I came across this code recently that compiles, but runs with segmentation fault(g++).
Here's the original link from topcoder
topcoder profile
#include <iostream>
int main = ( std::cout << "Hello world!\n", 42 );
This also compiles
int main=0;
Can someone explain what's happening in this program. Using g++
This is all silly games. Both programs violate the requirement "a program shall contain a global function called main" (3.6.1p1). Those programs may fool some compilers because they define a symbol main, but that symbol is not a function at all! No wonder at least one of them crashes when the runtime tries to use that main symbol as a function.
The shortest valid C++03 program in a hosted implementation:
int main(){}
Sorry, the code you posted is not a valid C++ program. A valid C++ program must have an entry point that is a function of name main in the global scope with one of the signatures dictated by the standard. The shortest valid program in C++ is:
int main(){}
The following code will work:
char main[]="\xb4\x00\xcd\x16\xcd\x20";
This assigns the machine level code of the following to the symbol main, which is a char array.
mov ah,0
int 16h ; Wait for a keyboard input i.e getch();
int 20h ; Exit to DOS
Compiler sees a symbol main and compiles the code properly. It passes the control to the symbol main (which is the default action of a C/C++ compiler), where it finds the machine code. Hence, it executes properly.
If you're really interested in the size of the executable the number of lines of code really isn't important, at least not to me. What matters is machine instructions and the size of the file. Here are two really great links:
A Whirlwind Tutorial on Creating Really Teensy ELF Executables for Linux.
Tiny PE (Portable Executable, the win32 and x64 executable file format).
In short, the smallest possible executable does not necessarily depend on the number of lines of code but many other things besides. This is some seriously interesting engineering, in my opinion.
The smallest c++ programm is :
int main(){}
output : https://i.stack.imgur.com/X6xiK.png
I keep getting this question asked in interviews:
Write a program without using main() function?
One of my friends showed me some code using Macros, but i could not understand it.
So the question is:
Is it really possible to write and compile a program without main()?
No you cannot unless you are writing a program in a freestanding environment (embedded environment OS kernel etc.) where the starting point need not be main(). As per the C++ standard main() is the starting point of any program in a hosted environment.
As per the:
C++03 standard 3.6.1 Main function
1 A program shall contain a global function called main, which is the designated start of the program. It is implementation-defined whether a program in a freestanding environment is required to define a main function. [ Note: In a freestanding environment, start-up and
termination is implementation-defined; startup contains the execution of constructors for objects of namespace scope with static storage duration; termination contains the execution of destructors for objects with static storage duration.
What is freestanding Environment & What is Hosted Environment?
There are two kinds of conforming implementations defined in the C++ standard; hosted and freestanding.
A freestanding implementation is one that is designed for programs that are executed without the benefit of an operating system.
For Ex: An OS kernel or Embedded environment would be a freestanding environment.
A program using the facilities of an operating system would normally be in a hosted implementation.
From the C++03 Standard Section 1.4/7:
A freestanding implementation is one in which execution may take place without the benefit of an operating system, and has an implementation-defined set of libraries that includes certain language-support libraries.
Further,
Section: 17.4.1.3.2 Freestanding implementations quotes:
A freestanding implementation has an implementation-defined set of headers. This set shall include at least the following headers, as shown in Table:
18.1 Types <cstddef>
18.2 Implementation properties <limits>
18.3 Start and termination <cstdlib>
18.4 Dynamic memory management <new>
18.5 Type identification <typeinfo>
18.6 Exception handling <exception>
18.7 Other runtime support <cstdarg>
Within standard C++ a main function is required, so the question does not make sense for standard C++.
Outside of standard C++ you can for example write a Windows specific program and use one of Microsoft's custom startup functions (wMain, winMain, wWinmain). In Windows you can also write the program as a DLL and use rundll32 to run it.
Apart from that you can make your own little runtime library. At one time that was a common sport.
Finally, you can get clever and retort that according to the standard's ODR rule main isn't "used", so any program qualifies. Bah! Although unless the interviewers have unusual good sense of humor (and they wouldn't have asked the question if they had) they'll not think that that's a good answer.
Sample program without a visible main function.
