I need your help. Program A executes program B with fork(). Every 5 seconds the process belonging to program B is interrupted. If the user enters any key within a certain time, the process is continued and interrupted again after the same time interval. If no key is entered, both program A and program B are terminated prematurely. I have tried the following code, but it does not work. Any suggestions/tips that will help me?
#include <iostream>
#include <chrono>
#include <unistd.h>
#include <sys/wait.h>
#include <signal.h>
using namespace std;
using namespace chrono;
int pid;
void signal_handler(int signum) {
cout << "Programm B is interrupted. Please enter any key within 5 or the programm will be terminated" << endl;
kill(pid,SIGSTOP);
alarm(5);
pause();
alarm(5);
}
int main(int argc, char* argv[]) {
//Usage
if(string(argv[1]) == "h" || string(argv[1]) == "help"){
cout << "usage" << endl;
return 0;
}
signal(SIGALRM, signal_handler);
pid = fork();
if (pid == 0) {
cout << "Name of programm B: " << argv[1] << endl;
cout << "PID of programm B: " << getpid() << endl;
execvp(argv[1], &argv[1]);
} else if (pid > 0) {
cout << "PID of programm A: " << getpid() << endl;
high_resolution_clock::time_point t1 = high_resolution_clock::now();
waitpid(pid, nullptr, 0);
high_resolution_clock::time_point t2 = high_resolution_clock::now();
auto duration = duration_cast<milliseconds>(t2 - t1).count();
cout << "Computing time: " << duration << "ms" << endl;
} else {
cerr << "error << endl;
return 1;
}
return 0;
}
Any help or sulution. I am a beginner in c++ btw.
Signals can get tricky and there are lots of issues with your approach.
You should:
kick off the timer (alarm(5)) in main
do the sighandler registration and timer kick-off after you've spawned the child (or you somewhat risk running the signal handler in the child in between fork and execvp)
use sigaction rather than signal to register the signal, as the former has clear portable semantics unlike the latter
loop on EINTR around waitpid (as signal interruptions will cause waitpid to fail with EINTR)
As for the handler, it'll need to
use only async-signal-safe functions
register another alarm() around read
unblock SIGALRM for the alarm around read but not before you somehow mark yourself as being in your SIGALRM signal handler already so the potential recursive entry of the handler can do a different thing (kill the child and exit)
(For the last point, you could do without signal-unblocking if you register the handler with .sa_flags = SA_NODEFER, but that has the downside of opening up your application to stack-overflow caused by many externally sent (via kill) SIGALRMs. If you wanted to handle externally sent SIGALRMs precisely, you could register the handler with .sa_flags=SA_SIGINFO and use info->si_code to differentiate between user-sends and alarm-sends of SIGALRM, presumably aborting on externally-sent ones)
It could look something like this (based on your code):
#include <iostream>
#include <chrono>
#include <unistd.h>
#include <sys/wait.h>
#include <signal.h>
#include <string.h>
//AS-safe raw io helper functions
ssize_t /* Write "n" bytes to a descriptor */
writen(int fd, const char *ptr, size_t n)
{
size_t nleft;
ssize_t nwritten;
nleft = n;
while (nleft > 0) {
if ((nwritten = write(fd, ptr, nleft)) < 0) {
if (nleft == n)
return(-1); /* error, return -1 */
else
break; /* error, return amount written so far */
} else if (nwritten == 0) {
break;
}
nleft -= nwritten;
ptr += nwritten;
}
return(n - nleft); /* return >= 0 */
}
ssize_t writes(int fd, char const *str0) { return writen(fd,str0,strlen(str0)); }
ssize_t writes2(char const *str0) { return writes(2,str0); }
//AS-safe sigprockmask helpers (they're in libc too, but not specified as AS-safe)
int sigrelse(int sig){
sigset_t set; sigemptyset(&set); sigaddset(&set,sig);
return sigprocmask(SIG_UNBLOCK,&set,0);
}
int sighold(int sig){
