Get all input of int from cin separated with space in c++ - c++

Question

N = Input How much attempt (First Line).
s = Input How much value can be added (Second, fourth and sixth lines).
P = Input of numbers separated with space.
Example :
3 ( Input N )
2 ( s 1 )
2 3
3 ( s 2 )
1 2 3
1 ( s 3 )
12
Example :
Read #1: 5 (Output s1 = 2 + 3)
Read #2: 6 (Output s2 = 1+2+3)
Read #3: 12 (Output s3 = 12)
I've been searching and trying for very long but couldn't figure out such basic as how to cin based on given numbers, with spaces and add all values into a variable. For example:
#include <iostream>
using namespace std;
int main() {
int l, o[l], r, p[r], i;
cin >> l;
for(i = 0; i < l; i++) {
cin>>o[l];
r = o[l]; // for every o[0] to o[l]
}
while (cin>>o[l]) {
for (i = 0; i < l; i++){
cin>>p[o]; // for every o[0] to o[l]
// i.e o[l] = 1 then 2 values can be added (because it starts from zero)
// input 1 2
// o[1] = {1, 2}
int example += o[1];
cout<< "Read#2: " << example;
}
}
}
And it doesn't work. Then i found getline(), ignoring the s and just input anything that will finally be added to a number, turned out it is only usable for char string. I tried scanf, but I'm not sure how it works. So im wondering if it's all about s(values) × 1(column) matrix from a looping but sill not sure how to make it. Any easy solutions to this without additional libraries or something like that? Thanks in advance.

Answer 1

#include <iostream>
using namespace std;
int main() {
int t; //number of attempts
cin >> t;
while(t--) { // for t attempts
int n, s = 0; //number of values and initial sum
cin >> n;
while (n--) { //for n values
int k; //value to be added
cin >> k;
s += k; //add k to sum
}
cout << s << "\n"; //print the sum and a newline
}
return 0;
}
If you want to add more details, (i.e. print Read#n on the nth attempt), you can always use
for (int i = 1; i <= n; i++)
to replace while(t--) and at the end of the attempt just print
cout << "Read#" << i << ": " << s << "\n";