For Matomo outgoing link tracking I need the regex pattern, which matched the following URLs:
https://www.example.com/product/?sku=12345&utm_source=123456789
and
https://www.example.com/product/?utm_source=123456789
"https://www.example.com/" and "utm_source=123456789" are always fixed in the URL, just "product/" or "category/product/" change and must replaced by regex pattern.
Thanks
Maybe this example can help you reach your goal:
(?<=https:\/\/www\.example\.com\/).+(?=utm_source=123456789)
It looks for any characters between these two groups:
https://www.example.com/
utm_source=123456789
Given the examples:
https://www.example.com/product/?sku=12345&utm_source=123456789
https://www.example.com/product/?utm_source=123456789
Your matches would be:
product/?sku=12345&
product/?
Related
In google analytics, I have created the following include filter:
^https:\/\/(my\..*|accounts\..*|maya\..*\/reports\/(mymessages|favorites)|maya\..*\/account\/notification|info\..*\/(heb|eng)\/management\/generalpages\/pages\/(personalfolder|registration|change_password|userssearchindex|security%20search)\.aspx).*
In order to include only URLs that contains the following addresses:
https://my.tase.co.il
https://accounts.tase.co.il
https://maya.tase.co.il/reports/mymessages
https://maya.tase.co.il/reports/favorites
https://maya.tase.co.il/account/notification
https://info.tase.co.ilManagement/GeneralPages/Pages/PersonalFolder.aspx
https://info.tase.co.ilManagement/GeneralPages/Pages/Registration.aspx
https://info.tase.co.ilManagement/GeneralPages/Pages/Change_Password.aspx
https://info.tase.co.ilManagement/GeneralPages/Pages/UsersSearchIndex.aspx
https://info.tase.co.ilManagement/GeneralPages/Pages/Security%20Search.aspx
But for some reason i cant get it to work.
What am I doing wrong?
Thanks for your help!
The pattern does not match the links that start with info. because the pattern specifies info\..*\/(heb|eng) and in the example data there is no heb or eng present.
You can either remove that part or use a pattern that exactlty matches starting with those urls:
https:\/\/(?:(?:accounts|my)\.tase\.co\.il|maya\.tase\.co\.il\/(?:reports\/(?:mymessages|favorites)|account\/notification)|info\.tase\.co\.il\/Management\/GeneralPages\/Pages\/(?:PersonalFolder|Registration|Change_Password|UsersSearchIndex|Security%20Search)\.aspx).*
See a Regex demo.
I need to fix my url pattern:
/^((http(s)?(\:\/\/)){1}(www\.)?([\w\-\.\/])*(\.[a-zA-Z]{2,4}\/?)[^\\\/#?])[^\s\b\n|]*[^\.,;:\?\!\#\^\$ -]/
I thought this regex was ok, but it is not working for urls like: https://xx.xx (without www). 'www' should be optional ((www.)?). Where is the bug?
The problem is not in the (www\.)? part but that parts after that.
Take a look at the [^\\\/#?] and the [^\.,;:\?\!\#\^\$ -] parts.
So a valid URL would be https://xx.xx plus none of \/#? plus none of .,;:?!#^$_- making the url valid if you add those, for example https://xx.xx11.
I do advice you to not try to create your own regex because you are missing a lot!
For example, tlds like .amsterdam are valid. And why are you capturing so many groups?
Your regex as an image made with https://www.debuggex.com/:
this is a regex of a proxy, if I add this to my proxy:
(.*\.|)(abc|google)\.(org|net)
my proxy will not transmit the abc.org, abc.net, google.org, google.net's traffic.
how can I write a regex opposite to this regex? I mean only transmit the abc.org, abc.net, google.org, google.net's traffic.
EDIT-01
My thought is just want to transmit abc.org or www.abc.org, how can I do with that?
Try this:
^(?!(www\.)?(?:abc|google)\.(?:net|org)).*
Demo: https://regex101.com/r/WOnFx8/3/
I used ?! to reverse the matching of your regex. This way, it will match any domain except these specific 4 domains.
Another way to do it is by using this code to include anything before the desired domains:
^(?!(.*\.|)(?:abc|google)\.(?:net|org)).*
demo: https://regex101.com/r/WOnFx8/4/
Your regex you write
(.*\.|)(abc|google)\.(org|net)
mean any string is one of abc.org, gooogle.org, abc.net, google.net, with optional prefix string ends with dot (.)
Like: test.google.org, sub.abc.net,...
I think you want to match string like test.yahoo.com, but not test.google.org. If you can use negative look ahead, this is the answer:
^(.*\.|)(?!(abc|google)\.(org|net))\w+\.\w+$
Explain:
^ and $ to be sure your match is entire url string
Negative look ahead is to check the url is not something like abc.org, abc.net, google.org, google.net
And \w+\.\w+ to check the remain string is kind of URL type (something likes yahoo.com, etc...)
Im going to assume you have lookaheads, if so then you can simply use -
(^.*?\.(?!(abc|google))\w+\.(?:org|net)$)
Demo - https://regex101.com/r/5eC41R/3
What this does is -
Looks for the start of the url (till the first .)