sigset_t set; sigemptyset(&set); sigaddset(&set,sig);
return sigprocmask(SIG_BLOCK,&set,0);
}
#define INTERRUPT_TIME 5
using namespace std;
using namespace chrono;
int pid;
volatile sig_atomic_t recursing_handler_eh; //to differentiate recursive executions of signal_handler
void signal_handler(int signum) {
char ch;
if(!recursing_handler_eh){
kill(pid,SIGSTOP);
writes2("Programm B is interrupted. Please type enter within 5 seconds or the programm will be terminated\n");
alarm(5);
recursing_handler_eh = 1;
sigrelse(SIGALRM);
if (1!=read(0,&ch,1)) signal_handler(signum);
alarm(0);
sighold(SIGALRM);
writes2("Continuing");
kill(pid,SIGCONT);
recursing_handler_eh=0;
alarm(INTERRUPT_TIME);
return;
}
kill(pid,SIGTERM);
_exit(1);
}
int main(int argc, char* argv[]) {
//Usage
if(string(argv[1]) == "h" || string(argv[1]) == "help"){
cout << "usage" << endl;
return 0;
}
pid = fork();
if (pid == 0) {
cout << "Name of programm B: " << argv[1] << endl;
cout << "PID of programm B: " << getpid() << endl;
execvp(argv[1], &argv[1]);
} else if (pid < 0) { cerr << "error" <<endl; return 1; }
struct sigaction sa; sa.sa_handler = signal_handler; sigemptyset(&sa.sa_mask); sa.sa_flags=0; sigaction(SIGALRM, &sa,0);
//signal(SIGALRM, signal_handler);
alarm(INTERRUPT_TIME);
cout << "PID of programm A: " << getpid() << endl;
high_resolution_clock::time_point t1 = high_resolution_clock::now();
int r;
do r = waitpid(pid, nullptr, 0); while(r==-1 && errno==EINTR);
high_resolution_clock::time_point t2 = high_resolution_clock::now();
auto duration = duration_cast<milliseconds>(t2 - t1).count();
cout << "Computing time: " << duration << "ms" << endl;
return 0;
}
Not that the above will wait only for an enter key. To wait for any key, you'll need to put your terminal in raw/cbreak mode and restore the previous settings on exit (ideally on signal deaths too).
Related
image for what output is supposed to look like:My problem is that I need to write a program that will accept the names of 3 processes as command-line arguments. Each of these processes will run for as many seconds as:(PID%10)*3+5 and terminate. After those 3 children terminated, the parent process
will reschedule each child. When all children have been rescheduled 3 times, the parent will terminate. I have used fork to create the three children but am struggling with getting them to exit with that specific criteria?
using namespace std;
int main(){
int i;
int pid;
for(i=0;i<3;i++) // loop will run n times (n=3)
{
if(fork() == 0)
{
pid = getpid();
cout << "Process p" << i+1 << " pid:" << pid << " Started..." << endl;
exit(0);
}
}
for(int i=0;i<5;i++) // loop will run n times (n=3)
wait(NULL);
}
You can use sigtimedwait to wait for SIGCHLD or timeout.
Working example:
#include <cstdio>
#include <cstdlib>
#include <signal.h>
#include <unistd.h>
template<class... Args>
void start_child(unsigned max_runtime_sec, Args... args) {
// Block SIGCHLD.
sigset_t set;
sigemptyset(&set);
sigaddset(&set, SIGCHLD);
sigprocmask(SIG_BLOCK, &set, nullptr);
// Enable SIGCHLD.
signal(SIGCHLD, [](int){});
pid_t child_pid = fork();
switch(child_pid) {
case -1:
std::abort();
case 0: {
// Child process.
execl(args..., nullptr);
abort(); // never get here.
}
default: {
// paren process.
timespec timeout = {};
timeout.tv_sec = max_runtime_sec;
siginfo_t info = {};
int rc = sigtimedwait(&set, nullptr, &timeout);
if(SIGCHLD == rc) {
std::printf("child %u terminated in time with return code %d.\n", static_cast<unsigned>(child_pid), info.si_status);
}
else {
kill(child_pid, SIGTERM);
sigwaitinfo(&set, &info);
std::printf("child %u terminated on timeout with return code %d.\n", static_cast<unsigned>(child_pid), info.si_status);
}
}
}
}
int main() {
start_child(2, "/bin/sleep", "/bin/sleep", "10");
start_child(2, "/bin/sleep", "/bin/sleep", "1");
}
Output:
child 31548 terminated on timeout with return code 15.
child 31549 terminated in time with return code 0.
