I would like to use a macro in SAS to calculate the last day of the current month when executed.
As i'm quite new to the SAS macro's i've tried to create on based on the information i've found on the internet.
%let last_day = %sysfunc(putn(%sysfunc(intnx(month,%sysfunc(today()),e), date9.));
However it does not seem to work when i execute it.
You left out the number of intervals in the INTNX() function call.
To create a macro variable with the string that looks like the last day of the current month in the style produced by the DATE9. format just use:
%let last_day = %sysfunc(intnx(month,%sysfunc(today()),0,e), date9.);
You could then use that macro variable to generate strings. Such as in a TITLE statement.
TITLE "End of the month is &last_day";
If you want to use it as an actual date you will need to convert it to a date literal by adding quotes and the letter d.
...
where date <= "&last_day"d ;
And if so it is probably simpler to not use the DATE9. format at all and just store the raw number of days since 1960 in the macro variable.
%let last_day = %sysfunc(intnx(month,%sysfunc(today()),0,e));
...
where date <= &last_day ;
Related
How to convert the default timestamp "0001-01-01-00.00.00.000000" in SAS, i have tried below code but it has returned null value. Can someone help on this please
data _NULL_;
x = "0001-01-01-00.00.00.000000";
rlstime = input(x,anydtdtm26.);
call symput('rlstime',rlstime);
run;
%put rlst: &rlstime;
As far as I remember, SAS cannot do that. Any date/timestamp before 1.1.1600 doesn't exist for SAS. Do you need it or can you just replace it with a null value? If you really need it you could transform it into another valid timestamp, split it into different columns (year, month, etc.) or just use it as a string. In your example you just write the timestamp into the log, meaning it's not necessary to transform it.
The earliest date that SAS will handle is 1st January, 1582. Additionally, a colon character should be used to delimit the time from the date, as well as the hours, minutes and seconds. Therefore, your code may be adjusted to the following:
data _NULL_;
x = "1582-01-01:00:00:00.000000";
rlstime = input(x,anydtdtm26.);
call symput('rlstime',rlstime);
run;
%put rlst: &rlstime;
A little new to SAS here. I am using the following data step to get the first and last day of the month.
Data _NULL_;
begindt=IntNX("Month", Date(), 0) ;
enddt=IntNX("Month", Date(),0,'E');
PUT begindt=E8601DA. enddt=E8601DA.;
Run;
The data step gets the results of begindt=2021-09-01 and enddt=2021-09-30.
However, I am having trouble converting the value to a date format to use in a where claus in a PROC SQL statement later in the program. The commented out code works, but I can't get the date from data step in the correct format for the PROC SQL statement to work.
/* AND "DETAILAR"."CLEAR_DOC_POSTING_DATE" = '2021-09-01' */
AND "DETAILAR"."CLEAR_DOC_POSTING_DATE" = begindt
SAS has date and time literals that make dealing with dates and times easy. SAS dates are the number of days since Jan 1 1960, and SAS datetimes are the number of seconds since Jan 1 1960. SAS automatically converts date literals to these times for you. Some examples of date and datetime literals:
'04SEP2021'd
'04SEP2021:00:00'dt
You don't have to use these all the time*, but they make debugging way easier. In your case, you simply need to feed a date literal into proc sql. If you're connecting to SAP HANA through SAS, the SAS/ACCESS engine to SAP will handle the conversion for you.
data _null_
begindt = intnx('month', today(), 0, 'B');
enddt = intnx('month', today(), 0, 'E');
call symputx('begindt', put(begindt, date9.) );
call symputx('enddt', put(enddt, date9.) );
run;
Or, equivalently:
%let begindt = %sysfunc(intnx(month, %sysfunc(today()), 0, B), date9.);
%let enddt = %sysfunc(intnx(month, %sysfunc(today()), 0, E), date9.);
Now you have two macro variables that you can not only easily read, but SAS will convert them for you. You can view them below:
%put &begindt;
%put &enddt;
Simply add them as date literals to your where clause in proc sql and let SAS do the rest.
proc sql;
create table want as
select *
from have
where CLEAR_DOC_POSTING_DATE BETWEEN "&begindt"d AND "&enddate"d
;
quit;
There are other literals too, like time literals, hex literals and name literals for variables with spaces in them.
'10:00't - Time Literal
'32'x - Hex literal
'this is a var'n - Name literal
*proc timeseries, proc timedata, and proc tsmodel require date/datetime literals for the start and end options. But those are the only ones I know of.
If you want to generate code like '2021-09-01' then why not create a macro variable with that string in it?
In your data _null_ step use:
call symputx('begindt',quote(put(intnx('month',date(),0),yymmdd10.),"'"));
Working from the inside out that statement will:
calculate today's date
convert to the start of the month
convert to a 10 character string representing that date
add single quotes around the string
store the value into a macro variable named begindt
Now you reference the macro variable to generate the code you want
and "DETAILAR"."CLEAR_DOC_POSTING_DATE" = &begindt.
Which will generate the code:
and "DETAILAR"."CLEAR_DOC_POSTING_DATE" = '2021-09-01'
I am new to SAS and I am struggling struggling with my code. I would love some help. Am I thinking about this the right way? I have a huge table and I want to extract that data from certain dates. My two dates: 1969-12-01 and 1948-01-01 my sample code:
data null;
call symput ('timenow',put (time(),time.));
call symput ('datenow',put (date(),date9.));
run;
title "The current time is timenow and the date is datenow";
proc print data=sashelp.buy;
run;
So first learn about your dataset. So for example run PROC CONTENTS.
proc contents data=sashelp.buy; run;
Which will show you that there is variable named DATE that has date values (number of days since 1960).
