In a Google Sheet with a cell range of 26x26 (so A1:Z26), I need to conditionally format (change the color to green) a rectangle area that is defined by user input.
Example of user input (4 values required):
hsize = 5 / vsize = 4 / starth = 3 / startv = 2
This means that the conditionally formatted area should be a rectangle from C2:G5 because the start cell horizontally is 3 (column C) and vertically 2 (row 2), and the size of the rectangle horizontally is 5 (C,D,E,F,G) and vertically 4 (2,3,4,5).
I already solved this with Apps Script but due to given restrictions I have to implement this without using any scripts.
I have numbered the whole 26x26 area (=sequence(26,26)) to get numbers from 1 to 676 that I could then use for the conditional formatting.
By doing this, I can limit the conditional formatting to the values between the start and the end value (in the example above that would be 29 (C2) and 111 (G5)). This works by using a simple and/if formula in the conditional formatting.
But the problem with this is that all the cells with values from 29 to 111 are now colored, not only the rectangle C2:G5.
I can't figure out how to define a formula that does what I need. How can I do this and limit the highlighted area to the defined cell range of the rectangle?
[Picture here]: green is the conditional formatting from 29 (C2) to 111 (G5), but what I actually need is that only the red-framed area should be shown in green.
try:
=REGEXMATCH(""&A1, "^"&TEXTJOIN("$|^", 1, INDIRECT(
ADDRESS($AB$4, $AB$3)&":"&ADDRESS($AB$2+$AB$4-1, $AB$1+$AB$3-1)))&"$")
or better:
=(COLUMN(A1)>=$AB$3) *(ROW(A1)>=$AB$4)*
(COLUMN(A1)<$AB$1+$AB$3)*(ROW(A1)<$AB$2+$AB$4)
Related
I have this Google sheet, using sparklines to graph a change over time. I want a horizontal line at 2 different points, which cannot be done with a sparkline. So as a workaround, I have 3 different sparklines covering the same data but with different mins and maxes so I can draw a border between them.
But there are 6 parts (encircled in red) where lines are showing on the sparkline where they should not be.
What am I doing wrong?
https://docs.google.com/spreadsheets/d/1paFqu2hWAlpnzc3Ba0uo2kBfy9Inf2X6iWjQTzr_6XE/edit?usp=sharing
those are SPARKLINE glitches caused by ymax when the dataset contains the same consecutive values in the array (rows 10 & 11, 12 & 13 and 23 & 24) which are out of bound limited by ymax parameter.
an easy fix would be to slightly alter/manipulate duplicates before they hit the SPARKLINE output:
E17 cell:
=ARRAYFORMULA(SPARKLINE({A$3:A,
IF(COUNTIF(B$3:B, B$3:B)>1, B$3:B+(ROW(B$3:B)*0.0000000001), B$3:B)},
{"Ymin", 280; "Ymax", 285}))
E19 cell:
=ARRAYFORMULA(SPARKLINE({A$3:A,
IF(COUNTIF(B$3:B, B$3:B)>1, B$3:B+(ROW(B$3:B)*0.0000000001), B$3:B)},
{"Ymin", 275; "Ymax", 280}))
Hey there I am using Opencv3.3 and Pyhton2.7 for recognizing a Maze in an image.
I have to find the outermost limit of the Maze in the image.
I tried closing the entrance and exit gaps of the maze and finding the outermost shape. I worked on this for closing the gaps but it is useless for my problem because I need these gaps to solve the maze.
This is the original image
I want to find outermost limit of the maze.
This is what I want
How can I extract outermost contour?
I would do this with numpy rather than OpenCV, but the two are compatible so you can mix and match anyway, or you can adapt the technique to OpenCV once you get the idea of how I am tackling it.
The strategy is to sum all the pixels across every row and make a single pixel wide image (shown on the right below) that is the sum of all the pixels in each row. I then find the biggest value in that column and divide by that to normalise everything to the range 0..100. Now any pixel that is less than 30 in that single pixel wide image means that the corresponding row had less than 30% of white pixels in the original image - i.e. it was largely black.
Then I make the same summation of all the columns to produce the column sums - shown across the bottom of the image below:
I think some folks refer to this technique as a "projection" if you want to Google it.