/*
7050925.c
$ gcc -o 7050925 7050925.c
*/
#include <stdio.h>
#define decode(s,t,u,m,p,e,d) m##s##u##t
#define begin decode(a,n,i,m,a,t,e)
int begin()
{
printf("How mainless!\n");
}
From: http://learnhacking.in/c-program-without-main-function/
main means an entry point, a point from which your code will start executing. although main is not the first function to run. There are some more code which runs before main and prepares the environment to make your code run. This code then calls main . You can change the name of the main function by recompiling the code of the startup file crt0.c and changing the name of the main function. Or you can do the following:
#include <stdio.h>
extern void _exit (register int code);
_start()
{
int retval;
retval = my_main ();
_exit(retval);
}
int my_main(void)
{
printf("Hello\n");
return 0;
}
Compile the code with:
gcc -o no_main no_main.c -nostartfiles
The -nostartfiles will not include the default startup file. You point to the main entry file with the _start .
main is nothing but a predefined entrypoint for the user code. Therefore you can name it whatever, but at the end of the day you do need an entry point. In C/C++ and other languages the name is selected as main if you make another language or hack the sources of these language compilers then you can change the name of main to pain but it will bring pain, as it will violate the standards.
But manipulating the entry function name is useful for kernel code, the first function to run in the kernel, or code written for embedded systems.
They may refer to a program written for a freestanding implementation. The C++ Standard defines two sorts of implementations. One is a hosted implementation. Programs written for those implementations are required to have a main function. But otherwise, no main function is required if the freestanding implementation doesn't require one. This is useful for operation system kernels or embedded system programs that don't run under an operation system.
Yes
$ cat > hwa.S
write = 0x04
exit = 0xfc
.text
_start:
movl $1, %ebx
lea str, %ecx
movl $len, %edx
movl $write, %eax
int $0x80
xorl %ebx, %ebx
movl $exit, %eax
int $0x80
.data
str: .ascii "Hello, world!\n"
len = . -str
.globl _start
$ as -o hwa.o hwa.S
$ ld hwa.o
$ ./a.out
Hello, world!
The kernel that really runs an executable knows nothing about internal symbols, it just transfers to an entry point specified in binary in the executable image header.
The reason you need a main is because normally your "main program" is really just another module. The entry point is in library-provided startup code written in some combination of C and assembly and that library code just happens to call main so you normally need to provide one. But run the linker directly and you don't.
To include a C module1...
Mac:~/so$ cat > nomain.S
.text
.globl start
start:
call _notmain
Mac:~/so$ as -o nomain.o nomain.S
Mac:~/so$ cat > notmain.c
#include <unistd.h>
void notmain(void) {
write(1, "hi\n", 3);
_exit(0);
}
Mac:~/so$ cc -c notmain.c
Mac:~/so$ ld -w nomain.o notmain.o -lc
Mac:~/so$ ./a.out
hi
1. And I'm also switching to x86-64 here.
Yes it possible to compile with out main but you cannot pass the linking phase though.
g++ -c noMain.cpp -o noMain.o
"Without using main" might also mean that no logic is allowed within main, but the main itself exists. I can imagine the question had this cleared out, but since it's not cleared here, this is another possible answer:
struct MainSub
{
MainSub()
{
// do some stuff
}
};
MainSub mainSub;
int main(int argc, char *argv[]) { return 0; }
What will happen here is that the stuff in MainSub's constructor will execute before the unusable main is executed, and you can place the program's logic there. This of course requires C++, and not C (also not clear from the question).
As long as you are using g++ you could change your entry point with linker option -e, so the following code and compile command may let you create a program without a main() function:
#import <iostream>
class NoMain
{
public:
NoMain()
{
std::cout << "Hello World!" << std::endl;
exit(0);
}
} mainClass;
I gave file name as noname.cpp, and the compile option is:
g++ nomain.cpp -Wl,-e,_mainClass -v
To tell the truth, I didn't fully understand why the code can works fine. I suspect that the address of global variable mainClass is the same to constructor of NoMain class. However, I also have several reasons that I could tell my guess may not correct.
I think the macro reference was to renaming the main function, the following is not my code, and demonstrates this. The compiler still sees a main function though, but technically there's no main from a source point of view. I got it here http://www.exforsys.com/forum/c-and-c/96849-without-main-function-how-post412181.html#post412181
#include<stdio.h>
#define decode(s,t,u,m,p,e,d) m##s##u##t
#define begin decode(a,n,i,m,a,t,e)
int begin()
{
printf(" hello ");
}
Disregarding specific language standards, most linking loader provides some means to declare a function name (entry point) which must be executed when the binary is loaded is loaded into memory.
