Grouping 3 elements into a node - xslt

Question

I have the following xml where a the xml element name have a number in it..
<Root>
<Row>
<Coverage>Partial</Coverage>
<Admission>Self</Admission>
<Sequence1>1</Sequence1>
<Qualifier1>221</Qualifier1>
<Date1>2017-06-01</Date1>
<Sequence2>2</Sequence2>
<Qualifier2>222</Qualifier2>
<Date2>2022-05-06</Date2>
</Row>
<Row>
<Coverage>Partial</Coverage>
<Admission>Self</Admission>
<Sequence1>1</Sequence1>
<Qualifier1>321</Qualifier1>
<Date1>2017-06-01</Date1>
<Sequence2>2</Sequence2>
<Qualifier2>322</Qualifier2>
<Date2>2022-05-06</Date2>
</Row>
<Row>
<Coverage>Full</Coverage>
<Admission>Self</Admission>
<Sequence1>1</Sequence1>
<Qualifier1>421</Qualifier1>
<Date1>2017-06-01</Date1>
<Sequence2>2</Sequence2>
<Qualifier2>422</Qualifier2>
<Date2>2022-05-06</Date2>
</Row>
</Root>
I would like to group Sequence, Qualifier and Date into a group node called Benefit like below. Also, Based on the first element "Coverage" value, should be merged. XML output should as below.
<Root>
<Row>
<Coverage>Partial</Coverage>
<Admission>Self</Admission>
<Benefits>
<Benefit>
<Sequence>1</Sequence>
<Qualifier>221</Qualifier>
<Date>2017-06-01</Date>
</Benefit>
<Benefit>
<Sequence>2</Sequence>
<Qualifier>222<Qualifier>
<Date>2022-05-06</Date>
<Benefit>
<Benefit>
<Sequence>3</Sequence>
<Qualifier>321</Qualifier>
<Date>2017-06-01</Date>
</Benefit>
<Benefit>
<Sequence>4</Sequence>
<Qualifier>322<Qualifier>
<Date>2022-05-06</Date>
<Benefit>
</Benefits>
</Row>
<Row>
<Coverage>Full</Coverage>
<Admission>Self</Admission>
<Benefits>
<Benefit>
<Sequence>1</Sequence>
<Qualifier>421</Qualifier>
<Date>2017-06-01</Date>
</Benefit>
<Benefit>
<Sequence>2</Sequence>
<Qualifier>422<Qualifier>
<Date>2022-05-06</Date>
<Benefit>
</Benefits>
</Row>
</Root>
Any help is greatly appreciated.

Answer 1

Here's a simple method, based on the assumption that the 3 elements to be grouped will always come in a contiguous block that starts with a SequenceX:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Row">
<xsl:copy>
<xsl:copy-of select="Coverage | Admission"/>
<Benefits>
<xsl:for-each select="*[starts-with(name(), 'Sequence')]">
<Benefit>
<xsl:for-each select=". | following-sibling::*[position() < 3]">
<xsl:element name="{translate(name(), '0123456789', '')}">
<xsl:value-of select="." />
</xsl:element>
</xsl:for-each>
</Benefit>
</xsl:for-each>
</Benefits>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If the above assumption is not true, you can perform actual grouping based on the number included in the element names:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Row">
<xsl:copy>
<xsl:copy-of select="Coverage | Admission"/>
<Benefits>
<xsl:for-each-group select="*[matches(name(), '^Sequence|^Qualifier|^Date')]" group-by="replace(name(), '\D', '')">
<Benefit>
<xsl:for-each select="current-group()">
<xsl:element name="{replace(name(), '\d', '')}">
<xsl:value-of select="." />
</xsl:element>
</xsl:for-each>
</Benefit>
</xsl:for-each-group>
</Benefits>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>