Dynamic Array resizing in C++ Doesn't work properly - c++

Question

i have this reSize function in my Array header
void reSize(int newsize) {
T* old = items;
size = newsize;
items = new T[newsize];
for (int i = 0;i < length;i++)
items[i] = old[i];
delete[]old;
}
and my main code:
struct User{
string name;
Array<int> data;
};
int main() {
Array<User> x(3);
x.get(0).name = "Kmal";
x.get(0).data.push_back(2); x.get(0).data.push_back(3);
x.reSize(10);
cout << x.get(0).data.get(0) <<endl;
return 0;
}
the problem is after resizing, my values that were stored in "data" variable are gone.
when i commented the code.
//delete[] old
in the reSize function
it worked fine...so i guess the problem is when i delete the pointer it deletes also the pointer inside the struct object which i don't want it to happen..
i don't want to comment the command becuz a leak in the memory will happen...how to fix this problem ?.
Update: My Array Class .
#include <iostream>
using namespace std;
template <class T>
class Array {
private :
T* items;
int size;
int length;
public :
Array() {
this->size = 0;
items = new T[this->size];
length = 0;
}
Array(int size) {
this->size = size;
items = new T[this->size];
length = 0;
}
int getsize() {
return this->size;
}
template <class T> void push_back(T x) {
if ((length+1) <= size) {
items[length] = x;
length++;
}
else {
this->reSize(size+1);
items[length] = x;
length++;
}
}
template <class T> void Insert(int index, T x) {
if (length + 1 <= size) {
for (int i = length;i > index;i--) {
items[i] = items[i - 1];
}
items[index] = x;
length++;
}
else {
this->reSize(size+1);
for (int i = length;i > index;i--) {
items[i] = items[i - 1];
}
items[length] = x;
length++;
}
}
template <class T> int Find(T x) {
int index = -1;
for (int i = 0;i < length;i++) {
if (items[i] ==x) {
index = i;
break;
}
}
return index;
}
void remove(int index) {
items[index] = "";
if(index+1 < length)
for (int i = index;i < length-1;i++) {
items[i] = items[i + 1];
items[i + 1] = "";
}
length--;
}
void reSize(int newsize) {
T* old = items;
size = newsize;
items = new T[newsize];
for (int i = 0;i < length;i++)
items[i] = old[i];
delete[]old;
}
void Merge(Array<T> x){
T* old = items; int oldlength = length;
items = new T[size + x.size];
size = size + x.size;
length += x.length;
for (int i = 0;i < length;i++) {
if(i< oldlength)
items[i] = old[i];
else
items[i] = x.items[i-oldlength];
}
delete[] old;
}
T& get(int index) {
return items[index];
}
}

Answer 1

struct User{
string name;
Array<int> data;
};
int main() {
Array<User> x(3);
// this line causes some problems
x.get(0).name = "Kmal";
x.get(0).data.push_back(2); x.get(0).data.push_back(3);
x.reSize(10);
cout << x.get(0).data.get(0) <<endl;
return 0;
}
In your code, declaring Array<User> x(3) declares an empty array with 3 elements that are preallocated. The length property of the array is 0. When the array is copied, length(0) elements are copied over into the resized storage. When you access the 0th element, it won't be copied on resize. What you actually need to do is call push_back() to add an element to the array so that length becomes 1 and the element is copied on resize.
Also, your array class is lacking a proper copy constructor and move constructor, which means copying it won't work at all. This means that User cannot be copied properly since it contains an array, which means that resizing an array of User won't work. You need to implement a copy constructor and copy assignment operator to be able to copy the array. You also need a destructor since, right now, the array is leaking memory when it goes out of scope.