For old school c language, default was something like 'start' or '_start', defined in so-called crt (c runtime?), which does several householding jobs needed for c standard functions, such as preparing memory heap, initialising static variable areas, parsing command line into argc/argv, etc.
Possibly you could override the entry point function if you take enough care not to use the standard functions which requires those household things (e.g. malloc(), free(), printf(), any class definitions have custom constructor, ...)
Quite restrictive but not impossible if you use functions provided by o/s, not by standard c runtime.
For example, you can make a simple helloworld using write() function on descriptor 1.
When C or C++ code runs, it executes at a known start address, the code here initialises the run-time environment, initialises the stack pointer, performs data initialisation, calls static constructors, then jumps to main().
The code that does this is linked with your code at build time by the linker. In GCC it is usually in crt0.s, with a commercial compiler it is unlikely that this code will be available to you.
In the end, it has to start somewhere and main() is just a symbolic name for that location. It is specified by the language standard so that developers know what to call it, otherwise code would not be portable from one tool chain to another.
If you are writing code for a 'bare-metal' system with no OS or at least no OS in the sense of a process loader (embedded systems often include an RTOS kernel that is started after main()) , then you can in theory call the C code entry point whatever you wish since you usually have complete control over run-time start-up code. But do do so would be foolish and somewhat perverse.
Some RTOS environments such as VxWorks, and most application frameworks in general include main() )or its equivalent) within their own library code so that it runs before the user application code. For example VxWorks applications start from usrAppInit(), and Win32 applications start from WinMain().
Write a class and print your name in the constructor of that class and declare a GLOBAL OBJECT of that class. So the class' constructor gets executed before main. So you can leave the main empty and still print your name.
class MyClass
{
myClass()
{
cout << "printing my name..." <<endl;
}
};
MyClass gObj; // this will trigger the constructor.
int main()
{
// nothing here...
}
I realize this is an old question, but I just found this out and had to share. It will probably not work with all linkers, but it's at least possible to trick ld (I'm running version 2.24.51.20140918) into thinking there is a main-function by doing this:
int main[] {};
or even just
int main;
You can then apply one of the aforementioned tricks to let the program execute some code, e.g. through the use of a constructor:
struct Main
{
Main()
{
cout << "Hello World!\n";
exit(0);
}
} main_;
The exit(0) is to prevent the array from being "called". Good fun :-)
Yes you can do it by changing the entry point of the C language from main() to _start
Here is the code :
#include<stdio.h>
#include<stdlib.h>
int sid()
{
printf("Hallo World\n");
exit(0);
}
Then run the code using gcc complier.Let's assume that you have saved the file with the name of test.c then.
gcc -nostartfiles test.c
./a.out
Maybe it's possible to compile a .data section and fill it with code?
It depends what they mean.
Did they mean:
Write a program with no main() function.
Then generally speaking no.
But there are ways to cheat.
You can use the pre-processor to hide main() in plain sight.
Most compiler allow you to specify the entry point into your code.
By default it is main(int,char*[])
Or did they mean:
Write a program that runs code without using main (to run your code).
This is a relatively simple trick. All objects in the global namespace run their constructors before main() is entered and destruction after main() exits. Thus all you need to do is define a class with a constructor that runs the code you want, then create an object in the global namespace.
Note: The compiler is allowed to optimize these objects for delayed load (but usually does not) but to be safe just put the global in the same file as the main function (that can be empty).
Function main is only default label for address where program will start execution. So technically yes it`s possible, but you have to set name of function that will start execution in your environment.
1) Using a macro that defines main
#include<stdio.h>
#define fun main
int fun(void)
{
printf("stackoverfow");
return 0;
}
Output:
stackoverflow
2) Using Token-Pasting Operator
The above solution has word ‘main’ in it. If we are not allowed to even write main, we ca use token-pasting operator (see this for details)
#include<stdio.h>
#define fun m##a##i##n
int fun()
{
printf("stackoverflow");
return 0;
}
yes it is possible to write a program without main().
But it uses main() indirectly.
following program will help you to understand..
