I am working with pydrive to list files in a directory using the following loop
file_list = drive.ListFile({'q': 'trashed=false'}).GetList()
for file1 in file_list:
print('title: %s, id: %s' % (file1['title'], file1['id']))
I adjusted the oauth_scope as mentioned in another question response however I can only list the files created by pydrive and not uploaded by the user
My settings.yaml is having the following scope
oauth_scope:
https://www.googleapis.com/auth/drive
Any idea why I only get the files uploaded by pydrive, is there something that I need to adjust in the credentials settings in the google drive API?
Thanks and best regards
I tried adjusting outh scope in settings.yamlwith no luck
Related
I'm building an app where the user uploads 1-4 files to shiny through fileinput. An issue arrises where, should the user not drag/select multiple files in one go, then the app will not be able to access them. For example, say the user has 4 files saved locally in 4 different folders and they try uploading them one by one, the app will not function. This happens because when the files are uploaded, fileinput creates a dataframe where one column (datapath) contains the path to a temp file which you can then reference in the server. In the documentation it states...
datapath
The path to a temp file that contains the data that was uploaded. This file may be deleted if the user performs another upload operation.
https://shiny.rstudio.com/reference/shiny/1.6.0/fileInput.html
Is there any way around this problem to prevent this datapath being deleted or perhaps find a way to store the temp file so it won't be lost should a user upload another file?
I had considered multiple fileinput boxes but that just makes the app messy.
There is a reproducible example in the example section of the documentation above.
I am creating a file download functionality on link click from admin panel in django. I am using FileField for storing the files. For the download purpose I researched and found help on stackoverflow. After using that help, I have the following code for file download (with some minor changes of my own).
def pdf_download(request):
#print("request: ", request.META["PATH_INFO"])
a = request.META["PATH_INFO"]
#print(type(a))
a = a.split("/")
a = a[-1]
#print(a)
#print(os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
with open(os.path.dirname(os.path.dirname(os.path.abspath(__file__)))+"\\router_specifications\\"+a ,"rb") as pdf:
#Here router_specifications is the directory on local storage where the uploaded files are being stored.
response = HttpResponse(pdf.read()) #can add ', content_type = "application/pdf" as a specific pdf parameter'
response["Content-Disposition"] = "attachment; filename ="+a
pdf.close()
return response
Now, when I this code runs in my laptop, the file is downloaded automatically. but, when I switch to some other laptop, it asks me where should I save the file i.e. it's not automatically getting downloaded.
What changes should I do so that the file automatically gets downloaded without asking for manual save. Requesting help at the earliest.
You can try adding the following content_type:
content_type='application/force-download'
I have an analysis project that is requiring me to extract the 'current state' of a PDF that houses our report that is sent out 4 times daily. I have the code written to scrape my PDF but I need to figure out how to extract the PDF from the email so I can step through it with my code.
I tried using the code below
import win32com.client
import os
location = r'C:\Users\myusername\OneDrive - companyinfo\Department Projects\TestEmails'
files = [f for f in os.listdir(location)]
print(files)
for file in files:
if file.endswith('.msg'):
outlook = win32com.client.Dispatch("Outlook.Application").GetNamespace("MAPI")
msg = outlook.OpenSharedItem(file)
att = msg.Attachments
for i in att:
i.SaveAsFil`e(os.path.join(r'C:\Users\username\OneDrive - companyname\Department Projects\TestPDF', i.FileName))
The error it produces is:
pywintypes.com_error: (-2147352567, 'Exception occurred.', (4096, u'Microsoft Outlook', u"We can't open 'Stats Report.msg'. It's possible the file is already open, or you don't have permission to open it.\n\nTo check your permissions, right-click the file folder, then click Properties.", None, 0, -2147287038), None)
I am only currently testing with one saved test.msg file but I have over 1400 I need to parse through. Maybe this isn't the best technique as I know VBA could do something similar within outlook, but I don't have much skills in the VBA region.
I have outlook 2016 installed on Windows 7 computer running python 2.7. Is this error something easy to fix? Is there a better technique to take an attached PDF and save it to a folder so my other program can grab the necessary data?
Desired output: PDF Attachment is Extracted and Saved into a separate folder.
Thank you for your help and expertise,
Andy
So I figured out the answer and how simple and stupid it was makes me unreasonably frustrated.....
My working directory was wrong even though I grabbed the file, the file name was the only item created.
I created a true_location variable that gave it the true full working directory and it worked like a charm.
true_location = location + '\\' + file
Enter that in the for loop under the if clause and it works like a charm.
Best,
Andy
I currently have a 34x22 .xlsx spreadsheet. I am downloading it via pydrive, filling in some of the blank values, and uploading the file back via pydrive. When I upload the file back, all cells with formulas are blank (any cell that starts with =). I have a local copy of the file I want to upload, and it looks fine so I'm pretty sure the issue must be with pydrive.
My code:
def upload_r1masterfile(filename='temp.xlsx'):
"""
Upload a given file to drive as our master file
:param filename: name of local file to upload
:return:
"""
# Get the file we want
master_file = find_r1masterfile()
try:
master_file.SetContentFile(filename)
master_file.Upload()
print 'Master file updated. ' + str(datetime.datetime.now())
except Exception, e:
print "Warning: Something wrong with file R1 Master File."
print str(e)
return e
The only hint I have is that if I add the param={'convert': True} tag to Upload, then there is no loss. However, that means I am now working in google sheets format, and I would rather not do that. Not only because it's not the performed format to work with here, but also because if I try to master_file.GetContentFile(filename) I get the error: No downloadLink/exportLinks for mimetype found in metadata
Any hints? Is there another attribute on upload that I am not aware of?
Thanks!
Robin was able to help me answer this question at the github repository. Both suggested solutions worked:
1) When you upload the file, did you close Excel first? IIRC MS Office writes a lot of the content to a temporary file, so that may explain why some parts are missing. If you tried the non converting upload first, the full file may have been saved to disk between the two tries, and thus the second converting upload attempt worked.
2) GetContentFile takes a second argument called mimetype, which should allow you to download the file. Could you try .GetContentFile(filename, mimetype="application/vnd.ms-excel")? If that mimetype doesn't work as anticipated, there is a great StackOverflow post here which lists a bunch of different types you can try.
Thanks again Robin!
I am building a sync app with a customprovider and a filesyncprovider. I based my provider on this example:
https://code.msdn.microsoft.com/File-Sync-with-Simple-c497bf87
Now I want to extend to a hierarchical folderstructure. So in the EnumerateItems method of the custom syncprovider I return all files and folders just like I did before with only the files in the directory. Now on the filesyncprovider side, this results in a creation of folders with the name of the file and the file being placed in this folder. E.g.
Folder1\textfile.txt\textfile.txt
I have no idea, what I am doing wrong and I find it hard to know the part of the MS filesyncprovider where I could debug to see, what's happening.
My question is, what am I doing wrong and how can I correct it, so that the correct output would be
Folder1\textfile.txt?
Best regards,
Tobias
// Must return the relative path without the filename
public string RelativeDirectoryPath
{
get
{
return _relativeFilePath;
}
Read first - then ask: I returned the path to the file instead of the path to the folder... comment above even warns not to do that...