With these changes your program produces the desired output:
#include <stdlib.h>
#include <unistd.h>
#include <sys/wait.h>
#include <iostream>
using namespace std;
int main()
{
for (int round = 0; ++round <= 4; )
{
int i;
cout << "*** ROUND: " << round << " ***\n";
for (i=0; i<3; i++) // loop will run n times (n=3)
{
if (fork() == 0)
{
int pid = getpid();
cout << "Process p" << i+1 << " pid:" << pid << " started...\n";
unsigned int seconds = pid%10*3+5;
cout << "Process " << pid << " exiting after "
<< seconds-sleep(seconds) << " seconds\n";
exit(0);
}
}
while (i--) // loop will run n times (n=3)
{
int status;
cout << "Process " << wait(&status);
cout << " exited with status: " << status << endl;
}
}
}
As Serge suggested, we're using sleep() for every child before exiting it. it will pause the process for a number of seconds.
To get the actual status information, we call wait(&status) instead of wait(NULL).
We're doing this all for the first scheduling round plus the desired 3 times of rescheduling.
I'm playing with signal handling in UNIX and C++ and came across with this issue. I'm trying to write a program that counts to 10, one number per second, and when the user tries to interrupt it with a SIGINT (like CTRL+C) it prints a message telling it it will continue to count no matter what.
So far, I got this:
#include <iostream>
#include <signal.h>
#include <zconf.h>
using namespace std;
sig_atomic_t they_want_to_interrupt = 0;
void sigint_handler(int signum) {
assert(signum == SIGINT);
they_want_to_interrupt = 1;
}
void register_handler() {
struct sigaction sa;
sigemptyset(&sa.sa_mask);
sigaddset(&sa.sa_mask, SIGINT);
sa.sa_handler = sigint_handler;
sigaction(SIGINT, &sa, 0);
}
int main() {
register_handler();
cout << "Hi! We'll count to a hundred no matter what" << endl;
for (int i = 1; i <= 100; i++) {
if (they_want_to_interrupt == 1) {
cout << endl << "DON'T INTERRUPT ME WHILE I'M COUNTING! I'll count ALL THE WAY THROUGH!!!" << endl;
they_want_to_interrupt = 0;
}
cout << i << " " << flush;
sleep(1);
}
cout << "Done!" << endl;
return 0;
}
Now, the first time around I send the interrupt signal it works properly:
Hi! We'll count to a hundred no matter what
1 2 ^C
DON'T INTERRUPT ME WHILE I'M COUNTING! I'll count ALL THE WAY THROUGH!!!
3 4
But if I send a second interrupt signal, the process is stopped.
Why does it happen? I tried reading the manual on ´sigaction´ to try to see if there's something that will make the handler I created not be popped when the signal is caught and roll back to SIG_DFL, but couldn't work it out.
Thanks
You can just reset the signal handler each time a signal is sent. I've seen this for handling SIGUSR when a signal might be expected repeatedly.
#include <iostream>
#include <cassert>
#include <signal.h>
#include <zconf.h>
using namespace std;
void register_handler();
sig_atomic_t they_want_to_interrupt = 0;
void sigint_handler(int signum) {
assert(signum == SIGINT);
they_want_to_interrupt = 1;
register_handler();
}
void register_handler() {
struct sigaction sa;
sigemptyset(&sa.sa_mask);
sigaddset(&sa.sa_mask, SIGINT);
sa.sa_handler = sigint_handler;
sigaction(SIGINT, &sa, 0);
}
int main() {
register_handler();
cout << "Hi! We'll count to a hundred no matter what" << endl;
for (int i = 1; i <= 100; i++) {
if (they_want_to_interrupt == 1) {
cout << endl << "DON'T INTERRUPT ME WHILE I'M COUNTING! I'll count ALL THE WAY THROUGH!!!" << endl;
they_want_to_interrupt = 0;
}
cout << i << " " << flush;
sleep(1);
}
cout << "Done!" << endl;
return 0;
}
In this code:
struct sigaction sa;
sigemptyset(&sa.sa_mask);
sigaddset(&sa.sa_mask, SIGINT);
sa.sa_handler = sigint_handler;
sigaction(SIGINT, &sa, 0);
the sa.sa_flags field (and others) are uninitialized which may cause unexpected results. It would be better to zero-initialize the struct at the start, e.g.:
struct sigaction sa = { 0 };
Also, the sig_atomic_t flag should be declared as volatile to prevent the optimizer introducing unexpected behaviour.
