I am working to merge two data sets and get the following error:
Variable DOB has been defined as both character and numeric.
Here is my code. I know I need a set statement to change the character to numeric. I was thinking:
DATA Merged1;
SET Aug21 Aug22;
RUN;
set (rename=(DOB=DOBnum));
length DOB $ 10.;
DOB= put(DOBnum,f10. -L);
drop DOBnum;
Would this be placed before my Set statement to merge to Aug 21 Aug 22?
Thank you!
I tried to run the code but it would not merge, unsure if where the Set statement for DOB would go
You do not need the second SET statement. You need to add the RENAME= dataset option to the dataset where it is mentioned in the first SET statement.
So something like:
DATA BOTH;
SET Aug21 Aug22(in=in2 rename=(DOB=DOBnum));
if in2 then DOB= put(DOBnum,f10. -L);
drop DOBnum;
RUN;
To get a more detailed answer provide more details about the variables and the types of values they contain. For example if DOB means Date of Birth then it does not make much sense to use the F format. If DOB should be an actual DATE then it should be numeric and not character. And if the version that is numeric has actual date values then converting them to text using the F format is going to generate strings that will be confusing for humans.
If you're a beginner I recommend two steps so you can trace the work.
Convert dob from character to numeric
Append the two datasets together (assume you're stacking the data sets)
Use format to control how the date is displayed
*convert character to numeric SAS date;
data aug21_convert2num;
set aug21(rename=dob=dobchar);
dob = input(dob, anydtdte.);
drop dobchar;
run;
*append the two data sets;
data want;
set aug21_convert2num aug22;
format dob yymmdd10.;
run;
Related
What I have
I have a column/variable named Release_Date with length 8 format 11. and informat 11.
The observation in that column are in the form YYYYMMDD SAS actually reads them as pure number
What I want
I want to convert those observation in DD/MM/YYYY format with format and informat as DDMMYY10.
Example
Release_Date is 20180612 then I want 12/06/2018
Any help with this regard will be appreciated
Convert to character
Read back in as date
make sure the variable is different since SAS does not allow you to change a variable type
releaseDate_NUM = input(put(Release_Date, 8. -l), yymmdd10.);
The following solution creates a simple dataset, then processes that dataset to add the converted date:
data myDates;
input intDate;
datalines;
20110101
20120202
;run;
data myDates;
set myDates;
format cvtDate mmddyy10.; * create new variable by specifying the format;
cvtDate = input(put(intDate,8.),yymmdd8.); * assign new variable value;
run;
Results should be:
intDate cvtDate
-------- ----------
20110101 01/01/2011
20120202 02/02/2012
I want to extend the question asked at Sum consecutive observations by some variable.
When I define the following macro variable
%let varnames=id dose supply date;
Since I don't know the fomat of the original data, how do I get the format for the rename automatically to apply it in the following extract of the above link?
data want(drop=id_i dose_i supply_i date_i);
format id dose supply 8. date mmddyy10.;
retain id dose supply date;
set have(rename=(id=id_i dose=dose_i supply=supply_i date=date_i)) end=last;
I have a column that contains date values. So when imported as numeric, it shows 20668, 20669...etc. if I format it as yymmddn8, it shows 20160802 etc. However, what I really want is a numeric variable that shows 20160802. I have tried to create other to get day, month, year and then concatenate them. Unfortunately, the issue is if month and day is 1 digit, it would only show 201682. what would be the quickest way to achieve my goal. I guess a can turn the day and month variable to text and add 0 if day or month is less than 10. But this is not elegant and efficient. Please help.
Thanks
You can just wrap an input around that format:
data test;
date = 20668;
full_date = input(put(date,yymmddn8.),best12.);
run;
The put is converting the date to character in the format as you want it to appear, and the input with the best12. format is converting it back to numeric in that format.
It sounds like you just need to attach a format to your variable.
format date yymmddn8. ;
Try running this program to see a few of the different formats that are available for displaying dates.
data _null_;
do date = 20668, 20669 ;
put (6*date) (=10. =date9. =yymmddn8. =mmddyy10. =ddmmyy10. =yymmdd10.) ;
end;
run;
I want to convert a String to Date in SAS, I tried:
data _null_;
monyy = '05May2013';
date = input(substr(strip(monyy),1,9),yymmdd.);;
put date=date9.;
run;
But it did not work. Can this be done?
Formats like
date9.
or
mmddyy10.
are not valid for input command while converting text to a sas date. You can use
Date = input( cdate , ANYDTDTE11.);
or
Date = input( cdate , ANYDTDTE10.);
for conversion.
You don't need substr or strip.
input(monyy,date9.);
As stated above, the simple answer is:
date = input(monyy,date9.);
with the addition of:
put date=yymmdd.;
The reason why this works, and what you did doesn't, is because of a common misunderstanding in SAS. DATE9. is an INFORMAT. In an INPUT statement, it provides the SAS interpreter with a set of translation commands it can send to the compiler to turn your text into the right numbers, which will then look like a date once the right FORMAT is applied. FORMATs are just visible representations of numbers (or characters). So by using YYMMDD., you confused the INPUT function by handing it a FORMAT instead of an INFORMAT, and probably got a helpful error that said:
Invalid argument to INPUT function at line... etc...
Which told you absolutely nothing about what to do next.
In summary, to represent your character date as a YYMMDD. In SAS you need to:
change the INFORMAT - date = input(monyy,date9.);
apply the FORMAT - put date=YYMMDD10.;
Try
data _null_;
monyy = '05May2013';
date = input(substr(strip(monyy),1,9),date9.);
put date=date9.;
run;
input(char_val, date9.);
You can consider to convert it to word format using
input(char_val, worddate.)
You can get a lot in this page http://v8doc.sas.com/sashtml/lrcon/zenid-63.htm
This code helps:
data final; set final;
first_date = INPUT(compress(char_date),date9.); format first_date date9.;
run;
I personally have tried it on SAS
input(char_val,current_date_format);
You can specify any date format at display time, like set char_val=date9.;
I've got a dataset that's full of data all in character format.
Now I want to create another dataset from this one, put put everything it it's correct decimal or date or character format.
Here's what I'm trying.
data work.testout;
attrib account_open_date informat = mmddyy10.;
do i = 1 to nobs;
set braw.accounts point = i nobs = nobs;
output;
end;
stop;
run;
this gives me:
Variable 'account_open_date' from data set braw.accounts (at line 7 column 21) has a different type (character) to the variable type on the data vector (numeric)
What's the best way of doing this?
You cannot use an informat to convert a variable directly from character to numeric. At least in SAS proper, you cannot convert a variable from character to numeric, period, without using an intermediary. You must do something along the lines of the following:
data want;
set have(rename=varwant=temp);
varwant=input(temp,MMDDYY10.);
drop temp;
run;
There you rename the (character) variable to a temporary name, then convert it to numeric using INPUT.