regex extract exact one string - regex

Question

I have two strings:
"John Johnson Phone Number"
"John Johnson Alternate Phone Number"
Need to extract first one, name and last name might change
I was matching first string with this regex as Name and Last name might change.
^\w+ \w+( \w+)? Phone Number$
Seems pretty easy but I've brain freeze cannot solve it for few hours.
Issue now that same regex picks up 2nd string which I do not want to be picked up.
Maybe someone could give me a hint how to match only first string and do not take strings which contains Alternate word? Thanks

Answer 1

If I understand correctly, you want to capture the whole string, and extract the words before "Phone number". You can do this with capture groups. You can name your capture groups to such that you do not have to worry about which index number the group is at (if you add/remove groups later).
The syntax is (?P<name>...).
So for your situation I put the first two \w+ into the capture group name. The returned matches is the full string matched in index 0. Indices after are the subgroups. You can use re.SubexpIndex("name") to find the correct subgroup index for the named subgroup name.
https://goplay.tools/snippet/dcwWg3FBWUd
re := regexp.MustCompile(`^(?P<name>\w+ \w+)( \w+)? Phone Number$`)
str := "John Johnson Alternate Phone Number"
index := re.SubexpIndex("name")
matches := re.FindStringSubmatch(str)
if len(matches) > 0 {
fmt.Printf("Name: %s\n", matches[index])
} else {
fmt.Println("No Match")
}
EDIT: I thought this was a golang question :facepalm:
This still works using capture groups to extract the relevant sub matches out.