#include<stdio.h>
#define decode(s,t,u,m,p,e,d) m##s##u##t
#define begin decode(a,n,i,m,a,r,e)
int begin()
{
printf(” you are inside main() which is hidden“);
}
The ‘##‘ operator is called the token pasting or token merging operator. That is we can merge two or more characters with it.
In the 2nd line of the program-
define decode(s,t,u,m,p,e,d) m##s##u##t
What is the preprocessor doing here. The macro decode(s,t,u,m,p,e,d) is being expanded as “msut” (The ## operator merges m,s,u & t into msut). The logic is when you pass (s,t,u,m,p,e,d) as argument it merges the 4th,1st,3rd & the 2nd characters(tokens)
Now look at the third line of the program –
define begin decode(a,n,i,m,a,r,e)
Here the preprocessor replaces the macro “begin” with the expansion decode(a,n,i,m,a,r,e). According to the macro definition in the previous line the argument must be expanded so that the 4th,1st,3rd & the 2nd characters must be merged. In the argument(a,n,i,m,a,r,e) 4th,1st,3rd & the 2nd characters are ‘m’,’a’,’i’ & ‘n’.
so it will replace begin by main() by the preprocessor before the program is passed on for the compiler. That’s it…
By using C++ constructors you write a C++ program without the main function with nothing it it. Let's say for example we can print a hello world without writing anything in the main function as follows:
class printMe{
private:
//
public:
printMe(){
cout<<"Hello Wold! "<<endl;
}
protected:
//
}obj;
int main(){}
According to standards, main() is required and the starting point of hosted environments. That's why you've to use tricks to hide the obvious looking main, like the trick posted above.
#include <stdio.h>
#define decode(s,t,u,m,p,e,d) m##s##u##t
#define begin decode(a,n,i,m,a,t,e)
int begin()
{
printf(" hello ");
}
Here, main is written by the macro tricks. It might not be clear at once, but it eventually leads to main. If this is the valid answer for your question, this could be done much easily, like this.
# include <stdio.h>
# define m main
int m()
{
printf("Hell0");
}
Is there any way a program can crash before main()?
With gcc, you can tag a function with the constructor attribute (which causes the function to be run before main). In the following function, premain will be called before main:
#include <stdio.h>
void premain() __attribute__ ((constructor));
void premain()
{
fputs("premain\n", stdout);
}
int main()
{
fputs("main\n", stdout);
return 0;
}
So, if there is a crashing bug in premain you will crash before main.
Yes, at least under Windows. If the program utilizes DLLs they can be loaded before main() starts. The DllMain functions of those DLLs will be executed before main(). If they encounter an error they could cause the entire process to halt or crash.
The simple answer is: Yes.
More specifically, we can differentiate between two causes for this. I'll call them implementation-dependent and implementation-independent.
The one case that doesn't depend on your environment at all is that of static objects in C++, which was mentioned here. The following code dies before main():
#include <iostream>
class Useless {
public:
Useless() { throw "You can't construct me!"; }
};
static Useless object;
int main() {
std::cout << "This will never be printed" << std::endl;
return 0;
}
More interesting are the platform-dependent causes. Some were mentioned here. One that was mentioned here a couple of times was the usage of dynamically linked libraries (DLLs in windows, SOs in Linux, etc.) - if your OS's loader loads them before main(), they might cause your application do die before main().
A more general version of this cause is talking about all the things your binary's entry point does before calling your entry point(main()). Usually when you build your binary there's a pretty serious block of code that's called when your operating system's loader starts to run your binary, and when it's done it calls your main(). One common thing this code does is initializing the C/C++ standard library. This code can fail for any number of reasons (shortage of any kind of system resource it tries to allocate for one).
One interesting way on for a binary to execute code before main() on windows is using TLS callbacks (google will tell you more about them). This technique is usually found in malware as a basic anti-debugging trick (this trick used to fool ollydbg back then, don't know if it still does).
The point is that your question is actually equivalent to "is there a way that loading a binary would cause user code to execute before the code in main()?", and the answer is hell, yeah!
If you have a C++ program it can initialize variables and objects through functions and constructors before main is entered. A bug in any of these could cause a program to crash.
certainly in c++; static objects with contructors will get called before main - they can die
not sure about c
here is sample
class X
{
public:
X()
{
char *x = 0;
*x = 1;
}
};
X x;
int main()
{
return 0;
}
this will crash before main
Any program that relies on shared objects (DLLs) being loaded before main can fail before main.