Checks that next part is not abc or google
looks for the next section (till the next .)
Looks for a closing org or net
Note that since it is a lookahead it will be slow compared to other regex matches
I hope someone can help, this is driving me crazy!
I am attempting to modify Logstash Grok filters to parse a domain name.
Currently the regex is:
\b(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(\.?|\b) and correctly separates the domain however, I need to add an additional check to remove www..
This is what I have come up with so far:
\b(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(^(?<!www$).*$?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(\.?|\b)
I can only seem to keep the www. part of the domain, and not the domain itself.
Example of what I need to achieve:
www.stackoverflow.com should be stackoverflow.com.
I need to remove specifically www. and not the entire subdomain.
Thank you in advance!
UPDATE
Example inputs to expected outputs (using this post as an example):
In it's current state:
https://stackoverflow.com/questions/37070358/ returns www.stackoverflow.com
What I need is for it to return stackoverflow.com
You can add a (?!www\.) and (?!http:\/\/www\.) negative lookaheads right after the first \b to exclude matching www. or http://www.:
\b(?!www\.)(?!http:\/\/www\.)(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(?:\.?|\b)
^^^^^^^^^^^^^^^^^^^^^^^^^^^
See the regex demo
You may add more negative lookaheads to exclude https:// or ftp/ftps links.
ALTERNATIVE:
\b(?!(?:https?|ftps?):\/\/)(?!www\.)(?:[0-9A-Za-z][0-9A-Za-z-]{0,62})(?:\.(?:[0-9A-Za-z][0-9A-Za-z-]{0,62}))*(?:\.?|\b)
See this regex demo
The (?!(?:https?|ftps?):\/\/) and (?!www\.) lookaheads will just let you skip the protocol and www parts of the URLs.
This will match the part after www if the url starts with www.
(?!www\.)\b(?:(?!-)[0-9A-Za-z]{1,63})(?:\.(?:(?!-)[0-9A-Za-z-]{1,63}))*(\.?|\b)
I simplified the rest of your regex too by using a negative look ahead for - in the subdomains.
I'm basically not in the clue about regex but I need a regex statement that will recognise anything after the / in a URL.
Basically, i'm developing a site for someone and a page's URL (Local URL of Course) is say (http://)localhost/sweettemptations/available-sweets. This page is filled with custom post types (It's a WordPress site) which have the URL of (http://)localhost/sweettemptations/sweets/sweet-name.
What I want to do is redirect the URL (http://)localhost/sweettemptations/sweets back to (http://)localhost/sweettemptations/available-sweets which is easy to do, but I also need to redirect any type of sweet back to (http://)localhost/sweettemptations/available-sweets. So say I need to redirect (http://)localhost/sweettemptations/sweets/* back to (http://)localhost/sweettemptations/available-sweets.
If anyone could help by telling me how to write a proper regex statement to match everything after sweets/ in the URL, it would be hugely appreciated.
To do what you ask you need to use groups. In regular expression groups allow you to isolate parts of the whole match.
for example:
input string of: aaaaaaaabbbbcccc
regex: a*(b*)
The parenthesis mark a group in this case it will be group 1 since it is the first in the pattern.
Note: group 0 is implicit and is the complete match.
So the matches in my above case will be:
group 0: aaaaaaaabbbb
group 1: bbbb
In order to achieve what you want with the sweets pattern above, you just need to put a group around the end.
possible solution: /sweets/(.*)
the more precise you are with the pattern before the group the less likely you will have a possible false positive.
If what you really want is to match anything after the last / you can take another approach:
possible other solution: /([^/]*)
The pattern above will find a / with a string of characters that are NOT another / and keep it in group 1. Issue here is that you could match things that do not have sweets in the URL.
Note if you do not mind the / at the beginning then just remove the ( and ) and you do not have to worry about groups.
I like to use http://regexpal.com/ to test my regex.. It will mark in different colors the different matches.
Hope this helps.
I may have misunderstood you requirement in my original post.
if you just want to change any string that matches
(http://)localhost/sweettemptations/sweets/*
into the other one you provided (without adding the part match by your * at the end) I would use a regular expression to match the pattern in the URL but them just blind replace the whole string with the desired one:
(http://)localhost/sweettemptations/available-sweets
So if you want the URL:
http://localhost/sweettemptations/sweets/somethingmore.html
to turn into:
http://localhost/sweettemptations/available-sweets
and not into:
localhost/sweettemptations/available-sweets/somethingmore.html
Then the solution is simpler, no groups required :).
when doing this I would make sure you do not match the "localhost" part. Also I am assuming the (http://) really means an optional http:// in front as (http://) is not a valid protocol prefix.
so if that is what you want then this should match the pattern:
(http://)?[^/]+/sweettemptations/sweets/.*
This regular expression will match the http:// part optionally with a host (be it localhost, an IP or the host name). You could omit the .* at the end if you want.
If that pattern matches just replace the whole URL with the one you want to redirect to.
use this regular expression (?<=://).+