Move semantics in parameter passing - c++

Question

I have following test example:
#include <iostream>
#include <vector>
void foo (std::vector<int> value) {
std::cout << "value "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
}
void foo2 (std::vector<int>&& rvalure_ref) {
std::cout << "rvalue_ref "
<< &rvalure_ref
<< " "
<< rvalure_ref.data()
<< " "
<< rvalure_ref.size()
<< std::endl;
}
int main() {
std::vector<int> value(5, 0);
std::cout << "init "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
foo(std::move(value));
std::cout << "done "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
}
The result of the code above is:
init 0x7ffed27c6450 0x56480bc1eeb0 5
value 0x7ffed27c6470 0x56480bc1eeb0 5
done 0x7ffed27c6450 0 0
Looks great:
Now, move to:
#include <iostream>
#include <vector>
void foo (std::vector<int> value) {
std::cout << "value "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
}
void foo2 (std::vector<int>&& rvalure_ref) {
std::cout << "rvalue_ref "
<< &rvalure_ref
<< " "
<< rvalure_ref.data()
<< " "
<< rvalure_ref.size()
<< std::endl;
}
int main() {
std::vector<int> value(5, 0);
std::cout << "init "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
foo2(std::move(value));
std::cout << "done "
<< &value
<< " "
<< value.data()
<< " "
<< value.size()
<< std::endl;
}
The result is:
init 0x7ffccc93a5c0 0x56124b3a8eb0 5
rvalue_ref 0x7ffccc93a5c0 0x56124b3a8eb0 5
done 0x7ffccc93a5c0 0x56124b3a8eb0 5
My problem is:
For the 1st case, it is perfectly called by "move semantics", and as you see, the ownership of the vector has been transfered to the function parameter. Finally, at "done", the data is null to verify the the vector at main() no longer owns the vector.
Now to explicitly claim the parameter is "rvalue reference", as case 2. As you see, actually it is like "call by (l)reference".
How can I figure out it?