I have written code below but I get warning C6001: using uninitialized memory
in merge function before last line at arr[z] = S[z] , I have used dynamic array because VS-2022 don't support VLA.
I have seen different types of merge algorithms but I want this specific code to run because I am using an instruction that I have to follow for my project!
#include <iostream>
void merge(int*, int, int, int);
void merge_sort(int*, int, int);
void printArrey(int*, int);
int main()
{
int arr[9] = { 9,8,7,6,5,4,3,2,1 };
printArrey(arr, 9);
merge_sort(arr, 0, 8);
printArrey(arr, 9);
system("pause");
}
void merge(int* arr, int start, int mid, int end)
{
int i = start, j = mid+1, k = start;
int* S = new int[end+1];
while (i <= mid && j <= end)
{
if (arr[i] < arr[j])
{
S[k] = arr[i];
i++;
}
else
{
S[k] = arr[j];
j++;
}
k++;
}
if (i > mid)
{
for (; j <= end; k++, j++)
{
S[k] = arr[j];
}
}
else if (j > end)
{
for (; i <= mid; k++, i++)
{
S[k] = arr[i];
}
}
for (int z=0; z < k; z++)
{ arr[z] = S[z]; }
delete[] S;
}
void merge_sort(int* arr, int start, int end)
{
if (start < end)
{
int mid = start+ (end - start) / 2;
merge_sort(arr, start, mid);
merge_sort(arr, mid+1, end);
merge(arr, start, mid, end);
}
}
void printArrey(int* arr, int size)
{
for(int i = 0; i < size; i++)
{
std::cout << arr[i] << "\t";
}
std::cout << "\n";
}
I had to use
while(start<=end)
{
arr[start] = S[start];
start++;
}
instead of
for (int z=0; z < k; z++)
{ arr[z] = S[z]; }
tnx to anyone who helped!
Related
I am trying to implement a hybrid of mergesort and insertion sort. When the subarray size reaches below a threshold, it should switch to insertion sort.
However I tried with a bunch of array of different length and different threshold amount, and most of the time there isn't any noticeable difference, other than just a 2-3 lesser comparisons. I was told that switching to insertion sort for smaller sized array would help greatly.
Am I doing it wrong?
#include <iostream>
int comparisons = 0;
int swaps = 0;
void mergesort(int x[], int l, int r);
void insertionSort(int x[],int start, int end);
int main() {
int x[] = {9,5,1,4,3,10,29,69,5,9,11,19,21,69,0,2,3,4,5,11,111,96,25,32,21,2,12,3,52,55,23,32,15,15,14,13,9,5,1,4,3,10,29,69,5,9,11,19,21,69,0,2,3,4,5,11,111,96,25,32,21,2,12,3,52,55,23,32,15,15,14,13,};
// insertionSort(x,10);
int sizeX= sizeof(x)/sizeof(x[0]) ;
mergesort(x, 0, sizeX-1);
for(int i =0;i<sizeX;i++){
std::cout << x[i] << " ";
}
// std::cout << "\nSWAPS: " << swaps;
std::cout << "\nCOMPARISONS: " << comparisons;
}
void insertionSort(int arr[], int start,int end)
{
int i, key, j;
for (i = start +1 ; i < end; i++)
{
key = arr[i];
j = i - 1;
/* Move elements of arr[0..i-1], that are
greater than key, to one position ahead
of their current position */
while (j >= 0 && arr[j] > key)
{
comparisons++;
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
void insertionSort2(int x[],int start, int end){
for(int i =start; i < end;i++){
for (int j= i; j!= 0;j--){
comparisons++;
if(x[j] < x[j-1]){
int temp = x[j-1];
x[j-1] = x[j];
x[j] = temp;
swaps++;
}
else{
break;
}
}
}
}
void mergesort(int x[], int l, int r) {
if (l >= r)
return;
int mid = (l + r) / 2;
if(r - l < 3){
insertionSort(x, l,r+1);
}else{
mergesort(x, l, mid);
mergesort(x, mid + 1, r);
int i = l;
int j = mid + 1;
int k = 0;
int tmp[r - l + 1];
while (i <= mid && j <= r) {
comparisons++;
if (x[i] >= x[j]) {
tmp[k] = x[j];
j++;
} else {
tmp[k] = x[i];
i++;
}
swaps++;
k++;
}
while (i <= mid) {
tmp[k] = x[i];
i++;
k++;
}
while (j <= r) {
tmp[k] = x[j];
j++;
k++;
}
for (i = 0; i < k; i++) x[l + i] = tmp[i];
}
}
Part method is not doing anything it outputs same array as entered and i don't know whats wrong
void part(int array[100], int start, int end){
int pivot = array[start];
int i = start;
int j = end;
int temp, temp2;
// i to swap elements greater than pivot
// j to swap elements less than or equal to pivot
while(i > j){
while(true){
if(array[i] <= pivot ){
break;
}
++i;
}
while(array[j] > pivot){
if(array[j] > pivot){
break;
}
--j;
}
if(i < j){
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
if(j < i){ // j - i cross each other
temp2 = pivot;
pivot = array[j];
pivot = temp2;
}
for(int k = 0; k<end;++k){
cout<<array[k];
}
}
void quick(int array[100], int start, int end){
if(start < end){
part(array, start, end);
}
}
You call part only if
if(start < end){
part(array, start, end);
but then you do
int i = start;
int j = end;
while(i > j){
So, it is expected this will do nothiong. The while will never enter.
