c++ operator overloading code have no data ouput - c++

class mod5
{
private:
unsigned i;
public:
mod5() :
i{}
{
}
mod5(mod5 const&) = default;
mod5& operator=(mod5 const&) = default;
explicit mod5(unsigned value) :
i{value}
{
}
unsigned mod_value() const
{
return i % 5;
}
friend auto operator<=>(mod5 const& lhs, mod5 const& rhs)
{
return lhs.mod_value() <=> rhs.mod_value();
}
};
std::istream& operator>>(std::istream& is, mod5& m)
{
unsigned int temp;
if(is >> temp ){
m = mod5(temp);
}
else{
is.setstate(std::ios_base::failbit);
}
return is;
}
std::ostream& operator<<(std::ostream& os, mod5 const& m)
{
os << m.mod_value();
return os;
}
//=============================================================================
The code has been compiled successfully, but there will be no data when the file is added and run. I want to know which step is wrong?
The result of running is as shown below。
rel_demo: operator==(): rel_demo: operator<(): rel_demo: operator>(): stack(0):
The data does not seem to be well imported resulting in no data flow output.
The problem lies in the function of std::ostream& operator<<? Or is it on the function of std::istream& operator>>?

Related

No operator "<<" matches these operands error between an object and a string literal

The code:
catch (test& t)
{
cout << t /*error here*/<</*to here*/ " is not a positive number";
}
causes an error:
No operator "<<" matches these operands
The compiler (c++ 20) says that the error is the << between t and " is not a positive number". It might be caused because I overloaded the operator wrong?
Here's my operator << overload:
ostream& operator << (ostream& os, const test& t)
{
os << t.getX(); //getX is just a method for getting private member
return os;
}
The entire code, if this isn't enough:
class test
{
int x;
public:
explicit test(const int _x)
{
x = _x;
}
int getX() const
{
return x;
}
friend test& operator << (ostream&, test&);
};
ostream& operator << (ostream& os, const test& t)
{
os << t.getX();
return os;
}
auto main() -> int
{
int n;
cin >> n;
try
{
if (n < 0)
{
throw test(n);
}
}
catch (test& t)
{
cout << t /*error here*/ <</*to here*/ " is not a positive number";
}
}
You have declared one operator<<, and defined a different one. And the wrongly-formed one turns out to be the best match.
Replace* this, which you have declared in your class:
test & operator << (ostream & , test & )
With this, which you have defined:
ostream & operator << (ostream & os, const test & t)
Edit:
*An astute observation from the frequently-astute Mark Ransom:
The bad declaration isn't needed at all. The function doesn't need to be declared friend. That declaration could simply be removed.
The friend modifier is required if you declare operator overloading as a class/structure member. In the case of declaring globally, it is not necessary indeed!
First option:
class test {
int x;
public:
explicit test(const int _x) { x = _x; }
int getX() const { return x; }
};
std::ostream& operator<<(std::ostream& os, const test &t) {
os << t.getX();
return os;
}
Second option:
class test {
int x;
public:
explicit test(const int _x) { x = _x; }
int getX() const { return x; }
friend std::ostream& operator<<(std::ostream& os, const test &t) {
os << t.getX();
return os;
}
};

