When I generate gRPC code in my django-grpc-framework project using command:
python -m grpc_tools.protoc --proto_path=./ --python_out=./temp --grpc_python_out=./temp ./config.proto
something generates, but config_pb2 looks so empty:
# -*- coding: utf-8 -*-
# Generated by the protocol buffer compiler. DO NOT EDIT!
# source: config.proto
"""Generated protocol buffer code."""
from google.protobuf.internal import builder as _builder
from google.protobuf import descriptor as _descriptor
from google.protobuf import descriptor_pool as _descriptor_pool
from google.protobuf import symbol_database as _symbol_database
# ##protoc_insertion_point(imports)
_sym_db = _symbol_database.Default()
from google.protobuf import empty_pb2 as google_dot_protobuf_dot_empty__pb2
DESCRIPTOR = _descriptor_pool.Default().AddSerializedFile(b'\n\x0c\x63onfig.proto\x12\x0c\x63onfig_proto\x1a\x1bgoogle/protobuf/empty.proto\"u\n\rConfigMessage\x12\x0f\n\x07service\x18\x01 \x01(\t\x12\x0f\n\x07version\x18\x02 \x01(\t\x12\x0f\n\x07is_used\x18\x03 \x01(\x08\x1a\x31\n\x03Key\x12\x13\n\x0bservice_key\x18\x01 \x01(\t\x12\x15\n\rservice_value\x18\x02 \x01(\t\"\x1a\n\x18\x43onfigMessageListRequest\"*\n\x1c\x43onfigMessageRetrieveRequest\x12\n\n\x02id\x18\x01 \x01(\x05\x32\x88\x03\n\x10\x43onfigController\x12O\n\x04List\x12&.config_proto.ConfigMessageListRequest\x1a\x1b.config_proto.ConfigMessage\"\x00\x30\x01\x12\x44\n\x06\x43reate\x12\x1b.config_proto.ConfigMessage\x1a\x1b.config_proto.ConfigMessage\"\x00\x12U\n\x08Retrieve\x12*.config_proto.ConfigMessageRetrieveRequest\x1a\x1b.config_proto.ConfigMessage\"\x00\x12\x44\n\x06Update\x12\x1b.config_proto.ConfigMessage\x1a\x1b.config_proto.ConfigMessage\"\x00\x12#\n\x07\x44\x65stroy\x12\x1b.config_proto.ConfigMessage\x1a\x16.google.protobuf.Empty\"\x00\x62\x06proto3')
_builder.BuildMessageAndEnumDescriptors(DESCRIPTOR, globals())
_builder.BuildTopDescriptorsAndMessages(DESCRIPTOR, 'config_pb2', globals())
if _descriptor._USE_C_DESCRIPTORS == False:
DESCRIPTOR._options = None
_CONFIGMESSAGE._serialized_start=59
_CONFIGMESSAGE._serialized_end=176
_CONFIGMESSAGE_KEY._serialized_start=127
_CONFIGMESSAGE_KEY._serialized_end=176
_CONFIGMESSAGELISTREQUEST._serialized_start=178
_CONFIGMESSAGELISTREQUEST._serialized_end=204
_CONFIGMESSAGERETRIEVEREQUEST._serialized_start=206
_CONFIGMESSAGERETRIEVEREQUEST._serialized_end=248
_CONFIGCONTROLLER._serialized_start=251
_CONFIGCONTROLLER._serialized_end=643
# ##protoc_insertion_point(module_scope)
So when I look at config_pb2_grpc i see imports:
config__pb2.ConfigMessage
But there is no implemented ConfigMessage in config_pb2. And more then this config_pb2 has one underscore and this import has two underscores. In my mind this is rather strange.
Is it all right?
For example when i generate code in my ordinary django-rest-framework project using:
protoc -I=$SRC_DIR --python_out=$DST_DIR $SRC_DIR/data.proto
I get in data_pb2.py:
...
ConfigMessage = _reflection.GeneratedProtocolMessageType('ConfigMessage', (_message.Message,), {
...
Related
I am very new to Python and am trying to append some functionality to an existing Python program. I want to read values from a config INI file like this:
[Admin]
AD1 = 1
AD2 = 2
RSW = 3
When I execute the following code from IDLE, it works as ist should (I already was able to read in values from the file, but deleted this part for a shorter code snippet):
#!/usr/bin/python
import ConfigParser
# buildin python libs
from time import sleep
import sys
def main():
print("Test")
sleep(2)
if __name__ == '__main__':
main()
But the compiled exe quits before printing and waiting 2 seconds. If I comment out the import of ConfigParser, exe runs fine.
