Is it possilbe to rename a job in AWS Glue? - amazon-web-services

As in the title of my post, it is possible? I don't see any options.
Also, the job details include advanced properties that include the name of my script, for example, job-name.py When the python script is renamed, will the job name also change? I'm afraid I might mess something up after the change.
Thanks in advance

From CloudFormation docs (https://docs.aws.amazon.com/AWSCloudFormation/latest/UserGuide/aws-resource-glue-job.html) is stated that changing the name parameter would replace the job so I would say no.

Expanding on the answer from #zoran2709:
From CloudFormation docs (https://docs.aws.amazon.com/AWSCloudFormation/latest/UserGuide/aws-resource-glue-job.html) is stated that changing the name parameter would replace the job so I would say no.
In the console, it doesn't look like you can. If you defined this job in CloudFormation, you can update the name of the job, but it will replace the resource with a new one. I would recommend setting the UpdateReplacePolicy on the resource to Retain just to be safe. Checkout the docs here:
If you update a resource property that requires that the resource be replaced, CloudFormation recreates the resource during the update. Recreating the resource generates a new physical ID. CloudFormation creates the replacement resource first, and then changes references from other dependent resources to point to the replacement resource. By default, CloudFormation then deletes the old resource. Using the UpdateReplacePolicy, you can specify that CloudFormation retain or, in some cases, create a snapshot of the old resource.

Related

How to move terraform resource in terraform apply

I have custom resource defined in my terraform module:
resource "aws_alb_target_group" "whatever"
{
....
}
Turns out whatever is not good name, and I need to update it.
Classic way of doing it would be to login onto each environment and execute terraform state mv, however I have lots of environments, and no automation for such action.
How I can change name of resource without manually moving state (only through editing terraform modules and applying plans)?
Based on the explanation in the question, I guess your best bet would be to use the moved block [1]. So for example, in your case that would be:
resource "aws_alb_target_group" "a_much_better_whatever"
{
....
}
moved {
from = aws_alb_target_group.whatever
to = aws_alb_target_group.a_much_better_whatever
}
EDIT: As #Matt Schuchard noted, the moved block is available only for Terraform versions >=1.1.0.
EDIT 2: As per #Martin Atkins' comments, changed the resource name to be the name of the resource moving to instead of moving from.
[1] https://www.terraform.io/language/modules/develop/refactoring#moved-block-syntax
I'm in the same situation.
My plan is to create the new resource group in Terraform, apply it, move the resources in the Azure portal to the new resource group, and then do terraform state mv to move the resources in terraform.
Yes, if you have a lot of resources its boring.. but I guess I won't brake anything this way.

Update Cloudformation stack name

I have a CF stack in the name gtm-test-commit-9ttyhf7old. I want to know if there is a way to update the same stack with the new commit ID. Something like gtm-test-commit-9ttyhf7new without creating a new stack altogether.
It's not possible to rename a stack. You have to delete it and create a new one with the name you want.
For most resources, changing the logical name of a resource is
equivalent to deleting that resource and replacing it with a new one.
Any other resources that depend on the renamed resource also need to
be updated and might cause to be replaced. Other resources require you
to update a property (not just the logical name) in order to initiate
an update.
Check out this doc: AWS Official Document