So to reference a specific date use a date literal. That is a quoted string in the style that the DATE informat can read followed by the letter D. You can then use a WHERE statement to filter the data.
data want;
set sashelp.buy;
where date = '31dec1969'd ;
run;
Which will not find any observations since that date does not appear in that dataset.
If you want to select for multiple dates you could either add more conditions using OR.
where (date = '31dec1969'd) or (date = '01jan1948'd);
You can also use the IN operator:
where date in ('31dec1969'd '01jan1948'd);
Note that if your variable contains datetime values (number of seconds) then to pick a specific date you would either need to use a range of datetime literals:
where datetime between '31dec1969:00:00'dt and '31dec1969:11:59:59'dt);
Or convert the number of seconds into number of days and compare to the date literal.
where datepart(datetime) = '31dec1969'd ;
Welcome to StackOverflow Sportsguy3090.
Here I make a dataset called sample with some sample dates. That dataset has a variable called name and another variable called date. Internally, SAS stores dates as the number of days until or after January 1st 1970. That is rough to look at. So I use the format statement to have the dates appear as a 10 character string with month/day/year.
data sample;
name = "Abe "; date = "01Dec1969"d; output;
name = "Betty"; date = "01Jan1948"d; output;
name = "Carl"; date = "06Jun1960"d; output;
name = "Doug"; date = "06Dec1969"d; output;
name = "Ed"; date = "01Jan1947"d; output;
format date mmddyy10.;
run;
The code below subsets the data and puts the good records into a new dataset called keepers. It only keeps the records that are in the date range (including the limit dates).
data keepers;
set sample;
where date between "01jan1948"d and "01Dec1969"d;
run;
I hope that helps.... if not send up another flare.
I'm compiling order data using a program that has already been built, but am trying to update a section of the code to take today's date minus 61 days and plus 56 days for the respective start and end dates, rather than a manually typed in date as shown below. The current, functional code as well as one of my attempts is below.
The current format that is working and executing is:
/* Set report dates (dd-mm-yyyy) */
%let fore_start = %str(08-SEP-2019);
%let fore_end = %str(03-JAN-2020);
I'm attempting to build something like:
/* Set report dates (dd-mm-yyyy) */
%let fore_start = %str(TODAY()-61);
%let fore_end = %str(TODAY()+56);
I'm looking for help devising a syntactically sound line to solve this problem. Any help would be appreciated!
Try this:
%let fore_start = %sysfunc(putn(%eval(%sysfunc( today() ) - 61), ddmmyyd10.) );
%let fore_end = %sysfunc(putn(%eval(%sysfunc( today() ) + 56), ddmmyyd10.) );
It looks like there's a lot there, but it really isn't. Removing all of the syntax of macro language and converting it into data step functions, here's all you are doing:
fore_start = put(today() - 61, ddmmyyd10.);
fore_end = put(today() + 56, ddmmyyd10.);
There are a few things at play:
In macro language, SAS functions such as putn and today() need to both be enclosed with %sysfunc(). %sysfunc() is your connection to SAS system functions and the macro facility.
%eval will subtract two integers from each other.
putn, another SAS function, will convert the resulting SAS date into your desired format of ddmmyyd10.. putn is required for macro language instead of put.
The date representations you show as being kept in macro variables fore_start and fore_end are actually dd-mmm-yyyy, or format DATE11.
The %sysfunc marco function will invoke a DATA step function and optionally format the result. The INTNX function will perform date arithmetic.
%let fore_start = %sysfunc(intnx(DAY, %sysfunc(today()), -61), DATE11);
%let fore_end = %sysfunc(intnx(DAY, %sysfunc(today()), +56), DATE11);
Background:
I have a code that pulls transactional data starting at the beginning of the current calendar quarter, but from an year ago.
For example, if I run the code today (August 16, 2013) it will have to pull all the data from July 1, 2012 onwards.
Problem:
I want to automate the starting date for the data pull with a macro variable.
So far, I'm stuck here:
%let ThisYear = %Sysfunc(Date(), YEAR.);
%let LastYear= %eval(&ThisYear-1); /* I get the starting year */
%let QTR_start_month= %eval(3*%Sysfunc(Date(), qtr.)-2); /* this gives me the current quarter starting month. If I run it in August, it outputs 7 for July */
%let start_date=%str(01/%Sysfunc(month(&QTR_start_month))/&lcy);
The final macro variable outputs the date which I want, but in a format which is not recognized by SAS.
I will greatly appreciate any help.
Many thanks in advance!
You can either input that date to a date format, or construct it like a SAS date literal ('01JUL2013'), DDMONYY(YY), or construct it as a date value directly.
INTNX is probably your best option here to construct it; you don't need all that work.
%let start_date = %sysfunc(intnx(Quarter,%sysfunc(date()),-4),DATE9.);
%put &start_date;
You can leave DATE9. to use it as a date literal, or remove the ,DATE9. to get the numeric value that can be used directly. You would use this as "&start_Date."d to use the date literal.
This should do the job.
data test;
format todays_date starting_qtr date9.;
todays_date=today();
/*this takes today's date and rolls back 4 qtrs and sets that date to the first day of that quarter*/
starting_qtr = intnx('qtr',todays_date,-4,'b');
/*so, running this code today, 16AUG2013 would yield starting_qtr=01JUL2012 */
call symputx('start_date', put(starting_qtr, date9.));
run;
%put &start_date.;