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What's the diff between \n and endl? Is \n faster?
#include <iostream>
using namespace std;
int main()
{
cout << "Please enter 2 numbers:" << endl;
int a = 0, b = 0;
cin >> a >> b;
cout << "The sum of " << a << " and " << b << " is " << a + b << endl;
return 0;
}
Yes, '\n' is faster here. std::endl will additionally call flush() which is not needed in this case.
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double n;
cout << "Enter a number: " << endl;
cin >> n;
cout<<setprecision(4)<<n;
I want to set floting point precision dynamicly i. e. at runtime instead of static value 4.
You can do something like:
double n;
cout << "Enter a number : " << endl;
cin >> n;
cout << "Enter required precision : ";
int precision;
cin >> precision;
cout << setprecision(precision) << n;
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Hello guys actually i want to show output with input
e.g:
int main()
int a, b, c;
cin >>a >>b;
c = a-b;
cout <<"Here would be input e.g: 4+5=" << c <<endl;
cout <<"Here would be input e.g: 4-5=" << e <<endl;
If input is in this format a+b and user enter input's then output show after input like this 4+5= and after equal answer would there. Thanx in advance
cout << "Here would be input e.g: " << a << "+" << b<<"=" << c << endl;
cout << "Here would be input e.g: " << a << "-" << b<<"=" << e << endl;
Add the input variables in the cout command as follows:
cout << a << " + " << b<<" = " << c << endl;
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I developed this program to add and the retrieve 15$ in the stack.
I was wondering is there another more efficient way to write my code.
#include <iostream>
#include <stack>
#include <vector>
using namespace std;
int main()
{
const int MAX = 100;
int count;
stack<int, vector<int> > billStack;
for (int i=0; i<15; i++) {
billStack.push(i); // add 15 bills onto stack
}
cout << "The stack has " << billStack.size() << " bills.\n";
int cash;
cout << "How many bills to retrieve?\n";
cin >> cash;
for (int i = 0; i< cash; i++) {
billStack.pop();
}
cout << "Cash out :" << cash << ". Remaining: " << billStack.size() << endl;
return 0;
}
Considering that you don't ever use the actual contents of the stack, just its size:
#include <iostream>
using namespace std;
int main()
{
int stackSize = 15;
cout << "The stack has " << stackSize << " bills.\n";
int cash;
cout << "How many bills to retrieve?\n";
cin >> cash;
stackSize -= cash;
cout << "Cash out :" << cash << ". Remaining: " << stackSize << endl;
return 0;
}
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I'm trying to make a time like this:
00:00:59;
But I can't get it to show 00 instead it show only one 0.
A simple way using std::setw and std::setfill is this:
int hour = 0;
int minute = 0;
int second = 59;
std::cout << std::setw(2) << std::setfill('0') << hour << ":";
std::cout << std::setw(2) << std::setfill('0') << minute << ":";
std::cout << std::setw(2) << std::setfill('0') << second << endl;
It will print:
00:00:59
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I have a problem in the for-construction, I don't know why my counting starts from 0 but you can't write on it(you can write starting with Register 1).I've marked in the code where is the problem.
#include <iostream>
#include <string>
#include <vector>
int main()
{
std::string day, date;
int registerCount;
std::cout << "INPUT DATA"
<< std::endl << std::endl
<< "Enter the day in which you want to perform the register: "
<< std::endl;
std::cin >> day;
std::cout << "DATE:" << std::endl;
std::cin >> date;
std::cout << "Enter the number of registers you wanna perfom for the day "
<< day << ":" << std::endl;
std::cin >> registerCount;
std::vector<std::string> registers(registerCount);
for (int i = 0; i < registerCount; ++i) **here is the problem**
{
std::cout << "Register " << i << ":" << std::endl; **it starts from 0 but you can't write on Register 0**
std::getline(std::cin, registers[i]);
}
std::cout << "The data for the day of " << day << " are the following: "
<< std::endl;
std::cout << "DATE: " << date << std::endl;
for (int i = 0; i < registerCount; ++i)
std::cout << registers[i] << std::endl;
}
Use
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
Header - #include<limits>
after your
std::cin >> registerCount;
to "eat up" the trailing newline coming from previous std::cin which is cause of skipping of the first input
for (int i = 0; i < registerCount; ++i)
You're defining i as starting at 0 here. Very simply, all you need to do is change the "i = 0" to "i = 1".
The way you're assigning to that vector looks a little bit wrong too. I think you need to use push_back() on the vector in that syntax, but I'm not too familiar with all the different operators for vector.