I need a formula that can multiply or divide all the numbers in a string without changing the text attached to the numbers.
I need the numbers in the next column to automatically change according to the given mathematical operation, but the text from the original line must remain unchanged.
I've tried using a combination of REGEXMATCH and REGEXEXTRACT and by doing this I just get the result of multiplying/dividing all the numbers in the string (no text whatsoever).
I also had no success using REGEXREPLACE. I'm not even sure we can actually use it in this case, and maybe I need a different formula instead. Maybe you first need to extract the numbers, multiply them and use something like TEXTJOIN or CONCATENATE to put them together in a string with the values already changed, and is this even possible in this specific example? It's totally fine to perform the operation in several steps if needed (for example, adding SPLIT function or something like that), but the format of the raw data we need to enter and recalculate, unfortunately, cannot be modified.
A sample table for better visualisation can be seen below. Any help would be greatly appreciated!
Raw data
Operation
Desired outcome
25STR/40DEX/70FRES
*0.25
6.25STR/10DEX/17.5FRES
80VIT/30INT/50CRES
*0.75
60STR/22.5INT/37.5CRES
60VIT/20STR/45LRES
*1.25
75VIT/25STR/56.25LRES
You may try:
=byrow(index(bycol(split(A2:A,"/"),lambda(z,ifna(ifs(left(B2:B,1)="*",regexextract(z,"\d+")*mid(B2:B,2,99),left(B2:B,1)="/",round(regexextract(z,"\d+")/mid(B2:B,2,99),2))®exextract(z,"\d+(.*)"))))),lambda(y,if(y="",,join("/",y))))
Related
enter image description here
I have a table in OpenOffice that contains a column with region's codes (column J). Using table functions, how to get all codes that appear more than 5 times and write them in one cell?
Normally I would recommend breaking this problem down into smaller parts using helper columns. Or better yet, move the data into LibreOffice Base which can easily work with distinct values.
However, I managed to come up with a rather large formula that seems to do what you asked. Enter it as an array formula.
=TEXTJOIN(",";1;IF(COUNTIF(исходник.J$2:J$552;исходник.J2:J552)>5;IF(ROW(исходник.J2:J552)=MATCH(исходник.J2:J552;исходник.J$2:J$552;0)+ROW(J$2)-1;исходник.J2:J552;"")))
I can't test this on your actual data since your example is only an image, but let's say that there are six of both 77 and 37. Then this would show 77,37 as the result.
Here is a breakdown. Look up the functions in LibreOffice Online Help for more information.
=TEXTJOIN(",";1; — Join all results into a single cell, separated by commas.
IF(COUNTIF(исходник.J$2:J$552;исходник.J2:J552)>5; — Find codes that occur more than 5 times. This is the same as what you wrote.
IF(ROW(исходник.J2:J552)= — Compare the next result to the row number that we are currently looking at.
MATCH(исходник.J2:J552;исходник.J$2:J$552;0)+ROW(J$2)-1; — Determine the first row that has this code. We do this to get unique results instead of 6 or more of each code in the result.
исходник.J2:J552;""))) — Return the code. (Your formula simply returns 1 here, which doesn't seem to be what you want.) If it doesn't match, return an empty string rather than 0, because TEXTJOIN ignores empty strings.
I am working with a messy manually maintained "database" that has a column containing a string with name,value pairs. I am trying to parse the entire column with regexp to pull out the values. The column is huge (>100,000 entries). As a proxy for my actual data, let's use this code:
line1={'''thing1'': ''-583'', ''thing2'': ''245'', ''thing3'': ''246'', ''morestuff'':, '''''};
line2={'''thing1'': ''617'', ''thing2'': ''239'', ''morestuff'':, '''''};
line3={'''thing1'': ''unexpected_string(with)parens5'', ''thing2'': 245, ''thing3'':''246'', ''morestuff'':, '''''};
mycell=vertcat(line1,line2,line3);
This captures the general issues encountered in the database. I want to extract what thing1, thing2, and thing3 are in each line using cellfun to output a scalar cell array. They should normally be 3 digit numbers, but sometimes they have an unexpected form. Sometimes thing3 is completely missing, without the name even showing up in the line. Sometimes there are minor formatting inconsistencies, like single quotes missing around the value, spaces missing, or dashes showing up in front of the three digit value. I have managed to handle all of these, except for the case where thing3 is completely missing.
