How can I use regex in notepad++ to make a query like this:
I have a list with subdomains containing three words such as
web1.com
test.web2.com
www.test.web3.com
I want to filter so that only three words remain and something like this comes out:
web1.com
test.web2.com
test.web3.com
I was able to delete so that only the domain remains, but this is not what I want
^(?:.+\.)?([^.\r\n]+\.[^.\r\n]+)$
An idea to match until the endpart starts and capture that.
^.*?\.([\w-]+\.[\w-]+\.[\w-]+)$
Replace with $1 (what was captured by the first group)
.*? matches lazily any amount of any characters (besides newline)
[\w-]+ char-class matches one or more word characters and hyphen
See this demo at regex101 (more explanation on the right side)
In Notepad++ be sure to have unchecked: [ ] dot matches newline
Another take at it using a positive lookahead to assert the 3 "words" to the right, allowing for non whitespace chars excluding a dot using [^\s.]
In the replacement use an empty string.
^\S+?\.(?=[^\s.]+\.[^\s.]+\.[^\s.]+$)
See a regex demo.
Related
For example, I have these strings
APPLEJUCE1A
APPLETREE2B
APPLECAKE3C
APPLETEA1B
APPLEWINE3B
APPLEWINE1C
I want all of these strings except those that have TEA or WINE1C in them.
APPLEJUCE1A
APPLETREE2B
APPLECAKE3C
APPLEWINE3B
I've already tried the following, but it didn't work:
^APPLE(?!.*(?:TEA|WINE1C)).*$
Any help is appreciated as I'm also kinda new to this.
If you indeed have mutliple strings as you claim, there's no need to jam all that in one regex pattern.
/^APPLE/ && !/TEA|WINE1C/
If you have a single string, the best approach is probably to splice it into lines (split /\n/), but you could also use a single regex match too
/^APPLE(?!.*TEA|WINE1C).*/mg
You can use
^APPLE(?!.*TEA)(?!.*WINE1C).*
See the regex demo.
Details:
^ - start of string
APPLE - a fixed string
(?!.*TEA) - no TEA allowed anywhere to the right of the current location
(?!.*WINE1C) - no WINE1C allowed anywhere to the right of the current location
.* - any zero or more chars other than line break chars as many as possible.
If you don't want to match a string that has both or them (which is not in the current example data):
^APPLE(?!.*(WINE1C|TEA).*(?!\1)(?:TEA|WINE1C)).*
Explanation
^ Start of string
APPLE match literally
(?! Negative lookahead
.*(WINE1C|TEA) Capture either one of the values in group 1
.* Match 0+ characters
(?!\1)(?:TEA|WINE1C) Match either one of the values as long as it is not the same as previously matched in group 1
) Close the lookahead
.* Match the rest of the line
Regex demo
I have a string and would like to match a part of it.
The string is Accept: multipart/mixedPrivacy: nonePAI: <sip:4168755400#1.1.1.238>From: <sip:4168755400#1.1.1.238>;tag=5430960946837208_c1b08.2.3.1602135087396.0_1237422_3895152To: <sip:4168755400#1.1.1.238>
I want to match PAI: <sip:4168755400#
the whitespace can be a word so i would like to use .* but if i used that it matches most of the string
The example on that link is showing what i'm matching if i use the whitespace instead of .*
(PAI: <sip:)((?:\([2-9]\d{2}\)\ ?|[2-9]\d{2}(?:\-?|\ ?))[2-9]\d{2}[- ]?\d{4})#
The example on that link is showing what i'm trying to achieve with .* but it should only match PAI: <sip:4168755400#
(PAI:.*<sip:)((?:\([2-9]\d{2}\)\ ?|[2-9]\d{2}(?:\-?|\ ?))[2-9]\d{2}[- ]?\d{4})#
I tried lookaround but failing.
Any idea?
thanks
Matching the single space can be updated by using a character class matching either a space or a word character and repeat that 1 or more times to match at least a single occurrence.
Note that you don't have to escape the spaces, and in both occasions you can use an optional character class matching either a space or hyphen [ -]?
If you want the match only, you can omit the 2 capturing groups if you want to.