reverse function doesn't reverse the referenced string of a class instantiation

I'm trying to reverse the string from the FunnyNumber class. The problem is that when I call the method reverse in main on f2, it doesn't reverse the f2 string. But when I print out the reversed string from the reverse method implementation, it works. Also I overloaded the << operator to print out the string value in the class Number which is inherited in FunnyNumber class. Any help would be appreciated.
#ifndef NUMBER_H
#define NUMBER_H
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
class Number {
public:
// Make a number with value 0
Number();
// Make a number with value val
Number(string val);
// Get the number's value
virtual string getValue() const;
// Print this number to the stream
virtual void print(ostream& stream) const;
// Read this number from the stream
virtual void read(istream& stream);
// Overload the insertion operator
friend ostream& operator <<(ostream& outs, const Number& n);
// Overload the extraction operator
friend istream& operator >> (istream& ins, Number& n);
protected:
string value;
};
#endif
Number::Number()
{
value = "";
}
Number::Number(string args)
{
value = args;
}
string Number::getValue()const
{
return value;
}
ostream& operator <<(ostream& outs, const Number& n)
{
n.print(outs);
return outs;
}
void Number::print(ostream& stream)const
{
stream << getValue();
}
void Number::read(istream& stream)
{
stream >> value;
}
istream& operator >> (istream& ins, Number& n)
{
n.read(ins);
return ins;
}
#ifndef FUNNYNUMBER_H
#define FUNNYNUMBER_H
#include<iostream>
#include<string>
#include"Number.h"
#include<algorithm>
using namespace std;
class FunnyNumber : public Number
{
public:
FunnyNumber();
FunnyNumber(string val);
virtual string operator+(const FunnyNumber &other)const;
virtual bool operator==(const FunnyNumber &other)const;
void reverse();
int find_first_not_this(char a);
protected:
string value;
};
#endif // !FUNNYNUMBERS_H
FunnyNumber::FunnyNumber()
{
value = "";
}
FunnyNumber::FunnyNumber(string val) : Number(val)
{
value = val;
}
string FunnyNumber::operator+ (const FunnyNumber& other)const
{
return getValue() + other.getValue();
}
int FunnyNumber::find_first_not_this(char a)
{
int pos = 0;
for(int i = 0; i < value.length(); i++)
{
if(value[i] != a)
{
pos = i;
return pos;
}
}
return pos;
}
bool FunnyNumber::operator==(const FunnyNumber& other)const
{
bool isEqual = true;
for (int i = 0; i < other.getValue().length(); i++)
{
bool found = false;
for (int j = 0; j < getValue().length(); j++)
{
if(getValue()[j] == other.getValue()[i])
{
found = true;
break;
}
}
if(!found)
{
isEqual = found;
return isEqual;
}
}
return isEqual;
}
void FunnyNumber::reverse()
{
std::reverse(value.begin(), value.end());
value.erase(0, find_first_not_this('0'));
}
#include <iostream>
#include<string.h>
#include "FunnyNumber.h"
using namespace std;
int main()
{
FunnyNumber f2;
f2 = FunnyNumber("223");
f2.reverse();
cout<<"Reversed value "<<f2<<endl;
system("pause");
return 0;
}
output is 223 instead of 322
Your FunnyNumber stores the value twice, once in a subobject of type Number, and once in string FunnyNumber::value.
Your reverse function modifies the second one, but doesn't have any effect on the Number base subobject. And then the only output function you call is working on the Number base subobject, and knows nothing about string FunnyNumber::value. That's why what is printed is not the result of reversal.
the overloaded operator << is a friend function on the Number class and friend functions are not inherited.
class Number {
public:
// Make a number with value 0
Number();
// Make a number with value val
Number(string &val);
// Get the number's value
virtual string getValue() const;
// Print this number to the stream
virtual void print(ostream& stream) const;
// Read this number from the stream
virtual void read(istream& stream);
// Overload the insertion operator
friend ostream& operator <<(ostream& outs, const Number& n);
// Overload the extraction operator
friend istream& operator >> (istream& ins, Number& n);
protected:
string *value;
};
Number::Number()
{
value = NULL;
}
Number::Number(string &args)
{
value = &args;
}
string Number::getValue()const
{
return *value;
}
ostream& operator <<(ostream& outs, const Number& n)
{
n.print(outs);
return outs;
}
void Number::print(ostream& stream)const
{
stream << getValue();
}
void Number::read(istream& stream)
{
stream >> *value;
}
istream& operator >> (istream& ins, Number& n)
{
n.read(ins);
return ins;
}

Is it possible to get private variable value using class instance name?

