Merge two columns of dates in the same data set - sas

I would like to concatenate two columns of the same dataset:
ID Date1 Date2
001 1-1999
002 2-2021
003 3-2021
004 03-2019
.... ....... ......
I tried:
data out1
set out
Test = coalesce(Date1 Date2);
run;
but without success.
Any suggestion?
Thank you in advance

My 2 suggestions:
Make sure that you use the correct function. Coalesce for numeric values, coalesceC for character
You are missing a comma between Date1 and Date2.
Do this
data have;
input ID $ (Date1 Date2)($);
infile datalines dlm = '|' missover;
datalines;
001|1-1999 |
002| |2-2021
003| |3-2021
004|03-2019|
;
data want;
set have;
test = coalescec(Date1, Date2);
run;

COALESCEC chooses the first non-missing value in the list of passed values. Coalescing is NOT concatenation. Concatenation is "the operation of joining character strings end-to-end"
For the case of your data always having one of date1 or date2 being missing, concatenation would
have the same result of coalescing.
result = cats(date1, date2);

Related

Concatenating a variable dynamically in SAS

I want to create a variable that resolves to the character before a specified character (*) in a string. However I am asking myself now if this specified character appears several times in a string (like it is in the example below), how to retrieve one variable that concatenates all the characters that appear before separated by a comma?
Example:
data have;
infile datalines delimiter=",";
input string :$20.;
datalines;
ABC*EDE*,
EFCC*W*d*
;
run;
Code:
data want;
set have;
cnt = count(string, "*");
_startpos = 0;
do i=0 to cnt until(_startpos=0);
before = catx(",",substr(string, find(string, "*", _startpos+1)-1,1));
end;
drop i _startpos;
run;
That code output before=C for the first and second observation. However I want it to be before=C,E for the first one and before=C,W,d for the second observation.
You can use Perl regular expression replacement pattern to transform the original string.
Example:
data have;
infile datalines delimiter=",";
input string :$20.;
datalines;
ABC*EDE*,
EFCC*W*d*
;
data want;
set have;
csl = prxchange('s/([^*]*?)([^*])\*/$2,/',-1,string); /* comma separated letters */
csl = prxchange('s/, *$//',1,csl); /* remove trailing comma */
run;
Make sure to increment _STARTPOS so your loop will finish. You can use CATX() to add the commas. Simplify selecting the character by using CHAR() instead of SUBSTR(). Also make sure to TELL the data step how to define the new variable instead of forcing it to guess. I also include test to handle the situation where * is in the first position.
data have;
input string $20.;
datalines;
ABC*EDE*
EFCC*W*d*
*XXXX*
asdf
;
data want;
set have;
length before $20 ;
_startpos = 0;
do cnt=0 to length(string) until(_startpos=0);
_startpos = find(string,'*',_startpos+1);
if _startpos>1 then before = catx(',',before,char(string,_startpos-1));
end;
cnt=cnt-(string=:'*');
drop i _startpos;
run;
Results:
Obs string before cnt
1 ABC*EDE* C,E 2
2 EFCC*W*d* C,W,d 3
3 *XXXX* X 1
4 asdf 0
call scan is also a good choice to get position of each *.
data have;
infile datalines delimiter=",";
input string :$20.;
datalines;
ABC*EDE*,
EFCC*W*d*
****
asdf
;
data want;
length before $20.;
set have;
do i = 1 to count(string,'*');
call scan(string,i,pos,len,'*');
before = catx(',',before,substrn(string,pos+len-1,1));
end;
put _n_ = +7 before=;
run;
Result:
_N_=1 before=C,E
_N_=2 before=C,W,d
_N_=3 before=
_N_=4 before=

