DPHPV = /usr/local/nginx/conf/php81-remi.conf;
I am unable to figure out how to match a string that contains any 2 digits:
if [[ "$DPHPV" =~ *"php[:digit:][:digit:]-remi.conf"* ]]
You are not using the right regex here as * is a quantifier in regex, not a placeholder for any text.
Actually, you do not need a regex, you may use a mere glob pattern like
if [[ "$DPHPV" == *php[[:digit:]][[:digit:]]-remi.conf ]]
Note
== - enables glob matching
*php[[:digit:]][[:digit:]]-remi.conf - matches any text with *, then matches php, then two digits (note that the POSIX character classes must be used inside bracket expressions), and then -rem.conf at the end of string.
See the online demo:
#!/bin/bash
DPHPV='/usr/local/nginx/conf/php81-remi.conf'
if [[ "$DPHPV" == *php[[:digit:]][[:digit:]]-remi.conf ]]; then
echo yes;
else
echo no;
fi
Output: yes.
Related
I am trying to do compare a string in bash to a regex pattern and have found something odd. For starters I am using GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu). This is within WSL.
For example here is sample program demonstrating the problem:
#!/bin/env bash
name="John"
if [[ "${name}" =~ "John"* ]]; then
echo "found"
else
echo "not found"
fi
exit
As expected this will echo found since the name "John" matches the regex pattern described. Now what I find odd is if I drop the n in John, it still echos found. Imo "Joh" does match the pattern of "John"*.
If you drop the "hn" and just set $name to "Jo" then it echos not found. It seems to only affect the last character in the Regex pattern (aside from the wildcard).
I am converting an old csh script to bash and this behavior is not happening in csh. What is causing bash to do this?
You're mixing up syntax for shell patterns and regular expressions. Your regular expression, after stripping the quoting, is John*: Joh followed by any number of n, including 0. Matches Joh, John, Johnn, Johnnn, ...
It's not anchored, so it also matches any string containing one of the matches above.
Since it's not anchored, depending on what you want, you could do any of these:
Any string containing John should match:
Regex: [[ $name =~ John ]]
Shell pattern: [[ $name == *John* ]]
Any string that begins with John should match:
Regex: [[ $name =~ ^John ]]
Shell pattern: [[ $name == John* ]]
Notice that shell patterns, unlike the regular expressions, must match the entire string.
A note on quoting: within [[ ... ]], the left-hand side doesn't have to be quoted; on the right-hand side, quoted parts are interpreted literally. For regular expressions, it's a good practice to define it in a separate variable:
re='^John'
if [[ $name =~ $re ]]; then
This avoids a few edge cases with special characters in the regex.
The =~ operator compares using regular expression syntax, not glob syntax. The * isn't a shell wildcard, it means, "the previous character, 0 or more times".
The string Joh matches the regular expression John* because it contains Joh followed by zero n characters.
I need a regex in shell to match all strings except those with specific pattern.
My specific pattern can be variable, i.e. (i|I)[2 digits numbers](u|U)[2 digits numbers] in every string should not match.
For example :
Some.text.1234.text => should match
Some.text.1234.i10u20.text => shouldn't match
Some.text.1234.I01U02.text => shouldn't match
Some.text.1234.i83U23.text => shouldn't match
You can try with that:
^(?!.*[tuTU]\d{2}).*$
Demo
Explanation:
^ start of a line
?!.* negative look ahead
[tuTU]\d{2} check if there exists such character following 2 digits only
.*$ if previous condition is negative then match entire string to end of string $
The Bash script checking if a string matches a regex or not can look like
f='It_is_your_string_to_check';
if [[ "${f^^}" =~ I[0-9]{2}U[0-9]{2} ]]; then
echo "$f is invalid";
else
echo "$f is valid"
fi;
Here, "${f^^}" turns the string into uppercase (so as not to use (U|u) and (I|i)), and then =~ operator triggers a regex check here since the pattern on the right side is not quoted. You may play it safe and define the regex pattern with a separate single-quoted string variable and use
rx='I[0-9]{2}U[0-9]{2}'
if [[ "${f^^}" =~ $rx ]]; then ...
See a Bash demo online:
s='Some.text.1234.text
Some.text.1234.i10u20.text
Some.text.1234.I01U02.text
Some.text.1234.i83U23.text'
for f in $s; do
if [[ "${f^^}" =~ I[0-9]{2}U[0-9]{2} ]]; then
echo "$f is invalid";
else
echo "$f is valid"
fi;
done;
Output:
Some.text.1234.text is valid
Some.text.1234.i10u20.text is invalid
Some.text.1234.I01U02.text is invalid
Some.text.1234.i83U23.text is invalid
How to match below signs in Bash?