For example, I've written a class called Length:
class Length {
public:
void setValue(float);
private:
float value_;
};
void
Length::setValue(float newValue) {
value_ = newValue;
}
void print(float value) {
std::cout << value;
}
void computeStuff(float value) {
//do the computing
}
int main() {
Length width;
width.setValue(5);
std::cout << width; // <-- this is actually just an example
//what I actually want is:
print(width); // print 5
//or perhaps even
computeStuff(width);
return 0;
}
Now how to make width return value_ or 5?
Technically, width is not an instance name, it's a name of a variable of type Length. You can change your code to retrieve a variable in two ways:
Add a friend operator << for Length that does the printing, or
Add an implicit conversion operator from Length to float.
The first approach works only for output. You cannot pull the value directly:
friend ostream& operator <<(ostream& out, const Length& len) {
out << len.value_;
return out;
}
The second approach looks like this:
class Length {
...
public:
operator float() const { return value_; }
};
You must overload operator<< for your custom type, something like:
class Length
{
..
friend std::ostream& operator<<(std::ostream& os, const Length& o);
..
}
std::ostream& operator<<(std::ostream& os, const Length& o)
{
os << o.value_;
return os;
}
Mind that this
must be non member
is nothing special , just an operator overload applied to a standard way of inserting things into stream of <iostream>
You need to define an operator() method to print the value 5.
You need to overload the << operator for your class. You could also use a function to do the operator's work.
Operator <<
#include <iostream>
class Length {
friend std::ostream& operator<<(std::ostream& os, const Length& l);
public:
void setValue(float);
private:
float value_;
};
void
Length::setValue(float newValue) {
value_ = newValue;
}
std::ostream& operator<<(std::ostream& os, const Length& l)
{
os << l.value_;
return os;
}
int main() {
Length width;
width.setValue(5);
std::cout << width << std::endl; // print 5
return 0;
}
function:
#include <iostream>
class Length {
friend std::ostream& print(std::ostream &,const Length &l);
public:
void setValue(float);
private:
float value_;
};
void
Length::setValue(float newValue) {
value_ = newValue;
}
std::ostream& print(std::ostream &os, const Length &l)
{
os << l.value_;
return os;
}
int main() {
Length width;
width.setValue(5);
print(std::cout, width) << std::endl;
return 0;
}

