Overwrite Django ImageField to accept absolute URIs as well as files - django

What ImageField does under the hood , is that is stores the image path as string in the db.
I would like to overwrite the field in such a way, that it can accept either a binary image file or absoulte URI path and return the path as string and store it as char in the db.
Which method would have to be overwritten to achieve this operation ?
thanks

Without overriding ImageField() you can do those things using one extra URLField() like this...
models.py
class Product(models.Model):
name = models.CharField(max_length=200, null=True)
image = models.ImageField(upload_to ='Products')
img_abs_url = models.URLField(blank=True,null=True)
def __str__(self):
return self.name
form.py
class ProductForm(forms.ModelForm):
class Meta:
model = Product
fields = "__all__"
exclude = ['img_abs_url']
views.py
def HomeView(request):
form = ProductForm()
products = Product.objects.all()
if request.method == 'POST':
form = ProductForm(request.POST,request.FILES)
if form.is_valid():
product_name = form.cleaned_data['name']
image = form.cleaned_data['image']
create_product = Product.objects.create(name=product_name,image=image)
create_product.img_abs_url = request.build_absolute_uri(create_product.image.url)
create_product.save()
context = {'form': form, 'products': products}
return render(request, 'index.html', context)
Output (admin panel)

Related

With Django, how do I reference an existing model in a form save method instead of creating a new instance?

I'm trying to use a ModelChoiceField to display options populated from model, and when a user selects a choice, store that method in a different model.
I'm using a standard form instead of a ModelForm, because I wasn't able to get the form to display how I wanted to when using a Modelform.
My issue is that in my form save method, a new instance is created, which is not what I want.
Here are the relevant models:
class Client(models.Model):
client_email = models.EmailField(max_length = 254)
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
phone = PhoneField(blank=True)
assigned_manager = models.ForeignKey(Manager, on_delete=models.CASCADE, blank=True, null=True)
created_date = models.DateTimeField(default=timezone.now)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
class Manager(models.Model):
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
manager_email = models.EmailField(max_length = 254)
username = models.OneToOneField(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, blank=True, null=True)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
My view:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
form = AssignManagerForm()
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
form.save()
return render(request, 'mysite/manageclient.html', {})
else:
form = AssignManagerForm()
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
And my forms.py
class AssignManagerForm(forms.Form):
full_name = forms.ModelChoiceField(queryset=Manager.objects.all())
def save(self):
data = self.cleaned_data
client = Client(assigned_manager=data['full_name'])
client.save()
What I need to do is pass the urlid in my view to my save method in my forms.py, but I am unsure how to do that. Even if i could do that, I'm not sure how to modify form save to use urlid to refer to a specific record and set only the assigned_manager record.
Additionally, while I want the meta field to be used to display the form, I know it isn't what should be being passed to the assigned_manager field. How would I pass a Manager of instance to establish the foreign key relationship?
edit: edited to correct queryset in forms.py as per comments
Here is a solution using a ModelForm, by using a ModelForm you no longer have to manually set attributes on save or provide initial values when updating an existing instance.
The field assigned_manager will still be named assigned_manager but it's label can be overridden to be whatever you want it to be by passing labels in the ModelForm.Meta
class AssignManagerForm(forms.ModelForm):
class Meta:
model = Client
fields = ['assigned_manager']
labels = {'assigned_manager': 'Full name'}
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST, instance=client)
if form.is_valid():
client = form.save()
# The general convention is to redirect after a successful POST
else:
form = AssignManagerForm(instance=client)
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
Instead of saving it in form, you can directly do this operation in view. For example:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
client.assigned_manager = form.cleaned_data['full_name']
client.save()
return render(request, 'mysite/manageclient.html', {})

