Jinja Expression In Statement - django

I am wanting to include dynamic variables inside of an if statement.
{% elif request.path == "/order/**{{city}}**" %}
I have a database I can refer to, to get the city names I need out depending on the url but am having a hard time sending that info in through this if statement.
(Everything works dynamically up until this point)
Solutions?

Backtrack a bit and just make the condition in the views.py then pass a boolean in the context which saves you the trouble of this complicated notation which contains far too many special symbols to be worth the headache

In the views.py
city = City.objects.get(city_slug=city_slug)
my_city = "https://www.wesbsite.com/order/{}".format(city)
was my solution to including dynamic variables in the url
found at
How to add variable to URL?
I overcomplicated it but Blye pointed in the right direction, telling me to do so in the views.py as opposed to directly in the html file.

Related

Django: Refer to an url name in a template and passing parameter

I know you can refer to a urlname in a template so that you don't need to hardcode your url links in your templates whenever you want to change them.
For example in a template, I use:
The link
My problem is, if I want to pass a more complex parameter to be used in the url regex. In my case, I want to pass a concatenation of two strings separated by an "_". Those strings come from Python objects and I don't get how to do that. Let's say for example, those strings are the firstname and lastname of a user.
I tried:
The link
And others tricks but none worked.
Can someone help?
Simply, you don't.
You either adjust your url to have two capture groups (which would also require a slight change to the view)
url(r'(?P<first_name>\w+)_(?P<last_name>\w+)/$', view_name, name='url_name')
{% url 'urlname' user.firstname user.lastname %}
Or you just find a different url that suffices.
Please have a look at this thread. The good answer for you, assuming you're using posititionnal arguments :
The link
Assuming your url conf is like so :
url(r'^urlname/(?P<parameter>(catching regexp))$',...)

is it good approach to parse urls yourself rather than by urlpattern match groups?

Let's assume I am building a blogging app and create the following url pattern:
url(r'^(?P<category>.+?)/(?P<date>.+)$', views.post_list, name='post_list'),
Then I create multiple templates adding this everywhere:
{% url 'myapp:post_list' category date %}
But then I think hmm... I don't want date there, let it be <category> and <slug> instead.
Then I have to change corresponding {% url tags everywhere in my templates!
Wouldn't it be better to rewrite url regex like this:
url(r'^(?P<url>.+?/.+)$', views.post_list, name='post_list'),
and define some url_split() function somewhere, which would parse it in the views, add url() method or property to corresponding model and be able to use the following url tags:
{% url 'myapp:post_list' obj.url %}
and therefore never touch them in case I want to change something in my url regex/parameters etc?
Is it good design or am I missing something?
But then I think hmm... I don't want date there, let it be
and instead.
Then I have to change corresponding {% url tags everywhere in my
templates!
Why is this a problem?
Is it good design
No it is not:
The function becomes ambiguous. It is doing too many things at once.
You are replicating functionality already available in the framework.
You have now effectively creating a choke point by creating a "blanket" catch-all request method. In this method there will be a bunch of decision tree if/else clauses and such branching is prime spot for bugs.
The entire purpose of doing this is for some imagined use case that may or may not happen.
From xkcd # 974:

