How to check if a certain character is in an array [duplicate] - c++

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I am trying to make my own WORDLE game with C++. I have gotten to the point where I can check if a character is in the right spot but I do not know how to check if a letter is in the word but in a different place. This is what I have so far:
#include <iostream>
#include <fstream>
#include <string>
#include <stdio.h>
#include <cstdlib>
using namespace std;
string pickword();
string checkword(string ans, string word);
int main() {
string guess;
cout << "Hi welcome to WORDLE\n\n*Hit enter to start*";
cin.ignore();
string word = pickword();
cout << endl << word;
cout << "\nEnter a 5-letter word: ";
cin >> guess;
checkword(guess, word);
}
string pickword() {
srand((unsigned) time(NULL));
int random = 1 + (rand() % 1999);
string string;
ifstream ReadFile;
ReadFile.open("words.txt");
for (int i = 1; i <= random; i++) {
getline(ReadFile, string);
}
ReadFile.close();
return string;
}
string checkword(string ans, string word) {
char anslst[5];
char wrdlst[5];
for (int i = 0; i <= 4; i++) {
anslst[i] = ans[i];
wrdlst[i] = word[i];
}
//Green = \033[32m
//Red = \033[31m
//Yellow = \033[33m
for (int i = 0; i <= 4; i++) {
if (anslst[i] == wrdlst[i]) {
cout << "\033[32m" << anslst[i];
}
else if (anslst[i] != wrdlst[i]) {
cout << "\033[31m" << anslst[i];
}
}
return word;
}
the part relevent to the question is the bottom of checkword(). how can I see if the letters in the player's guess are in the the list containing the letters of the answer?

Answer 1

This main problem you're faced with isn't so much a question about C++, but instead an algorithmic question of "what to do with repeated letters?" For example, my understanding of the rules of Wordle are that a guess of "APPLE" when the answer was "PASTE", your first "P" should be yellow, but your second "P" should be grey. But if the answer had been "SPIPE", then "APPLE"'s second "P" should be yellow (because its first "P" is now green).
If we were to extend your C++ example with some of the programming choices you've already made, the central part of your checkword() might be written something like this:
EResult result[5];
for (int i = 0; i <= 4; i++) {
if (anslst[i] == wrdlst[i]) {
result[i] = GREEN;
}
else {
result[i] = GREY;
}
}
for (int i = 0; i <= 4; i++) {
if (result[i] != GREEN) {
bool searchingForYellow = true;
for (int j = 0; j <= 4 && searchingForYellow; j++) {
if (result[j] == GREY && anslst[i] == wrdlst[j]) {
result[j] = YELLOW;
searchingForYellow = false;
}
}
}
}
for (int i = 0; i <= 4; i++) {
if (result[i] == GREEN) {
cout << "\033[32m" << wrdlst[i];
}
else if (result[i] == YELLOW) {
cout << "\033[33m" << wrdlst[i];
}
else { // GREY
cout << "\033[31m" << wrdlst[i];
}
}
Notice that I've assumed you have an enumeration type named EResult with values GREEN or YELLOW or GREY (I haven't defined that type in my example code). You might need to study a bit about C++ enumerations if that is a new concept for you. Also consider using a "switch" statement instead of the condition at the end (but I'm not sure if you're familiar with "switch", so I wrote it this way for you instead). Also, consider using a "break" statement instead of the boolean variable (but again, I'm not sure how familiar you are with that programming element).