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How can I make the following regex ignore case sensitivity? It should match all the correct characters but ignore whether they are lower or uppercase.
G[a-b].*
Assuming you want the whole regex to ignore case, you should look for the i flag. Nearly all regex engines support it:
/G[a-b].*/i
string.match("G[a-b].*", "i")
Check the documentation for your language/platform/tool to find how the matching modes are specified.
If you want only part of the regex to be case insensitive (as my original answer presumed), then you have two options:
Use the (?i) and [optionally] (?-i) mode modifiers:
(?i)G[a-b](?-i).*
Put all the variations (i.e. lowercase and uppercase) in the regex - useful if mode modifiers are not supported:
[gG][a-bA-B].*
One last note: if you're dealing with Unicode characters besides ASCII, check whether or not your regex engine properly supports them.
Depends on implementation
but I would use
(?i)G[a-b].
VARIATIONS:
(?i) case-insensitive mode ON
(?-i) case-insensitive mode OFF
Modern regex flavors allow you to apply modifiers to only part of the regular expression. If you insert the modifier (?im) in the middle of the regex then the modifier only applies to the part of the regex to the right of the modifier. With these flavors, you can turn off modes by preceding them with a minus sign (?-i).
Description is from the page:
https://www.regular-expressions.info/modifiers.html
regular expression for validate 'abc' ignoring case sensitive
(?i)(abc)
The i flag is normally used for case insensitivity. You don't give a language here, but it'll probably be something like /G[ab].*/i or /(?i)G[ab].*/.
Just for the sake of completeness I wanted to add the solution for regular expressions in C++ with Unicode:
std::tr1::wregex pattern(szPattern, std::tr1::regex_constants::icase);
if (std::tr1::regex_match(szString, pattern))
{
...
}
JavaScript
If you want to make it case insensitive just add i at the end of regex:
'Test'.match(/[A-Z]/gi) //Returns ["T", "e", "s", "t"]
Without i
'Test'.match(/[A-Z]/g) //Returns ["T"]
In JavaScript you should pass the i flag to the RegExp constructor as stated in MDN:
const regex = new RegExp('(abc)', 'i');
regex.test('ABc'); // true
As I discovered from this similar post (ignorecase in AWK), on old versions of awk (such as on vanilla Mac OS X), you may need to use 'tolower($0) ~ /pattern/'.
IGNORECASE or (?i) or /pattern/i will either generate an error or return true for every line.
C#
using System.Text.RegularExpressions;
...
Regex.Match(
input: "Check This String",
pattern: "Regex Pattern",
options: RegexOptions.IgnoreCase)
specifically: options: RegexOptions.IgnoreCase
[gG][aAbB].* probably simples solution if the pattern is not too complicated or long.
Addition to the already-accepted answers:
Grep usage:
Note that for greping it is simply the addition of the -i modifier. Ex: grep -rni regular_expression to search for this 'regular_expression' 'r'ecursively, case 'i'nsensitive, showing line 'n'umbers in the result.
Also, here's a great tool for verifying regular expressions: https://regex101.com/
Ex: See the expression and Explanation in this image.
References:
man pages (man grep)
http://droptips.com/using-grep-and-ignoring-case-case-insensitive-grep
In Java, Regex constructor has
Regex(String pattern, RegexOption option)
So to ignore cases, use
option = RegexOption.IGNORE_CASE
Kotlin:
"G[a-b].*".toRegex(RegexOption.IGNORE_CASE)
You also can lead your initial string, which you are going to check for pattern matching, to lower case. And using in your pattern lower case symbols respectively .
You can practice Regex In Visual Studio and Visual Studio Code using find/replace.
You need to select both Match Case and Regular Expressions for regex expressions with case. Else [A-Z] won't work.enter image description here
How can I make the following regex ignore case sensitivity? It should match all the correct characters but ignore whether they are lower or uppercase.
G[a-b].*
Assuming you want the whole regex to ignore case, you should look for the i flag. Nearly all regex engines support it:
/G[a-b].*/i
string.match("G[a-b].*", "i")
Check the documentation for your language/platform/tool to find how the matching modes are specified.
If you want only part of the regex to be case insensitive (as my original answer presumed), then you have two options:
Use the (?i) and [optionally] (?-i) mode modifiers:
(?i)G[a-b](?-i).*
Put all the variations (i.e. lowercase and uppercase) in the regex - useful if mode modifiers are not supported:
[gG][a-bA-B].*
One last note: if you're dealing with Unicode characters besides ASCII, check whether or not your regex engine properly supports them.