So, the code looks like this:
#!/usr/local/bin/python3
import numpy as np
from PIL import Image
# Load image - you can use OpenCV "imread()" just the same and convert to grayscale
im = np.array(Image.open('maze.jpg').convert('L'))
# Get height and width
h,w = im.shape[0:2]
# Make a single pixel wide column, same height as image to store row sums in
rowsums=np.empty((h))
# Sum all pixels in each row
np.sum(im,axis=1,out=rowsums)
# Normalize to range 0..100, if rowsum[i] < 30 that means fewer than 30% of the pixels in row i are white
rowsums /= np.max(rowsums)/100
# Find first and last row that is largely black
first = last = -1
for r in range(h):
if first < 0 and rowsums[r] < 30:
first = r
if rowsums[r] < 30:
last = r
print(first,last)
# Make a single pixel tall row, same width as image to store col sums in
colsums=np.empty((w))
# Sum all pixels in each col
np.sum(im,axis=0,out=colsums)
# Normalize to range 0..100, if colsum[i] < 30 that means fewer than 30% of the pixels in col i are white
colsums /= np.max(colsums)/100
# Find first and last col that is largely black
first = last = -1
for c in range(w):
if first < 0 and colsums[c] < 30:
first = c
if colsums[c] < 30:
last = c
print(first,last)
That outputs:
62 890
36 1509
So the top row of the maze is row 62, and the bottom one is row 890. The left column of the maze is column 36 and the rightmost column is col 1509.
If I draw on an 80% transparent red rectangle to match those locations, I get:
I am trying to learn creating GUI using Tkinter .I created a window which includes text,Messagebox,Entry widget,labels and Radio buttons.
I used grid method for frames and tried to make entry boxes in row0 and row1 .And a message Box with Some text.But these are not properly aligned even though i gave correct rows and columns but output is not in order.
Entry box is created very far though i mentioned column1 .And message box is created as per the column specified.Can anyone help me how to solve this.If i am missing anything please let me now .
from Tkinter import*
import tkMessageBox
class Example:
def __init__(self,root):
root.title("Sample")
#Entry functions ---------------------------------------
Label(root, text="First Name").grid(row=0)
Label(root, text="Last Name").grid(row=1)
self.e1 = Entry(root)
self.e1.bind("<Return>",self.ShowChoice_radio)
self.e2 = Entry(root)
self.e2.bind("<Return>",self.ShowChoice_radio)
self.e1.grid(row=0,column=1)
self.e2.grid(row =1,column = 1)
#------------------------------------------------------------------------
self.frame=Frame(root)
self.frame.grid(row=3,sticky=W)
self.label=Label(self.frame, text="mine", width=12,bg="green",fg="white",justify=LEFT)
self.label.grid(row=3,column=4,sticky=W,pady=4)
root.minsize(width=666, height=220)
self.v=IntVar()
role=[("ENGLISH",1),("SPANISH",2),("GERMAN",3)]
Label(self.frame,text="Choose your role of target:",justify=LEFT,padx=2,pady=2).grid(row=4,sticky=W)
i=0
for txt,val in role:
i=i+1
self.rad_bt=Radiobutton(self.frame,text=txt,padx=20,variable=self.v,
command=self.ShowChoice_radio,value=val)
self.rad_bt.grid(row=4,column=i+1)
self.bottomframe = Frame(root)
self.bottomframe.grid(row=12,sticky=W)
self.hello(12)
T=Text(self.bottomframe,height=2,width=30)
T.pack(padx=100,side=TOP)
T.insert(END,"just a normal text to display!\n")
self.mbutton=Button(self.bottomframe,text='Quit',command=self.callback,state='normal')
self.mbutton.pack(padx=3,pady=3,side='left')
self.help=Button(self.bottomframe,text='Help',command=self.help_msg,width=5,justify=CENTER)
self.help.pack(padx=93,pady=3,side='left')
def ShowChoice_radio(self):
print self.v.get()
def help_msg(self):
tkMessageBox.showinfo("Help to print ",message="Not yet implemented")
root.minsize(width=666, height=666)
self.show_entry_fields()
self.help.config(state=DISABLED)
def callback(self):
if tkMessageBox.askyesno('verify','Really Quit?'):
root.destroy()
def hello(self,name):
w=Label(root,text="Hello Tkinter!",width=15).grid(row=10)
whatever_you_do = "Whatever . it is my test that \n i can anble to display manner in this case find out whether it is correct one or wrong \n)"
msg=Message(root, anchor='s',width=200,text = whatever_you_do)
msg.config(bg='lightgreen', font=('times', 14, 'italic'))
msg.grid(row=10,column=1,sticky=W)
def show_entry_fields(self):
print "First Name: %s\nLast Name: %s" % (self.e1.get(), self.e2.get())
if __name__=="__main__":
root=Tk()
app=Example(root)
root.mainloop()
Even the quit and Help buttons are not proper...!!!