+
-
/
*
This my code which I try to use but it did not work.
is_sign(){
yoursign=$1
re="^[+,-,\/,\*]$"
if ! [[ $yoursign =~ $re ]] ; then
echo "Not a sign"
return 2
else
return 0
fi
}
is_sign $1
The pattern you used contains the following issues:
You escape special characters thinking it will make them literal chars, but in fact, in POSIX bracket expressions, backslashes are treated as regular literal backslashes, and all you did is you also allow a literal \ to be matched with the regex
- must be either at the start or end of a POSIX bracket expression if you want to match a literal hyphen
By adding commas to the regex, it can now also match a comma.
Use
re='^[+/*-]$'
Demo:
is_sign() {
yoursign=$1
re='^[+/*-]$'
if ! [[ $yoursign =~ $re ]] ; then
echo "Not a sign"
#return 2
else
echo "Yeah, is a sign"
#return 0
fi
}
echo "$(is_sign "+")" # => Yeah, is a sign
echo "$(is_sign "m")" # => Not a sign
You have two solutions:
Regular expression:
re='^[+/*-]$'
if ! [[ $yoursign =~ $re ]] ; then
Glob:
glob='[+/*-]'
if ! [[ $yoursign == $glob ]] ; then
Please note that the minus sign - is special in a character class (both in a glob and in a regular expression), so you need to either put it in the beginning or at the end
Inside of my $foo variable I have this data (please pay close attention to the .s and ,s):
,example.com,de.wikipedia.org,reddit,stackoverflow.com.,amazon.,
I am trying to write an if statement in bash that basically works like this:
if [[ "${foo}" =~ *','[a-z0-9]','* || "${foo}" =~ *','[a-z0-9]'.,'* ]]; then
echo "Invalid input detected"
else
echo "OK"
fi
It would echo Invalid input detected since reddit and amazon. are in $foo.
If I change the contents of $foo to be:
,example.com,de.wikipedia.org,www.reddit.com,stackoverflow.com.,amazon.com,
Then it would echo OK.
I am using bash 3.2.57(1)-release on OS X 10.11.6 El Capitan.
Try:
if [[ $foo =~ ,[a-z0-9]*, || $foo =~ ,[a-z0-9]*\., ]]; then
echo "Invalid input detected"
else
echo "OK"
fi
Notes:
=~ is a regular expression operator. The right-hand-side needs to be a regular expression, not a glob.
, is not a shell-active character. Thus, it does not need any special quoting.
[a-z0-9] matches exactly one alphanumeric. Since we want to allow for more any number, use [a-z0-9]*
In regular expressions, ','* matches zero or more commas. This is not what you want. One might write ,.* which, because, . is a wildcard, matches a comma followed by zero or more of anything. Since the regex is not anchored to the end, adding a final .* makes no difference.
Inside of [[...]] there is no word splitting. So shell variables do not the double-quoting that need elsewhere.
Note that, in [a-z0-9], the exact characters that match a-z or 0-9 depend on the collation order in the locale.
keyFileName=$1;
for fileExt in "${validTypes[#]}"
do
echo $fileExt;
if [[ $keyFileName == *.$fileExt ]]; then
keyStatus="true";
fi
done;
I am trying to check the file extension of a file passed in against an array of multiple file extensions. However it doesn't seem to be working properly. Any help?
validTypes=(".txt" ".mp3")
keyFileName="$1"
for fileExt in "${validTypes[#]}"
do
echo $fileExt;
if [[ $keyFileName =~ ^.*$fileExt$ ]]; then
keyStatus="true";
echo "Yes"
fi
done;
Effectively, you could change your if statement to either:
if [[ $keyFileName == ?*$fileExt ]] # Glob pattern case, ? denotes single char
or:
if [[ $keyFileName =~ .*$fileExt ]] # Regex case, . denotes single char
Looping over the array to do a regex match on each element seems rather inefficient. You're using regex; it's easy to combine the expressions and avoid looping at all.
Mangling the array into a valid regex is not entirely trivial, though. Here's my attempt:
validTypes=('\.txt' '\.mp3')
fileExtRe=$(printf '|%s' "${validTypes[#]}"
# Trim off the first alternation, add parens and anchor
fileExtRe="(${fileExtRe#?})$"
if [[ $keyFileName =~ $fileExtRe ]]; then
:
Notice how the elements in validTypes are regular expressions now, with the dot escaped to only match a literal dot.