modifying character variable contents based on lookup table in SAS

HAVE is a wide dataset with names stored in the variables name1-name250. Here are the first two obs and several vars:
episode name1 name2 name3 name4 name5 ...
121 DETWEILER.TJ.M BLUMBERG.MIKEY GRISWOLD.GUS.N
451 BOB.KING KID.HUSTLER FINSTER.MS PRICKLEY.PETEY GRISWOLD.GUS
...
Some of the names need to be corrected. The corrections are stored in the dataset FIXES:
goodname badname
DETWEILER.TJ DETWEILER.TJ.M
GRISWOLD.GUS GRISWOLD.GUS.N
I simply need to find the badname from FIXES that appear in HAVE and replace them with goodname. I currently loop through name1-name250 in a data step for each row in FIXES to accomplish this:
data WANT;
set HAVE;
array name {*} name1-name250;
do i=1 to dim(name);
if name{i} = "DETWEILER.TJ.M" then name{i} = "DETWEILER.TJ";
else if name{i} = "GRISWOLD.GUS.N" then name{i} = "GRISWOLD.GUS";
/*manually add other corrections from FIXES dataset*/
else name{i} = name{i};
end;
run;
This feels really inefficient. What is a better way?
When you have a simple exact match translation like that a FORMAT is a simple way to implement it. You can convert your "lookup" data into a format.
data fixes ;
input goodname :$30. badname :$30. ;
cards;
DETWEILER.TJ DETWEILER.TJ.M
GRISWOLD.GUS GRISWOLD.GUS.N
;
data format ;
retain fmtname '$FIXNAME' ;
set fixes end=eof;
rename badname=start goodname=label;
run;
proc format cntlin=format;
run;
Then just use the format to convert the names.
data want;
set have;
array name name1-name5;
do over name;
name=put(name,$fixname30.);
end;
run;
Result:
episode name1 name2 name3 name4 name5
121 DETWEILER.TJ BLUMBERG.MIKEY GRISWOLD.GUS
451 BOB.KING KID.HUSTLER FINSTER.MS PRICKLEY.PETEY GRISWOLD.GUS

SAS: How can I pad a character variable with zeroes while reading in from csv

Most of my data is read in in a fixed width format, such as fixedwidth.txt:
00012000ABC
0044500DEFG
345340000HI
00234000JKL
06453MNOPQR
Where the first 5 characters are colA and the next six are colB. The code to read this in looks something like:
infile "&path.fixedwidth.txt" lrecl = 397 missover;
input colA $5.
colB $6.
;
label colA = 'column A '
colB = 'column B '
;
run;
However some of my data is coming from elsewhere and is formatted as a csv without the leading zeroes, i.e. example.csv:
colA,colB
12,ABC
445,DEFG
34534,HI
234,JKL
6453,MNOPQR
As the csv data is being added to the existing data read in from the fixed width file, I want to match the formatting exactly.
The code I've got so far for reading in example.csv is:
data work.example;
%let _EFIERR_ = 0; /* set the ERROR detection macro variable */
infile "&path./example.csv" delimiter = ',' MISSOVER DSD lrecl=32767 firstobs=2 ;
informat colA $5.;
informat colB $6.;
format colA z5.; *;
format colB z6.; *;
input
colA $
colB $
;
if _ERROR_ then call symputx('_EFIERR_',1); /* set ERROR detection macro variable */
run;
But the formats z5. & z6. only work on columns formatted as numeric so this isn't working and gives this output:
ColA colB
12 ABC
445 DEFG
34534 HI
234 JKL
6453 MNOPQR
When I want:
ColA colB
00012 000ABC
00445 00DEFG
34534 0000HI
00234 000JKL
06453 MNOPQR
With both columns formatted as characters.
Ideally I'd like to find a way to get the output I need using only formats & informats to keep the code easy to follow (I have a lot of columns to keep track of!).
Grateful for any suggestions!
You can use cats to force the csv columns to character, without knowing what types the csv import determined they were. Right justify the resultant to the expected or needed variable length and translate the filled in spaces to zeroes.
For example
data have;
length a 8 b $7; * dang csv data, someone entered 7 chars for colB;
a = 12; b = "MNQ"; output;
a = 123456; b = "ABCDEFG"; output;
run;
data want;
set have (rename=(a=csvA b=csvB));
length a $5 b $6;
* may transfer, truncate or convert, based on length and type of csv variables;
* substr used to prevent blank results when cats (number) is too long;
* instead, the number will be truncated;
a = substr(cats(csvA),1);
b = substr(cats(csvB),1);
a = translate(right(a),'0',' ');
b = translate(right(b),'0',' ');
run;
SUBSTR on the left.
data test;
infile cards firstobs=2 dsd;
length cola $5 colb $6;
cola = '00000';
colb = '000000';
input (a b)($);
substr(cola,vlength(cola)-length(a)+1)=a;
substr(colb,vlength(colb)-length(b)+1)=b;
cards;
colA,colB
12,ABC
445,DEFG
34534,HI
234,JKL
6453,MNOPQR
;;;;
run;
proc print;
run;

SAS function to every observaton (finance xirr)