I initially voted to close this because there is not a clear question, but mostly only a series of statements and opinions, at least one of which is incorrect. After looking more, I think I can answer your implied question "Why is tkinter behaving in a way that seems wrong to me?". The answer, I believe, is that you do not understand that grid coordinates are independent (start over) for each container gridded. Also, coordinates not used are ignored. In particular:
Root has a grid of 5 rows and 2 columns. Renumbering the rows 0, 1, 2, 3, 4 instead of the confusing labeling you used, there is no entry in column 1 for rows 2 and 4. The width of column 0 is determined by the width of self.frame in row 2, column 0. The entry boxes are far to the right because column 0 is very wide.
Self.frame has a grid of 2 rows and 4 columns. The first 3 columns of row 0 are empty. Self.bottomframe is packed instead of gridded. The buttons are to the left of where you want because you packed them to the left. In other words, tkinter did just what you said, which is apparently not what you want.
You might list the result better if you got rid of self.frame, put 'mine' in (2,0) or (2,0), 'Choose...' in (3, 0), and a frame with 3 radio buttoms in (3,1). Then root column 0 would not be so overly wide.
I'm using GetTextExtentPoint32W to get width of a text in a cell in MS Excel 2010. The cell width is fetched using ActiveCell.Width. These two widths are then compared to determine whether the text fits in the cell or extends out of the cell.
Visually, even though the text fits perfectly in the cell, the text width returned by the method is more than the cell width. Also, when I increase the font size the difference between actual text width and that returned by the method increases.
Following is a part of the source code used to achieve the result. Please help me solve this error.
hDC = ctypes.windll.user32.GetDC(self.windowHandle)
tempBMP = ctypes.windll.gdi32.CreateCompatibleBitmap(hDC, 1, 1)
hBMP = ctypes.windll.gdi32.SelectObject(hDC, tempBMP)
iFontSize = self.excelCellObject.Font.Size
deviceCaps = ctypes.windll.gdi32.GetDeviceCaps(hDC, 90)
iFontSize = int(iFontSize)
iFontSize = ctypes.c_int(iFontSize)
iFontSize = ctypes.windll.kernel32.MulDiv(iFontSize, deviceCaps, 72)
iFontSize = iFontSize * -1
iFontWeight = 700 if self.excelCellObject.Font.Bold else 400
sFontName = self.excelCellObject.Font.Name
sFontItalic = self.excelCellObject.Font.Italic
sFontUnderline = True if self.excelCellObject.Font.Underline else False
sFontStrikeThrough = self.excelCellObject.Font.Strikethrough
#Create a font object with the correct size, weight and style
hFont = ctypes.windll.gdi32.CreateFontW(iFontSize,
0, 0, 0,
iFontWeight,
sFontItalic,
sFontUnderline,
sFontStrikeThrough,
False, False, False,
False, False,
sFontName)
#Load the font into the device context, storing the original font object
hOldFont = ctypes.windll.gdi32.SelectObject(hDC, hFont)
sText = self.excelCellObject.Text
log.io("\nText \t"+sText+"\n")
textLength = len(sText)
class structText(ctypes.Structure):
_fields_ = [("width", ctypes.c_int),
("height",ctypes.c_int)]
StructText = structText()
getTextExtentPoint = ctypes.windll.gdi32.GetTextExtentPoint32W
getTextExtentPoint.argtypes = [ctypes.c_void_p,
ctypes.c_char_p,
ctypes.c_int,
ctypes.POINTER(structText)]
getTextExtentPoint.restype = ctypes.c_int
#Get the text dimensions
a = ctypes.windll.gdi32.GetTextExtentPoint32W(hDC,
sText,
textLength,
ctypes.byref(StructText))
#Delete the font object we created
a = ctypes.windll.gdi32.DeleteObject(hFont)
a = ctypes.windll.gdi32.DeleteObject(tempBMP)
#Release the device context
a = ctypes.windll.user32.ReleaseDC(self.windowHandle, hDC)
textWidth = StructText.width
cellWidth = self.excelCellObject.Width
Thanks.