My general approach has been to use expressions like this:
expr1='(?<=thing1''):\s?''?-?([\w\d().]*?)''?,';
expr2='(?<=thing2''):\s?''?-?([\w\d().]*?)''?,';
expr3='(?<=thing3''):\s?''?-?([\w\d().]*?)''?,';
This looks behind for thingX' and then tries to match : followed by zero or one spaces, followed by 0 or 1 single quote, followed by zero or one dash, followed by any combination of letters, numbers, parentheses, or periods (this is defined as the token), using a lazy match, until zero or one single quote is encountered, followed by a comma. I call regexp as regexp(___,'tokens','once') to return the matching token.
The problem is that when there is no match, regexp returns an empty array. This prevents me from using, say,
out=cellfun(#(x) regexp(x,expr3,'tokens','once'),mycell);
unless I call it with 'UniformOutput',false. The problem with that is twofold. First, I need to then manually find the rows where there was no match. For example, I can do this:
emptyout=cellfun(#(x) isempty(x),out);
emptyID=find(emptyout);
backfill=cell(length(emptyID),1);
[backfill{:}]=deal('Unknown');
out(emptyID)=backfill;
In this example, emptyID has a length of 1 so this code is overkill. But I believe this is the correct way to generalize for when it is longer. This code will change every empty cell array in out with the string Unknown. But this leads to the second problem. I've now got a 'messy' cell array of non-scalar values. I cannot, for example, check unique(out) as a result.
Pardon the long-windedness but I wanted to give a clear example of the problem. Now my actual question is in a few parts:
Is there a way to accomplish what I'm trying to do without using 'UniformOutput',false? For example, is there a way to have regexp pass a custom string if there is no match (e.g. pass 'Unknown' if there is no match)? I can think of one 'cheat', which would be to use the | operator in the expression, and if the first token is not matched, look for something that is ALWAYS found. I would then still need to double back through the output and change every instance of that result to 'Unknown'.
If I take the 'UniformOutput',false approach, how can I recover a scalar cell array at the end to easily manipulate it (e.g. pass it through unique)? I will admit I'm not 100% clear on scalar vs nonscalar cell arrays.
If there is some overall different approach that I'm not thinking of, I'm also open to it.
Tangential to the main question, I also tried using a single expression to run regexp using 3 tokens to pull out the values of thing1, thing2, and thing3 in one pass. This seems to require 'UniformOutput',false even when there are no empty results from regexp. I'm not sure how to get a scalar cell array using this approach (e.g. an Nx1 cell array where each cell is a 3x1 cell).
At the end of the day, I want to build a table using these results:
mytable=table(out1,out2,out3);
Edit: Using celldisp sheds some light on the problem:
celldisp(out)
out{1}{1} =
246
out{2} =
Unknown
out{3}{1} =
246
I assume that I need to change the structure of out so that the contents of out{1}{1} and out{3}{1} are instead just out{1} and out{3}. But I'm not sure how to accomplish this if I need 'UniformOutput',false.
Note: I've not used MATLAB and this doesn't answer the "efficient" aspect, but...
How about forcing there to always be a match?
Just thinking about you really wanting a match to skip this problem, how about an empty match?
Looking on the MATLAB help page here I can see a 'emptymatch' option, perhaps this is something to try.
E.g.
the_thing_i_want_to_find|
Match "the_thing_i_want_to_find" or an empty match, note the | character.
In capture group it might look like this:
(the_thing_i_want_to_find|)
As a workaround, I have found that using regexprep can be used to find entries where thing3 is missing. For example:
replace='$1 ''thing3'': ''Unknown'', ''morestuff''';
missingexpr='(?<=thing2'':\s?)(''?-?[\w\d().]*?''?,) ''morestuff''';
regexprep(mycell{2},missingexpr,replace)
ans =
''thing1': '617', 'thing2': '239', 'thing3': 'Unknown', 'morestuff':, '''
Applying it to the entire array:
fixedcell=cellfun(#(x) regexprep(x,missingexpr,replace),mycell);
out=cellfun(#(x) regexp(x,expr3,'tokens','once'),fixedcell,'UniformOutput',false);
This feels a little roundabout, but it works.
cellfun can be replaced with a plain old for loop. Your code will either be equally fast, or maybe even faster. cellfun is implemented with a loop anyway, there is no advantage of using it other than fewer lines of code. In your explicit loop, you can then check the output of regexp, and build your output array any way you like.
I currently have a dataset filled with the following pattern:
My goal is to get each value into a different cell.
I have tried with the following formula, but it's not yielded the results I am looking for.
=SPLIT(D8,"[Stock]",FALSE,FALSE)
I would appreciate any guidance on how I can get to the ideal output, using Google Sheets.
Thank you in advance!
I will assume here from your post that your original data runs D8:D.
