How to select either but not both in Doctrine Collection? - doctrine-orm

Question

In a Doctrine Collection, I have identical objects, each with an integer property 'player' and another integer property called 'team'. Player could be 1,2,3... and Team can be 0,1,2,3,... and so on. 0 means 'default team'. All players belong to the default team first and foremost. A player can then become a member of other teams too. For example, player 2 can be a member of team 0, 2 and 3.
Now, I would like to get the object where Player 3 is a member of Team 2. If not, return the object where Player 3 is a member of Team 0.
How would I achieve this?

Answer 1

What about filter method ?
// get all your player 3 data
$player3Collection = Collection->filter(function(ObjectType $object) {
return ($object->getPlayer() == 3);
});
// then filter again or do other stuff ...
if ($player3Collection->filter(///filter team callback///)->isEmpty() {
throw new NoTeamException();
}
if ($player3Collection->count() == 1) {
return $player3Collection->first(); // default team
}
// etc ...

Answer 2

Found an answer using the collection's filter.
$team=2;
return $player3Collection
->filter(static function(Player $player) use ($team, $player3Collection){
if($player->team===$team){
return true;#/Got it
} elseif($player3Collection->filter(static fn(Player $p) => $p->id===$player->id && $p->team===$team)){
return false;#/A counterpart Player object with correct team exists in player3Collection, so skip it here.
} elseif($player->team===0){
return true;#/Fallback team record
}
return false;#/Exclude other teams
});