I am creating a program to practice using threads. I am trying to name them so that when the program is run, you can clearly see "Flight 1 is taking off..." or "Flight 6 is landing..." and so on. I would like every thread to have a flyTime (so I know what order they will use the runway in) which will be randomly generated. I have tried and am having difficulty using struct/typedef to give each pthread these characteristics so i can say for example flight.flyTime and use it throughout the program. Here is the relevant part of my code without my landing/takeoff functions:
#include <pthread.h>
#include <stdio.h>
#include <cstdlib>
#include <iostream>
#include <queue>
#define NUM_THREADS 8 //8 flights
pthread_mutex_t runway1lock;
void *FlightID(void *flightid){
long fid;
fid = (long)flightid;
pthread_exit(NULL);
}
typedef struct{ //each plane has these characteristics
long fid;
int StartState; // if start=1 ==> taking off:::if start=2 ==> landing
int flyTime; //fly == randomly generated time (order)
}FLIGHTS;
FLIGHTS flights[NUM_THREADS];
int StartState(flights[NUM_THREADS]){
int startState;
for (int i=0; i<=NUM_THREADS; i++){
startState = rand() % 1+2;
}
std::string start;
if(startState == 1){
start = "Taking off";
}
if(startState == 2){
start = "Landing";
}
for (int t=0; t<NUM_THREADS; t++){
std::cout << "Start State for Flight# " << FlightID << " is " << start << std::endl;
}
return startState;
}
int main(int argc, char *argv[]){
// pthread_t flights[NUM_THREADS]; //pthread_t keeps a thread ID after the thread is created with pthread_create()
//it's like an index on a vector of threads
int rc;
long t;
for (t=1; t<=NUM_THREADS; t++){ //loop creates threads(flights)
printf("In main: Creating flight %1d\n", t);
rc = pthread_create(&flights[t], NULL, FlightID, (void *)t);
if (rc){
printf("ERROR: return code from pthread_create() is %d\n", rc);
return (-1);
}
printf("Created flight %1d\n", t);
StartState(flights[t]); //gives every flight a start state
if(StartState(flights[t])==1){
std::cout << "Flight # " << &flights[t] << " is listed as waiting at the gate." << std::endl;
//go to takeoff function and go through switch case
}
if(StartState(flights[t])==2){`enter code here`
std::cout << "Flight # " << &flights[t] << " is listed as waiting to land." << std::endl;
//go to landing function and go through switch case
}
}
pthread_exit(NULL);
}
There is a code snippet below that represents how I would implement it.
You should also take a look at pthread_key_create, pthread_getspecific and pthread_setspecific. This is a set of functions that allow you to have data, specific to each thread, stored in the thread's memory context. It may come in handy for in your code, later on.
typedef struct{
long fid;
int StartState;
int flyTime;
} FLIGHTS;
FLIGHTS** flights = new FLIGHTS*[NUM_THREADS];
pthread_key_t pkey:
void *FlightID(void *flightid){
long fid;
fid = (long)flightid;
FLIGHTS* flight = new FLIGHTS();
flight->fid = fid;
flights[fid] = flight;
pthread_setspecific(pkey, flight);
int startState;
for (int i=0; i<=NUM_THREADS; i++){
startState = rand() % 1+2;
}
std::string start;
if(startState == 1){
start = "Taking off";
}
if(startState == 2){
start = "Landing";
}
for (int t=0; t<NUM_THREADS; t++){
std::cout << "Start State for Flight# " << fid << " is " << start << std::endl;
}
flight->StartState = startState;
}
int main(int argc, char* argv[]) {
pthread_key_create(&pkey, NULL);
for (t=1; t<=NUM_THREADS; t++){
rc = pthread_create(&flights[t], NULL, FlightID, (void *)t);
if (rc){
printf("ERROR: return code from pthread_create() is %d\n", rc);
return (-1);
}
printf("Created flight %1d\n", t);
}
}
Also, I don't know if I'm understanding your code correctly or if you just have some coding errors on it, so I leave you with some questions or remarks that could be mistakes/bugs:
1) You invoke pthread_exit in the start callback function:
void *FlightID(void *flightid){
long fid;
fid = (long)flightid;
pthread_exit(NULL);
}
2) You pass to the << operator a function with no return value:
std::cout << "Start State for Flight# " << FlightID << " is " << start << std::endl;
3) You invoke the same function 3 times just to get the return value. Shouldn't it be int state = StartState(flights[i]) and then test the state variable value?