I try to implement the merge sort algorithm and I get a segmentation fault. Why? The error seems to be in the MergeSort function. The merge sort function (on the 2nd call) when should check only an array of 4 numbers (the length should be 4) shows the length = 27. Why? (tested on an array with 8 elements)
#include<iostream>
using namespace std;
int n, A[1000];
void citire(int lungime) {
for (int i = 0; i < lungime; i++) cin >> A[i];
}
void afisare(int lungime) {
for (int i = 0; i < lungime; i++)
cout << A[i] << " ";
cout << '\n';
}
int lungime(int A[]) {
int i = 0;
while (A[i]) i++;
return i;
}
void Merge(int L[], int R[], int A[]) {
int nL = lungime(L);
int nR = lungime(R);
int i = 0, j = 0, k = 0;
while (i < nL && j < nR) {
if (L[i] <= R[j]) {
A[k] = L[i];
i++;
}
else {
A[k] = R[j];
j++;
}
k++;
}
while (i < nL) {
A[k] = L[i];
i++;
k++;
}
while (j < nR) {
A[k] = R[j];
j++;
k++;
}
}
void MergeSort(int A[]) {
int n1 = lungime(A);
if (n1 < 2) return;
else
{
int mid = (int)n1 / 2;
int L[mid];
int R[n - mid];
for (int i = 0; i < mid; i++)
L[i] = A[i];
for (int i = mid; i < n; i++)
R[i - mid] = A[i];
MergeSort(L);
MergeSort(R);
Merge(L, R, A);
}
}
int main() {
cin >> n;
citire(n);
MergeSort(A);
afisare(n);
return 0;
}
Changes made in this example. A[], L[], R[] are allocated using new. A[] is passed as a parameter. L[] and R[] are allocated in Merge(). Size and/or indices passed as parameters, and lungime() is no longer used to get size. Other changes noted in comments.
#include<iostream>
using namespace std;
void citire(int A[], int lungime) { // A is parameter
for (int i = 0; i < lungime; i++) cin >> A[i];
}
void afisare(int A[], int lungime) { // A is parameter
for (int i = 0; i < lungime; i++)
cout << A[i] << " ";
cout << '\n';
}
// A, low, mid, end are parameters
// L and R allocated here
void Merge(int A[], int low, int mid, int end) {
int sizeL = mid-low;
int sizeR = end-mid;
int *L = new int[sizeL];
int *R = new int[sizeR];
for(int i = 0; i < sizeL; i++)
L[i] = A[low+i]; // A[low+i]
for(int i = 0; i < sizeR; i++)
R[i] = A[mid+i]; // A[mid+i]
int i = 0, j = 0, k = low; // k = low
while (i < sizeL && j < sizeR) {
if (L[i] <= R[j]) {
A[k] = L[i];
i++;
}
else {
A[k] = R[j];
j++;
}
k++;
}
while (i < sizeL) {
A[k] = L[i];
i++;
k++;
}
while (j < sizeR) {
A[k] = R[j];
j++;
k++;
}
delete[] R;
delete[] L;
}
// A, low, end are parameters
void MergeSort(int A[], int low, int end) {
int sizeA = end - low;
if(sizeA < 2)
return;
int mid = low + (sizeA / 2); // mid = low + ...