Database localization in Django

I am using .mo files for localization in Django.
Also, in my database, I store some translated text in different fields, such as:
name_en, name_es, name_de (they are all columns in each row).
What will be the best method to choose the correct field inside a template?
i.e.:
{{ name.some_method }} will generate the correct translation based on the current localization.
Thanks,
Meit
You should look at http://goodcode.io/articles/django-multilanguage/ Here’s a simple solution that may fit your use case and is easy to implement and understand.
You should look at Django Transmeta, it work the same way as what you've done (DB fields with language code) but it's a more complete solution. It already deal with the template stuff, etc.
You can check Model Internationalization and Django Packages for more info and ideas in this domain.
I can see two method for doing this, one in your view and the other one is in the template...
In view:
Probably you keep the user language information somewhere so,
user_lang = 'es'
obj = Somemodel.objects.get(pk=123434)
obj.local_name = getattr(obj, 'name_%s'%user_lang)
So, you keep local translation in a specific variable of the instance and in your template you can use is as:
{{obj.local_name}}
But that might be costly if you wish to pass the template a queryset instead of a single instance. For a such usege you have to evaluate that value for each object in your queryset.
In template:
That is a more complex way of solving the porblem in the template...
Define a template tag and pass object_id, and local language information and get the translated text using a similar getattr function. But in that point, if you wish to use this for more than one model, you probably have to pass a content type information for your template tag too, such as:
{% get_translation <object_id> <content_type_id> <local_language> %}
And in your template tag function, do something like:
from django.contrib.contenttypes.models import ContentType
....
cont_obj = Content_type.objects.get_for_id(<cotent_type_id>) #get the related model
obj = cont_obj.get_object_for_this_type(pk=<object_id>) # get your object
return getattr(obj, 'name_%s'%<local_language>)

is there a way to use django generic views and some smart urlpatterns for quick ordering/sorting of queries?

let's assume I have a django model like this:
class Event(CommonSettings) :
author = models.ForeignKey(User)
timestamp = models.DateTimeField(auto_now_add=True)
event_type = models.ForeignKey(Event_Type, verbose_name="Event type")
text_field = models.TextField()
flag_box = models.BooleanField()
time = models.TimeField()
date = models.DateField()
project = models.ForeignKey(Project)
now, by default, I have a view where I sort all events by time & date:
event_list = Event.objects.filter().order_by('-date', '-time')
however, maybe the user wants to sort the events by time only, or by the date, or maybe in ascending order instead of descending. I know that I can create urlpatterns that match all these cases and then pass on the these options to my view, however I feel like I'm reinventing the wheel here. the django admin site can do all of this out of the box.
So here's my question: is there a clever, easy way of getting this done in a generic way, or do I have to hard code this for my models / views / templates?
and yes, I did find solutions like this (https://gist.github.com/386835) but this means you use three different projects to achieve one thing - this seems to be a too complicated solution for such a simple thing.
EDIT1:
how do I have to change the template so that I can combine multiple filters? Right now I have
Desc
Asc
but I want to allow the user to also change number of entries that get displayed. So I have:
order by date
order by name
This works all fine, but if I click on 'order by date' and then I click on 'Asc', then my previously selected order disappears. That's not what I want. I want the user to be able to combine some options but not others.
EDIT2:
unfortunately your solution doesn't work with
from django.views.generic.list_detail import object_list
and it's
paginate_by
option.
I tried:
prev
{% trans "next" %}
but the links then just don't work (nothing happens). maybe you need to do something special with "object_list"?
I don't think it's as much work as you're making it out to be - you can use variables instead of explicitly creating separate url patterns. If you look at how the django admin handles it, they tack on request variables to the url like ?ot=asc&o=2 This corresponds to sort in ascending order in by the 2nd column. Of course, if you designing a particular page, you might as well use more readable naming. So instead of numbering the categories, i'd do ?sort=desc&order_by=date and then put a regular expression in the view to match the different possibilities. Something like:
order = re.match(r"(?:date|time|name)$", request.GET['order_by'])
if request.GET['sort'] == 'desc':
order = '-' + order
results = Event.objects.filter().order_by(order)
You could instead use the regexp as a url pattern matcher as you suggested, but it's more common to let the url itself represent which part of the site you're at (i.e. website.com/events/) and the url request variables represent how that content is being displayed (i.e. ?order_by=date&sort=desc).
Hope that helps!
EDIT: For the second part of your question, use Django's templating system (which reads variables) instead of just html. There are several ways I can think of to do this, depending on personal preference and how exactly you want the UI to function (i.e. page loads with new variables anytime the user chooses a filter, or the user chooses all filter options in a form and then submits it so the page only has to reload once, etc). In this case, you could just do:
Ascending
Descending
Name
Date
Then in the view make sure your render_to_response arguments include a dictionary that looks like: {'order': request.GET['order_by'], 'sort': request.GET['sort_by'], }
Unfortunately, (and someone please correct me if I'm wrong) I don't think there's a template tag to generate a url with request.GET parameters - the url tag {% url name_of_view order_by=name sort_by=desc %} would generate "path/to/name_of_view/name/desc/", but I don't think there's a tag to generate "path/to/name_of_view?order_by=name&sort_by=desc". It would be pretty easy to write a custom tag for this though (I wouldn't be surprised if there's already one on django-snippets or something, although I just did a quick google search and didn't find anything).