Renaming Resource in CloudFormation Template

Can you rename a resource in a CloudFormation template?
Let's say I've created a stack template that creates a single lambda function.
GetTheFunnyPhraseText:
Type: AWS::Serverless::Function
Properties:
CodeUri: ../Lambda/
Handler: GetFunnyPhrase.handler
FunctionName: GetFunnyPhrase
Role: !GetAtt [ ExecuteFunctionGetFunnyPhrase, Arn ]
For whatever reason, I want to change the resource name GetTheFunnyPhraseText to GetFunnyPhrase. Is there a mechanism to change the name?
A couple things I tried...
Changing the resource name in the template. It looks like this acts like a delete on GetTheFunnyPhraseText and create of GetFunnyPhrase. Problem here is the resource creation happens before the resource deletion causing the action to fail because the Lambda function exists.
Create two drafts of the template. Draft-1: Change the function name for the existing resource(s). Draft-2: Delete the old resource (omit their definition from the template) and add the new resource. Execute the draft templates in sequence: 1st then 2nd. This works. It's just gross.
For folks that suggest not naming the function, understood; put a pin in that piece of feedback for the moment.
Now that CloudFormation import is available it's technically possible to do this, although it's tedious.
Here's what you'd need to do:
Update the definition for GetTheFunnyPhraseText to add DeletionPolicy: "Retain", upload to CloudFormation
Remove GetTheFunnyPhraseText entirely from your template. Upload to CloudFormation. This will not actually delete the underlying Lambda because of the previously added DeletionPolicy
Revert your template back to the previous state in Step #1 (add GetTheFunnyPhraseText back) and change the logical name to GetFunnyPhrase
Start the "Stack Actions" > "Import resources into stack" workflow.
Upload your reverted template (with the changed logical name, still including the DeletionPolicy)
The import process will notice the new GetFunnyPhrase logical name and ask you what actual FunctionName should be mapped to that name. Provide the existing GetFunnyPhrase Lambda name and complete the import.
Finally, you can re-upload your template and remove the DeletionPolicy
A tedious process for sure, but technically possible if you really don't want to delete the existing resource.
No! Renaming a resource's logical name is not possible in Cloud Formation.
As you tested as well, CloudFormation sees it as the removal of the old resource and creation of the new one. This is so because the logical resource IDs are bound to the physical IDs of the resources by CloudFormation after creation. But for CloudFormation template language, it only recognizes the logical ID while parsing the template so any changes to that would mean the resource associated to it is going to be changed.
In some resource types though you can set the physical IDs yourself by using certain name properties which are resource-specific, for example a resource AWS::RDS::DBInstance may have a property DBInstanceIdentifier which will be the physical name of the db instance itself.

How to conditionally update a resource in Terraform

Seems it's common practice to make use of count on a resource to conditionally create it in Terraform using a ternary statement.
I'd like to conditionally update an AWS Route 53 entry based on a push_to_prod variable. Meaning I don't want to delete the resource if I'm not pushing to production, I only want to update it, or leave the CNAME value as it is.
Has anyone done something like this before in Terraform?
Currently as it stands interpolation syntax isn't supported in lifecycle tags. You can read more here. Which will make this harder because you could use the "Prevent Destroy". However, without more specifics I am going to take my best guess on how to get your there.
I would use the allow_overwrite property on the Route53 record and set that based on your flag. That way if you are pushing to prod you can set it it false. Which should trigger creating a new one. I haven't tested that.
Also note that if you don't make any changes to the Route53 resource it should trigger any changes in Terraform to be applied. So updating any part of the record will trigger the deployment.
You may want to combine this with some lifecycle events, but I don't have enough time to dig into that specific resource and how it happens.
Two examples I can think of are:
type = "${var.push_to_prod == "true" ? "CNAME" : var.other_value}" - this will have a fixed other_value, there is no way to have terraform "ignore" the resource once it's being managed by terraform.
or
type = "${var.aws_route53_record_type}" and you can have dev.tfvars and prod.tfvars, with aws_route53_record_type defined as whatever you want for dev and CNAME for prod.
The thing is with what you're trying to do, "I only want to update it, or leave the CNAME value as it is.", that's not how terraform works. Terraform either manages the resource for you or it doesn't. If it's managing it, it'll update the resource based on the config you've defined in your .tf file. If it's not managing the resource it won't modify it. It sounds like what you're really after is the second solution where you pass in two different configs from your .tfvars file into your .tf file and based off the different configs, different resources are created. You can couple this with count to determine if a resource should be created or not.

AWS Cloudformation : Encountered unsupported property LaunchConfigurationName

How do we create Launch configurations in cloudformation with specific name.? I looked at the docs https://docs.aws.amazon.com/AWSCloudFormation/latest/UserGuide/aws-properties-as-launchconfig.html, there is no property that sets the name of the launch configuration that we create in template.
Is there any way?
You should not try to name the LaunchConfiguration yourself, as cloudformation need to setup its own name to be able to update it later.
Usually, the LauchConfiguration will be named according to the stack and resource name from the template, something like: {stack-name}-{resource-name}-{AWS-generated-id}, this gived me for example: amp-g2g-preprod-api-ec2-ApiLaunchConfiguration-1PQ85HXBX7DVC.
If you need to reference anywhere else your LaunchConfiguration, use {"Ref":"..."} from within the template, or use output export/import from another template.