Can you update a table using a partition within the where clause? - sql-update

Question

I have a query:
SELECT *, ORDER = MAX(ORDER) OVER (PARTITION BY ID)
FROM MY TABLE
Where MY_TABLE is currently
ID
ORDER
AGE
RECENT
12
34
50
TRUE
99
41
17
TRUE
12
34
24
TRUE
99
42
12
TRUE
12
33
15
TRUE
12
33
38
TRUE
I want the table to be updated as the result from the query to be
ID
ORDER
AGE
RECENT
12
34
50
TRUE
99
41
17
FALSE
12
34
24
TRUE
99
42
12
TRUE
12
33
15
FALSE
12
33
38
FALSE
Is there a way to do this with an UPDATE statement.
I was trying
UPDATE MY_TABLE
SET RECENT = FALSE
WHERE ORDER <> MAX(ORDER) OVER (PARTITION BY ID);
But I am not sure how to incorporate the partition statement into the update.

Answer 1

Try this:
update my_table
set recent = false
where (id, order) not in (select id, max(order) from my_table group by 1);

Answer 2

As suggested by #Tim Biegeleisen, running this as an update may not be the best idea. Rather than updating the table you could create a view over the top of it to always show the latest information, without needing to update the table. This removes the risk of the RECENT column going out of date between new values being added, and the update process being executed.
CREATE TABLE my_tbl (id NUMBER, "ORDER" NUMBER, age NUMBER);
INSERT INTO my_tbl VALUES
(12, 34, 50),
(99, 41, 17),
(12, 34, 24),
(99, 42, 12),
(12, 33, 15),
(12, 33, 38);
CREATE OR REPLACE VIEW my_view AS
SELECT
*,
"ORDER" = MAX("ORDER") OVER (PARTITION BY ID) AS RECENT
FROM
my_tbl
;
This gives the output:
ID
ORDER
AGE
RECENT
12
34
50
TRUE
99
41
17
FALSE
12
34
24
TRUE
99
42
12
TRUE
12
33
15
FALSE
12
33
38
FALSE
Adding another row:
INSERT INTO my_tbl VALUES (12, 35, 51);
Gives:
ID
ORDER
AGE
RECENT
12
34
50
FALSE
99
41
17
FALSE
12
34
24
FALSE
99
42
12
TRUE
12
33
15
FALSE
12
33
38
FALSE
12
35
51
TRUE