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I'm making a right click menu in my application. And I want to check whether the menu is shown or not. But I read the Microsoft docs of CMenu and found that there is no way to make it. How to get the menu state, and is there any way to get the menu disappear event?
The system sends a WM_ENTERMENULOOP message to a menu's owner window whenever a menu is about to be shown, and a WM_EXITMENULOOP message after it has been dismissed.
Those messages map to the CWnd::OnEnterMenuLoop and CWnd::OnExitMenuLoop message handlers that your code can override to keep track of the menu state. The bIsTrackPopupMenu argument is set to TRUE for a popup menu.
Related
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notificationHi,,,
On successful creation of a record in ORacle APEX form, a green coloured notification appears. Is there anyway to close that notification automatically after 10-20 seconds? sample pic below.
Go to the Global page(page 0)
Set a dynamic action, on page load
Set it to execute Javascript:
apex.message.setThemeHooks({
beforeShow: function(pMsgType, pElement$){
if (pMsgType=='success'){
setTimeout(function() {
$('.t-Alert').fadeOut('slow');
}, 5000);
}
}
});
I have it set to 5 sec, the 5000 in the code, but you can have it whatever you want.
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Recently I made a program by Qt(c++) to get screen resolution and show it by moving mouse. Currently, it works well but just on the MainWindow form;
How can I make it work when I move mouse on desktop also?
I Really appreciate you if you answer.;)
If you want to get mouse input outside of the widget then you have to call QWidget::grabMouse() and later QWidget::releaseMouse() when done. Bear in mind that it may not work on some operating systems or it may stop working when your widget (MainWindow on your case) loses focus. Also it may work worse with next update of operating system. That is because operating system vendors do not like spyware that spies mouse clicks or malware that locks whole desktop.
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I would like to bring your attention regarding a detail which might be ridiculous for advanced people in Qt" but not for newbies as me.
I would like to connect a pushButton to a signal/slot while the user didn't press on a specified pushButton B:
What I want to do is:
do
{
QObject::connect(pushButton_image, SIGNAL(clicked()), this, SLOT(image()))
}
while (// THE USER DIDN'T PRESS THE PUSHBUTTON B ...)
As soon as the user press the PUSHBUTTON B, I want to disconnect pushButton_image with its previous signal / slot.
Thanks!
Connect it once, out of that while.
That's wrong because:
You can connect a slot to a signal multiple times. But it will be called s many times as you connected it.
You won't get out of that while loop.
A slot is connected as long as it gets disconnected. Being connected Its more like an state that an active task.
To disconnect you use
QObject::disconnect
In slot call
QObject::disconnect(pushButton_image, SIGNAL(clicked()), this, SLOT(image()))
Done
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#include "MessageBoxThread.h"
MessageBoxThread::MessageBoxThread(NfcUIConfirmProcessUC* dialogUC)
{
this->dialogUC = dialogUC;
}
MessageBoxThread::~MessageBoxThread(void)
{
}
void* MessageBoxThread::Entry()
{
this->dialogUC->Show(true);
return 0;
}
To quote from the wxThread docs:
GUI calls, such as those to a wxWindow or wxBitmap are explicitly not safe at all in secondary threads and could end your application prematurely. This is due to several reasons, including the underlying native API and the fact that wxThread does not run a GUI event loop similar to other APIs as MFC. [...] the recommended way is to simply process the GUI calls in the main thread through an event that is posted by wxQueueEvent()
So basically the best way to solve this problem is rather than calling Show to create an event (for example a wxThreadEvent) post it back to the dialog and then using an event macro or bind connect it to a dialog member which shows the dialog.
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I mean it hides automatically, but I can still see it as a white line in the bottom which is annoying in fullscreen mode. Is there any way to completely remove it from the screen? I still can reach it with ctrl + home, so I don't need it to popup on mouse hover
Open the command prompt, navigate to the folder where vboxmanage is and execute the code below.
VBoxManage setextradata global GUI/Customizations noMenuBar,noStatusBar
You don't have to fool with VBoxManage if you'd rather use CLI. If you launch your VM with the VBoxSDL command, then the VM is displayed in a simple window without any pretty icons.
VBoxSDL --startvm
Reference:
http://www.virtualbox.org/manual/ch09.html#vboxsdl