Cin entry fails when previous calls do not - c++

Question

I have this section of code for generating an array of randomly generated and sorted ints, but the nosearch cin quits the program. Calling Cin.ignore() & cin.clear() before and/or after this line does not correct this, no error message is shown, the program just quits as soon as I hit enter on that section. This is the only statement to do this.
#include <iostream>
#include <stdlib.h>
#include <ctime>
#include "search.hpp" //a function called sarch is here, program quits before sarch is called.
using namespace std;
int main () {
srand(time(0));
int tenn;
int minrange;
int maxrange;
cout << "Enter the number of integers: ";
cin >> tenn;
cout << endl << "Enter the lower limit: ";
cin >> minrange;
cout << endl << "Enter the upper limit: ";
cin >> maxrange;
int *arr = new int(tenn*10);
for (int i = 0; i < tenn*10; i++){
*(arr+i) = (rand() % maxrange) + minrange;
}
cout << "list, unsorted: " << endl;
for (int i = 0; i < tenn*10; i++){
cout << *(arr+i) << " ";
}
cout << endl;
for (int i = 0; i < tenn*10; i++){
int low = i;
for (int j = i; j < tenn*10; j++){
if (*(arr+j) < *(arr+low)){
low = j;
}
}
int temp = *(arr+i);
*(arr+i) = *(arr+low);
*(arr+low) = temp;
}
cout << "sorted list: " << endl;
for (int i = 0; i < tenn*10; i++){
cout << *(arr+i) << " ";
}
cout << endl;
int nosearch;
cout << "Enter the number of values you wish to search for: " << endl;
//The next cin will fail
cin >> nosearch;
cout << "v";
//more code here...
I use a makefile to compile the code, and when I run it in terminal, this is what happens:
>./Needle.exe
Enter the number of integers: 2
Enter the lower limit: 0
Enter the upper limit: 10
list, unsorted:
9 4 6 2 4 5 2 9 1 4 7 8 3 4 9 4 6 7 9 9
sorted list:
1 2 2 3 4 4 4 4 4 5 6 6 7 7 8 9 9 9 9 9
Enter the number of values you wish to search for:
3
>
I can only assume something I did above triggered this error, which is why I included so much of the code.