I do not use Python or Excel 2010 so cannot comment on your current approach. However, I have struggled with a similar problem. I hope the following points will be helpful.
Background
If you hover over the right boundary of an Excel column and hold the left mouse button you will get a display of the format: “Width: n.nn (mm pixels)”.
The help for the ColumnWidth property says:
One unit of column width is equal to the width of one character in the
Normal style. For proportional fonts, the width of the character 0
(zero) is used.
Use the Width property to return the width of a column in points.
As far as I can tell, “Normal style” means the standard font name and size at the time the workbook was created. Changing the standard font name and size for an existing workbook does not appear to have any effect. Changing the font name and size for a worksheet has no effect.
Two example displays for a standard width column are:
For Arial 10 Width: 8.43 (64 pixels)
For Tahoma 10.5 Width: 8.38 (72 pixels)
I have created a string of zeros and attempted to measure how many are visible depending on the width of the column. I found the number of zeroes that I could see matched the value displayed reasonably well for such as subjective measure.
With VBA, the ColumnWidth property of a column or cell sets or returns the width in characters.
With VBA, The read only Width property of a column or cell returns .75 * the width in pixels.
The significance of the above information is that the width values obtained from Excel are not necessarily correct for the font being used.
My problem and the solution I discovered
The problem I had was that I was merging cells and filling them with text. Although Excel will adjust the height of a row so the text within an unmerged cell is visible, it will not do so for a merged cell. I tried many techniques including Microsoft’s .Net, text rendering routines without success. Nothing I tried would reliably emulate Excel’s system for determining the width of text.
The technique I eventually used successfully involved picking a cell to the right and below all used cells for experimental use. I adjusted the width of the experimental cell’s column to match the combined width of the merged cell and copied the formatted value from the cell whose height I wanted. Because the experimental cell was unmerged, Excel would adjust the height as appropriate. I then made sure the source row was at least this height.
The key feature of this technique was that I was not trying to emulate Excel’s system for determining the width of text; I was using Excel’s system.
You would need to try different column widths for the experimental cell. I would start with the current width of the source column. If the row height matches that for a single row, the width of the source column is already sufficient. If the row height is more than that for a single row, I would increase the column width until the row height matched that for a single row and then adjust the source column’s width to match. If you start with the widest value (in characters or Python’s text width) you will probably get the source column width correct at the first attempt which would avoid the need for later adjustments.
I'm encountering this problem and would like to seek your help.
The context:
I'm having a bag of balls, each of which has an age (red and blue) and color attributes.
What I want is to get the top 10 "youngest" balls and there are at most 3 blue balls (this means if there are more than 3 blue balls in the list of 10 youngest balls, then replace the "redudant" oldest blue balls with the youngest red balls)
To get top 10:
sel_balls = Ball.objects.all().sort('age')[:10]
Now, to also satisfy the conditions "at most 3 blue balls", I need to process further:
Iterate through sel_balls and count the number of blue balls (= B)
If B <= 3: do nothing
Else: get additional B - 3 red balls to replace the oldest (B - 3) blue balls (and these red balls must not have appeared in the original 10 balls already taken out). I figure I can do this by getting the oldest age value among the list of red balls and do another query like:
add_reds = Ball.objects.filter(age >= oldest_sel_age)[: B - 3]
My question is:
Is there any way that I can satisfy the constraints in only one query?
If I have to do 2 queries, is there any faster ways than the one method I mentioned above?
Thanks all.
Use Q for complex queries to the database: https://docs.djangoproject.com/en/dev/topics/db/queries/#complex-lookups-with-q-objects
You should use annotate to do it.
See documentation.
.filter() before .annotate() gives 'WHERE'
.filter() after .annotate() gives 'HAVING' (this is what you need)