XSLT select all text - xslt

I want to select all text and do a search and replace.
I want to turn all dashed into non-breaking dashes.
I am using this template for the search and replace part,
now I just need to run all text thru it..

I don't know what do you mean by "non-breaking dash", but here is a simple solution:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="vRep" select="'—'"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of select="translate(.,'-', $vRep)"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on any XML document, the result is the same document in which any '-' is replaced by whatever is specified as the value of the global parameter $vRep.
For example, when applied on this XML document:
<a>
<b>Hi - hi</b>
- - -
<c>
<d>Wow... - cool</d>
</c>
- - -
</a>
the result is:
<a>
<b>Hi — hi</b>
— — —
<c><d>Wow... — cool</d></c>
— — —
</a>
Explanation: Use of the identity rule, overriden by a template matching any text node, and translating any '-' character in it to the character contained in $vRep -- by using the standard XPath function translate().

Related

XSL Sort specifc value last

Is it possible to sort nodes as follows:
Example XML
<record>
<id>0</id>
<sku>0</sku>
<name>Title</name>
<prop>456</prop>
<number>99</number>
</record>
If I apply this template
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="record/*">
<xsl:param select="." name="value"/>
<div>
<xsl:value-of select="concat(local-name(), ' - ', $value)"/>
</div>
</xsl:template>
</xsl:stylesheet>
Ouput:
<div>id - 0</div>
<div>sku - 0</div>
<div>name - Title</div>
<div>prop - 456</div>
<div>number - 99</div>
However, I would like all 0 values to be outputted last, as so:
<div>name - Title</div>
<div>prop - 456</div>
<div>number - 99</div>
<div>id - 0</div>
<div>sku - 0</div>
Is this possible by applying a sort to the <xsl:apply-templates/>?
There is an easy way of achieving this with XSLT-1.0. Just use a predicate on xsl:apply-templates checking if the content is zero:
<xsl:template match="record/*">
<div>
<xsl:value-of select="concat(local-name(), ' - ', .)"/>
</div>
</xsl:template>
<xsl:template match="/record">
<xsl:apply-templates select="*[normalize-space(.) != '0']" />
<xsl:apply-templates select="*[normalize-space(.) = '0']" />
</xsl:template>
This does not sort the output, but groups it the way you want it. The xsl:param is unnecessary.
As far as I see your question, the issue is not any sort at all.
You even didn't write what is the specific value, which you mentioned
it the title. It is rather an arbitrary sequence of child elements of record.
Try the following script, performing just that:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="record">
<xsl:copy>
<xsl:apply-templates select="name, prop, number, id, sku"/>
</xsl:copy>
</xsl:template>
<xsl:template match="record/*">
<div><xsl:value-of select="concat(local-name(), ' - ', .)"/></div>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy><xsl:apply-templates select="#*|node()"/></xsl:copy>
</xsl:template>
</xsl:transform>
I used XSLT 2.0, because initially you did't specify the XSLT version.
Could you move on to version 2.0? As you can see, it allows to write quite
an elegent solution (impossible in version 1.0).
I also changed your template matching record/*. You actually don't
need any param. It is enough to use . - the value of the current
element.
Edit
Another possibility is that you want the following sort:
First, elements with non-numeric value (in your case, only name),
maybe without any sort.
Then elements with numeric value, sorted descending on this value.
If this is the case, then change the template matching record to the
following:
<xsl:template match="record">
<xsl:copy>
<xsl:apply-templates select="*[not(. castable as xs:integer)]"/>
<xsl:apply-templates select="*[. castable as xs:integer]">
<xsl:sort select="." order="descending" data-type="number"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
And add:
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
to transform tag.
But I still can't see anything, which can be called the specific value.

Replacing particuar String using xsl

I have a block as below.
<rightOperand>.*ifIndedx.*</rightOperand>
But i need to change the above snippet to the below one
<rightOperand>(?i)(?s).*ifIndex.*</rightOperand>
This translation needs to be done only when the right operand starts and ends with the string .*
please provide me some pointers .
You can do this my overriding the identity transform with an extra template just to match the text within rightOperand that matches your criteria
<xsl:template match="rightOperand/text()
[starts-with(., '.*')]
[substring(., string-length(.) - 1, 2) = '.*']">
Note that XSLT 1.0 does not have the ends-with function, which is why there is the extra work to check the ending with substring. If you were using XSLT 2.0 you could simplify this with ends_with though.
Here is the full XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="rightOperand/text()
[starts-with(., '.*')]
[substring(., string-length(.) - 1, 2) = '.*']">
<xsl:text>(?i)(?s)</xsl:text><xsl:copy />
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
When applied to your sample XML, the following is output:
<rightOperand>(?i)(?s).*ifIndedx.*</rightOperand>

