I have this string: ](-test-word-another)
I'm trying to find every single occurrence of - in between ] and )
Basically the return should be: ](-test-word-another)
Currently I have (?<=\]\()(-)(?=\)) but that just finds if there is only one -
Thank you in advance
Try this: /(?<=\].*)-(?=.*\))/gm
Test here: https://regex101.com/r/xkmTZs/3
This basically matches all - only if they occur after a ] and before ).
You can use
text.replace(/]\([^()]*\)/g, (x) => x.replace(/-/g, '_'))
See the demo below:
const text = 'Word-word ](-test-word-another) text-text-.';
console.log( text.replace(/]\([^()]*\)/g, (x) => x.replace(/-/g, '_')) );
The ]\([^()]*\) regex matches a ]( substring, then any zero or more chars other than ( and ) and then a ), and then all - chars inside the match value (x here) are replaced with _ using (x) => x.replace(/-/g, '_').
Another, single regex solution can look like
(?<=]\((?:(?!]\()[^)])*)-(?=[^()]*\))
See this regex demo. It matches any - that is immediately preceded with ]( and any zero or more chars other than ) that does not start a ]( char sequence, and is immediately followed with any zero or more chars other than ( and ) and then a ) char.
Related
I would like to extract two different test strings /i/int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45/,640-1_999899,480-1_999899,960-1_999899,1280-1_999899,1920-1_999899,.mp4.csmil/master.m3u8?set-segment-duration=responsive
and
/i/int/2021/11/25/,live_20211125_215206_sendeton_640x360-50p-1200kbit,live_20211125_215206_sendeton_480x270-50p-700kbit,live_20211125_215206_sendeton_960x540-50p-1600kbit,live_20211125_215206_sendeton_1280x720-50p-3200kbit,live_20211125_215206_sendeton_1920x1080-50p-5000kbit,.mp4.csmil/master.m3u8
with a single RegEx and in Group-1.
By using this RegEx ^.[i,na,fm,d]+\/(.+([,\/])?(\/|.+=.+,\/).+\/[,](live.([^,]).).+_)?.+(640).*$ I can get the second string to match the desired result int/2021/11/25/,live_20211125_215206_
but the first string does not match in Group-1 and the missing expected test string 1 extraction is int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45
Any pointers on this is appreciated.
Thanks!
If you want both values in group 1, you can use:
^/(?:[id]|na|fm)/([^/\s]*/\d{4}/\d{2}/\d{2}/\S*?)(?:/,|[^_]+_)640(?:\D|$)
The pattern matches:
^ Start of string
/ Match literally
(?:[id]|na|fm) Match one of i d na fm
/ Match literally
( Capture group 1
[^/\s]*/ Match any char except a / or a whitespace char, then match /
\d{4}/\d{2}/\d{2}/ Match a date like pattern
\S*? Match optional non whitespace chars, as few as possible
) Close group 1
(?:/,|[^_]+_) Match either /, or 1+ chars other than _ and then match _
640 Match literally
(?:\D|$) Match either a non digits or assert end of string
See a regex demo and a go demo.
We can't know all the rules of how the strings your are matching are constructed, but for just these two example strings provided:
package main
import (
"fmt"
"regexp"
)
func main() {
var re = regexp.MustCompile(`(?m)(\/i/int/\d{4}/\d{2}/\d{2}/.*)(?:\/,|_[\w_]+)640`)
var str = `
/i/int/2021/11/18/019e1691-614c-4402-a8c1-d0239ad1ac45/,640-1_999899,480-1_999899,960-1_999899,1280-1_999899,1920-1_999899,.mp4.csmil/master.m3u8?set-segment-duration=responsive
/i/int/2021/11/25/,live_20211125_215206_sendeton_640x360-50p-1200kbit,live_20211125_215206_sendeton_480x270-50p-700kbit,live_20211125_215206_sendeton_960x540-50p-1600kbit,live_20211125_215206_sendeton_1280x720-50p-3200kbit,live_20211125_215206_sendeton_1920x1080-50p-5000kbit,.mp4.csmil/master.m3u8`
match := re.FindAllStringSubmatch(str, -1)
for _, val := range match {
fmt.Println(val[1])
}
}
I need a Regular Expression to check whether a value contains any other characters than digits between 0 and 9.
