Printing an array with a symbol next to it - c++

Question

I would like to print a '>' sign next to an array which is able to move up and down when different things are inputted.
I am able to print a 12x12 array of 0s but when I try to print a '>' in line 7, the '>' is inputted into the array and the row itself is shifted over instead of the array being kept uniform (i.e. the '>' must be independent to the array).
I have tried creating two arrays of the '>' and the 0s but I am not able to print two things horizontally next to each other.
#include <stdio.h>
#include <stdlib.h>
int main(void) {
int row = 0;
while (row < 12){
int col = 0;
while (col < 12){
printf(" 0");
col = col + 1;
}
printf("\n");
row = row + 1;
if (row == 7) {
printf(">");
}
}
return 0;
}
output:
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
intended output:
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
> 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0
thank you !

Answer 1

To display a ">" sign before your matrix you can use a conditional statement specifically for the required line number.
#include <stdio.h>
#include <stdlib.h>
int main(void) {
for (int i = 0; i < 12; i++)
{
if(i == 7) // conditional statement
printf("> "); // for ">" followed by
else // a space to maintain
printf(" "); // the structure of matrix
for (int j = 0; j < 12; j++)
{
printf("0 ");
}
printf("\n");
}
return 0;
}
Hope it helps!!!