XSLT: Match all elements of a namespace except one element

I want to write an XSLT template that matches all elements of one namespace except one element. For example I want to match all elements foo:*, but not foo:bar.
Is that possible to define this in a selector or do I have to write an xsl:if condition within the xsl:template (and how can I test the local name of the element)?
To do this, you can just have a template that matches foo:bar that does nothing with it like so:
<xsl:template match="foo:bar" />
To match other foo elements, you can use a more general template
The XSLT processor should match the more specific template first, and so foo:bar will be ignored, and all other foo elements matched by the other template.
So, for example, given this input XML
<foo:root xmlns:foo="foo.com">
<foo:bar>No match</foo:bar>
<foo:pie>Match</foo:pie>
</foo:root>
When you apply the following XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:foo="foo.com">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="foo:bar" />
<xsl:template match="foo:*">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you wanted to do different processing on foo:bar, just add code to the relevant template.
The following is output, without any sign of foo:bar
<foo:root xmlns:foo="foo.com">
<foo:pie>Match</foo:pie>
</foo:root>
XSLT 1.0:
<xsl:template match="foo:*[not(local-name()='bar')]">
<!--do stuff-->
</xsl:template>
XSLT 2.0:
<xsl:template match="foo:*[. except self::foo:bar]">
<!--do stuff-->
</xsl:template>

XSLT: add node inner text

This is a slightly version of other question posted here:
XSLT: change node inner text
Imagine i use XSLT to transform the document:
<a>
<b/>
<c/>
</a>
into this:
<a>
<b/>
<c/>
Hello world
</a>
In this case i can't use neither the
<xsl:strip-space elements="*"/>
element or the [normalize-space() != ''] predicate since there is no text in the place where i need to put new text. Any ideas? Thanks.
Here is what I would do:
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<!-- identity template to copy everything unless otherwise noted -->
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<!-- match the first text node directly following a <c> element -->
<xsl:template match="text()[preceding-sibling::node()[1][self::c]]">
<!-- ...and change its contents -->
<xsl:text>Hello world</xsl:text>
</xsl:template>
</xsl:stylesheet>
Note that text nodes contain "surrounding" whitespace - in the sample XML in the question the matched text node is whitespace only, which is why the above works. It will stop to work as soon as the input document looks like this:
<a><b/><c/></a>
because here is no text node following <c>. So if this is too brittle for your use case, an alternative would be:
<!-- <c> nodes get a new adjacent text node -->
<xsl:template match="c">
<xsl:copy-of select="." />
<xsl:text>Hello world</xsl:text>
</xsl:template>
<!-- make sure to remove the first text node directly following a <c> node-->
<xsl:template match="text()[preceding-sibling::node()[1][self::c]]" />
In any case, stuff like the above makes clear why intermixing of text nodes and element nodes is best avoided. This is not always possible (see XHTML). But when you have the chance and the XML is supposed to be purely a container for structural data, staying clear of mixed content makes your life easier.
This transformation inserts the desired text (for generality) after the element named a7:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*" name="identity">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="a7">
<xsl:call-template name="identity"/>
<xsl:text>Hello world</xsl:text>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document:
<a>
<a1/>
<a2/>
.....
<a7/>
<a8/>
</a>
the desired result is produced:
<a>
<a1/>
<a2/>
.....
<a7/>Hello world
<a8/>
</a>
Do note:
The use of the identity rule for copying every node of the source XML document.
The overriding of the identity rule by a specific template that carries out the insertion of the new text.
How the identity rule is both applied (on every node) and called by name (for a specific need).
edit: fixed my fail to put proper syntax in.
<xsl:template match='a'>
<xsl:copy-of select="." />
<xsl:text>Hello World</xsl:text>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>

XSLT: remove all but the first occurrence of a given node

I have XML something like this:
<MyXml>
<RandomNode1>
<TheNode>
<a/>
<b/>
<c/>
</TheNode>
</RandomeNode1>
<RandomNode2>
</RandomNode2>
<RandomNode3>
<RandomNode4>
<TheNode>
<a/>
<b/>
<c/>
</TheNode>
</RandomNode4>
</RandomNode3>
</MyXml>
Where <TheNode> appears throughout the XML but not at the same level, often deep within other nodes. What I need to do is eliminate all occurrences of <TheNode> EXCEPT the first. The rest are redundant and taking up space. What would be the XSL that could do this?
I have something like this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="node() | #*">
<xsl:copy>
<xsl:apply-templates select="node() | #*" />
</xsl:copy>
</xsl:template>
<xsl:template match="//TheNode[position()!=1]">
</xsl:template>
</xsl:stylesheet>
But that is not correct. Any suggestions?
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="node() | #*">
<xsl:copy>
<xsl:apply-templates select="node() | #*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="TheNode[preceding::TheNode]"/>
</xsl:stylesheet>
//TheNode[position()!=1] does not work because here, position() is relative to the parent context of each <TheNode>. It would select all <TheNode>s which are not first within their respective parent.
But you were on the right track. What you meant was:
(//TheNode)[position()!=1]
Note the parentheses - they cause the predicate to be applied to the entire selected node-set, instead of to each node individually.
Unfortunately, even though this is valid XPath expression, it is not valid as a match pattern. A match pattern must be meaningful (applicable) to an individual node, it cannot be a select expression.
So #Alohci's solution,
//TheNode[preceding::TheNode]
is the correct way to express what you want.
Other approach for the pattern would be:
<xsl:template match="TheNode[generate-id()
!= generate-id(/descendant::TheNode[1)]"/>
Note: It's more likely that an absolute expression gets optimizated inteads of a relative expression like preceding::TheNode