I also want to check the length of the value.
The RegEx I´ve made: ^([0-9]\d{6})$
My test value is: 123Z45 and 123456
The ABAP code:
FIND ALL OCCURENCES OF REGEX '^([0-9]\d{6})$' IN L_VALUE RESULTS DATA(LT_RESULTS).
I´m expecting a result in LT_RESULTS, when I´m testing the first test value '123Z45', because there is a non-digit character.
But LT_RESULTS is in nearly every test case empty.
Your expression ^([0-9]\d{6})$ translates to:
^ - start of input
( - begin capture group
[0-9] - a character between 0 and 9
\d{6} - six digits (digit = character between 0 and 9)
) - end capture group
$ - end of input
So it will only match 1234567 (7 digit strings), not 123456, or 123Z45.
If you just need to find a string that contains non digits you could use the following instead: ^\d*[^\d]+\d*$
* - previous element may occur zero, one or more times
[^\d] - ^ right after [ means "NOT", i.e. any character which is not a digit
+ - previous element may occur one or more times
Example:
const expression = /^\d*[^\d]+\d*$/;
const inputs = ['123Z45', '123456', 'abc', 'a21345', '1234f', '142345'];
console.log(inputs.filter(i => expression.test(i)));
You can also use this character class if you want to extract non-digit group:
DATA(l_guid) = '0074162D8EAA549794A4EF38D9553990680B89A1'.
DATA(regx) = '[[:alpha:]]+'.
DATA(substr) = match( val = l_guid
regex = regx
occ = 1 ).
It finds a first occured non-digit group of characters and shows it.
If you want to just check if they are exists or how much of them reside in your string, count built-in function is your friend:
DATA(how_many) = count( val = l_guid regex = regx ).
DATA(yes) = boolc( count( val = l_guid regex = regx ) > 0 ).
Match and count exist since ABAP 7.50.
If you don't need a Regular Expression for something more complex, ABAP has some nice comparison operators CO (Contains Only), CA, NA etc for you. Something like:
IF L_VALUE CO '0123456789' AND STRLEN( L_VALUE ) = 6.
I am trying to match all content between parentheses, including parentheses in a non-greedy way. There should be a space before and after the opening parentheses (or the start of a line before the opening parentheses) and a space before and after the closing parentheses. Take the following text:
( )
( This is a comment )
1 2 +
\ a
: square dup * ;
( foo bar
baz )
(quux)
( ( )
(
( )
The first line should be matched, the second line including its content should be matched, the second last line should not be matched (or raise an error) and the last line should be matched. The two lines foo bar baz should be matched, but (quux) should not as it doesn't contain a space before and after the parentheses. The line with the extra opening parentheses inside should be matched.
I tried a few conventional regexes for matching content between parentheses but without much success. The regex engine is that of Go's.
re := regexp.MustCompile(`(?s)\(( | .*? )\)`)
s = re.ReplaceAllString(s, "")
Playground: https://play.golang.org/p/t93tc_hWAG
Regular expressions "can't count" (that's over-simplified, but bear with me), so you can't match on an unbounded amount of parenthesis nesting. I guess you're mostly concerned about matching only a single level in this case, so you would need to use something like:
foo := regexp.MustCompile(`^ *\( ([^ ]| [^)]*? \)$`)
This does require the comment to be the very last thing on a line, so it may be better to add "match zero or more spaces" there. This does NOT match the string "( ( ) )" or try to cater for arbitrary nesting, as that's well outside the counting that regular expressions can do.
What they can do in terms of counting is "count a specific number of times", they can't "count how many blah, then make sure there's the same number of floobs" (that requires going from a regular expression to a context-free grammar).