How to retrieve user selections from a previous form

I have several forms that take people through steps and below are the first two and the simplest ones and makes it easy to explain what i am having problem with.
The following two views are login required and contain one form on each. First view is the new_operator where the user fills out a single text input field. Second view is the new_asset where the user fills one text input field as the asset name and selects an operator from the a select/dropdown field. The question is how can i get the form to remember the operator name the user created in the previous form and make it as the default option? To be clear, i still want the user to select any other operator if they choose to do so but i want the option they just created to be the default. Thanks a lot in advance for the help.
First, here are the models:
class OperatorCompany(models.Model):
name = models.CharField(max_length=50, unique=True)
created_at = models.DateTimeField(default=timezone.now)
created_by = models.ForeignKey(User, related_name='operator_added_by', null=True, on_delete=models.SET_NULL)
class Meta:
verbose_name = "Operator Company"
verbose_name_plural = "Operator Companies"
def __str__(self):
return self.name
class AssetName(models.Model):
name = models.CharField(max_length=50, unique=True)
operator = models.ForeignKey(OperatorCompany, related_name='asset', on_delete=models.CASCADE)
created_at = models.DateTimeField(default=timezone.now)
created_by = models.ForeignKey(User, related_name='asset_added_by', null=True,
on_delete=models.SET_NULL)
class Meta:
verbose_name = "Asset"
verbose_name_plural = "Assets"
def __str__(self):
return self.name
views.py
def new_operator(request):
if request.method == 'POST':
form = NewOperatorForm(request.POST)
if form.is_valid():
newoperator = form.save(commit=False)
newoperator.created_by = request.user
newoperator.created_at = timezone.now()
newoperator.save()
return redirect('wellsurfer:new_asset')
else:
form = NewOperatorForm()
return render(request, 'wellsurfer/create_new_operator.html', {'create_operator': form})
def new_asset(request):
if request.method == 'POST':
form = NewAssetForm(request.POST)
if form.is_valid():
newasset = form.save(commit=False)
newasset.created_by = request.user
newasset.created_at = timezone.now()
newasset.save()
return redirect('wellsurfer:new_pad')
else:
form = NewAssetForm()
return render(request, 'wellsurfer/create_new_asset.html', {'create_asset': form})
and following are the forms.py without the init, clean functions and the widgets
class NewOperatorForm(forms.ModelForm):
class Meta:
model = OperatorCompany
fields = ('name',)
class NewAssetForm(forms.ModelForm):
class Meta:
model = AssetName
fields = ('name', 'operator')
To share data between multiple pages, you can use session variables. These are stored on the server and associated to clients according to the session cookie they communicate to the server at every request.
Typically, in the first view, you would add after save():
request.session['latest_created_operator_id'] = newoperator.id
to save in the session the operator id.
And in the second view, after the else,
operator_id = request.session.get('latest_created_operator_id', None)
operator = Operator.objects.filter(id=operator_id).first() # returns None if not found
form = NewAssetForm(initial={'operator': operator})
retrieves the operator and populates the form.
(That's untested code; you may need to edit a bit.)
At a glance, maybe something like this would work.
What you can do is add another URL in urls.py for new_asset which accepts a OperatorCompany id. I don't have your url config but it could be something like:
urls.py
path('wellsurfer/new_asset/<int:operator_id>', new_asset, name='wellsurfer:new_asset_operator')
view.py
def new_operator(request):
if request.method == 'POST':
form = NewOperatorForm(request.POST)
if form.is_valid():
newoperator = form.save(commit=False)
newoperator.created_by = request.user
newoperator.created_at = timezone.now()
newoperator.save()
return redirect('wellsurfer:new_asset', operator_id=newoperator.id)
else:
form = NewOperatorForm()
return render(request, 'wellsurfer/create_new_operator.html', {'create_operator': form})
def new_asset(request, operator_id=None):
if request.method == 'POST':
form = NewAssetForm(request.POST)
if form.is_valid():
newasset = form.save(commit=False)
newasset.created_by = request.user
newasset.created_at = timezone.now()
newasset.save()
return redirect('wellsurfer:new_pad')
else:
form = NewAssetForm()
if operator_id is not None:
operator_company = OperatorCompany.objects.get(pk=operator_id)
form.fields['operator'].initial = operator_company
return render(request, 'wellsurfer/create_new_asset.html', {'create_asset': form})

django - How to upload file to the folder in filefield

i am saving a form with a filefield, and saying upload_to to a user_path from the userprofile. I do not know how to write the view for the form
models.py
def nice_user_folder_upload(instance, filename):
extension = filename.split(".")[-1]
return (
f"{instance.UserProfile.Assigned_Group}/{filename}"
)
class Metadataform(models.Model):
id = models.AutoField(primary_key=True)
Authors_Name = models.CharField(max_length=500, blank=True, null=True)
Document = models.FileField(upload_to=nice_user_folder_upload)
class UserProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
Assigned_Group= models.CharField(max_length=500, choices=Group_choices, default='Please Select')
def __str__(self):
return self.user.username
views.py
def Metadata_submission(request):
Authors_Name = request.POST["Authors_Name"]
if request.method == 'POST':
form = Fileuploadform(request.POST, request.FILES)
if form.is_valid():
form.save()
return render(request, "home.html")
else:
form = Fileuploadform()
# forms.py
class Fileuploadform(forms.ModelForm):
class Meta:
model = Metadataform
fields = ['Authors_Name','Affliations','Dataset_Creation_Date','Publication_Ref','Embargo_Time','DataGeneration_Type','Methods','Instruments','Software','Models','Device','Configuration','Precursor','Data_Type','Variables','Error_Estimation','Document']
class UserProfileForm(forms.ModelForm):
class Meta:
model = UserProfile
fields = ('Assigned_Group',)
i am getting an AttributeError at /Metadata_submission/
'Metadataform' object has no attribute 'UserProfile'
The problem here I think is you have so many fields here that might not be associated with your Metadataform model (Maybe you haven't posted it in full). I think you should consider reading doc. By the look of it, you are trying to add UserProfile somewhere on your form, which is causing the error.

