How to build a table of objects without knowing their attributes? - django

Question

I'm trying to build a table dynamically in my django template. I got the column names in my views.py and also got the contents of the table:
table = tenant_tables.models[table_name].objects.all()
headers = table.model._meta.get_fields(include_parents=True, include_hidden=False)
context = {'table': table, 'headers': headers}
return render(request, template_name=template_name, context=context)
Based on the received data, I want to build a table using a template, but I don't know how to sort through all the attributes of the object
<table
id="example"
class="table table-striped data-table"
style="width: 100%"
>
<thead>
<tr>
{% for header in headers %}
<th>{{header.verbose_name}}</th>>
{% endfor %}
</tr>
</thead>
<tbody>
{% for obj in table %}
<tr>
<td>{{obj}}</td>
</tr>
{% endfor %}
</tbody>
<tfoot>
<tr>
{% for header in headers %}
<th>{{header.verbose_name}}</th>>
{% endfor %}
</tr>
</tfoot>
</table>
Can I implement this or should I create a view for each model in my application?

Answer 1

Yes, it's possible to implement this. But first you need to implement a custom filter which works like the getattr function in python.
Then you can do this:
...
<tbody>
{% for obj in table %}
<tr>
{% for header in headers %}
<td>{{ obj | getattr_filter:header }}</td>
{% endfor %}
</tr>
{% endfor %}
</tbody>
...
The filter should looks something like this:
#register.filter(name='getattr_filter')
def getattr_filter(obj, attribute):
return getattr(obj, attribute, None)
Check the docs for more details on how to implement a custom template filter.