This is how I compile into exe:
from distutils.core import setup
import py2exe, sys
sys.argv.append('py2exe')
setup(
options = {'py2exe': {'bundle_files': 1}},
zipfile = None,
console=['Test.py'],
)
What am I doing wrong? Is there maybe another way to read in a configuration in an easy way, if ConfigParser for some reason doesnt work in a compiled exe?
Thanks in advance for your help!
I'm trying to write a simple macro with a for loop but keep getting this error about indentation. I've seen several threads about this and feel certain my indentation is fine so I'm not sure what's wrong. Here it is:
# -*- coding: mbcs -*-
# Do not delete the following import lines
from abaqus import *
from abaqusConstants import *
import __main__
def ex():
import section
#...more imports
import connectorBehavior
a = mdb.models['Model'].rootAssembly
r1 = a.referencePoints
for i in range(0,9):
print(r1(i))
And the error it returns is
IndentationError: ('unexpected indent', ('C:\\Users\\user\\abaqusMacros.py', 14, 1, '\tfor i in range(0,9):\n'))
Do I need to change the indentation? Thank you.
The script includes:
import random
from urllib import urlopen
import sys
WORD_URL = "http://learncodethehardway.org/words.txt"
WORDS = []
...
# load up the words from the website
for word in urlopen(WORD_URL).readlines():
WORDS.append(word.strip())
...
My problem occurs when I try to run the script. I get the following tracebacks:
xterm_003.jpg
I've two files.
test.py
from pyspark import SparkContext
from pyspark import SparkConf
from pyspark import SQLContext
class Connection():
conf = SparkConf()
conf.setMaster("local")
conf.setAppName("Remote_Spark_Program - Leschi Plans")
conf.set('spark.executor.instances', 1)
sc = SparkContext(conf=conf)
sqlContext = SQLContext(sc)
print ('all done.')
con = Connection()
test_test.py
from test import Connection
sparkConnect = Connection()
when I run test.py the connection is made successfully but with test_test.py it gives
raise KeyError(key)
KeyError: 'SPARK_HOME'
KEY_ERROR arises if the SPARK_HOME is not found or invalid. So it's better to add it to your bashrc and check and reload in your code. So add this at the top of your test.py
import os
import sys
import pyspark
from pyspark import SparkContext, SparkConf, SQLContext
# Create a variable for our root path
SPARK_HOME = os.environ.get('SPARK_HOME',None)
# Add the PySpark/py4j to the Python Path
sys.path.insert(0, os.path.join(SPARK_HOME, "python", "lib"))
sys.path.insert(0, os.path.join(SPARK_HOME, "python"))
pyspark_submit_args = os.environ.get("PYSPARK_SUBMIT_ARGS", "")
if not "pyspark-shell" in pyspark_submit_args: pyspark_submit_args += " pyspark-shell"
os.environ["PYSPARK_SUBMIT_ARGS"] = pyspark_submit_args
Also add this at the end of your ~/.bashrc file
COMMAND: vim ~/.bashrc if you are using any Linux based OS
# needed for Apache Spark
export SPARK_HOME="/opt/spark"
export IPYTHON="1"
export PYSPARK_PYTHON="/usr/bin/python3"
export PYSPARK_DRIVER_PYTHON="ipython3"
export PYSPARK_DRIVER_PYTHON_OPTS="notebook"
export PYTHONPATH="$SPARK_HOME/python/:$PYTHONPATH"
export PYTHONPATH="$SPARK_HOME/python/lib/py4j-0.9-src.zip:$PYTHONPATH"
export PYSPARK_SUBMIT_ARGS="--master local[2] pyspark-shell"
export CLASSPATH="$CLASSPATH:/opt/spark/lib/spark-assembly-1.6.1-hadoop2.6.0.jar
Note:
In the above bashrc code, I have given my SPARK_HOME value as /opt/spark you can give the location where you keep your spark folder(the downloaded one from the website).
Also I'm using python3 you can change it to python in the bashrc if you are using python 2.+ versions
I was using Ipython, for easy testing during runtime, like load the data once and test your code many times. If you are using plain old text editor, let me know I will update the bashrc accordingly.
I can't make output in Russian language only output of Unicode=(
I use Pythonv.2.7.9
Microsoft 8
How I can do that with list?
#! /usr/bin/env python
# -*- coding: utf-8 -*-
import requests
from bs4 import BeautifulSoup
r = requests.get("http://fs.to/video/films/group/film_genre/")
response = r.content.decode('utf-8')
page = BeautifulSoup(response)
for tag in page.findAll('li'):
a = tag.find('a')
for b in a.contents:
print (u'{0}'.format(u'○'),unicode(b.string))
Example of output must be like:
Аниме
Биография
...
Фэнтези
Эротика
Change the last line to:
print (u'{0}'.format(u'○'),b.string