Double numbers output gets truncated - c++

I have a problem where I need to print some double value using basic C++ output system (such as iostream or sstream) and this value somehow gets truncated a lot.
For example:
double a = 283752.24234;
std::cout << 283752.24234 << std::endl;
std::cout << a << std::endl;
Both of the outputs will be 283752
Why is this happening and what can I do to get complete output of any double value?

Why is this happening ...
That's because the default precision is 6 and thus only the foremost 6 digits are rendered 283752.
... and what can I do to get complete output of any double value?
First option is to use a bigger precision value using the std::setprecision() I/O manipulator:
#include <iostream>
#include <iomanip>
int main(){
double a = 283752.24234;
std::cout << std::setprecision(12) << 283752.24234 << std::endl;
std::cout << std::setprecision(12) << a << std::endl;
}
See Live Demo
Second option is to use the std::fixed I/O manipulator to show the values after the decimal point:
#include <iostream>
#include <iomanip>
int main(){
double a = 283752.24234;
std::cout << std::fixed << 283752.24234 << std::endl;
std::cout << std::fixed << a << std::endl;
}
See Live Demo
Output:
283752.242340
283752.242340

Related

"Double" is not printing more than 6 significant digits even after setprecision

I'm self learning C++ and for some reason "double" doesn't print more than 6 significant digits even after std::setprecision. Do I need to do something else? Most recent version of codeblocks if that helps. This is all the code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
std::setprecision(9);
double A = 654321.987;
cout << A << endl;
return 0;
}
You need to feed the result of std::setprecision(9) to std::cout. Otherwise it has no way of knowing what output stream it applies to (and so it won't apply to anything).
std::cout << std::setprecision(9) << A << std::endl;
Or if you prefer you can do it separately:
std::cout << std::setprecision(9);
std::cout << A << std::endl;

Setprecision in a function is also applying in another function. I can't seem to know why [duplicate]

I want to control the precision for a double during a comparison, and then come back to default precision, with C++.
I intend to use setPrecision() to set precision. What is then syntax, if any, to set precision back to default?
I am doing something like this
std::setPrecision(math.log10(m_FTOL));
I do some stuff, and I would like to come back to default double comparison right afterwards.
I modified like this, and I still have some errors
std::streamsize prec = std::ios_base::precision();
std::setprecision(cmath::log10(m_FTOL));
with cmath false at compilation, and std::ios_base also false at compilation. Could you help?
You can get the precision before you change it, with std::ios_base::precision and then use that to change it back later.
You can see this in action with:
#include <ios>
#include <iostream>
#include <iomanip>
int main (void) {
double d = 3.141592653589;
std::streamsize ss = std::cout.precision();
std::cout << "Initial precision = " << ss << '\n';
std::cout << "Value = " << d << '\n';
std::cout.precision (10);
std::cout << "Longer value = " << d << '\n';
std::cout.precision (ss);
std::cout << "Original value = " << d << '\n';
std::cout << "Longer and original value = "
<< std::setprecision(10) << d << ' '
<< std::setprecision(ss) << d << '\n';
std::cout << "Original value = " << d << '\n';
return 0;
}
which outputs:
Initial precision = 6
Value = 3.14159
Longer value = 3.141592654
Original value = 3.14159
Longer and original value = 3.141592654 3.14159
Original value = 3.14159
The code above shows two ways of setting the precision, first by calling std::cout.precision (N) and second by using a stream manipulator std::setprecision(N).
But you need to keep in mind that the precision is for outputting values via streams, it does not directly affect comparisons of the values themselves with code like:
if (val1== val2) ...
In other words, even though the output may be 3.14159, the value itself is still the full 3.141592653590 (subject to normal floating point limitations, of course).
If you want to do that, you'll need to check if it's close enough rather than equal, with code such as:
if ((fabs (val1 - val2) < 0.0001) ...
Use C++20 std::format and {:.2} instead of std::setprecision
Finally, this will be the superior choice once you can use it:
#include <format>
#include <string>
int main() {
std::cout << std::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
Expected output:
3.14 3.145
This will therefore completely overcome the madness of modifying std::cout state.
The existing fmt library implements it for before it gets official support: https://github.com/fmtlib/fmt Install on Ubuntu 22.04:
sudo apt install libfmt-dev
Modify source to replace:
<format> with <fmt/core.h>
std::format to fmt::format
main.cpp
#include <iostream>
#include <fmt/core.h>
int main() {
std::cout << fmt::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
and compile and run with:
g++ -std=c++11 -o main.out main.cpp -lfmt
./main.out
Output:
3.14 3.142
See also:
How do I print a double value with full precision using cout?
std::string formatting like sprintf
Pre C++20/fmt::: Save the entire state with std::ios::copyfmt
You might also want to restore the entire previous state with std::ios::copyfmt in these situations, as explained at: Restore the state of std::cout after manipulating it
main.cpp
#include <iomanip>
#include <iostream>
int main() {
constexpr float pi = 3.14159265359;
constexpr float e = 2.71828182846;
// Sanity check default print.
std::cout << "default" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
// Change precision format to scientific,
// and restore default afterwards.
std::cout << "modified" << std::endl;
std::ios cout_state(nullptr);
cout_state.copyfmt(std::cout);
std::cout << std::setprecision(2);
std::cout << std::scientific;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout.copyfmt(cout_state);
std::cout << std::endl;
// Check that cout state was restored.
std::cout << "restored" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
}
GitHub upstream.
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out
Output:
default
3.14159
2.71828
modified
3.14e+00
2.72e+00
restored
3.14159
2.71828
Tested on Ubuntu 19.04, GCC 8.3.0.
You need to keep track of your current precison and then reset back to the same once done with your operations with required modified precison. For this you can use std::ios_base::precision:
streamsize precision ( ) const;
streamsize precision ( streamsize prec );
The first syntax returns the value of the current floating-point precision field for the stream.
The second syntax also sets it to a new value.
setprecision() can be used only for output operations and cannot be used for comparisons
To compare floats say a and b , you have to do it explicitly like this:
if( abs(a-b) < 1e-6) {
}
else {
}
You can use cout << setprecision(-1)