MergeSort(A, low, mid);
MergeSort(A, mid, end);
Merge(A, low, mid, end);
}
int main() {
int n;
cin >> n;
int *A = new int[n]; // A is allocated
citire(A, n); // A, n are parameters
MergeSort(A, 0, n); // A, 0, n are parameters
afisare(A, n); // A, n are parameters
delete[] A;
return 0;
}
"The lungime function is the length of the string and this function works good. I've tested it on different arrays".
Well, this is purely accidental; uninitialized memory can contain zeros, and provide the array terminator by accident.
If you want to keep the current design, you should:
initialize A to zeros
make sure that there are no more than 999 elements in the input stream,
that no element has the value zero, as zero is reserved, and used as terminator, and
define L and R (in MergeSort) one element longer, and initialize the last element to zero.
Unless there are overwhelming reasons for a "roll your own" sort solution, you might have a look at prefab sort support. The vector class in C++ offers just that.
So i've for a school project i've been assigned to implement a merge sort from a pseudo code given by the professor. This is what i came up with, in my use case,
instead of ordering:
0 1 4 5 9
it orders it:
5 4 1 0 9
My use case:
5 9 1 0 5 4
here is the merge part of the merge sort and the global variables
long long intercambio;
int aux[5555], arr[555];
void merge(int begin, int middle, int end) {
int i = begin, j = middle+1, k = begin, temp;
while (i <= middle && j <= end) {
if (arr[i] < arr[j]) {
aux[k] = arr[i];
i++;
}
else {
aux[k] = arr[j];
j++;
}
k++;
noSwaps++;
}
if (i > middle) {
while (j <= end) {
if (aux[k -1] > arr[j]) {
temp = aux[k - 1];
aux[k - 1] = arr[j];
aux[k] = temp;
noSwaps++;
}
else {
aux[k] = arr[j];
}
k++;
j++;
}
}
else {
while (i <= middle) {
if (aux[k -1] > arr[i]) {
temp = aux[k - 1];
aux[k - 1] = arr[i];
aux[k] = temp;
noSwaps++;
}
else {
aux[k] = arr[i];
}
k++;
i++;
}
}
}
Here i call recursively the merge sort
void mergeSort(int begin, int end) {
if (begin < end) {
int middle = (begin + end) / 2;
mergeSort(begin, middle);
mergeSort(middle + 1, end);
merge(begin, middle, end);
}
}
This is the main class
int main(int argc, const char * argv[])
{
int len;
cin >> len;
while (len != 0) {
for (int x = 0; x < len; x++)
cin >> arr[x];
noSwaps = 0;
mergeSort(0, len - 1);
for (int x = 0; x < len; x++)
cout << aux[x] << " ";
cout << endl;
cout << noSwaps << endl;
cin >> len;
}
return 0;
}
I don't see why your code inside the if (i > middle) block and its else block are so complicated. All you have to do is copy the remaining elements into aux, and then from aux back to arr:
void merge(int begin, int middle, int end) {
int i = begin, j = middle+1, k = begin, temp;
while (i <= middle && j <= end) {
// ... same as before ...
}
while (i <= middle)
{
aux[k++] = arr[i++];
}
while (j <= end)
{
aux[k++] = arr[j++];
}
for (i = begin; i <= end; ++i)
{
arr[i] = aux[i];
}
}
This may or may not be less (or more) efficient than your solution, but at least it works :)
By the way, there is a cute trick to implementing merge sort where you don't have to worry about exhausting one range before the other. You copy the left range to aux in ascending order, and the right range in descending order. Then you start merging from both ends, and when the indexes meet, both ranges are exhausted:
void merge(int begin, int middle, int end)
{
int i, j, k;
for (i = begin; i <= middle; ++i)
{
aux[i] = arr[i];
}
for (j = end; j > middle; --j, ++i)
{
aux[i] = arr[j];
}
i = begin;
j = end;
k = begin;
while (i <= j)
{
arr[k++] = aux[(aux[i] < aux[j]) ? i++ : j--];
}
}
This solution appears to produce the wrong output, but only because there is a bug inside main:
for (int x = 0; x < len; x++)
cout << aux[x] << " ";
You are printing aux, when in fact you should be printing arr:
for (int x = 0; x < len; x++)
cout << arr[x] << " ";
I have studied the theory of the merge sort but don't have any idea of how to implement it in C++. My question is, merge sort creates arrays in recursion. But when implementing, how do we create arrays in runtime? or what is the general approach for this?
