Many to many in django Admin - django

Question

I want to ask. Can i create multiple view my items in django admin.
I have a many to many relationship, so i created an associative entity. But i can't understand how view this in django admin. Can someone help me.
models.py
from django.db import models
from django.contrib import admin
class Client(models.Model):
f_name = models.CharField(verbose_name = "Фамилия", max_length = 100)
l_name = models.CharField(verbose_name = "Имя", max_length = 100)
m_name = models.CharField(verbose_name = "Отчество", max_length = 100)
phone = models.CharField(verbose_name = "Телефон", max_length = 100)
city = models.CharField(verbose_name = "Город", max_length = 100)
address = models.CharField(verbose_name = "Адрес", max_length = 200)
def __str__(self):
return self.f_name + " " + self.l_name + " (" + self.phone + ")"
class Item(models.Model):
name = models.CharField(verbose_name = "Название", max_length = 100)
TYPE_ITEMS = (
("shirt", "Футболка"),
("shoes", "Обувь"),
("bags", "Рюкзаки и сумки"),
("heads", "Головные уборы"),
("others", "Другое"),
)
type_item = models.CharField(verbose_name = "Тип продукта",
choices = TYPE_ITEMS, max_length = 6,
default = "shirt")
other = models.TextField("другая информация")
color = models.CharField("Цвет(а)", max_length = 100)
cost = models.IntegerField("Стоимость за штуку", default = 0)
is_available_now = models.BooleanField("Есть ли в наличии?",
default = False)
available_count = models.IntegerField("Количество в наличии", default = 0)
photo = models.ImageField("Фото", upload_to = "media")
def __str__(self):
return self.name + " " + self.color + " (" + str(self.cost) + " грн)"
class Order(models.Model):
id_client = models.ForeignKey(Client, null = True, blank = True,
verbose_name = "Клиент")
date_order = models.DateField(verbose_name = "Дата заказа")
date_taken = models.DateField(verbose_name = "Дата получения")
is_paid = models.BooleanField(verbose_name = "Оплачено?", default = False)
is_taken = models.BooleanField(verbose_name = "Получил покупатель?",
default = False)
class Order_item(models.Model):
id_order = models.ForeignKey(Order)
id_item = models.ForeignKey(Item)
admin.py
admin.site.register(Item)
admin.site.register(Order)
admin.site.register(Client)
admin.site.register(Order_item)
If user creates order, how can i view what he buy?
If user in admin selects an order i want to view many items. Can i create this with django admin ?

Answer 1

I have done this job. So this is my code:
admin.py
from django.contrib import admin
from myapp.models import Client, Item, Order, Ordering
class ClientAdmin(admin.ModelAdmin):
list_display = ("f_name", "l_name", "m_name", "phone", "city", "address")
list_filter = ["f_name", "l_name", "city"]
class ItemAdmin(admin.ModelAdmin):
list_display = ("name", "type_item", "color", "cost", "is_available_now",
"available_count")
list_filter = ["name", "type_item", "color", "cost", "available_count"]
class OrderingAdmin(admin.ModelAdmin):
list_display = ("id_order", "id_item", "count_items")
list_filter = ["id_order", "id_item", "count_items"]
class OrderingInline(admin.TabularInline):
model = Ordering
fk_name = "id_order"
max_num = 1
class OrderAdmin(admin.ModelAdmin):
list_display = ("id", "id_client", "date_order", "date_taken", "is_paid",
"is_taken")
list_filter = ["date_order", "date_taken", "is_paid", "is_taken"]
inlines = [
OrderingInline,
]
admin.site.register(Item, ItemAdmin)
admin.site.register(Order, OrderAdmin)
admin.site.register(Client, ClientAdmin)
admin.site.register(Ordering, OrderingAdmin)
And what I take:
Thanks to all)))

Answer 2

Instead of use Order_item class, you should add a items = models.ManyToManyField(Item) field into your current Order class.