deleting sheets with a date older than the past two days - regex

Question

Working in Google Scripts, I'm trying to create a function that will look at the names of all tabs in a Google Sheet, and delete all sheets that meet these conditions: 1) tab name include a date (sheet names that do have a date are prefaced with some other text - the mm/dd/yyyy formatted date is in the string) and 2) the date in that sheet name is older than today's date minus 2 days).
There are two sheet names that include dates: "Leadership Review mm/dd/yyyy" and "Leadership Review w/notes mm/dd/yyyy". I have a script that auto-runs DAILY to create these sheets, so the goal is to automate a one-time clean-up for old sheets and set up a daily trigger to auto-run that function.
So far, I've created an array to capture the names of each sheet name ("tabNameArray") and have a regexp for use in matching for mm/dd/yyyy text that shows up in a sheet name.
My thought on how this would work - not sure how to accomplish 2 and 3:
create that array
parse the array - match each sheetname in the array against the regexp mm/dd/yyyy to identify sheetnames with a date.
A loop through that array... IF that sheetname has a date (create a new array or subarray with just those? doesn't seem necessary, but a thought), AND that date is > 2 days from today(), delete those sheets.
function deleteOldReportSheets() {
var sheetNameArray = new Array();
var sheetWithDatesArray = new Array(); //not sure this is necessary
var dateRegex = new RegExp("[0-3]?[0-9]\/[0-3]?[0-9]\/(?:[0-9]{2})?[0-9]{2}"); //for mm/dd/yyyy match, tested successfully on regex101.com
var sheets = SpreadsheetApp.getActiveSpreadsheet().getSheets();
for (var i=0 ; i<sheets.length ; i++) sheetNameArray.push( [ sheets[i].getName() ] ) // populates the sheetNameArray with names of each sheet
(do this: for sheets that have a date that is older than 2 days from today, delete...)
I'd appreciate support to code this - even better if there's a more efficient way than what I started thinking through.
Thanks for your assistance.

Answer 1

Description
The following example will compare the named sheets containing the date to today and indicate which sheets should be deleted. I leave the deletion operation to the OP.
Script
function test() {
try {
let spread = SpreadsheetApp.getActiveSpreadsheet();
let sheets = spread.getSheets();
let dateRegex = new RegExp("[0-3]?[0-9]\/[0-3]?[0-9]\/(?:[0-9]{2})?[0-9]{2}"); //for mm/dd/yyyy match, tested successfully on regex101.com
let today = new Date();
console.log("today = "+Utilities.formatDate(today,"GMT","MM/dd/yyyy"));
today = new Date(today.getFullYear(),today.getMonth(),today.getDate()-2);
for( let i=0; i<sheets.length; i++ ) {
let sheet = sheets[i];
let name = sheet.getName();
console.log("Sheet name = "+name);
let match = name.match(dateRegex);
if( match ) {
match = new Date(match[0]);
if( match.valueOf() <= today.valueOf() ) {
console.log("delete");
}
else {
console.log("keep");
}
}
}
}
catch(err) {
console.log(err);
}
}
Console.log
11:45:16 AM Notice Execution started
11:45:17 AM Info today = 05/01/2022
11:45:17 AM Info Sheet name = Sheet1
11:45:17 AM Info Sheet name = Sheet 04/29/2022
11:45:17 AM Info delete
11:45:17 AM Info Sheet name = Sheet 04/30/2022
11:45:17 AM Info keep
11:45:17 AM Info Sheet name = Sheet 05/01/2022
11:45:17 AM Info keep
11:45:16 AM Notice Execution completed
Reference
Date()
String.match()

Answer 2

I think it can be something like this:
function myFunction() {
const reg = new RegExp(/\d{2}\/\d{2}\/\d{4}/);
const ss = SpreadsheetApp.getActiveSpreadsheet();
const if_two_days_ago = date =>
new Date(date).valueOf() < new Date().valueOf() - 3600000 * 48;
ss.getSheets()
.filter(s => reg.test(s.getName()))
.filter(s => if_two_days_ago(s.getName().match(reg)))
.forEach(s => { console.log('bye-bye -->', s.getName()); ss.deleteSheet(s) });
}

Answer 3

Delete Sheets with dates older than two days
function delSheets() {
const ss = SpreadsheetApp.getActive();
const dt = new Date();
const dtv = new Date(dt.getFullYear(),dt.getMonth(),dt.getDate() - 2).valueOf();//date threshold value
ss.getSheets().forEach(sh => {
let m = sh.getName().match(/\d{1,2}\/\d{1,2}\/\d{4}/g);//includes a date
if(m && new Date(m[0]).valueOf() < dtv) {
ss.deleteSheet(sh);
}
});
}