If you want to retain [Stock] in each entry, try the following in the Row-8 cell of a column that is otherwise empty from Row 8 downward:
=ArrayFormula(IF(D8:D="",,TRIM(SPLIT(REGEXREPLACE(D8:D&"~","(\[Stock\]).","$1~"),"~",1,1))))
If you don't want to retain [Stock] in each entry, use this version:
=ArrayFormula(IF(D8:D="",,TRIM(SPLIT(REGEXREPLACE(D8:D&"~","\[Stock\].","~"),"~",1,1))))
These formulas don't function based on using any punctuation at all as markers. They also assure that you don't wind up with blank (and therefore unusable) cells interspersed for ending SPLITs.
, only used in the separator
=ARRAYFORMULA(SPLIT(D8:D,", ",FALSE))
, used also in each string ([stock] will be replaced)
=ARRAYFORMULA(SPLIT(D8:D," [Stock], ",FALSE))
, used also in each string ([stock] will not be replaced)
=ArrayFormula(SPLIT(REGEXREPLACE(M9:M11,"(\[Stock\]), ","$1♦"),"♦"))
use:
=INDEX(TRIM(IFNA(SPLIT(D8:D; ","))))
In desperate need of some assistance with this!
Wasn't sure how to title this question...
SAMPLE SHEET - CLICK ME! :)
In SupportingSheet!H1 I have the following formula:
=ArrayFormula(if(G1:G<>"", IF(DASHBOARD!N2<>"", G1:G/DASHBOARD!$P$2-filter(DASHBOARD!O1:O100,REGEXMATCH(DASHBOARD!N1:N100,E1:E100)),G1:G/(DASHBOARD!$M$3)),))
The part I struggle with is:
G1:G/DASHBOARD!$P$2-filter(DASHBOARD!O1:O100,REGEXMATCH(DASHBOARD!N1:N100,E1:E100))
It needs to divide two numbers and then subtract another number. I can't seem to get this formula to pull the correct number.
It needs to check if the text in E1:E100 exist in DASHBOARD!N1:N100, if yes, pull the number from DASHBOARD!O1:O100.
For example, text in SupportingSheet!E1 can be found in DASHBOARD!N2, hence it needs to pull the number from DASHBOARD!O2.
Column SupportingSheet!J has the actual end result that a formula needs to produce.
It doesn't look like Regexmatch works as an Arrayformula and I am not sure how to go about it.
Please note, that text in SupportingSheet!E1:E is not always identical. Often it will have a random number of "space" at the end (long story...). That is why Regexmatch was a perfect option until I realised it didn't work.
Please let me know if further clarification is needed.
Below is an image of the random spaces (non-printable characters) at the end.
use:
=ARRAYFORMULA(IF(G1:G="",,IF(DASHBOARD!N2<>"",
IFNA(G1:G/DASHBOARD!$P$2-VLOOKUP(E1:E1000, DASHBOARD!N1:O100, 2, 0),
G1:G/DASHBOARD!$M$3))))
I have multiple cells that I am attempting to extract a number from, and need help finding a regex alternative.
The cells range in the following formats:
asdfs. Seat#29 asfddsa
asdfsa. Seat#5d
asdfasN/A . Seat#22 as789fsd
Seat#111 words33
The closest that I came to a solution is:
=IFERROR(TRIM(MID([#DisplayName],FIND("#",[#DisplayName])+1,3)),"")
As you can see this will extract most of the numbers but for some it leaves a character at the end.
The only commonality is the # preceding the seat number. I am trying to extract only the seat number, no other numbers.
I cannot use VBA, this must be done using formulas. I have figured this out once before but stupidly pasted over the formulas with a values only paste.
This can be done utilizing a flash fill, but I was hoping for a more stable formula.
If you want just the numbers then use:
=--MID(A1,FIND("#",A1)+1,AGGREGATE(15,6,ROW(1:5)/(ISERROR(--MID(REPLACE(A1,1,FIND("#",A1),""),ROW(1:5),1))),1)-1)
If you want the letter also then:
=MID(A1,FIND("#",A1)+1,FIND(" ",REPLACE(A1,1,FIND("#",A1),""))-1)
If you do not need the letter following the seat number, you can use
.*#(\d+)
Edit for clarity: Excel does not have regex functions built in. You will either have to use a UDF (I can help with that if you'd like) or use a non-regex solution.
Here is a solution without VBA to extract all numbers inside the strings.
https://drive.google.com/open?id=1Fk6VFznD3i8s6scADy_vXCEj-1zQpBPW
Sheet #3