C++ Macro with "double function" - c++

Question

I am looking for a way to use a single macro call (multiple times):
#define MAGIC ???????
MAGIC(ref1, "text 1");
MAGIC(ref2, "text 2");
to expand into something like this:
const char *texts[] = {"text 1", "text 2"};
enum {ref1, ref2}
I got two ways of create first line:
#define _COUNT(z, a, b, c, d, e, f, g, h, i, j, count, ...) count
#define COUNT(...) _COUNT(0, ##__VA_ARGS__, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1)
#define EVENTS(...) \
const struct \
{ \
int n = COUNT(__VA_ARGS__); \
const char *texts[COUNT(__VA_ARGS__)] = {__VA_ARGS__}; \
}
EVENTS("text 1", "text 2", "text N");
and:
#define BEGIN(n) \
const struct \
{ \
int cnt = (n); \
const char *texts[(n) + 1] = {
#define EVENT(id, text) text,
#define END \
0 \
} \
; \
} \
;
BEGIN(2)
EVENT(ref1, "text 1")
EVENT(ref2, "text 2")
END
both will work to create the fist line. However the first not even include the reference name and the second one ignores it.
I am sure I can create de second line as well, but how to create both at the same time?
I have hundreds of pairs like this to declare in a more complex code, and hope this will improve reading.
Any way to do it using GCC?

Answer 1

how to create both at the same time?
It is not possible - macros have no "state" that they can "set" from inside a macro expansion. You can't remember that you have seen some macro invocation and act on it later.
What you are (re-)implementing are X macros, where you use the same file with a different macro twice, solving the problem with remembering state. "State" depends on the location in the file, where you can change the macro definition.
// file_with_magic.h
MAGIC(ref1, "text 1")
MAGIC(ref2, "text 2")
// header.h
const char *texts[] = {
#define MAGIC(a, b) b
#include <file_with_magic.h>
#undef MAGIC
};
enum {
#define MAGIC(a, b) a
#include <file_with_magic.h>
#undef MAGIC
};