boost rational cast to double

Using the following bit of code compiled against boost 1.62:
#include <boost/rational.hpp>
#include <iostream>
int main() {
auto val = boost::rational<int64_t>(499999, 2);
std::cout << val << std::endl;
std::cout << boost::rational_cast<double>(val) << std::endl;
}
I get the following output:
499999/2
250000
I would expect rational_cast to output 249999.5
Can anyone explain what I am doing wrong?
Modify the default formatting for floating-point input/output:
std::cout << std::fixed << boost::rational_cast<double>(v) << std::endl; add std::fixed to it.

Stop the rounding on float c++

I am getting an issue when trying to output my float using std::cout <<
I have the following values:
vector2f = {-32.00234098f, 96.129380f} //takes 2 floats (x, y)
output: -32.0023:96.1294
What I am looking for is:
output: -32.00234098:96.129380
The actual numbers could be vary from the 7 decimal places (.0000007) to 3 decimal places (.003) so setting a fixed rounding number does not work in this case.
Any help would be great as I have tried changed to doubles as well but to no avail.
Thanks in advance!
There are 2 problems.
you need to include <iomanip> and use the std::setprecision manipulator.
To get the level of accuracy you want you will need to use doubles rather than floats.
e.g.:
#include <iostream>
#include <iomanip>
int main()
{
auto x = -32.00234098f, y = 96.129380f;
std::cout << std::setprecision(8) << std::fixed << x << ":" << y << std::endl;
// doubles
auto a = -32.00234098, b = 96.129380;
std::cout << std::setprecision(8) << std::fixed << a << ":" << b << std::endl;
}
example output:
-32.00234222:96.12937927
-32.00234098:96.12938000
You can set the output precision of the stream using std::precision manipulator.
To print trailing zeroes up to the given precision like in your example output, you need to use std::fixed manipulator.

