I have a column in my table which looks like below.
ResourceIdentifier
------------------
arn:aws:ec2:us-east-1:7XXXXXX1:instance/i-09TYTYTY79716
arn:aws:glue:us-east-1:5XXXXXX85:devEndpoint/etl-endpoint
i-075656565f7fea3
i-02c3434343f22
qa-271111145-us-east-1-raw
prod-95756565631-us-east-1-raw
prod-957454551631-us-east-1-isin-repository
i-02XXXXXXf0
I want a new column called 'Trimmed Resource Identifier' which looks at ResourceIdentifier and if the value starts with "arn", then returns value after last "/", else returns the whole string.
For eg.
arn:aws:ec2:us-east-1:7XXXXXX1:instance/i-09TYTYTY79716 ---> i-09TYTYTY797168
i-02XXXXXXf0 --> i-02XXXXXXf0
How do I do this ? I tried creating a new column called "first 3 letters" by extracting first 3 letters of the ResourceIdentifier column but I am getting stuck at the step of adding conditional column. Please see the image below.
Is there a way I can do all of this in one step using DAX instead of creating a new intermediate column ?
Many Thanks
The GUI is too simple to do exactly what you want but go ahead and use it to create the next step, which we can then modify to work properly.
Filling out the GUI like this
will produce a line of code that looks like this (turn on the Formula Bar under the View tab in the query editor if you don't see this formula).
= Table.AddColumn(#"Name of Previous Step Here", "Custom",
each if Text.StartsWith([ResourceIdentifier], "arn") then "output" else [ResourceIdentifier])
The first three letters bit is already handled with the operator I chose, so all that remains is to change the "output" placeholder to what we actually want. There's a handy Text.AfterDelimiter function we can use for this.
Text.AfterDelimiter([ResourceIdentifier], "/", {0, RelativePosition.FromEnd})
This tells it to take the text after the first / (starting from the end). Replace "output" with this expression and you should be good to go.
I have extracted files from an online database that consist of a roughly 100 titles. Associated with each of these titles is a DOI number, however, the DOI number is different for each title. To program this endeavor, I converted the contents of the website to a list. I then created for loop to iterate through each item of the list. What I want the program to do is iterate through the entire list and find where it says "DOI:" then to take the number which follows this. However, with the for loop I created, all it seems to do is print out the first DOI number, then terminates. How to I make the loop keep going once I have found the first one.
Here is the code:
resulttext = resulttext.split()
print(resulttext)
for item in resulttext:
if item == "DOI:":
DOI=resulttext[resulttext.index("DOI:")+1] #This parses out the DOI, then takes the item which follows it
print(DOI)
I have a query sequence that I blasted online using NCBIWWW.qblast. In my xml blast file result I obtained for a query sequence a list of hit (i.e: gi|). Each hit or gi| have multiple hsp. I made a dictionary my_dict1 where I placed gi| as key and I appended the bit score as value. So multiple values for each key.
my_dict1 = {
gi|1002819492|: [437.702, 384.47, 380.86, 380.86, 362.83],
gi|675820360| : [2617.97, 2614.37, 122.112],
gi|953764029| : [414.258, 318.66, 122.112, 86.158],
gi|675820410| : [450.653, 388.08, 386.27] }
Then I looked for max value in each key using:
for key, value in my_dict1.items():
max_value = max(value)
And made a second dictionary my_dict2:
my_dict2 = {
gi|1002819492|: 437.702,
gi|675820360| : 2617.97,
gi|953764029| : 414.258,
gi|675820410| : 450.653 }
I want to compare both dictionary. So I can extract the hsp with the highest score bits. I am also including other parameters like query coverage and identity percentage (Not shown here). The finality is to get the best gi| with the highest bit scores, coverage and identity percentage.
I tried many things to compare both dictionary like this :
First code :
matches[]
if my_dict1.keys() not in my_dict2.keys():
matches[hit_id] = bit_score
else:
matches = matches[hit_id], bit_score
Second code:
if hit_id not in matches.keys():
matches[hit_id]= bit_score
else:
matches = matches[hit_id], bit_score
Third code:
intersection = set(set(my_dict1.items()) & set(my_dict2.items()))
Howerver I always end up with 2 types of errors:
1 ) TypeError: list indices must be integers, not unicode
2 ) ... float not iterable...
Please I need some help and guidance. Thank you very much in advance for your time. Best regards.
It's not clear what you're trying to do. What is hit_id? What is bit_score? It looks like your second dict is always going to have the same keys as your first if you're creating it by pulling the max value for each key of the first dict.
You say you're trying to compare them, but don't really state what you're actually trying to do. Find those with values under a certain max? Find those with the highest max?
Your first code doesn't work because I'm assuming you're trying to use a dict key value as an index to matches, which you define as a list. That's probably where your first error is coming from, though you haven't given the lines where the error is actually occurring.