Depends on implementation
but I would use
(?i)G[a-b].
VARIATIONS:
(?i) case-insensitive mode ON
(?-i) case-insensitive mode OFF
Modern regex flavors allow you to apply modifiers to only part of the regular expression. If you insert the modifier (?im) in the middle of the regex then the modifier only applies to the part of the regex to the right of the modifier. With these flavors, you can turn off modes by preceding them with a minus sign (?-i).
Description is from the page:
https://www.regular-expressions.info/modifiers.html
regular expression for validate 'abc' ignoring case sensitive
(?i)(abc)
The i flag is normally used for case insensitivity. You don't give a language here, but it'll probably be something like /G[ab].*/i or /(?i)G[ab].*/.
Just for the sake of completeness I wanted to add the solution for regular expressions in C++ with Unicode:
std::tr1::wregex pattern(szPattern, std::tr1::regex_constants::icase);
if (std::tr1::regex_match(szString, pattern))
{
...
}
JavaScript
If you want to make it case insensitive just add i at the end of regex:
'Test'.match(/[A-Z]/gi) //Returns ["T", "e", "s", "t"]
Without i
'Test'.match(/[A-Z]/g) //Returns ["T"]
In JavaScript you should pass the i flag to the RegExp constructor as stated in MDN:
const regex = new RegExp('(abc)', 'i');
regex.test('ABc'); // true
As I discovered from this similar post (ignorecase in AWK), on old versions of awk (such as on vanilla Mac OS X), you may need to use 'tolower($0) ~ /pattern/'.
IGNORECASE or (?i) or /pattern/i will either generate an error or return true for every line.
C#
using System.Text.RegularExpressions;
...
Regex.Match(
input: "Check This String",
pattern: "Regex Pattern",
options: RegexOptions.IgnoreCase)
specifically: options: RegexOptions.IgnoreCase
[gG][aAbB].* probably simples solution if the pattern is not too complicated or long.
Addition to the already-accepted answers:
Grep usage:
Note that for greping it is simply the addition of the -i modifier. Ex: grep -rni regular_expression to search for this 'regular_expression' 'r'ecursively, case 'i'nsensitive, showing line 'n'umbers in the result.
Also, here's a great tool for verifying regular expressions: https://regex101.com/
Ex: See the expression and Explanation in this image.
References:
man pages (man grep)
http://droptips.com/using-grep-and-ignoring-case-case-insensitive-grep
In Java, Regex constructor has
Regex(String pattern, RegexOption option)
So to ignore cases, use
option = RegexOption.IGNORE_CASE
Kotlin:
"G[a-b].*".toRegex(RegexOption.IGNORE_CASE)
You also can lead your initial string, which you are going to check for pattern matching, to lower case. And using in your pattern lower case symbols respectively .
You can practice Regex In Visual Studio and Visual Studio Code using find/replace.
You need to select both Match Case and Regular Expressions for regex expressions with case. Else [A-Z] won't work.enter image description here
How to find word in string using regular expression regardless of case sensitivity ?
Exmaple:
A1234_front123 in this need to find _front word
a1235Front1234yy in this I need to find front
I need to design generic regular expression which can find any kind of words in given string
If front could be another word, this should try with such combination:
(?<=[0-9])[A-Za-z_]+(?=[0-9_])
DEMO
it will work without case insensitive mode i
You must use i modifier.
/front/i
Online example: https://regex101.com/r/hQ9hH6/1
I have a regular expression that finds two words in a line.
The problem is that it is case sensitive. I need to edit it so that it matches both the case.
reqular expression
^(.*?(\bPain\b).*?(\bfever\b)[^$]*)$
You can use RegexOptions.Ignorecase to set case insensitive matching mode. This way you make the entire pattern case insensitive. The same effect can be achieved with (?i) inline option at the beginning of the pattern:
(?i)^(.*?(\bPain\b).*?(\bfever\b)[^$]*)$
You can use the inline flag to only set case insensitive mode to part of a pattern:
^(.*?(\b(?i:Pain)\b).*?(\b(?i:fever)\b)[^$]*)$
Or you can just match "pain" or "Pain" with
^(.*?(\b(?i:P)ain\b).*?(\bfever\b)[^$]*)$
Another alternative is using character classes [Pp], etc.