Set back default floating point print precision in C++

I want to control the precision for a double during a comparison, and then come back to default precision, with C++.
I intend to use setPrecision() to set precision. What is then syntax, if any, to set precision back to default?
I am doing something like this
std::setPrecision(math.log10(m_FTOL));
I do some stuff, and I would like to come back to default double comparison right afterwards.
I modified like this, and I still have some errors
std::streamsize prec = std::ios_base::precision();
std::setprecision(cmath::log10(m_FTOL));
with cmath false at compilation, and std::ios_base also false at compilation. Could you help?
You can get the precision before you change it, with std::ios_base::precision and then use that to change it back later.
You can see this in action with:
#include <ios>
#include <iostream>
#include <iomanip>
int main (void) {
double d = 3.141592653589;
std::streamsize ss = std::cout.precision();
std::cout << "Initial precision = " << ss << '\n';
std::cout << "Value = " << d << '\n';
std::cout.precision (10);
std::cout << "Longer value = " << d << '\n';
std::cout.precision (ss);
std::cout << "Original value = " << d << '\n';
std::cout << "Longer and original value = "
<< std::setprecision(10) << d << ' '
<< std::setprecision(ss) << d << '\n';
std::cout << "Original value = " << d << '\n';
return 0;
}
which outputs:
Initial precision = 6
Value = 3.14159
Longer value = 3.141592654
Original value = 3.14159
Longer and original value = 3.141592654 3.14159
Original value = 3.14159
The code above shows two ways of setting the precision, first by calling std::cout.precision (N) and second by using a stream manipulator std::setprecision(N).
But you need to keep in mind that the precision is for outputting values via streams, it does not directly affect comparisons of the values themselves with code like:
if (val1== val2) ...
In other words, even though the output may be 3.14159, the value itself is still the full 3.141592653590 (subject to normal floating point limitations, of course).
If you want to do that, you'll need to check if it's close enough rather than equal, with code such as:
if ((fabs (val1 - val2) < 0.0001) ...
Use C++20 std::format and {:.2} instead of std::setprecision
Finally, this will be the superior choice once you can use it:
#include <format>
#include <string>
int main() {
std::cout << std::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
Expected output:
3.14 3.145
This will therefore completely overcome the madness of modifying std::cout state.
The existing fmt library implements it for before it gets official support: https://github.com/fmtlib/fmt Install on Ubuntu 22.04:
sudo apt install libfmt-dev
Modify source to replace:
<format> with <fmt/core.h>
std::format to fmt::format
main.cpp
#include <iostream>
#include <fmt/core.h>
int main() {
std::cout << fmt::format("{:.3} {:.4}\n", 3.1415, 3.1415);
}
and compile and run with:
g++ -std=c++11 -o main.out main.cpp -lfmt
./main.out
Output:
3.14 3.142
See also:
How do I print a double value with full precision using cout?
std::string formatting like sprintf
Pre C++20/fmt::: Save the entire state with std::ios::copyfmt
You might also want to restore the entire previous state with std::ios::copyfmt in these situations, as explained at: Restore the state of std::cout after manipulating it
main.cpp
#include <iomanip>
#include <iostream>
int main() {
constexpr float pi = 3.14159265359;
constexpr float e = 2.71828182846;
// Sanity check default print.
std::cout << "default" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
// Change precision format to scientific,
// and restore default afterwards.
std::cout << "modified" << std::endl;
std::ios cout_state(nullptr);
cout_state.copyfmt(std::cout);
std::cout << std::setprecision(2);
std::cout << std::scientific;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout.copyfmt(cout_state);
std::cout << std::endl;
// Check that cout state was restored.
std::cout << "restored" << std::endl;
std::cout << pi << std::endl;
std::cout << e << std::endl;
std::cout << std::endl;
}
GitHub upstream.
Compile and run:
g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out
Output:
default
3.14159
2.71828
modified
3.14e+00
2.72e+00
restored
3.14159
2.71828
Tested on Ubuntu 19.04, GCC 8.3.0.
You need to keep track of your current precison and then reset back to the same once done with your operations with required modified precison. For this you can use std::ios_base::precision:
streamsize precision ( ) const;
streamsize precision ( streamsize prec );
The first syntax returns the value of the current floating-point precision field for the stream.
The second syntax also sets it to a new value.
setprecision() can be used only for output operations and cannot be used for comparisons
To compare floats say a and b , you have to do it explicitly like this:
if( abs(a-b) < 1e-6) {
}
else {
}
You can use cout << setprecision(-1)