I have an sql table like this one
id | payment | date |
______|_____________|________________________|
obs1 | -20,10,13 | 21184,22765,22704 |
And so on (1M+ observation). I prepeared all the data for using finance() in SQL, so in SAS i just need to take them and pass to the function. I am confident, that the data i prepared will return right answer
The problem is that i can't find the most proper way to do caclulate the function on entire data. Right now i am going row by row in cycle and passing data to macro variables throught proc sql BUT i can't get string larger than 1000 characters, so my program isn't working.
I am running next function:
finance('XIRR', payment, date, 0.15);
Can you help me please? Thanks
The code i had before the answer. Worked unacceptable long!
%macro eir (input_data, cash_var, dt_var, output_data);
data rawdata;
set &input_data(dbmax_text=32000);
run;
proc sql noprint;
select count(*) into :n from rawdata ;
quit;
%let n = 100;
%do j=1 %to &n;
data x;
set rawdata(firstobs = &j obs= &j);
run;
proc sql noprint;
select &cash_var into: cf from x;
select &dt_var into: dt from x;
quit;
data x;
set x;
r= finance('xirr', &cf, &dt, 0.15);
drop &cash_var &dt_var;
run;
data out;
set %if &j>1 %then %do; out %end; x;
run;
%end;
proc append base = &output_data data=out;
run;
proc datasets nolist;
delete x out rawdata;
run;
%mend eir;
%eir(input_data = have, cash_var = pmt, dt_var = dt, output_data = ggg);
Took 20 minutes to calculate 50,000 rows
and now it's just
data want;
set have(dbmax_text=32000);
eir = input(resolve(catx(',','%sysfunc(finance(XIRR',pmt,dt,'0.15),hex16)')),hex16.);
run;
Took 6 minutes to calcuate 1,400,000 rows
Tom just saved our project =)
The FINANCE() function wants a list of values, not a character string. You could parse the string and convert the text back into numbers and pass those to the function. But if the lengths of the lists vary from observation to observation that will cause issues.
You could use the macro processor to help you. You can generate a call to %sysfunc(finance()) and read the generated string back into a numeric variable.
It also might work to pad the short lists with zero payments on the last recorded date.
Let's make some test data.
data have ;
infile cards dsd dlm='|' ;
length id $20 payment date $100 ;
input id payment date;
cards;
obs1 | -20,10,13 | 21184,22765,22704
obs2 | -20,10 | 21184,22765
;
Now let's try converting it two ways. One by creating numeric variables to pass to the FINANCE() function call and the other by generating %sysfunc(finance()) call so that we can make sure the %sysfunc() call is working properly.
data want;
set have ;
array v (3) _temporary_;
array d (3) _temporary_;
do i=1 to dim(v);
v(i)=coalesce(input(scan(payment,i,','),32.),0);
d(i)=input(scan(date,i,','),32.);
if missing(d(i)) and i>1 then d(i)=d(i-1);
end;
drop i;
value1=finance('XIRR',of v(*),of d(*),0.15);
value2=input(resolve(catx(',','%sysfunc(finance(XIRR',payment,date,'0.15),hex16)')),hex16.);
run;
Here's my best guess based on the limited details you've provided. I think you need to split out each date and payment into separate variables before you can call the finance function, e.g.:
data have;
infile datalines dlm='|';
input id :$8. amount :$20. date :$20.;
datalines;
obs1 | -20,10,13 | 21184,22765,22704
;
run;
data want;
set have;
array dates[3] d1-d3;
array amounts[3] a1-a3;
do i = 1 to 3;
amounts[i] = input(scan(amount, i, ','), 8.);
dates[i] = input(scan(date, i, ','), 8.);
end;
XIRR = finance('XIRR', of a1-a3, of d1-d3, 0.15);
run;
I suspect this will only work you have the same number of dates and payments in every row, otherwise you will run into array out of bounds issues or problems with the IRR calculation.

SAS group by first digits

I have a variable in SAS with a lot of numbers, for example 11000, 30129, 11111, 30999. I want to group this by the first two digits so "11000 and 11111" and "30129 and 30999" will be in a own table.
It's quite simple,
You have to create a second column and extract the 2 first digit.
Then sort the dataset by this second columns.
data test;
infile datalines dsd ;
input a : 15. ;
datalines;
11000,
30129,
11111,
309999,
;
run;
data test_a;
length val_a $2;
set test;
val_a= SUBSTRN(a,1,2);
run;
proc sort data=test_a out=test_b;
by val_a;
run;
Result will be :
val_a a
11 11000
11 11111
30 30129
30 309999
And then you can create 2 dataset with selection on the val_a like this :
data want data_11 data_30;
set test_b;
if val_a = 11 then output data_11;
if val_a = 30 then output data_30;
run;
Regards,
I think I did like you, but my new column only shows with ".". But I think your answer can give me some help anyways, thank you!
data books;
infile "&path\Boken.csv" dlm=';' missover dsd firstobs=2;
input ISBN: $12.
Book: $quote150.;
run;
data test_a;
format val_ISBN 15.;
set books;
val_ISBN= SUBSTRN(ISBN,1,2);
run;
proc sort data=test_a out=test_b;
by val_ISBN;
run;
proc print data=test_b (obs=10) noobs ;
run;