Thanks.
To answer the question: Creating dynamically sized arrays at run-time is done using std::vector<T>. Ideally, you'd get your input using one of these. If not, it is easy to convert them. For example, you could create two arrays like this:
template <typename T>
void merge_sort(std::vector<T>& array) {
if (1 < array.size()) {
std::vector<T> array1(array.begin(), array.begin() + array.size() / 2);
merge_sort(array1);
std::vector<T> array2(array.begin() + array.size() / 2, array.end());
merge_sort(array2);
merge(array, array1, array2);
}
}
However, allocating dynamic arrays is relatively slow and generally should be avoided when possible. For merge sort you can just sort subsequences of the original array and in-place merge them. It seems, std::inplace_merge() asks for bidirectional iterators.
Based on the code here: http://cplusplus.happycodings.com/algorithms/code17.html
// Merge Sort
#include <iostream>
using namespace std;
int a[50];
void merge(int,int,int);
void merge_sort(int low,int high)
{
int mid;
if(low<high)
{
mid = low + (high-low)/2; //This avoids overflow when low, high are too large
merge_sort(low,mid);
merge_sort(mid+1,high);
merge(low,mid,high);
}
}
void merge(int low,int mid,int high)
{
int h,i,j,b[50],k;
h=low;
i=low;
j=mid+1;
while((h<=mid)&&(j<=high))
{
if(a[h]<=a[j])
{
b[i]=a[h];
h++;
}
else
{
b[i]=a[j];
j++;
}
i++;
}
if(h>mid)
{
for(k=j;k<=high;k++)
{
b[i]=a[k];
i++;
}
}
else
{
for(k=h;k<=mid;k++)
{
b[i]=a[k];
i++;
}
}
for(k=low;k<=high;k++) a[k]=b[k];
}
int main()
{
int num,i;
cout<<"*******************************************************************
*************"<<endl;
cout<<" MERGE SORT PROGRAM
"<<endl;
cout<<"*******************************************************************
*************"<<endl;
cout<<endl<<endl;
cout<<"Please Enter THE NUMBER OF ELEMENTS you want to sort [THEN
PRESS
ENTER]:"<<endl;
cin>>num;
cout<<endl;
cout<<"Now, Please Enter the ( "<< num <<" ) numbers (ELEMENTS) [THEN
PRESS ENTER]:"<<endl;
for(i=1;i<=num;i++)
{
cin>>a[i] ;
}
merge_sort(1,num);
cout<<endl;
cout<<"So, the sorted list (using MERGE SORT) will be :"<<endl;
cout<<endl<<endl;
for(i=1;i<=num;i++)
cout<<a[i]<<" ";
cout<<endl<<endl<<endl<<endl;
return 1;
}
I have completed #DietmarKühl s way of merge sort. Hope it helps all.
template <typename T>
void merge(vector<T>& array, vector<T>& array1, vector<T>& array2) {
array.clear();
int i, j, k;
for( i = 0, j = 0, k = 0; i < array1.size() && j < array2.size(); k++){
if(array1.at(i) <= array2.at(j)){
array.push_back(array1.at(i));
i++;
}else if(array1.at(i) > array2.at(j)){
array.push_back(array2.at(j));
j++;
}
k++;
}
while(i < array1.size()){
array.push_back(array1.at(i));
i++;
}
while(j < array2.size()){
array.push_back(array2.at(j));
j++;
}
}
template <typename T>
void merge_sort(std::vector<T>& array) {
if (1 < array.size()) {
std::vector<T> array1(array.begin(), array.begin() + array.size() / 2);
merge_sort(array1);
std::vector<T> array2(array.begin() + array.size() / 2, array.end());
merge_sort(array2);
merge(array, array1, array2);
}
}
I've rearranged the selected answer, used pointers for arrays and user input for number count is not pre-defined.