See in-code comments below:
# First off, this needs to be a dict.
matches{}
# This will never happen if you've created these dicts as you stated.
if my_dict1.keys() not in my_dict2.keys():
matches[hit_id] = bit_score # Not clear what bit_score is?
else:
# Also not sure what you're trying to do here. This will assign a tuple
# to matches with whatever the value of matches[hit_id] is and bit_score.
matches = matches[hit_id], bit_score
Regardless, we really need more information and the full code to figure out your actual goal and what's going wrong.
i have this code in python:
sensor16=['1','-','\\','/','*','!']
sensor15=['4','G','H','I']
sensor14=['7','P','Q','R','S']
sensor13=['*']
sensor12=['2','A','B','C']
sensor11=['5','J','K','L']
sensor10=['8','T','U','V']
sensor09=['0',' ']
sensor08=['3','D','E','F']
sensor07=['6','M','N','O']
sensor06=['9','W','X','Y','Z']
sensor05=['#']
sensor04=['BACKSPACE']
sensor03=['DELETE ALL']
sensor02=['READ']
sensor01=['TRANSMITE']
sensor= [sensor01,sensor02,sensor03,sensor04,sensor05,sensor06,sensor07,sensor08,sensor09,sensor10,sensor11,sensor12,sensor13,sensor14,sensor15,sensor16]
press=[1,1,1,1,1,5,4,4,2,4,4,4,1,5,4]
num_press=0
for steps in range(15) :
sensor[steps]
num_press=press[steps]
for i in range(num_press) :
print(sensor[steps][num_press])
How can I access the value in each sensorXX list which corresponds to the value in press[] list?
For example press[9] is 4, so I want to print sensor10[4] which is V
the reason that i have to go through press[] list is that i have already managed to get some timing functions so i know how much time passed since my last press, so i can either printout the next character inside the specific sensor number list ( e.g sensor01[] or sensor[12] ) and when i reach the maximum number of presses to reloop or i have to move my cursor one place right and start from begin.
i have already build and running in arduino but the code is in C. now i would like to move everything to my raspberry pi 2 and in python.
this was where the first idea came from, and i actually used most of that code to do so in arduino.
youtube video for arduino use of my code
arduino code
I ran your code and got index out of range error. It looks like you just have off by one error. Try this: (Also removed your nested for loop it seems like a mistake)
for steps in range(15) :
sensor[steps]
num_press=press[steps]
print (sensor[steps]) [num_press-1]
Output:
TRANSMITE
READ
DELETE ALL
BACKSPACE
#
Z
O
F
V
L
C
*
S
I
DOOOOONE ! AND THANK YOU ALL FOR YOUR RESPONSE ! :D
sensor16=['1','-','\\','/','*','!']
sensor15=['4','G','H','I']
sensor14=['7','P','Q','R','S']
sensor13=['*']
sensor12=['2','A','B','C']
sensor11=['5','J','K','L']
sensor10=['8','T','U','V']
sensor09=['0',' ']
sensor08=['3','D','E','F']
sensor07=['6','M','N','O']
sensor06=['9','W','X','Y','Z']
sensor05=['#']
sensor04=['BACKSPACE']
sensor03=['DELETE ALL']
sensor02=['READ']
sensor01=['TRANSMITE']
sensor=[sensor01,sensor02,sensor03,sensor04,sensor05,sensor06,sensor07,sensor08,sensor09,sensor10,sensor11,sensor12,sensor13,sensor14,sensor15,sensor16]
press=[1,1,1,1,1,5,4,4,2,4,4,4,1,5,4]
num_press=0
steps=0
for steps in range (15):
for i in range (press[steps]):
print (sensor[steps][i])
and it goes to every value individually.
again ! thanks a lot ....
I have to create a function that takes an input, and returns a corresponding Grade.
So for example if the user inputs A+ output is 90%
or
if the input is A output is 80%
or
if the input is B output is 70%
I have some sort of Idea on how to do this... but I am having trouble on wrapping my head around on how I can return the statement??
def percent (percentage):
if ( percentage )== A+
return ("90%")
elif (percentage)== A
return ("80%")
Is this the correct way of going about it?
OK, so first, welcome to Python. Second, this is Pythonic way of doing this - define a dict:
grades = {'A+': "90%", 'A': "80%", ...}
then
return grades[precentage]
will do the job.
You need to protect against the case where the grade is not in the dict, for example, if the user entered some mistake, like G. There are a few ways to go about that:
A simple if:
if precentage in grades:
return grades[precentage]
else:
return "bad precentage"
After you get used to Python you will be more aesthetic about your code and will want to do better than state twice bote grades and precentage, so you can do simply:
return grades.get(precentage, "bad precentage")
Or using a special dict with default values:
import collections
grades = collections.defaultdict(lambda: "bad precentage", [("A+", "90%"), ("A", "80%")])
then
grades[precentage]
will automatically return "bad precentage" upon bad input.
#user2829744 You don't want to have to repeatedly call if statements based on what the percentage is, that would make the code unnecessarily long.
Instead, you want to have a list or tuple (a variable which stores multiple elements) that the program can compare the user's inputted value to, and then calculate the percentage mark.
Take this for example:
def percentage(per):
grades=["A+","A","B","C","D","E","F"]
percentage=("90%","80%","70%","60%","50%","40%","30%")
for i in range(7):
if per.upper()==grades[i]:
return percentage[i]
d="a"
print(percentage(d))
What happens is that i counts up to the number seven, and if the value of i in grades (let's say i is 5, then that would be grades[5] which would be an "E") then the function returns the value of i in the percentage tuple. In my case, the interpreter outputs 80%
Logically, your way of going about it (by actually dealing with every grade possible in separate if statements) would work too, however like I said your code would be longer and chances are you'd make a few typos along the way that you'd have to edit. Of course, my code has a few problems too, like what if the user enters a grade which I don't have in the tuple. This is easily fixable though as you would just need to tell the interpreter what to do if that happens.
A bit brief I know, but I hope this helps
You could do something like this
user_input = int(input("percentage: ")
if user_input < 0 and user_input > 10:
print('F")
And then you can just duplicate the code and change the numbers and the return grade
Hope it helps :)