Playground
Here is a way to match all the 3 lines in question:
(?m)^[\t\p{Zs}]*\([\pZs}\t](?:[^()\n]*[\pZs}\t])?\)[\pZs}\t]*$
See the Go regex demo at the new regex101.com
Details:
(?m) - multiline mode on
^ - due to the above, the start of a line
[\t\p{Zs}]* - 0+ horizontal whitespaces
\( - a (
[\pZs}\t] - exactly 1 horizontal whitespace
(?:[^()\n]*[\pZs}\t])? - an optional sequence matching:
[^()\n]* - a negated character class matching 0+ characters other than (, ) and a newline
[\pZs}\t] - horizontal whitespace
\) - a literal )
[\pZs}\t]* - 0+ horizontal whitespaces
$ - due to (?m), the end of a line.
Go playground demo:
package main
import (
"regexp"
"fmt"
)
func main() {
var re = regexp.MustCompile(`(?m)^[\t\p{Zs}]*\([\pZs}\t](?:[^()\n]*[\pZs}\t])?\)[\pZs}\t]*$`)
var str = ` ( )
( This is a comment )
1 2 +
\ a
: square dup * ;
( foo bar
baz )
(quux)
( ( )
(
( )`
for i, match := range re.FindAllString(str, -1) {
fmt.Println("'", match, "' (found at index", i, ")")
}
}
I have the following string
([Valor][Corr][Fat]: 6M UC x Viz. Lógicos IN('3','6')) AND (((SUM_RevisionAnomalia_UltRevision_1M = 1) AND (CANT_ConsumoFact_UltRevision_1M > 1)) OR ((SUM_RevisionNoAnomalia_UltRevision_1M + 1) AND (CANT_ConsumoFact_UltRevision_1M BETWEEN 1 - 2))) OR (SUM_RevisionNoAnomalia_UltRevision_1M <= 1)
and I am trying to extract all inner groups, so my answer should contain
([Valor][Corr][Fat]: 6M UC x Viz. Lógicos IN('3','6'))
(SUM_RevisionAnomalia_UltRevision_1M = 1)
(CANT_ConsumoFact_UltRevision_1M > 1)
(SUM_RevisionNoAnomalia_UltRevision_1M + 1)
(CANT_ConsumoFact_UltRevision_1M BETWEEN 1 - 2)
(SUM_RevisionNoAnomalia_UltRevision_1M <= 1)
It is quite easy to extract this when there is only 1 set of those strings inside parentheses, but when given the example above my regex captures the whole string.
The regex i am using is
/(\([a-zA-Z0-9\[\]:_+=-\s\.\(\),'óáéíúüçãôàäê><]+\))/g
It seems you just want to match what is in-between ( and ) that is not ( and ) unless these are (...) that are preceded with a word character.
You can use
\((?:[^()]|\b\([^()]*\))*\)
See the regex demo
The regex breakdown:
\( - matching a literal (
(?:[^()]|\b\([^()]*\))* - zero or more sequences of:
[^()] - any character other than ( and )
| - or...
\b\([^()]*\) - a word boundary (i.e. before that position, there must be a word character) followed with ( followed with zero or more characters other than ( and )
\) - a closing )
An alternative pattern can be an unrolled one (more efficient with longer inputs):
\([^()]*(?:\b\([^()]*\)[^()]*)*\)
See another demo
str must be true if it has at least one non-whitespace enclosed in the parenthesis:
str = (a)
str = ( as bs)
str = (as e)
and false if it has non-whitespace at all
str = ( )
Im not sure if i can do that + but this condition is also passing the 0 non-whitespaces. Correct it please.
/^\([\S+\s*]+\)$\.test(str)/
You can use this:
/^\(.*\S.*\)$/.test(str)
This matches any character, then a non-whitespace character (that makes it at least one non-whitespace character), and then any character till the end.
You can use the following:
^\((?!\s*\)).+\)$
This matches an open parentheses ( and then it fails if it is followed just by whitespaces and a ), or it accepts the entire line.
Assuming str must satisfy TRUE and FALSE and nesting is implicitly not allowed
^(?:[^()]*\([^\S()]*[^\s()][^\S()]*\))+[^()]*$
expanded
^
(?:
[^()]*
\(
[^\S()]*
[^\s()]
[^\S()]*
\)
)+
[^()]*
$