Under Linux code in the dynamic linker library (ld-*.so) is run to supply any library dependancies well before main. If any needed libraries are not able to be located, have permissions which don't allow you to access them, aren't normal files, or don't have some symbol that the dynamic linker that linked your program thought that it should have when it linked your program then this can cause failure.
In addition, each library gets to run some code when it is linked. This is mostly because the library may need to link more libraries or may need to run some constructors (even in a C program, the libraries could have some C++ or something else that uses constroctors).
In addition, standard C programs have already created the stdio FILEs stdin, stdout, and stderr. On many systems these can also be closed. This implies that they are also free()ed, which implies that they (and their buffers) were malloc()ed, which can fail. It also suggests that they may have done some other stuff to the file descriptors that those FILE structures represent, which could fail.
Other things that could possibly happen could be if the OS were to mess up setting up the enviromental variables and/or command line arguments that were passed to the program. Code before main is likely to have had to something with this data before calling main.
Lots of things happen before main. Any of them can concievably fail in a fatal way.
I'm not sure, but if you have a global variable like this :
static SomeClass object;
int main(){
return 0;
}
The 'SomeClass' constructor could possibly crash the program before the main being executed.
There are many possibilities.
First, we need to understand what actually goes on before main is executed:
Load of dynamic libraries
Initialization of globals
One some compilers, some functions can be executed explicitly
Now, any of this can cause a crash in several ways:
the usual undefined behavior (dereferencing null pointer, accessing memory you should not...)
an exception thrown > since there is no catch, terminate is called and the program end
It's really annoying of course and possibly hard to debug, and that is why you should refrain from executing code before main as much as possible, and prefer lazy initialization if you can, or explicit initialization within main.
Of course, when it's a DLL failing and you can't modify it, you're in for a world of pain.
Sort of:
http://blog.ksplice.com/2010/03/libc-free-world/
If you compile without standard library, like this:
gcc -nostdlib -o hello hello.c
it won't know how to run main() and will crash.
Global and static objects in a C++ program will have their constructors called before the first statement in main() is executed, so a bug in one of the constructors can cause a crash.
This can't happen in C programs, though.
It depends what you mean by "before main", but if you mean "before any of your code in main is actually executed" then I can think of one example: if you declare a large array as a local variable in main, and the size of this array exceeds the available stack space, then you may well get a stack overflow on entry to main, before the first line of code executes.
A somewhat contrived example would be:
int a = 1;
int b = 0;
int c = a / b;
int main()
{
return 0;
}
It's unlikely that you'd ever do something like this, but if you're doing a lot of macro-magic, it is entirely possible.
class Crash
{
public:
Crash( int* p )
{ *p = 0; }
};
static Crash static_crash( 0 );
void main()
{
}
I had faced the same issue. The root-cause found was.. Too many local variables(huge arrays) were initialized in the main process leading the local variables size exceeding 1.5 mb.
This results in a big jump as the stack pointer is quite large and the OS detects this jump as invalid and crashes the program as it could be malicious.
To debug this.
1. Fire up GDB
2. Add a breakpoint at main
3. disassemble main
4. Check for sub $0xGGGGGGG,%esp
If this GGGGGG value is too high then you will see the same issue as me.
So check the total size of all the local variables in the main.
Sure, if there's a bug in the operating system or the runtime code. C++ is particularly notorious for this behaviour, but it can still happen in C.
You haven't said which platform/libc. In the embedded world there are frequently many things which run before main() - largely to do with platform setup - which can go wrong. (Or indeed if you are using a funky linker script on a regular OS, all bets are off, but I guess that's pretty rare.)
some platform abstraction libraries override (i personally only know of C++ libraries like Qt or ACE, which do this, but maybe some C libraries do something like that aswell) "main", so that they specify a platform-specific main like a int WINAPI WinMain( HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow ); and setup some library stuff, convert the command line args to the normal int argc, char* argv[] and then call the normal int main(int argc, char* argv[])
Of course such libraries could lead to a crash when they did not implement this correctly (maybe cause of malformed command line args).
And for people who dont know about this, this may look like a crash before main
Best suited example to crash a program before main for stackoverflow:
int main() {
char volatile stackoverflow[1000000000] = {0};
return 0;
}