#include <iostream>
using namespace std;
void merge(int*, int*, int, int, int);
void mergesort(int *a, int*b, int start, int end) {
int halfpoint;
if (start < end) {
halfpoint = (start + end) / 2;
mergesort(a, b, start, halfpoint);
mergesort(a, b, halfpoint + 1, end);
merge(a, b, start, halfpoint, end);
}
}
void merge(int *a, int *b, int start, int halfpoint, int end) {
int h, i, j, k;
h = start;
i = start;
j = halfpoint + 1;
while ((h <= halfpoint) && (j <= end)) {
if (a[h] <= a[j]) {
b[i] = a[h];
h++;
} else {
b[i] = a[j];
j++;
}
i++;
}
if (h > halfpoint) {
for (k = j; k <= end; k++) {
b[i] = a[k];
i++;
}
} else {
for (k = h; k <= halfpoint; k++) {
b[i] = a[k];
i++;
}
}
// Write the final sorted array to our original one
for (k = start; k <= end; k++) {
a[k] = b[k];
}
}
int main(int argc, char** argv) {
int num;
cout << "How many numbers do you want to sort: ";
cin >> num;
int a[num];
int b[num];
for (int i = 0; i < num; i++) {
cout << (i + 1) << ": ";
cin >> a[i];
}
// Start merge sort
mergesort(a, b, 0, num - 1);
// Print the sorted array
cout << endl;
for (int i = 0; i < num; i++) {
cout << a[i] << " ";
}
cout << endl;
return 0;
}
#include <iostream>
using namespace std;
template <class T>
void merge_sort(T array[],int beg, int end){
if (beg==end){
return;
}
int mid = (beg+end)/2;
merge_sort(array,beg,mid);
merge_sort(array,mid+1,end);
int i=beg,j=mid+1;
int l=end-beg+1;
T *temp = new T [l];
for (int k=0;k<l;k++){
if (j>end || (i<=mid && array[i]<array[j])){
temp[k]=array[i];
i++;
}
else{
temp[k]=array[j];
j++;
}
}
for (int k=0,i=beg;k<l;k++,i++){
array[i]=temp[k];
}
delete temp;
}
int main() {
float array[] = {1000.5,1.2,3.4,2,9,4,3,2.3,0,-5};
int l = sizeof(array)/sizeof(array[0]);
merge_sort(array,0,l-1);
cout << "Result:\n";
for (int k=0;k<l;k++){
cout << array[k] << endl;
}
return 0;
}
The problem with merge sort is the merge, if you don't actually need to implement the merge, then it is pretty simple (for a vector of ints):
#include <algorithm>
#include <vector>
using namespace std;
typedef vector<int>::iterator iter;
void mergesort(iter b, iter e) {
if (e -b > 1) {
iter m = b + (e -b) / 2;
mergesort(b, m);
mergesort(m, e);
inplace_merge(b, m, e);
}
}
I know this question has already been answered, but I decided to add my two cents. Here is code for a merge sort that only uses additional space in the merge operation (and that additional space is temporary space which will be destroyed when the stack is popped). In fact, you will see in this code that there is not usage of heap operations (no declaring new anywhere).
Hope this helps.
void merge(int *arr, int size1, int size2) {
int temp[size1+size2];
int ptr1=0, ptr2=0;
int *arr1 = arr, *arr2 = arr+size1;
while (ptr1+ptr2 < size1+size2) {
if (ptr1 < size1 && arr1[ptr1] <= arr2[ptr2] || ptr1 < size1 && ptr2 >= size2)
temp[ptr1+ptr2] = arr1[ptr1++];
if (ptr2 < size2 && arr2[ptr2] < arr1[ptr1] || ptr2 < size2 && ptr1 >= size1)
temp[ptr1+ptr2] = arr2[ptr2++];
}
for (int i=0; i < size1+size2; i++)
arr[i] = temp[i];
}
void mergeSort(int *arr, int size) {
if (size == 1)
return;
int size1 = size/2, size2 = size-size1;
mergeSort(arr, size1);
mergeSort(arr+size1, size2);
merge(arr, size1, size2);
}
int main(int argc, char** argv) {
int num;
cout << "How many numbers do you want to sort: ";
cin >> num;
int a[num];
for (int i = 0; i < num; i++) {
cout << (i + 1) << ": ";
cin >> a[i];
}
// Start merge sort
mergeSort(a, num);
// Print the sorted array
cout << endl;
for (int i = 0; i < num; i++) {
cout << a[i] << " ";
}
cout << endl;
return 0;
}
Here's a way to implement it, using just arrays.