Note that you do not have to set a capturing group round the whole pattern, you will have access to it via rx.Match(str).Groups(0).Value.
^.*?(\b[pP]ain\b).*?(\b[Ff]ever\b)[^$]*$
You can usually set a flag for that, depending on your language, or you can mess up your regex into a more ugly looking one using multiple character classes. [pP][aA][iI][nN] is essentially the word "pain" without it being case sensitive at all.
Well, if you're using VB.net, you can tell the regex object to ignore the case sensitivity when you create it
'Defines the pattern
Dim MyPattern As String = "BlaBla"
'Create a new instance of the regex class with the above pattern
'and the option to ignore the casing
Dim Regex As New Regex(MyPattern, RegexOptions.IgnoreCase)
How can I make the following regex ignore case sensitivity? It should match all the correct characters but ignore whether they are lower or uppercase.
G[a-b].*
Assuming you want the whole regex to ignore case, you should look for the i flag. Nearly all regex engines support it:
/G[a-b].*/i
string.match("G[a-b].*", "i")
Check the documentation for your language/platform/tool to find how the matching modes are specified.
If you want only part of the regex to be case insensitive (as my original answer presumed), then you have two options:
Use the (?i) and [optionally] (?-i) mode modifiers:
(?i)G[a-b](?-i).*
Put all the variations (i.e. lowercase and uppercase) in the regex - useful if mode modifiers are not supported:
[gG][a-bA-B].*
One last note: if you're dealing with Unicode characters besides ASCII, check whether or not your regex engine properly supports them.
Depends on implementation
but I would use
(?i)G[a-b].
VARIATIONS:
(?i) case-insensitive mode ON
(?-i) case-insensitive mode OFF
Modern regex flavors allow you to apply modifiers to only part of the regular expression. If you insert the modifier (?im) in the middle of the regex then the modifier only applies to the part of the regex to the right of the modifier. With these flavors, you can turn off modes by preceding them with a minus sign (?-i).
Description is from the page:
https://www.regular-expressions.info/modifiers.html
regular expression for validate 'abc' ignoring case sensitive
(?i)(abc)
The i flag is normally used for case insensitivity. You don't give a language here, but it'll probably be something like /G[ab].*/i or /(?i)G[ab].*/.
Just for the sake of completeness I wanted to add the solution for regular expressions in C++ with Unicode:
std::tr1::wregex pattern(szPattern, std::tr1::regex_constants::icase);
if (std::tr1::regex_match(szString, pattern))
{
...
}
JavaScript
If you want to make it case insensitive just add i at the end of regex:
'Test'.match(/[A-Z]/gi) //Returns ["T", "e", "s", "t"]
Without i
'Test'.match(/[A-Z]/g) //Returns ["T"]
In JavaScript you should pass the i flag to the RegExp constructor as stated in MDN:
const regex = new RegExp('(abc)', 'i');
regex.test('ABc'); // true
As I discovered from this similar post (ignorecase in AWK), on old versions of awk (such as on vanilla Mac OS X), you may need to use 'tolower($0) ~ /pattern/'.
IGNORECASE or (?i) or /pattern/i will either generate an error or return true for every line.
C#
using System.Text.RegularExpressions;
...
Regex.Match(
input: "Check This String",
pattern: "Regex Pattern",
options: RegexOptions.IgnoreCase)
specifically: options: RegexOptions.IgnoreCase
[gG][aAbB].* probably simples solution if the pattern is not too complicated or long.
Addition to the already-accepted answers:
Grep usage:
Note that for greping it is simply the addition of the -i modifier. Ex: grep -rni regular_expression to search for this 'regular_expression' 'r'ecursively, case 'i'nsensitive, showing line 'n'umbers in the result.
Also, here's a great tool for verifying regular expressions: https://regex101.com/
Ex: See the expression and Explanation in this image.
References:
man pages (man grep)
http://droptips.com/using-grep-and-ignoring-case-case-insensitive-grep
In Java, Regex constructor has
Regex(String pattern, RegexOption option)
So to ignore cases, use
option = RegexOption.IGNORE_CASE
Kotlin:
"G[a-b].*".toRegex(RegexOption.IGNORE_CASE)
You also can lead your initial string, which you are going to check for pattern matching, to lower case. And using in your pattern lower case symbols respectively .
You can practice Regex In Visual Studio and Visual Studio Code using find/replace.
You need to select both Match Case and Regular Expressions for regex expressions with case. Else [A-Z] won't work.enter image description here