How to modify url in a django get request - django

Question

I have a web page which displays some data (with get parameters to filter in the view) and I use a pagination.
To go through the data i use a link to change the page in the paginator :
<li class="paginator-data">Next</li>
Here is the view :
#login_required
def search_and_export(request):
# initialisation
page_obj = Tree.objects.all()
# FORM
if request.method == 'GET':
## Here I get GET parameters or a default value like
data = str(request.GET.get('data', 1))
page = str(request.GET.get('page', 1))
## creating a queryDict
querydict = QueryDict('data=' data + '&page=' + page)
big_request_form = BigRequestForm(querydict)
if big_request_form.is_valid():
# Getting data from front endda
data = big_request_form.cleaned_data['data']
# Extracting QuerySet
page_obj = filtering_function(data)
paginator = Paginator(page_obj,25)
page_obj = paginator.get_page(page)
page_obj.adjusted_elided_pages = paginator.get_elided_page_range(number = page, on_each_side=1, on_ends=1)
else:
big_request_form = BigRequestForm()
# return values
context = {
'big_request_form' : big_request_form,
'page_obj' : page_obj,
}
return render(request, 'filtered_stats.html', context)
Here is the problem : url looks like that after browsing a few pages :
http://127.0.0.1:8000/?data=x&page=2&page=3&page=4&page=5&page=6
The view is working well (It displays me the last page) but I got this ugly link.
I tried something like that :
request.GET.get = querydict
(with querydict a QueryDict object with only one page data)
But It didn't work. I also thought of parsing data in the template but maybe there is a better way.

Answer 1

What you want to do in HTML template is to get current URL. But actually you don't have to do it - relative path can be used instead. So just remove it:
<li class="paginator-data">Next</li>
The browser knows current URL and will use href attribute relative to it.
UPD
alternative - to keep other parameters in the URL is to construct "next URL" inside the view and pass it in context as next_url.
I.e. something like so:
In views:
next_url = request.get_full_path()
next_url.replace(f'page={current}', f'page={page_obj.next_page_number}')
context['next_url'] = next_url
In template:
<li class="paginator-data">Next</li>