#include <iostream>
using namespace std;
//The merge function
void merge(int a[], int startIndex, int endIndex)
{
int size = (endIndex - startIndex) + 1;
int *b = new int [size]();
int i = startIndex;
int mid = (startIndex + endIndex)/2;
int k = 0;
int j = mid + 1;
while (k < size)
{
if((i<=mid) && (a[i] < a[j]))
{
b[k++] = a[i++];
}
else
{
b[k++] = a[j++];
}
}
for(k=0; k < size; k++)
{
a[startIndex+k] = b[k];
}
delete []b;
}
//The recursive merge sort function
void merge_sort(int iArray[], int startIndex, int endIndex)
{
int midIndex;
//Check for base case
if (startIndex >= endIndex)
{
return;
}
//First, divide in half
midIndex = (startIndex + endIndex)/2;
//First recursive call
merge_sort(iArray, startIndex, midIndex);
//Second recursive call
merge_sort(iArray, midIndex+1, endIndex);
merge(iArray, startIndex, endIndex);
}
//The main function
int main(int argc, char *argv[])
{
int iArray[10] = {2,5,6,4,7,2,8,3,9,10};
merge_sort(iArray, 0, 9);
//Print the sorted array
for(int i=0; i < 10; i++)
{
cout << iArray[i] << endl;
}
return 0;
}
This would be easy to understand:
#include <iostream>
using namespace std;
void Merge(int *a, int *L, int *R, int p, int q)
{
int i, j=0, k=0;
for(i=0; i<p+q; i++)
{
if(j==p) //When array L is empty
{
*(a+i) = *(R+k);
k++;
}
else if(k==q) //When array R is empty
{
*(a+i) = *(L+j);
j++;
}
else if(*(L+j) < *(R+k)) //When element in L is smaller than element in R
{
*(a+i) = *(L+j);
j++;
}
else //When element in R is smaller or equal to element in L
{
*(a+i) = *(R+k);
k++;
}
}
}
void MergeSort(int *a, int len)
{
int i, j;
if(len > 1)
{
int p = len/2 + len%2; //length of first array
int q = len/2; //length of second array
int L[p]; //first array
int R[q]; //second array
for(i=0; i<p; i++)
{
L[i] = *(a+i); //inserting elements in first array
}
for(i=0; i<q; i++)
{
R[i] = *(a+p+i); //inserting elements in second array
}
MergeSort(&L[0], p);
MergeSort(&R[0], q);
Merge(a, &L[0], &R[0], p, q); //Merge arrays L and R into A
}
else
{
return; //if array only have one element just return
}
}
int main()
{
int i, n;
int a[100000];
cout<<"Enter numbers to sort. When you are done, enter -1\n";
i=0;
while(true)
{
cin>>n;
if(n==-1)
{
break;
}
else
{
a[i] = n;
i++;
}
}
int len = i;
MergeSort(&a[0], len);
for(i=0; i<len; i++)
{
cout<<a[i]<<" ";
}
return 0;
}
This is my version (simple and easy):
uses memory only twice the size of original array.
[ a is the left array ] [ b is the right array ] [ c used to merge a and b ] [ p is counter for c ]
void MergeSort(int list[], int size)
{
int blockSize = 1, p;
int *a, *b;
int *c = new int[size];
do
{
for (int k = 0; k < size; k += (blockSize * 2))
{
a = &list[k];
b = &list[k + blockSize];
p = 0;
for (int i = 0, j = 0; i < blockSize || j < blockSize;)
{
if ((j < blockSize) && ((k + j + blockSize) >= size))
{
++j;
}
else if ((i < blockSize) && ((k + i) >= size))
{
++i;
}
else if (i >= blockSize)
{
c[p++] = b[j++];
}
else if (j >= blockSize)
{
c[p++] = a[i++];
}
else if (a[i] >= b[j])
{
c[p++] = b[j++];
}
else if (a[i] < b[j])
{
c[p++] = a[i++];
}
}
for (int i = 0; i < p; i++)
{
a[i] = c[i];
}
}
blockSize *= 2;
} while (blockSize < size);
}