StartState(flights[t]); //gives every flight a start state
if(StartState(flights[t])==1){
std::cout << "Flight # " << &flights[t] << " is listed as waiting at the gate." << std::endl;
//go to takeoff function and go through switch case
}
if(StartState(flights[t])==2){`enter code here`
std::cout << "Flight # " << &flights[t] << " is listed as waiting to land." << std::endl;
//go to landing function and go through switch case
}
4) You can't define a function like this:
int StartState(flights[NUM_THREADS]){
I need to implement barrier synchronization between 2 threads using mutex (only). Barrier synchronization is that 2 threads will wait for each other to meet at predefined step before proceeding.
I am able to do it using seamaphore but how can I achieve this only using mutex. I was given a hint that I need 2 mutex not 1 to do this.
Using Seamaphore:
#include <pthread.h>
#include <semaphore.h>
using namespace std;
sem_t s1;
sem_t s2;
void* fun1(void* i)
{
cout << "fun1 stage 1" << endl;
cout << "fun1 stage 2" << endl;
cout << "fun1 stage 3" << endl;
sem_post (&s1);
sem_wait (&s2);
cout << "fun1 stage 4" << endl;
}
void* fun2(void* i)
{
cout << "fun2 stage 1" << endl;
cout << "fun2 stage 2" << endl;
// sleep(5);
sem_post (&s2);
sem_wait (&s1);
cout << "fun2 stage 3" << endl;
}
main()
{
sem_init(&s1, 0, 0);
sem_init(&s2, 0, 0);
int value;
sem_getvalue(&s2, &value);
cout << "s2 = " << value << endl;
pthread_t iThreadId;
cout << pthread_create(&iThreadId, NULL, &fun2, NULL) << endl;
// cout << pthread_create(&iThreadId, NULL, &fun2, NULL) << endl;
pthread_create(&iThreadId, NULL, &fun1, NULL);
sleep(10);
}
Compile the above code as "g++ barrier.cc -lpthread"
How about NO MUTEXES and no locks? Using ATOMIC OPERATIONS only:
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <signal.h>
static sigset_t _fSigSet;
static volatile int _cMax=20, _cWait = 0;
static pthread_t _aThread[1000];
void * thread(void *idIn)
{
int nSig, iThread, cWait, id = (int)idIn;
printf("Start %d\n", id, cWait, _cMax);
// do some fake weork
nanosleep(&(struct timespec){0, 500000000}, NULL);
// barrier
cWait = __sync_add_and_fetch(&_cWait, 1);
printf("Middle %d, %d/%d Waiting\n", id, cWait, _cMax);
if (cWait < _cMax)
{
// if we are not the last thread, sleep on signal
sigwait(&_fSigSet, &nSig); // sleepytime
}
else
{
// if we are the last thread, don't sleep and wake everyone else up
for (iThread = 0; iThread < _cMax; ++iThread)
if (iThread != id)
pthread_kill(_aThread[iThread], SIGUSR1);
}
// watch em wake up
cWait = __sync_add_and_fetch(&_cWait, -1);
printf("End %d, %d/%d Active\n", id, cWait, _cMax);
return 0;
}
int main(int argc, char** argv)
{
pthread_attr_t attr;
int i, err;
sigemptyset(&_fSigSet);
sigaddset(&_fSigSet, SIGUSR1);
sigaddset(&_fSigSet, SIGSEGV);
printf("Start\n");
pthread_attr_init(&attr);
if ((err = pthread_attr_setstacksize(&attr, 16384)) != 0)
{
printf("pthread_attr_setstacksize failed: err: %d %s\n", err, strerror(err));
exit(0);
}
for (i = 0; i < _cMax; i++)
{
if ((err = pthread_create(&_aThread[i], &attr, thread, (void*)i)) != 0)
{
printf("pthread_create failed on thread %d, error code: %d %s\n", i, err, strerror(err));
exit(0);
}
}
for (i = 0; i < _cMax; ++i)
pthread_join(_aThread[i], NULL);
printf("\nDone.\n");
return 0;
}
I am not sure that you need two mutexes, with one mutex and a condition variable and an extra flag might be enough. The idea is that you enter the critical section by acquiring the mutex, then you check whether you are the first thread to come, if so, you wait on the condition. If you are the second thread coming then you wake up the waiting thread and both leave.
