std::stof() rounds numbers, how to avoid - c++

Question

Im trying to get a float value from a file.txt into a string. When I output that value with std::stof(str) it gets rounded. Example, in the text file there's "101471.71", whet i use the std::stof(str) it returns "101472", how to I avoid this?
Here's a part of that code (some parts are in spanish, sorry :p):
double CaptureLine(std::string filepath, int fileline, int linesize)
{
std::fstream file;
std::string n_str, num_n;
int current_line = 0, n_size, filesize = FileSize(filepath);
char ch_n;
double n_float = 0.0;
int n_line = filesize - fileline;
file.open("registros.txt");
if (file.is_open()) {
while (!file.eof()) {
current_line++;
std::getline(file, n_str);
if (current_line == n_line) break;
}
if (current_line < n_line) {
std::cout << "Error" << std::endl;
return 1;
}
file.close();
}
n_size = n_str.length();
for (int i = linesize; i < n_size; i++) {
ch_n = n_str.at(i);
num_n.push_back(ch_n);
}
std::cout << ">>" << num_n << "<<\n";
n_float = std::stof(num_n); //Here's the error
return n_float;
}

Answer 1

The issue probably isn't with std::stof, but is probably with the default precision of 6 in std::cout. You can use std::setprecision to increase that precision and capture all of your digits.
Here's a program that demonstrates:
#include <iostream>
#include <iomanip>
#include <string>
int main() {
std::cout << 101471.71f << "\n";
std::cout << std::stof("101471.71") << "\n";
std::cout << std::setprecision(8) << 101471.71f << "\n";
std::cout << std::stof("101471.71") << "\n";
return 0;
}
Outputs:
101472
101472
101471.71
101471.71
Be aware that std::setprecision sticks to the std::cout stream after it's called. Notice how the above example calls it exactly once but its effect sticks around.