I'm building APIs using Laravel, and for some reason, the response generated seems to add a new line before returning the response. An example of this issue is explained in this link.
I suspect this is because there is an empty space or new line character before the opening tags in one of the PHP files. I was wondering what's the easiest way to find it? I use PHPStorm, and it has a regex search option. I am quite clueless as to how to use it to find the files though. Any ideas?
You could use \s+<\?php. To remove the spaces, replace the matches with <?php.
Related
This probably isn't a VS Code-specific question but it's my tool of choice.
I have a log file with a lot of lines containing the following:
Company.Environment.Security.RightsBased.Policies.RightsUserAuthorizationPolicy
Those are debug-level log records that clutter the file I'm trying to process. I'm looking to remove the lines with that content.
I've looked into Regex but, unlike removing a blank line where you have the whole content in the search criteria (making find/replace easy), here I need to match from line break to line break on some criteria between the two, I think...
What are your thoughts on how criteria like that would work?
If the criteria is a particular string and you don't want to have to remember regexes, there is a few handy keyboard shortcuts that can help you out. I'm going to assume you're on a Mac.
Cmd-F to open find.
Paste your string.
Opt-Enter to select all of the instances of the string on the page.
Cmd-L to broaden the selection to the entire line of each instance on the page.
Delete/Backspace to remove those lines.
I think you should be able to just search for ^.*CONTENT.*$\n, where the content is the text you showed us. That is, search on the following pattern:
^.*Company\.Environment\.Security\.RightsBased\.Policies\.RightsUserAuthorizationPolicy.*$\n
And then just replace with empty string.
I have already up-voted answer of #james. But.. still I found one more easy and many feature available extension in VS Code. Here it is
It have much easy options to apply filters.
To match specific case mentioned in question. I am attaching screenshot which display how to use for it. I am posting this for others who come here in search for same issue. (Like I came)
I'm working with an enterprise CMS and in order to properly create our weekly-updated dropdown menu without republishing our entire site, I have an XML document being created which has a various number of useful XML elements. However, when pulling in a link with the CMS, the generated XML also outputs the link's contents (the entire HTML for the page). Needless to say, with roughly 50 items, the XML file is too big for use on the web (as it stands I think it's over 600KB). The element is <page-content>filler here</page-content>.
What I'm trying to do is use TextWrangler to find and replace all <page-content> tags as well as their containing content.
I've tried a few different regex's, but I can't seem to match the closing tag, so it will just trail on.
Here's what I've tried:
(<page-content>)(.*?)
The above will match up until the next starting <page-content> tag, which is not what I want.
(<page-content>)(.*?)(<\/page-content>)
(<page-content>)(.*?)(<\/page\-content>)
The above finds no matches, even though the below will find the 7 matches it should.
(<content>)(.*?)(<\/content>)
I don't know if there's a special way to deal with hyphens (I'm inexperienced in regular expressions), but if anyone could help me out, it would be greatly appreciated.
Thanks!
EDIT: Before you tell me that Regex isn't meant to parse HTML, I know that, but there seems to be no other way for me to easily find and replace this. There are too many occurences to manually delete it and save the file again every week.
It seems the problem is that your . is not matching newlines that exist between your open and close tags.
An easy solution for this would be to add the s flag in order for your . to match over newlines. TextWrangler appears to support inline modifiers (?s). You could do it like this:
(<page-content>)(?s)(.*?)(<\/page-content>)
More information on modifiers here.
I'm trying to use the Atomiq tool to check only one file for duplicate code. However there is only a regex exclusion option.
I've tried using .*(?!filename) to exclude all negative results which doesn't work. Does anybody have an idea?
Try following regex to get your result
(.*)filename
I'm trying to write some Perl to convert some HTML-based text over to MediaWiki format and hit the following problem: I want to search and replace within a delimited subsection of some text and wondered if anyone knew of a neat way to do it. My input stream is something like:
Please mail support. if you want some help.
and I want to change Please help and Please can some one help me out here to Please%20help and Please%20can%20some%20one%20help%20me%20out%20here respectively, without changing any of the other spaces on the line.
Naturally, I also need to be able to cope with more than one such link on a line so splicing isn't such a good option.
I've taken a good look round Perl tutorial sites (it's not my first language) but didn't come across anything like this as an example. Can anyone advise an elegant way of doing this?
Your task has two parts. Find and replace the mailto URIs - use a HTML parsing module for that. This topic is covered thoroughly on Stack Overflow.
The other part is to canonicalise the URI. The module URI is suitable for this purpose.
use URI::mailto;
my #hrefs = ('mailto:help#myco.com&Subject=Please help&Body=Please can some one help me out here');
print URI::mailto->new($_)->as_string for #hrefs;
__END__
mailto:help#myco.com&Subject=Please%20help&Body=Please%20can%20some%20one%20help%20me%20out%20here
Why dont you just search for the "Body=" tag until the quotes and replace every space with %20.
I would not even use regular expresions for that since I dont find them useful for anything except mass changes where everything on the line is changes.
A simple loop might be the best solution.
Problem:
^.+ matches only the first line of the source code in dreamweaver. I need it to match each line so that I can wrap each full line in P tags. I have 500 files to do this in.
I know ^ should match the beginning of a line and I also know that multi-line mode must be enabled for it to work on each line and not just at the beginning of the file. I also know dreamweaver uses javascript source code.
Is lack of multi-line mode the problem? Is there any way to turn it on in dreamweaver? I tried using /m at the beginning search to enable multi-line mode, but that didn't work either.
I'm open to any solution for my current problem, even if it involves a different program. However, a fix for dreamweaver is ideal, 2nd place is a way to do this in notepad++, 3rd place is a way do to this in python or something (I only know javascript, you'll have to spell it out exactly in another language).
Thank you,
robert
p.s.
I found I can "select all > right click > selection > indent" to add two spaces to the beginning of each line in dreamweaver. This allows me to find the beginning of each line with / {2,}/. I really don't want to select all > indent on all 500 files, but i'm about to start since I've already spent a few hours bludgeoning dreamweaver.
Don't use Dreamweaver for this - use Notepad++ (since you are familiar with it) at its regular expression support is superior.
If you are comfortable with a more robust scripting language (Python, Ruby, Perl, etc.) then that would be an ever better way to do it.
The way that I might do this in DW would not involve using the find-replace tool's "Regular Expression" option, but instead using just plain old matching on a CrLf.
In the Find portion, since you can't directly enter a CrLf, you'll have to copy one to your clipboard beforehand and paste it in where needed.
In the Replace portion, replace with:
</p>[CrLf]
<p>
Again, be sure to paste in a proper "[CrLf]". This will work on all but the very first and very last lines of your document, so I know this isn't a 100% solution. There are probably better solutions using other tools that someone else can recommend!
Good luck!
-Mike
I had a flash of insight right after posting. (isn't that the way of it?)
Dreamweaver can find the end of each line with \r\n so instead of trying to work forward, i should have just worked backwards.
search: (.+)(\r\n)
replace: <p>$1</p>$2
[\w\W]* matches anything, including a newline. Its greedy, so it fact it matches everything.