SSE slower than standard logic [duplicate] - c++

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SSE intrinsics without compiler optimization
(2 answers)
Idiomatic way of performance evaluation?
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Closed 3 days ago.
Add 2 arrays element by element. Standart logic and by SSE
int count = std::pow(2, 20);
alignas(16) float* fm1 = new float[count];
alignas(16) float* fm2 = new float[count];
alignas(16) float* res = new float[count];
for (int i = 0; i < count; ++i) {
fm1[i] = static_cast<float>(i);
fm2[i] = static_cast<float>(i);
}
{
auto start = std::chrono::high_resolution_clock::now();
for (int j = 0; j < 1000; ++j) {
for (int i = 0; i < count; ++i) {
res[i] = fm1[i] + fm2[i];
}
}
auto diff = std::chrono::high_resolution_clock::now() - start;
std::cout << "execute time duration = " << std::chrono::duration<double, std::milli>(diff).count() << " milliseconds" << std::endl;
}
{
assert(count % 4 == 0);
auto start = std::chrono::high_resolution_clock::now();
for (int j = 0; j < 1000; ++j) {
for (int i = 0; i < count; i += 4) {
__m128 a = _mm_load_ps(&fm1[i]);
__m128 b = _mm_load_ps(&fm2[i]);
__m128 r = _mm_add_ps(a, b);
_mm_store_ps(&res[i], r);
}
}
auto diff = std::chrono::high_resolution_clock::now() - start;
std::cout << "execute time duration = " << std::chrono::duration<double, std::milli>(diff).count() << " milliseconds" << std::endl;
}
result
execute time duration = 1692.19 milliseconds
execute time duration = 2339.49 milliseconds
laptop configuration
11th Gen Intel(R) Core(TM) i7-11370H # 3.30GHz 3.30 GHz
16,0 ГБ
I expect that SSE logic wil be faster at least 3 times, but it slover