Django Generic object_list pagination. Adding instead of replacing arguments

I'm having some trouble with the django generic object_list function's pagination not really being "smart" enough to compensate my daftness.
I'm trying to do a url for listing with optional arguments for page number and category.
The url in urls.py looks like this:
url(r'^all/(?:(?P<category>[-\w]+)/page-(?P<urlpage>\d+))?/$',
views.listing,
),
The category and urlpage arguments are optional beacuse of the extra "(?: )?" around them and that works nicely.
views.listing is a wrapper function looking like this( i don't think this is where my problem occurs):
def listing(request,category="a-z",urlpage="1"):
extra_context_dict={}
if category=="a-z":
catqueryset=models.UserProfile.objects.all().order_by('user__username')
elif category=="z-a":
catqueryset=models.UserProfile.objects.all().order_by(-'user__username')
else:
extra_context_dict['error_message']='Unfortunately a sorting error occurred, content is listed in alphabetical order'
catqueryset=models.UserProfile.objects.all().order_by('user__username')
return object_list(
request,
queryset=catqueryset,
template_name='userlist.html',
page=urlpage,
paginate_by=10,
extra_context=extra_context_dict,
)
In my template userlist.html I have links looking like this (This is where I think the real problem lies):
{%if has_next%}
<a href=page-{{next}}>Next Page> ({{next}})</a>
{%else%}
Instead of replacing the page argument in my url the link adds another page argument to the url. The urls ends up looking like this "/all/a-z/page-1/page-2/
It's not really surprising that this is what happens, but not having page as an optional argument actually works and Django replaces the old page-part of the url.
I would prefer this DRYer (atleast I think so) solution, but can't seem to get it working.
Any tips how this could be solved with better urls.py or template tags would be very appreciated.
(also please excuse non-native english and on the fly translated code. Any feedback as to if this is a good or unwarranted Stack-overflow question is also gladly taken)
You're using relative URLs here - so it's not really anything to do with Django. You could replace your link with:
Next Page> ({{ next }})
and all would be well, except for the fact that you'd have a brittle link in your template, which would break as soon as you changed your urls.py, and it wouldn't work unless category happened to be a-z.
Instead, use Django's built-in url tag.
Next Page> ({{ next }})
To make that work, you'll have to pass your category into the extra_context_dict, which you create on the first line of your view code:
extra_context_dict = { 'category': category }
Is /all/a-z/page-1/page-2/ what appears in the source or where the link takes you to? My guess is that the string "page-2" is appended by the browser to the current URL. You should start with a URL with / in order to state a full path.
You should probably add the category into the extra_context and do:
next page ({{next}})
"Instead of replacing the page argument in my url the link adds another page argument to the url. The urls ends up looking like this "/all/a-z/page-1/page-2/"
that is because
'<a href=page-{{next}}>Next Page> ({{next}})</a>'
links to the page relative to the current url and the current url is already having /page-1/ in it.
i'm not sure how, not having page as an optional argument actually works and Django replaces the old page-part of the url
one thing i suggest is instead of defining relative url define absolute url
'Next Page> ({{ next }})'