All I'm trying to do is search for a string made up of "s(NULL).(NULL)g", where (NULL) is an actual null character in Notepad++.
I figured out how to search for null as /0, but I don't know how to compose a string to search for 's''\0''.''\0''g'.
If you could help me out, I would really appreciate it.
Thanks! :)
do a notepad++ regex search using the following:
s\x00\.\x00g
Related
Is there a way to capture the first word of a string and then replace all commas using the captured first word?
I have attempted a hundred ways without success. I must be missing something. Is there a simple way to set a variable with regex?
string example:
"somename",'2','3','4','11','22','33','44','etc...'
desired results:
"somename",'2'
"somename",'3'
"somename",'4'
"somename",'11'
"somename",'22'
"somename",'33'
"somename",'44'
"somename",'etc...'
I'm using notepad++ (v7.5.6) for this. Any help would be greatly appreciated.
An interesting problem... the best I could come up with inside notepad++ was this: Find ^([^,]+)(,.+)(,[^,]+)$, replace with \1\2\n\1\3. This will replace
"somename",'2','3','4','11','22','33','44','etc...'
with
"somename",'2','3','4','11','22','33','44'
"somename",'etc...'
Continual pressing of Replace will eventually give you the desired output.
Hopefully someone else can do better...
I was looking for some help in regards to a csv file that i am trying to upload into a database. The problem I have is that within a csv I have a field of text with quotations and within this text I have a problem where users have added a carriage return (LF) and commas so the database is having some problems in adding the data to the correct fields. What I would like to do, is replace any (LF) within quotations with a space using regular expressions. I have had a look at the following link:
Seeking regex in Notepad++ to search and replace CRLF between two quotation marks ["] only
but the example shown doesnt seem to tackle the problem. If possible can somebody please advise how i can fix this issue.
Thanks in advance.
Try this:
Find What: (\"[^"]*?)(\r\n)([^"]*?\")
Replace With: $1 $3
thanks for all your help. I managed to open the file in Excel and the column that had the (LF) I wrote the formula =CLEAR(cell) and this brought everything into 1 line and when I opened the same file the in Notepad++ the issue was no longer there.
Thanks for taking your time to help me out, really appreciate it.
I have a big txt file ,with many strings ,say "string-I-want-to-change",now I need to change all of them into this :
string-insert-before-string-I-want-to-change-string-insert-after
I mean ,find a pattern ,insert something before and after the pattern ,but just keep the pattern.I tried many ways ,they just replaced the pattern with the string I want to insert.
I tried the method here
Using RegEX To Prefix And Append In Notepad++
and here
regular expression to add characters before and after numbers
But they seem do not work with my version of notepad++,I am using the newest version 6.1.2
Some one please help me :)
Thank you!
This would work for you.
find : (string-i-want-to-change)
replace : string-in-front-of-it-\1-string-after-it
test string :
other-strings-came-in-front-of-it-string-i-want-to-change-and-it-continues-like-that
output :
other-strings-came-in-front-of-it-string-in-front-of-it-string-i-want-to-change-string-after-it-and-it-continues-like-that
I have to deal with a problem and maybe you can help.
I took over a Website with a lot of code and would like to have it run on PHP 5.4.
But there are a LOT of statement's like this:
if($arrayname['keyname']>"") ....
I would like to replace them all with:
if(!empty($arrayname['keyname'])) ....
Doing it manually will take forever :-(
Do you know how to use Dreamweaver's CS5 search & replace with RegEx capabilites - unfortunately my RegEx knwoledge is limited.
Of course the regex must be "variable, as the arrayname and the keyname always changes.
Any help on finding the correct RegEx Stamtent is HIGHLY appreciated .
Regex to find all occurrences of if($arrayname['keyname']>""), whatever arrayname and keyname are, if only letters :
if\\(\\$[a-zA-Z]*\\[\'[a-zA-Z]*\'\\]>\"\"\\)
You'll have to find how to use BackReferences in Dreamweaver. If it uses standard Regex, then use the tutorial in the link, it will be of great help for you.
To complete and close this question:
In Dreamweaver search for (Regex Search in Code):
if\(\$(\w+)\[['"](\w+)['"]\]>""\)
Replace by:
if(!empty($$1['$2']))
I am in need a reg ex for the following:
/****** Object: AnyNumberofCharacters ******/
Here is what I have Tried but I cant make it work
/^\/\*\*\*\*\*\* Object\:.*\*\*\*\*\*\*\//
Could someone tell me what I'm doing wrong?
Edited: Sorry I'm using NotePad++ to search a number of text files for this string.
Since you are using Notepad++ to find that string, you don't need the delimiters. And therefore, you don't need to escape the forward slashes either.
^/\*\*\*\*\*\* Object\:.*\*\*\*\*\*\*/
I guess that
/^\/\*{6} Object: [\w]+ \*{6}\/$/
should do that...
Don't forget to adjust the [\w] range accordingly.