Intellisense thinks my symbols are ambiguous

I'm writing my own typesafe enum header-only library at https://bitbucket.org/chopsii/typesafe-enums
The idea is to replace the non-type-safe c-style enum like:
enum ItemCategory
{
BLOCK,
WEAPON
};
with something that's properly type safe.
So far, my solution uses a macro that, for an example equivalent to the above enum, looks like this:
TypesafeEnum(ItemCategory,
(BLOCK)
(WEAPON)
);
And expands to something that looks like this:
template<typename InnerType>
class Wrapped {
public:
InnerType getValue() const { return _val; }
bool operator<(const Wrapped<InnerType>& rhs) const { ; return _val < rhs._val; }
bool operator>(const Wrapped<InnerType>& rhs) const { ; return _val > rhs._val; }
bool operator==(const Wrapped<InnerType>& rhs) const { ; return _val == rhs._val; }
private:
InnerType _val;
protected:
explicit Wrapped<InnerType>(const InnerType& val) : _val(val) {}
void setValue(const InnerType& val) { _val = val; }
};
class WrappedTypeItemCategory : private Wrapped<int>
{
private:
typedef const std::string* strptr;
typedef const std::string* const cstrptr;
explicit WrappedTypeItemCategory(const std::string& label, int val): Wrapped<int>(val), str(&label)
{}
cstrptr str;
public:
static WrappedTypeItemCategory make(const std::string& label, int val)
{
return WrappedTypeItemCategory(label, val);
}
void operator=(const WrappedTypeItemCategory& rhs)
{
;
setValue(rhs.getValue());
const_cast<strptr>(str) = rhs.str;
}
int getValue() const
{
return Wrapped<int>::getValue();
}
const std::string& getString() const
{
return *str;
}
bool operator<(const WrappedTypeItemCategory & rhs) const
{
;
return getValue() < rhs.getValue();
}
bool operator>(const WrappedTypeItemCategory & rhs) const
{
;
return getValue() > rhs.getValue();
}
bool operator==(const WrappedTypeItemCategory & rhs) const
{
;
return getValue() == rhs.getValue();
}
friend std::ostream & operator<<(std::ostream &os, const WrappedTypeItemCategory& rhs)
{
;
return os << *rhs.str << "(" << rhs.getValue() << ")";
}
};
;
namespace {
template<typename T> class ItemCategoryInner : public TypesafeEnumBase
{
public:
static const WrappedTypeItemCategory BLOCK;
static const WrappedTypeItemCategory WEAPON;
static const std::string BLOCKStr;
static const std::string WEAPONStr;
};
template<typename T> const WrappedTypeItemCategory ItemCategoryInner<T>::BLOCK = WrappedTypeItemCategory::make(ItemCategoryInner<T>::BLOCKStr, 0);
template<typename T> const WrappedTypeItemCategory ItemCategoryInner<T>::WEAPON = WrappedTypeItemCategory::make(ItemCategoryInner<T>::WEAPONStr, 1);
template<typename T> const std::string ItemCategoryInner<T>::BLOCKStr("ItemCategory::BLOCK");
template<typename T> const std::string ItemCategoryInner<T>::WEAPONStr("ItemCategory::WEAPON");
struct ItemCategoryTemplateConstantTrick
{};
};
class ItemCategory : public ItemCategoryInner<ItemCategoryTemplateConstantTrick>
{
private:
const WrappedTypeItemCategory* const val;
public:
class InvalidValueError : public std::runtime_error
{
public:
const int val;
InvalidValueError(int val): std::runtime_error(std::string("Invalid value given for ") + "ItemCategory::make"), val(val)
{}
};
ItemCategory(const WrappedTypeItemCategory& value): val(&value)
{}
void operator=(const ItemCategory& rhs)
{
const_cast<const WrappedTypeItemCategory*>(val) = rhs.val;
}
static ItemCategory make(const int& val)
{
if (val == ItemCategory::BLOCK.getValue()) return ItemCategory(ItemCategory::BLOCK);
if (val == ItemCategory::WEAPON.getValue()) return ItemCategory(ItemCategory::WEAPON);
;
throw InvalidValueError(val);
}
const WrappedTypeItemCategory* const getWrappedValue() const
{
return val;
}
int getValue() const
{
return val->getValue();
}
const std::string & getString() const
{
return val->getString();
}
bool operator<(const ItemCategory& rhs) const
{
return *val < *rhs.val;
}
bool operator>(const ItemCategory& rhs) const
{
return *val > *rhs.val;
}
bool operator==(const WrappedTypeItemCategory& rhs) const
{
return *val == rhs;
}
bool operator!=(const WrappedTypeItemCategory& rhs) const
{
return !(*val == rhs);
}
bool operator<=(const WrappedTypeItemCategory& rhs) const
{
return (*val == rhs || *val < rhs);
}
bool operator>=(const WrappedTypeItemCategory& rhs) const
{
return (*val == rhs || *val > rhs);
}
void print(std::ostream& os) const override
{
os << *val;
}
friend std::ostream & operator<<(std::ostream &os, const ItemCategory& rhs)
{
rhs.print(os);
return os;
}
};
;
If I manually pre-expand it, like I have done here - by pre-compiling to file - then intellisense handles it all up until the line that says:
class ItemCategory : public ItemCategoryInner<ItemCategoryTemplateConstantTrick>
At which point it starts thinking ItemCategoryInner and ItemCategoryTemplateConstantTrick are ambiguous, along with many other things on every few lines of the file.
The header that contains this code is included in many places. I know I'm violating the One Definition Rule, which is why I'm using the Template Constant Trick, but I think I need to violate the ODR as my goal is to have an easy to use Macro based typesafe replacement for C++ enums.
I'm not sure if it's the violation of ODR that is the cause of my issues, or something else. I tried __declspec(selectany) but it didn't seem to help - and I would prefer if this macro would be eventually cross-platform, because if it works out, I have other projects I would use it in.
Either way, the .cpp files etc that make use of the enum are able to, and intellisense correctly suggests the options.
However, on a possibly related note, if I don't pre-expand the macro, intellisense isn't able to parse it and it doesn't know what a ItemCategory is at all, even though it compiles and works fine.
I just want my intellisense to work properly with my typesafe enums - it slows down intellisense and confuses it in other code in the same project.

Operator overloading with files

Is there a way in which I can use a operator overloader to output to a file. I understand the code behind the actual outputting to a file but I don't understand how I would actually invoke a overloader to carry out the out to the file
Any help in helping me understand this would be appreciated
struct A {
int a;
public:
std::ostream& save(std::ostream& out) const {
return out << a;
}
std::istream& load(std::istream& in) {
return in >> a;
}
};
std::ostream& operator<<(std::ostream& out, const A& obj) {
return obj.save(out);
}
std::istream& operator>>(std::istream& in, A& obj) {
return obj.load(in);
}
int main() {
A a;
std::cin >> a;
std::cout << a;
return 0;
}