Formula Parse Error Google Sheets using IF function [duplicate] - if-statement

This question already has an answer here:
I get Formula parse error with all formulas
(1 answer)
Closed 4 months ago.
I was trying to count checkboxes and I saw some tutorials for the formula
it was like this
=SUM(countif(B1:B8, TRUE))
it resulted in an error instead with "formula parse error"

try:
=SUM(COUNTIF(B1:B8; TRUE))
see: stackoverflow.com/questions/73767719/

Related

I am trying to get this Arrayformula to work [duplicate]

This question already has answers here:
Perform calculation only if both cells are not blank with arrayformula? [duplicate]
(3 answers)
ArrayFormula and "AND" Formula in Google Sheets
(4 answers)
Closed 4 months ago.
So I am trying to get this Arrayformula to work so I can plot this formula instead of calculating every Y myself.
=arrayformula(Sum(IF(Z3:Z294>Y$1;IFS(AB3:AB294>0;0;Z3:Z294>Y$1;Y3:Y294-(F3:F294*Y$1));0)-(Sum(IF(and(J3:J294>0;Z3:Z294>Y$1);F3:F294;0)))))
It gives me the (correct) return of this part:
Sum(IF(Z3:Z294>Y$1;IFS(AB3:AB294>0;0;Z3:Z294>Y$1;Y3:Y294-(F3:F294*Y$1));0)
But it doesn't subtract the second part:
-(Sum(IF(and(J3:J294>0;Z3:Z294>Y$1);F3:F294;0)))))
I am quite new to extensive Excel/Sheets formulas so I have no idea how to get this to work, It is also quite weird that the second part doesn't add up even seperate from the first part. So this also doesn't work:
=arrayformula(Sum(IF(and(J3:J294>0;Z3:Z294>Y$1);F3:F294;0)))
I hope it makes some sense without any context, thanks in advance!
Have a great rest of your day,
P.S. Please ignore simple mistakes, I don't code that often in Sheets ;)
AND is not supported. instead of
and(J3:J294>0;Z3:Z294>Y$1)
do this:
(J3:J294>0)*(Z3:Z294>Y$1)

Getting an formula parse error on a basic if statement [duplicate]

This question already has an answer here:
I get Formula parse error with all formulas
(1 answer)
Closed 4 months ago.
I am trying to use IF statement in a Google Sheet, but whatever I am typing in the IF I am always getting a formula parse error. Do I have to activate something, or am I missing something ?
A1 & B1 have the same type (integer)
I have no idea why.
Thanks in advance
instead of , use ; - this should solve your issue asap

Trying to separate the year month and day fields via RegEx [duplicate]

This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 4 years ago.
I have a series of dates that I am trying to separate into years, months and days. These dates are in the yyyy-mm-dd format. I'm not very familiar with RegEx, but I have tried (\dddd)\-(\dd)\-(\dd).
Any help is appreciated.
Accepted answer would also match invalid dates like 1234-56-78, or if mm & dd were in the wrong positions.
([1-2][0-9]{3})\-([0-1][0-9])\-([0-3][0-9])
Does a little more validation.

advanceby unaviable to advance an index by offer in swift 3 [duplicate]

This question already has answers here:
'advancedBy' in Swift is unavailable
(2 answers)
Closed 5 years ago.
My project issue in screenshort.
enter image description here
You should just do what the error says and use index(_:at:offsetBy:):
original.insert("-", at: original.index(original.startIndex, offsetBy: 14))
In Swift 3 string handling methods have been renamed a little. advanceBy turned into this offsetBy instead.

how to check the second character match in mongoDB. in sql we are using like '_a%'. how to use in mongoDB? [duplicate]

This question already has answers here:
How to query MongoDB with "like"
(45 answers)
Closed 6 years ago.
how to check the second character match in mongoDB. in sql we are using like '_a%'. how to use in mongoDB??
you should use syntax like below:-
db.users.find({"name": /.a./})
or like >> db.users.find({"name": /a/})
if you want to search for character "a"