(PAI:[ \w]+<sip:)((?:\([2-9]\d{2}\) ?|[2-9]\d{2}[ -]?)[2-9]\d{2}[- ]?\d{4})#
Regex demo
The regex should be like
PAI:.*?(<sip:.*?#)
Explanation:
PAI:.*? find the word PAI: and after the word it can be anything (.*) but ? is used to indicate that it should match as few as possible before it found the next expression.
(<sip:.*?#) capturing group that we want the result.
<sip:.*?# find <sip: and after the word it can be anything .*? before it found #.
Example
I have strings which look like this:
/xxxxx/xxxxx-xxxx-xxxx-338200.html
With my regex:
(?<=-)(\d+)(?=\.html)
It matches just the numbers before .html.
Is it possible to write a regex that matches everything that surrounds the numbers (matches the .html part and the part before the numbers)?
In your current pattern you already use a capturing group. In that case you might also match what comes before and after instead of using the lookarounds
-(\d+)\.html
To get what comes before and after the digits, you could use 2 capturing groups:
^(.*-)\d+(\.html)$
Regex demo
In the replacement use the 2 groups.
This should do the job:
.*-\d+\.html
Explanation: .* will match anything until -\d+ say it should match a - followed by a sequence of digits before a \.html (where \. represents the character .).
To capture groups, just do (.*-)(\d+)(\.html). This will put everything before the number in a group, the number in another group and everything after the number in another group.
I need to create regex to find last underscore in string like 012344_2.0224.71_3 or 012354_5.00123.AR_3.335_8
I have wanted find last part with expression [^.]+$ and then find underscore at found element but I can not handle it.
I hope you can help me :)
Just use a negative character class [^_] that will match everything except an underscore (this helps to ensure no other underscores are found afterwards) and end of string $
Pattern would look as such:
(_)[^_]*$
The final underscore _ is in a capturing group, so you are wanting to return the submatch. You would replace the group 1 (your underscore).
See it live: Regex101
Notice the green highlighted portion on Regex101, this is your submatch and is what would be replaced.
The simplest solution I can imagine is using .*\K_, however not all regex flavours support \K.
If not, another idea would be to use _(?=[^_]*$)
You have a demo of the first and second option.
Explanation:
.*\K_: Fetches any character until an underscore. Since the * quantifier is greedy, It will match until the last underscore. Then \K discards the previous match and then we match the underscore.
_(?=[^_]*$): Fetch an underscore preceeded by non-underscore characters until the end of the line
If you want nothing but the "net" (i.e., nothing matched except the last underscore), use positive lookahead to check that no more underscores are in the string:
/_(?=[^_]*$)/gm
Demo
The pattern [^.]+$ matches not a dot 1+ times and then asserts the end of the string. The will give you the matches 71_3 and 335_8
What you want to match is an underscore when there are no more underscores following.
One way to do that is using a negative lookahead (?!.*_) if that is supported which asserts what is at the right does not match any character followed by an underscore
_(?!.*_)
Pattern demo
Trying to match the third item in this list:
/text word1, word2, some_other_word, word_4
I tried using this perl style regex to no avail:
([^, ]*, ){$m}([^, ]*),
I want to match ONLY the third word, nothing before or after, and no commas or whitespace. I need it to be a regex, this is not in a program but UltraEdit for a word file.
What can I use to match some_other_word (Or anything third in the list.)
Based on some input by the community members I made the following change to make the logic of the regex pattern clearer.
/^(?:(?:.(?<!,))+,){2}\s*(\w+).*/x
Explanation
/^ # 1.- Match start of line.
(?:(?:.(?<!,))+ # 2.- Match but don't capture a secuence of character not containing a comma ...
,) # 3.- followed by a comma
{2} # 4.- (exactly two times)
\s* # 5.- Match any optional space
(\w+) # 6.- Match and capture a secuence of the characters represented by \w a leat one character long.
.* # 7.- Match anything after that if neccesary.
/x
This is the one suggested previously.
/(?:\w+,?\s*){3}(\w+)/
Try group 1 of this regex:
^(?:.*?,){2}\s*(.*?)\s*(,|$)
See a live demo using your sample, plus an edge case, input showing capture in group 1.
It can't only return one match at a time because your string has more than one occurrence of the same pattern and Regular Expression doesn't have a selective return option! So you can do whatever you want from the returned array.
,\s?([^,]+)
See it in action, 2nd matched group is what you need.