django - upload file to a specific folder

I have a userprofile that captures the username and the group the user is assigned to. I want the uploaded files to be saved under the group name folder. The folders already exit at the media root, the files shoud be routed to these folder
I solved the problem by the solution given. Now the username is shown as a dropdown list on the upload page. I want only the logged it username to be shown or exclude even showing it
models.py
class uploadmeta(models.Model):
path = models.ForeignKey(Metadataform, on_delete=models.CASCADE)
user_profile = models.ForeignKey(UserProfile, on_delete=models.CASCADE, null=True, verbose_name='Username')
tar_gif = models.FileField(upload_to=nice_user_folder_upload, verbose_name="Dataset") # validators=[FileExtensionValidator(allowed_extensions=['tar', 'zip'])]
def __str__(self):
return self.request.user.username
class UserProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
Group= models.CharField(max_length=500, choices=Group_choices, default='Please Select')
def __str__(self):
return self.user.username
view.py
def uploaddata(request):
if request.user.is_authenticated:
if request.method == 'POST':
form = uploadmetaform(request.POST, request.FILES)
if form.is_valid():
form.save()
return redirect('file_list')
else:
form = uploadmetaform()
return render(request, 'uploaddata.html', {
'form': form
})
else:
return render(request, 'home.html')
forms.py
class uploadmetaform(forms.ModelForm):
count = Metadataform.objects.all().latest('id').id #To know the id of latest object
data = Metadataform.objects.all().filter(id=count) #return the queryset with only latest object
path = forms.ModelChoiceField(queryset=data)
def __init__(self, *args, **kwargs):
super(uploadmetaform, self).__init__(*args, **kwargs)
count = Metadataform.objects.all().latest('id').id
data = Metadataform.objects.all().filter(id=count)
self.fields['path'] = forms.ModelChoiceField(queryset=data)
class Meta:
model = uploadmeta
fields = ['path', 'user_profile','tar_gif',]
You can use the upload_to argument in the FileField.
It accept a string representing the path where you want to store the file or you can pass in a function which let you add more details.
More info from the doc: https://docs.djangoproject.com/fr/2.2/ref/models/fields/#django.db.models.FileField.upload_to
You may need to add a foreign key form uploadmeta to UserProfile like :
user_profile = models.ForeignKey(UserProfile, on_delete=models.PROTECT)
Then you can use the following
def nice_user_folder_upload(instance, filename):
extension = filename.split(".")[-1]
return (
f"your_already_definied_folder/{instance.user_profile.group}/{file}.{extension}"
)
Then use it in uploadmeta FileField
doc = models.FileField(upload_to=nice_user_folder_upload, verbose_name="Dataset")

Saving Django ModelForm with a ForeignKey

This is probably a fairly simple question, but I can't seem to figure it out from the Django Docs. I'm trying to save a two ModelForms at once with one being a ForeignKey of another. I'm not sure how to write the logic in the views to ensure these go together properly.
models.py
class Address(models.Model):
address = models.CharField(max_length=100)
city = models.CharField(max_length=50)
zipcode = models.PositiveIntegerField()
class Store(models.Model):
name = models.CharField(max_length=100)
description = models.CharField(max_length=140, blank=True)
address = models.ForeignKey(Address, null=True)
forms.py
class CreateStore1Form(forms.ModelForm):
class Meta:
model = Store
exclude = ('address',)
class CreateStore2Form(forms.ModelForm):
class Meta:
model = Address
views.py
#login_required
def create(request):
if request.method == "POST":
form1 = CreateStore1Form(request.POST)
form2 = CreateStore2Form(request.POST)
if form1.is_valid() and form2.is_valid():
store = form1.save(address)
new_address = form2.save(commit=False)
new_address.store = store
mew_address.save()
else:
form1 = CreateStore1Form()
form2 = CreateStore2Form()
return render(request, 'create.html', locals())
Any help would be appreciated. Thanks!
Django provides inline formsets for this use case:
Inline formsets is a small abstraction layer on top of model formsets.
These simplify the case of working with related objects via a foreign
key.
forms.py
class AddressForm(forms.ModelForm):
class Meta:
model = Address
class StoreForm(forms.ModelForm):
class Meta:
model = Store
exclude = ('address',)
views.py
from django.forms.models import inlineformset_factory
#login_required
def create(request):
AddressInlineFormSet = inlineformset_factory(Address, Store, form=AddressForm)
if request.method == 'POST':
storeForm = StoreForm(request.POST)
if storeForm.is_valid():
new_store = storeForm.save()
addressInlineFormSet = AddressInlineFormSet(request.POST, request.FILES, instance=new_store)
if addressInlineFormSet.is_valid():
addressInlineFormSet.save()
return HttpResponseRedirect(reverse('some_happy_customer_url'))
else:
classificationformset = ClassificationInlineFormSet(request.POST, request.FILES, instance=new_store)
else:
addressInlineFormSet = AddressInlineFormSet()
storeForm = StoreForm()
return render(request, 'create.html', locals())
Please see also this question for more details.