I am forking a number of processes and I want to measure how long it takes to complete the whole task, that is when all processes forked are completed. Please advise how to make the parent process wait until all child processes are terminated? I want to make sure that I stop the timer at the right moment.
Here is as a code I use:
#include <iostream>
#include <string>
#include <fstream>
#include <sys/time.h>
#include <sys/wait.h>
using namespace std;
struct timeval first, second, lapsed;
struct timezone tzp;
int main(int argc, char* argv[])// query, file, num. of processes.
{
int pCount = 5; // process count
gettimeofday (&first, &tzp); //start time
pid_t* pID = new pid_t[pCount];
for(int indexOfProcess=0; indexOfProcess<pCount; indexOfProcess++)
{
pID[indexOfProcess]= fork();
if (pID[indexOfProcess] == 0) // child
{
// code only executed by child process
// magic here
// The End
exit(0);
}
else if (pID[indexOfProcess] < 0) // failed to fork
{
cerr << "Failed to fork" << endl;
exit(1);
}
else // parent
{
// if(indexOfProcess==pCount-1) and a loop with waitpid??
gettimeofday (&second, &tzp); //stop time
if (first.tv_usec > second.tv_usec)
{
second.tv_usec += 1000000;
second.tv_sec--;
}
lapsed.tv_usec = second.tv_usec - first.tv_usec;
lapsed.tv_sec = second.tv_sec - first.tv_sec;
cout << "Job performed in " <<lapsed.tv_sec << " sec and " << lapsed.tv_usec << " usec"<< endl << endl;
}
}//for
}//main
I'd move everything after the line "else //parent" down, outside the for loop. After the loop of forks, do another for loop with waitpid, then stop the clock and do the rest:
for (int i = 0; i < pidCount; ++i) {
int status;
while (-1 == waitpid(pids[i], &status, 0));
if (!WIFEXITED(status) || WEXITSTATUS(status) != 0) {
cerr << "Process " << i << " (pid " << pids[i] << ") failed" << endl;
exit(1);
}
}
gettimeofday (&second, &tzp); //stop time
I've assumed that if the child process fails to exit normally with a status of 0, then it didn't complete its work, and therefore the test has failed to produce valid timing data. Obviously if the child processes are supposed to be killed by signals, or exit non-0 return statuses, then you'll have to change the error check accordingly.
An alternative using wait:
while (true) {
int status;
pid_t done = wait(&status);
if (done == -1) {
if (errno == ECHILD) break; // no more child processes
} else {
if (!WIFEXITED(status) || WEXITSTATUS(status) != 0) {
cerr << "pid " << done << " failed" << endl;
exit(1);
}
}
}
This one doesn't tell you which process in sequence failed, but if you care then you can add code to look it up in the pids array and get back the index.
The simplest method is to do
while(wait() > 0) { /* no-op */ ; }
This will not work if wait() fails for some reason other than the fact that there are no children left. So with some error checking, this becomes
int status;
[...]
do {
status = wait();
if(status == -1 && errno != ECHILD) {
perror("Error during wait()");
abort();
}
} while (status > 0);
See also the manual page wait(2).
Call wait (or waitpid) in a loop until all children are accounted for.
In this case, all processes are synchronizing anyway, but in general wait is preferred when more work can be done (eg worker process pool), since it will return when the first available process state changes.
I believe the wait system call will accomplish what you are looking for.
for (int i = 0; i < pidCount; i++) {
while (waitpid(pids[i], NULL, 0) > 0);
}
It won't wait in the right order, but it will stop shortly after the last child dies.