations
...
string data = GetDBData(string);
Doing some operations
...
}
I want to divert/isolate the private method GetDBData(string) using moles so my test will not require the DB.
Obviously, my question is: how to do it?
thank you
Uria
EDIT
Additional information:
i tried to change the method accessors both to public and internal protected,
in both cases i can now see the methods as moles.
BUT when running the test, the original method is still being used and not the detour I've implemented in the PexMethod.
You can try any of the following.
Make the method internal and add an attribute like this to the assembly:
[assembly: InternalsVisibleTo("<corresponding-moles-assembly-name>")]
Change the method access to protected virtual and then use a stub.
Refactor your class so that it gets an interface (IDataAccessObject) as a constructor parameter, SomeMethod being one of the methods of that interface, and then pass a stub of that interface to your class in test methods.
I figured it out
If i have the public MyClass with private SomeMethod
public class MyClass
{
private string SomeMethod(string str){}
}
if you want to mole the SomeMethod method you need to use AllInstances in the test method:
[PexMethod]
SomeMethod(string str)
{
MMyClass.AllInstances.SomeMethod = (instance, str) => { return "A return string"; };
}
notice that the lambda receives an instance parameter as the first parameter. I'm not sure what it's function is.